
The digit-sum twist on a design
Fix a base b >= 3, a set E of m >= 1 excluded digits, the rest F with fill = b - m, and the missing-digit design S_F of mobius: the positive integers whose base-b digits all lie in F. That page bounds M_F(x) = sum_(n in S_F, n <= x) mu(n) unconditionally only at the shape A_F(x) exp(-c sqrt(log x)), and coprime carries the same shape for the primes of the design; in both, the ceiling is the major arcs, where mu and Lambda must be read in progressions mod powers of b through a zero-free region. This page twists the design by its digit sum and shows that the twisted transform loses a fixed share of its mass per pair of digits at every frequency, so the major arcs need no L-function and the saving becomes a power of x. Every number is printed by lab/py/digit-sum-twist.
The objects
s_b(n)is the sum of the base-bdigits ofn,D_kthe digit strings of lengthkoverFread as integers in[0, b^k),g_F(t) = sum_(d in F) e(d t)the digit symbol andA_F(x)the count ofS_Fup tox, all as on mobius.- The twisted weight is
w(n) = 1_(S_F)(n) e(alpha s_b(n))for a realalpha, and its transform at depthkishat w_k(t) = sum_(n in D_k) e(alpha s_b(n) + n t). Withn = sum_j d_j b^jthe phase issum_j d_j (b^j t + alpha), and the digits are independent, sohat w_k(t) = prod_(j < k) g_F(b^j t + alpha). Atalpha = 0this is the transformhat F_kof mobius. - The twisted meters are
M_F(x; alpha) = sum_(n in S_F, n <= x) mu(n) e(alpha s_b(n))andpsi_F(x; alpha) = sum_(n in S_F, n <= x) Lambda(n) e(alpha s_b(n)). beta = norm((b - 1) alpha)is the distance from(b - 1) alphato the nearest integer, and the lattice is the set(b - 1)^(-1) Zofalphawithbeta = 0.B_b(F) = sup_t sum_(r mod b) abs(g_F((t + r)/b))is the one-step constant of mobius, a supremum over every shiftt. The certificate (W) of that page's unconditional dissection isB_b(F) <= fill b^(alpha_1)withalpha_1 < 1/5, read from the per-digit constantsPB_b(m)orPB'_b(1, e_0);alpha_b = log(fill)/log(b).V_F = fill^(-1) sum_(d in F) (d - mean(F))^2is the variance of the digit set,K_b(x) = max(sin(pi b x)/sin(pi x), 1/sin(pi/b))andx_f = 1/(2(b - 1)).
The two-position lemma
- The lemma. Proved. Let
Fkeep two consecutive digits, putx_0 = beta/(b + 1)and letG_F(x_0) = sup of abs(g_F(v))overnorm(v) >= x_0. Then for every realuandalpha,abs(g_F(u + alpha) g_F(b u + alpha)) <= fill G_F(x_0), andG_F(x_0) <= min(G_1, G_2, G_3)with the pair formG_1 = fill - 4 sin^2(pi x_0/2), the kernel formG_2 = m + K_b(x_0)and the variance formG_3 = max(fill sqrt(1 - 16 x_0^2 V_F), min(m + K_b(x_f), fill - 4 sin^2(pi x_f/2))). So withc = c(b, F, beta) = 1 - min(G_1, G_2, G_3)/fill, which is positive wheneverbeta > 0becauseG_1 < fill,sup_t abs(hat w_k(t)) <= fill^k (1 - c)^(floor(k/2)) <= (1 - c)^(-1/2) fill^k b^(-gamma k)at everyk, withgamma = log(1/(1 - c))/(2 log b). - Proof. Locating: put
v_1 = u + alphaandv_2 = b u + alpha. Thenb v_1 - v_2 = (b - 1) alpha, sobeta = norm(b v_1 - v_2) <= b norm(v_1) + norm(v_2) <= (b + 1) max(norm(v_1), norm(v_2)), and one of the two phases hasnorm(v_i) >= x_0; its factor is at mostG_F(x_0)and the other at mostfill. The pair form: withd, d + 1inF,abs(g_F(v)) <= fill - 2 + abs(1 + e(v)) = fill - 2 + 2 abs(cos(pi v)) = fill - 4 sin^2(pi norm(v)/2), which falls asnorm(v)rises. The kernel form:g_F = D_b - g_EwithD_b(v) = sum_(n < b) e(n v)andabs(g_E) <= m; atx = norm(v)in(0, 1/b],abs(D_b(v)) = sum_(n < b) cos(2 pi (n - (b - 1)/2) x), each term falling inxbecause2 pi abs(n - (b - 1)/2) x < pi, so its supremum over[x_0, 1/b]sits atx_0 <= 1/(2(b + 1)) < 1/b, and on[1/b, 1/2]it is at most1/sin(pi/b). The variance form:abs(g_F(v))^2 = sum_(d, d' in F) cos(2 pi (d - d') x) = fill^2 - 2 sum_(d, d') sin^2(pi (d - d') x), and atx <= x_feveryabs(d - d') x <= 1/2, wheresin^2(pi y) >= 4 y^2, whilesum_(d, d') (d - d')^2 = 2 fill^2 V_F; soabs(g_F(v)) <= fill sqrt(1 - 16 x^2 V_F), falling inx, on[x_0, x_f], and pastx_f, which is at most1/b, the pair and kernel forms atx_fapply. The product: pair the positions2i, 2i + 1ofhat w_k(t) = prod_(j < k) g_F(b^j t + alpha)withu = b^(2i) t, bound an odd last factor byfill, and usefloor(k/2) >= (k - 1)/2. - The dichotomy is exact. Proved. On the lattice the lemma cannot hold: at
t = -alphaevery phase isb^j t + alpha = -(b^j - 1) alpha, an integer becauseb^j - 1is a multiple ofb - 1, soabs(hat w_k(-alpha)) = fill^kat everyk. With two consecutive digits the twisted transform loses a fixed fraction of its mass at every frequency exactly whenalphais off the lattice. - The consecutive pair is needed. Verified. At base 5,
F = {0, 2}andalpha = 1/8, off the lattice withbeta = 1/2, every phase5^j (3/8) + 1/8 = (3 * 5^j + 1)/8lies inZ/2, whereabs(g_F) = 2, soabs(hat w_k(3/8)) = 2^k = fill^kat everyk; the generator reads1to twelve digits atk = 4, 8, 12(verblemma). - The constants. Verified. At base 10 missing
7:c >= 0.1500andgamma >= 0.0352atalpha = 1/2,c >= 0.0463at1/7,0.0353at1/4,0.0224at1/5,0.0055at1/10, and5.55 * 10^-5at1/900(beta = 0.01), each from the variance form, which beats the pair form by a factor66atalpha = 1/2and61at1/900. At large base the kernel form carriesbeta = 1/2and0.2,c >= 0.3633and0.0644atbase 92317, and the variance form carries smallbeta,c >= 6.666 * 10^-7atbeta = 10^-3: to leading order it givesc = 8 x_0^2 V_F, and sinceV_Fis aboutb^2/12andx_0aboutbeta/b, that iscabout(2/3) beta^2at smallbetaand large base, where the pair form alone decays likebeta^2 b^(-3)(verblemma).
The twisted peel
- The peel. Proved. For every
alpha, everyi >= 1and every reals, the twisted grid sumSigma_i(s) = sum_(a < b^i) abs(hat w_i(s + a/b^i))obeysSigma_i(s) <= B_b(F) Sigma_(i-1)(b s), soSigma_i(s) <= B_b(F)^i, and under (W)Sigma_i(s) <= fill^i b^(i alpha_1): the certificate of mobius withC_F = 1, at every shift, for the twisted transform. Proof:hat w_i(t) = g_F(t + alpha) hat w_(i-1)(b t)andhat w_(i-1)has period1. Writea = a' + r b^(i-1)witha' < b^(i-1)andr < b; thenb (s + a/b^i) = b s + a'/b^(i-1) + r, so the second factor depends ona'alone, ands + a/b^i + alpha = (T + r)/bwithT = b (s + alpha) + a'/b^(i-1), so the sum overrissum_(r mod b) abs(g_F((T + r)/b)) <= B_b(F). The twist moves only the shiftT, andB_b(F)is a supremum over every shift. - The hybrid bound transfers. Proved. The hybrid
l^1bound of mobius reads the transform through three things: the splithat F_k(t) = hat F_(i_1)(t) hat F_(k - i_1 - i_2)(V_1 t) hat F_(i_2)(y t/V_2), the certificate at a shift or ats = 0, andabs(g_F') <= pi b (b - 1)at one position. The split holds forhat w_k = prod_(j < k) g_F(b^j t + alpha)with the same three factors read forhat w, the derivative ofg_F(v + alpha)invhas the same bound, and the shifted grids its proof integrates over are covered by the peel above, as isint_0^1 abs(hat w_i) <= b^(-i) B_b(F)^i. So under (W),sum_(a in R(D, H)) abs(hat w_k(a/y)) <= (1 + pi b) fill^k (V_1 V_2)^(alpha_1)at everyalpha, withR(D, H),V_1andV_2as there. - The chain and the window do not transfer as written. The digit-uniform chain of coprime, which carries the untwisted certificate down to
base 584, telescopes a run of positions into one Dirichlet kernel,prod_(j < l) D_b(b^j u) = D_(b^l)(u), which needs consecutive arguments in ratiob; the twisted arguments areb^j t + alpha, andb (b^j t + alpha) = b^(j+1) t + b alphadiffers fromb^(j+1) t + alphamod1unlessbeta = 0. The window certificates of the same page bound a supremum over the one-parameter family of shiftss, while a twisted window sees the shift vector(b^j s + alpha)_j. Neither is refuted; neither is carried, so only the per-digit (W) serves here. - The readings. Verified. At base 10 missing
7the grid supremum ofsum_(r mod b) abs(g_F((T + r)/b))reads24.702183on2 * 10^5shifts, certified below24.702781by the Lipschitz margin, against the floor2(b - 1) = 18and the step 3 bound39.6623. Over16classes ofalpha,12shifts and depths1..5,960checks, the one-step identity holds to1.40 * 10^-11andSigma_i(s)/B^iandSigma_i(s)/(B Sigma_(i-1)(b s))stay below0.999914. The twist raises the unshifted mass,Sigma_5(0)^(1/5)reading21.7151atalpha = 1/2and22.3176at1/7against19.5656untwisted: it moves mass toward the shifted supremum, which (W) already pays (verbpeel).
The power saving
- The theorem. Proved. Let
Fkeep two consecutive digits and satisfy (W), soB_b(F) <= fill b^(alpha_1)withalpha_1 < 1/5, and letbeta = norm((b - 1) alpha) > 0. Withc = c(b, F, beta)andgammaof the two-position lemma, putsigma = gamma (1 - 4 alpha_1)/(5 - 4 alpha_1),eta = min(1/5 - alpha_1, sigma)anddelta_0 = alpha_b eta/4. Then for everydelta < delta_0there is an effectiveC, depending onb,F,betaanddeltaalone, withabs(M_F(x; alpha)) <= C A_F(x) x^(-delta)andabs(psi_F(x; alpha)) <= C A_F(x) x^(-delta)at everyx >= 2. Sincecrises withbeta, the sameCserves everyalphawithnorm((b - 1) alpha) >= beta. The bullets below are the proof; the blocks, the dissection and the minor arcs are those of the unconditional dissection of mobius and its von Mangoldt form on coprime, and only the depth of the blocks and the major arcs change. - The blocks, at power depth. The block split of mobius writes
S_Fbelowxas at mostfill + 1blocksP y + D_k,y = b^k, at each scalek < L, the shorter elements included, and the pointx. On a blocks_b(P y + t) = s_b(P) + s_b(t)fort < y, so its twisted sum ise(alpha s_b(P)) Sigma(P, k)withSigma(P, k) = sum_(t in D_k) e(alpha s_b(t)) mu(P y + t) = y^(-1) sum_(a mod y) hat w_k(a/y) S_P(-a/y), by orthogonality onZ/yapplied tot -> 1_(D_k)(t) e(alpha s_b(t)), whose transform ata/yishat w_k(a/y), andS_P(theta) = sum_(P y <= n < (P+1) y) mu(n) e(n theta); forLambdareadLambdain both. Puttau = eta/4. The scales withb^k < x^(1 - tau)weigh at most2 (fill + 1) fill^(k_0),k_0the largest of them, withfill^(k_0) < x^((1 - tau) alpha_b), which is<< A_F(x) x^(-tau alpha_b)by the mass floorA_F(x) >= fill^(L-1) - 1 >= (x/b)^(alpha_b) - 1, timeslog xforLambda. Every other block hasr = x/y <= x^tau. - The dissection. On such a block put
Q = y^(3/5)andZ = y^zetawithzeta = 2 gamma/(5 - 4 alpha_1), which is below2/5: each ofG_1,G_2,G_3is at leastmin(fill - 1, m + b/pi) >= fill/pi, sogamma <= log(pi)/(2 log 3) < 0.53at every base,zeta < 0.26andzeta < gamma/2; give eacha mod yits Dirichlet fractionl/d,d <= Q, and its heighth = abs(a d - l y) <= y^(2/5), and cut three regions: A isd >= y^(2/5), B isd < y^(2/5)withmax(d, h) >= Z, and C isd < Zandh < Z, the union of the C1 and C2 of mobius. - The minor arcs. For
muthe bullet The minor-arc input of mobius (Basak, Robles and Zaharescu, Theorem 1.4, at both approximations) and forLambdathe bullet The minor arcs, at source of coprime (Maynard 2022, Lemma 4.2, at a coarser fraction) give, withx^(o(1))there replaced by the ratior: on A,x d^(-1/2) <= x y^(-1/5) = x^(4/5) r^(1/5)and(x d)^(1/2) <= x^(4/5), soabs(S_P(a/y)) <<_eps x^(4/5 + eps) r^(1/5); on B the same term plusx (log x)^4 max(d, h)^(-1/2), the second approximation'sx (h/y)^(1/2) <= x^(7/10) r^(3/10)lying belowx^(4/5) r^(1/5)becauser <= x. - Region A. By the peel at
s = 0its residues carry at mostB_b(F)^k <= fill^k y^(alpha_1), so region A is<<_eps y^(-1) fill^k y^(alpha_1) (r y)^(4/5 + eps) r^(1/5) <= fill^k r^(1 + eps) y^(alpha_1 - 1/5 + eps). - Region B. Group its residues into the classes
D <= d < 2D,H <= h < 2Horh = 0of mobius, at most(log_2 y + 2)^2of them, each with16 b^2 D (D + H) <= 32 b^2 y^(4/5) <= yoncey >= (32 b^2)^5andmax(D, H) > Z/2. By the transferred hybrid bound a class weighs at mosty^(-1) abs(S_P) (1 + pi b) fill^k (32 b^2 max(D, H)^2)^(alpha_1). The first term ofabs(S_P)withmax(D, H) <= y^(2/5)gives<<_eps fill^k r^(1 + eps) y^((4/5) alpha_1 - 1/5 + eps), below region A's exponent, and the second withmax(D, H) > Z/2and2 alpha_1 - 1/2 < 0gives<< fill^k r (log x)^4 Z^(2 alpha_1 - 1/2) = fill^k r (log x)^4 y^(-zeta (1/2 - 2 alpha_1)) = fill^k r (log x)^4 y^(-sigma). - Region C, with no L-function. It holds at most
sum_(d < Z) phi(d) (2Z/d + 1) <= 3 Z^2residues,abs(S_P) <= yformuand<= y log(2x)forLambda, and the two-position lemma givesabs(hat w_k(a/y)) <= (1 - c)^(-1/2) fill^k y^(-gamma)at every residue. So region C is at most3 (1 - c)^(-1/2) fill^k Z^2 y^(-gamma) log(2x) = 3 (1 - c)^(-1/2) fill^k y^(2 zeta - gamma) log(2x), andgamma - 2 zeta = sigmaby the choice ofzeta. No Lemma A', no input (M), no Perron integral and no exceptional zero enters: the whole region, C1 and C2 together, is paid by the lemma. - Assembly. The three regions give
abs(Sigma(P, k)) <<_eps fill^k r^(1 + eps) y^(-eta + eps) (log x)^6withr <= x^tauandy >= x^(1 - tau), and the blocks at these scales, at mostfill + 1per scale, carry(fill + 1) sum_(k < L) fill^k <= (fill + 1) fill^L <= (fill + 1) fill (A_F(x) + 1). So they weigh<<_eps A_F(x) x^(tau (1 + eps) - (1 - tau)(eta - eps)) (log x)^6, and attau = eta/4the exponent is at most-3 eta/4 + eta^2/4 + 2 eps <= -eta/2 + 2 epssinceeta <= 1/5; the discarded scales savex^(-tau alpha_b) = x^(-eta alpha_b/4). Everydelta < alpha_b eta/4 = delta_0follows on takingepssmall, every step that askedylarge holding forxpast an effective point and the rest absorbed intoC. - Where it holds. Proved. At one excluded digit (W) holds at every
base >= 92317through the step 3 constant, a half line by the proved floor of the ladder on mobius; so the theorem is Proved at every one-missing-digit set frombase 92317. Atm > 1it holds whereverPB_b(m) < fill b^(-4/5), which admitsm <= 176atbase 10^7; the wall itself is certified in interval arithmetic at 200 bits,1/5 - alpha_1 >= 1.87123612 * 10^-8at92317and<= -4.82092732 * 10^-8at92316(verblemma). - Below
92317on the scan. Verified. On the float-scanned chord wall of mobius (W) holds frombase 39363at every excluded digit and from28352ate_0 in {0, b - 1}, so the theorem holds there on that scan, which is never Proved. - The exponent. Verified.
delta_0 >= 4.678 * 10^-9atbase 92317atbeta = 1/2and atbeta = 0.2, where region A binds through1/5 - alpha_1 >= 1.871 * 10^-8, anddelta_0 >= 3.47 * 10^-10atbeta = 10^-3, where region C binds; on the chord walldelta_0 >= 6.741 * 10^-8atbase 39363,beta = 1/2; atbase 10^6,delta_0 >= 2.819 * 10^-4atbeta = 1/2and4.163 * 10^-5atbeta = 0.2. Each is printed withcandgammaread at the extreme excluded digit, whose variance is the least, and floored at four digits. Region A binds only just above the wall: bisection between92317and10^6puts the switch tosigmaat100084atbeta = 1/2and at93409atbeta = 0.2, andsigmabinds at10^6at both (verblemma). - The paper. The theorem, the two-position lemma, the twisted peel and the corollary are written up for an outside reader as A Power Saving for the Digit Sum on Missing Digits.
Which region needs what
- The ledger of inputs. Proved, by the proof above set beside the dissection of mobius.
- Region A: the certificate (W) through the peel at
s = 0and the minor-arc exponent4/5, unchanged by the twist; it asksalpha_1 < 1/5and sets the wall. - Region B: (W) through the transferred hybrid bound and the second approximation, unchanged; it asks
alpha_1 < 1/4, and withZa power ofyits savingZ^(2 alpha_1 - 1/2)becomes a power. - Region C, the old C1 and C2: only the two-position lemma, which asks two consecutive digits and
beta > 0; in the untwisted dissection C1 needed Lemma A' of coprime and C2 needed the input (M) formuor (M_Lambda) forLambda, the zero-free regions of Chang and Martin and of Koukoulopoulos and the finite family of exceptional characters, and none of them is used. - The blocks: depth
tau log_b xin place of thekappa sqrt(log x)of mobius, because no region now capsZatexp(C_0 sqrt(log x)). - The certificate: only the per-digit (W) serves, so the theorem's wall at one excluded digit is that of (W),
92317by proof and39363on the float scan, against584,301and115for the untwisted bound on the chain and window certificates. - So the twist trades the base for the shape: the untwisted bound is Proved from
base 584and holds frombase 115on the window certificates, atexp(-c sqrt(log x)); the twisted one is Proved frombase 92317, atx^(-delta).
The lattice and the ceiling
- On the lattice the twist is a character. Proved. If
(b - 1) alphais an integer thene(alpha s_b(n)) = e(alpha n), becausen - s_b(n)is a multiple ofb - 1; sohat w_k(t) = hat F_k(t + alpha), the untwisted transform translated, andM_F(x; alpha) = sum_(c mod b-1) e(alpha c) M_F(x; b - 1, c), a combination of the untwisted meters in the progressions modb - 1,M_F(x; b - 1, c)summingmu(n)over thenofS_Fup toxwithn = c mod b - 1. Read through the dissection, the major arcs of that sum sit at-alpha + l/b^j, where region C2 needs the input (M) at moduli dividing(b - 1) b^j: the zero-free region returns, with the primes ofb - 1added to the finite family of mobius, and the section Progressions and every modulus carries that case atexp(-c sqrt(log x)). - Where the ceiling sits. Proved. With two consecutive digits,
sup_t abs(hat w_k(t)) = fill^kat everykwhenalphais on the lattice andsup_t abs(hat w_k(t)) <= (1 - c)^(-1/2) fill^k b^(-gamma k)withc > 0when it is off, by the dichotomy bullet. The mechanism is the phase map: the phasesv_j = b^j t + alphaobeyv_(j+1) = b v_j - (b - 1) alpha, full mass needs everyv_jintegral, and the integers are invariant under that affine map exactly whenbeta = 0. Atalpha = 0the frequencies of large mass are theb-adic preimagesl/b^jof frequency0, the C2 set, and the input of zero-free-region strength in the untwisted dissection is used at C2 and nowhere else. Off the lattice those preimages carry no mass, and the power saving holds at everyalphawithbeta >= beta_0 > 0, uniformly. - What the statement does not say. In the untwisted dissection C1 also caps the saving at
exp(-c sqrt(log x)), through the ratec'^(floor(2k/(3 m_d)))of Lemma A' against the3 Z^2residues of the region, so the root-log ceiling there has two sources: the zero-free region, which sits exactly on the preimages of0, and the sup-times-count pricing of C1, which needs no L-function. The twist removes both at once. Whether the untwisted C1 can be priced at a power is open here.
Primes of a design by digit sum
- The corollary. Proved. Let
Fkeep two consecutive digits and satisfy (W) in its per-digit formPB_b(m) < fill b^(-4/5), or atm = 1its chord form, and letq >= 2be coprime tob - 1. Then for every classc mod qand everydeltabelow thedelta_0of the theorem atbeta = 1/q,sum_(n in S_F, n <= x, s_b(n) = c mod q) Lambda(n) = psi_F(x)/q + O(A_F(x) x^(-delta)), and#{p in S_F : p <= x, s_b(p) = c mod q} = (1 + o(1)) pi_F(x)/qwithpi_F(x)the count of primes ofS_Fup tox: the primes of a missing-digit design equidistribute in the classes of their digit sum, Gelfond's question asked on the design. Proof: orthogonality modqwrites the left side asq^(-1) sum_(r mod q) e(-r c/q) psi_F(x; r/q); the termr = 0ispsi_F(x)/q, and atr != 0the number(b - 1) r/qis not an integer becausegcd(q, b - 1) = 1andqdoes not divider, sonorm((b - 1) r/q) >= 1/qand the theorem applies withbeta = 1/q. The prime count of coprime,psi_F(x) = kappa_F A_F(x) + O(A_F(x) exp(-c sqrt(log x))), holds under (W), andkappa_F > 0because the per-digit form of (W) forcesm < b^(2/5)on mobius whilephi(b) >= sqrt(b)atb > 6, soFholds a digit coprime tob. The bare inequalityB_b(F) <= fill b^(alpha_1)does not suffice here: atb = 6^15the digits sharing a factor with6keep the pair2, 3and satisfy it through the triangle inequality on three Dirichlet kernels, yet hold no digit coprime tob, so their design holds no prime past3; the prime powers ofS_Fweigh at mostx^(1/2) (log x)^2, belowA_F(x) x^(-delta)sincealpha_b > 1/2 + delta, and partial summation turnsLambdainto the prime count. - The other moduli. When
g = gcd(q, b - 1) > 1the class ofs_b(p)modgis the class ofpmodg, so the count asks for the primes ofS_Fin progressions modg, the lattice case above; Mauduit and Rivat carry that case for all primes, with unrestricted digits, in their Theorem 3, and the bullet Gelfond at every modulus below carries it on the design frombase 92317, with the errorexp(-c sqrt(log x)). - The readings at base 10. Verified. Base 10 lies far below the wall of (W), so these readings test the shape and not the theorem. Below
10^7the design missing7holds266823primes; their digit sums deviate from1/qby at most0.00825,0.00880and0.00503of the class size atq = 2, 4, 5, but by0.05348,0.10263and0.24272atq = 7, 8, 10. The deviation is the design's and not the primes': the elements of the design coprime tob (b - 1) = 90, which carry the same mod3structure as the primes becauses_b(n) = n mod 3, deviate by0.04846,0.09911and0.23939on the same moduli, and the primes sit within0.02213of that model at everyqcoprime to9. The design missing0reads the same way,397866primes, deviations0.08164,0.14497,0.29072atq = 7, 8, 10against the model's0.07811,0.13695,0.29155, primes within0.02584of the model. The slow modulus is the one with a small twist near the lattice: atq = 10the classr = 3sits atalpha = 3/10 = 1/3 - 1/30, and the twist-1/30, far from the lattice inbeta = 0.3but small innorm(alpha), mixes byabs(g_F(1/30))/fillper digit. Atq = 3the class0holds one prime,3itself (verbgelfond).
The falsification
- The supremum, read. Verified. At base 10 missing
7the supremumsup_t abs(hat w_k(t))/fill^kis bracketed atk = 1..8by a max-product pass over the windows of six base-bdigits oft, each window's factor bounded above by its centre value plus a Lipschitz margin, and bounded below by the value attained at the best path refined on a local grid; sixteen classes ofalphaare sampled, five on the lattice and eleven off it. Off the lattice the attained value, the upper bound and the proved bound(1 - c)^(floor(k/2))read0.071152,0.071165and0.521973atk = 8,alpha = 1/2;0.310870,0.310915,0.826973at1/7;0.411592,0.411649,0.866052at1/4;0.870069,0.870167,0.977921at1/10and0.870069,0.870172,0.977921at1/90; and0.998609,0.998716,0.999778at1/900, wherebeta = 0.01; at every one of the eleven classes and everyk >= 2the upper bound sits below the proved bound, and the generator raises if either bracket fails to. On the lattice, atalpha = 0, 1/9, 1/3, 2/3, 4/9, the value att = -alphais1to twelve digits atk = 8: no decay, as the dichotomy demands. The class1/3is on the lattice at base 10,9/3 = 3, so it must not decay and does not; the off-lattice classes with largebeta,1/27withbeta = 1/3and1/2withbeta = 1/2, decay. The measured rate is far better than the proved one: the upper bound's eighth root is0.718676atalpha = 1/2against the proved(1 - c)^(1/2) = 0.921947, since the pairing books one deficit per two positions where the readings show one per position. At base 37 missing18,k = 1..4, the same holds at its nine off-lattice classes, and the classes1/2and1/4, on the lattice there because36is divisible by4, read1(verbsup). - The twisted meters below
10^7. Verified. On the designs missing7and missing0at base 10,abs(M_F(x; alpha))/A_F(x)reads at most0.0005atx = 10^7over all sixteen classes, and its running maximum at most0.0006ofA_F(10^7), with no visible difference between the lattice and the rest: at this heightmucancels at everyalpha, and a powerx^(-delta)withdeltanear10^-8is invisible. The von Mangoldt meter separates them. On the latticepsi_F(10^7; alpha)/psi_F(10^7)sits within0.0013of the Ramanujan valuec_q(r)/phi(q)that the primes carry modq = 9/gcd(9 alpha, 9):-0.5000atalpha = 1/3and2/3, near0at1/9and4/9, wherec_9(1) = 0. Off the lattice it sits within0.0076of the average ofe(alpha s_b(n))over the design's elements coprime to90, the model of the corollary's readings, which is near0at most classes and is still large at1/27,1/90and1/900, reading0.17,0.86and0.998in modulus on the design missing7: those classes carry a small twist, and at10^7the frequency-zero term(g_F(alpha)/fill)^7has barely begun to decay (verbmeter). - Decay at
alpha = 1/3at base 10. Refuted. The expectation that the twisted supremum at base 10 decays atalpha = 1/3is refuted by the witnessabs(hat w_k(-1/3)) = fill^kat everyk, since(b - 1)/3 = 3puts1/3on the lattice; the twist it was meant to test is anyalphawith9 alphanot an integer,alpha = 1/2the cleanest.
Against the literature
- The digit sum of primes. Verified at source. Mauduit and Rivat 2010, read in the published text, prove in Theorem 1 that
sum_(n <= x) Lambda(n) e(alpha s_q(n)) = O(x^(1 - sigma_q(alpha)))withsigma_q(alpha) > 0whenever(q - 1) alphais not an integer, and in Theorem 3 the count of primes withs_q(p) = a mod m, the main term(gcd(m, q - 1)/m) pi(x; a, gcd(m, q - 1)); the digits are unrestricted,muis in none of their theorems, and their proof runs through Type I and Type II sums with a carry truncation, not through major arcs. Martin, Mauduit and Rivat 2014, read at source in the authors' copy, extend Theorem 1 toe(f(n) + beta n)for every digital functionf(n) = sum_k alpha_k abs(n)_kwith realalpha_k, with the explicit exponentc_q norm((q - 1) theta)^2when thealpha_kform a progression, which they credit to Drmota, Mauduit and Rivat, and remark thatmufollows by the same method; a realfmakese(f(n))unimodular, so the indicator of a missing-digit set is outside that class. - The mechanism is in print for the full digit set. Verified at source. Maynard 2019 survey, read at source, proves a weak form of Mauduit-Rivat at large base by the circle method: its Lemma 8.4 (2) is the two-position lemma for the full digit set,
abs(hat g(theta)) << b^(k (1 - delta_(alpha, b)))withdelta_(alpha, b) = norm((b - 1) alpha)^2/(4 b^4), by the same locating stepnorm(b^i theta + alpha) + norm(b^(i+1) theta + alpha) >= norm((b - 1) alpha)/b, and its Lemma 10.1, as printed, bounds by that supremum times their count the major arcs whose denominator has a prime outsideb, while its proof of Theorem 2.4 applies the same supremum-times-count to every small denominator, the mechanism of region C of this page; it treats the missing-digit set and the digit sum as two separate theorems and never their product. So the shape of this page's argument is in print; what is written here is its object: the twist carried onto a missing-digit design, formuandLambda, with an effective constant, from an explicit base, and a two-position constant that does not decay withb. - The missing-digit side. Maynard 2019 and Maynard 2022, as REFS.md records them, carry the primes of a missing-digit set and no digit-sum twist; the dissection of mobius came from them.
- The search, stated as a search. A web search on the digit sum of primes with missing, restricted or ellipsephic digits, the publication lists of Martin and of Rivat, and the reference lists of Mauduit-Rivat 2010 and of the survey found no theorem on the digit sum of primes, or of
mu, restricted to a missing-digit set; the nearest found are Aloui 2015, read at the publisher page in its abstract only; its definition ofT_N(alpha, beta)and its Theorems 2.1, 2.5 and 2.6 are known here through a machine summary of that page and through the citation in Saavedra-Araya, the full text unread, which carries Gelfond's theorem onto the integers of a missing-digit set and theirz-free members with power-saving errors through the twisted transformsum_(n in S_F, n < N) e(n theta + alpha s_b(n)), with no prime and no Mobius sum, the integer neighbour of the corollary here; digit sums of ellipsephic palindromes (Aloui, Mauduit and Mkaouar 2017), which are not primes, and Saavedra-Araya 2024, read at source in its abstract and Theorem A: for the integers of a missing-digit set andgcd(g, a) = gcd(a, a') = 1, the classes ofn mod aands_g(n) mod a'are jointly uniform exactly whengcd(a a', d_2 - d_1, ..., d_t - d_1) = 1, by Markov chains; integers only, no primes, the integer neighbour of the corollary here. This page is first in its object as far as that search reaches, and never in its shape.
Progressions and every modulus
Off the lattice the twist decays; on it the twist is a character of n mod b - 1, so the lattice case is the design in progressions. This section proves the Mobius and prime sums of S_F in every class mod N for every N coprime to b, at root-log strength, and combines them with the power saving into the law of s_b(p) mod q at every q.
- The theorem in progressions. Proved. Let
Fkeep two consecutive digits and carry the shifted-grid certificate of the unconditional dissection of mobius,sum_(a < b^i) abs(hat F_i(s + a/b^i)) <= C_F fill^i b^(i alpha_1)at everyiand every reals,alpha_1 < 1/5, and letN >= 2withgcd(N, b) = 1. WriteM_F(x; N, r)andpsi_F(x; N, r)for the sums ofmu(n)andLambda(n)over thenofS_Fup toxwithn = r mod N, andkappa_F = (b/phi(b)) #{f in F : gcd(f, b) = 1}/fillas on coprime. Then there areC, c > 0, effective and depending onb,FandNalone, withabs(M_F(x; N, r)) <= C A_F(x) exp(-c sqrt(log x))at everyr, andabs(psi_F(x; N, r) - kappa_F A_F(x)/phi(N)) <= C A_F(x) exp(-c sqrt(log x))at everyrwithgcd(r, N) = 1, while atgcd(r, N) > 1only powers of the primes ofNcount, at mostomega(N) (log x)^2. At one missing digit the certificate holds frombase 584(mobius), so the theorem is Proved there at everyNcoprime tob,N = b - 1among them; the bullets below are the proof. - Orthogonality and the blocks.
M_F(x; N, r) = N^(-1) sum_(a mod N) e(-a r/N) M_F(x; a/N)withM_F(x; theta) = sum_(n in S_F, n <= x) mu(n) e(n theta). The block split of mobius is unchanged, and on a blocke((P y + t) theta) = e(P y theta) e(t theta), so its sum ise(P y theta) y^(-1) sum_(a' mod y) hat F_k(theta + a'/y) S_P(-a'/y), by orthogonality onZ/yapplied tot -> 1_(D_k)(t) e(t theta), whose transform ata'/yishat F_k(theta + a'/y).S_Pis the untwisted block sum, so the Dirichlet datal/d,hofa'/y, the cut into A, B and C, and the minor-arc bounds onS_Pare those of the dissection verbatim; only the transform is translated bytheta. - Regions A and B do not change. Region A reads the certificate at the shift
thetain place of0. The hybridl^1bound reads its top factor on the gridy theta/V_2 + a'/V_2, a shifted grid, and its bottom factor on the intervalstheta + J_(l,d), still disjoint, throughL^1norms ofhat F_(i_1)and its derivative over a period, which a translation does not change. Both bounds hold with the same constants, since the certificate holds at every shift. - Region C re-cut: the major arcs move to
l/(N_a b^j). PutN_a = N/gcd(a, N). At a C residuea'/y = l/d + eta,d < Z,abs(eta) = h/(d y) < Z/y, the transform is read ata/N + l/d + eta. Write the reduced denominator ofa/N + l/dasd''; thend'' < N Z. C1'' is the residues withd''carrying a prime outsideb: there the perturbed Lemma A' of coprime, as used in region C1 of mobius, givesabs(hat F_k(a/N + a'/y)) <= fill^k c'^(floor(2k/(3 m_(d''))))withm_(d'') <= log_b(N Z) + 1, its hypothesis onetaunchanged, and the3 Z^2count andabs(S_P) <= ypay it exactly as C1, withlog_b Nadded tom_d. C2'' is the rest:a/N + l/d = l''/d''withd''dividing a power ofb, sol/d = l''/d'' - a/Nandddividesd'' N_a, a divisor of(N b)^j. These are the frequencies where the translated transform can keep full mass:hat F_kat theb-adic fractionl''/d''. Partial summation ofe(n eta)along the block givesabs(S_P(a'/y)) <= (1 + 2 pi h/d) d max_(u, r') 2 abs(M(u; d, r')) <= 16 Z max_(u <= x, r') abs(M(u; d, r')), whether or notddividesy, and C2'' holds at most3 Z N'_Zresidues,N'_Z <= (1 + log_2 Z)^(omega(N b))the number ofd < Zdividing a power ofN b. So the one new input is (M) at the moduliddividing a power ofN b, the lemma below, and the assembly of mobius runs withc',c_1and the block depth read atN b. - The lemma (M_N). Proved. Let
R = N b. At everyu <= x, everyrand everyddividing a power ofRwithd <= exp(sqrt(log x)/2):abs(M(u; d, r)) <= C_1 x exp(-c_1 sqrt(log x))andabs(psi(u; d, r) - 1_(gcd(r,d)=1) u/phi(d)) <= C_2 x exp(-c_2 sqrt(log x)), withC_i,c_ieffective and depending onRalone. Proof. Atu <= x exp(-sqrt(log x))both are trivial. Otherwise putg = gcd(r, d); everyn = r mod dhasgcd(n, d) = g, soM = 0unlessgis squarefree, and thenM(u; d, r) = mu(g) sum_c M(u/g; d_1, c)over the classesc mod d_1 = (d/g) swithc = r/g mod d/gandgcd(c, s) = 1,sthe product of the primes ofgnot dividingd/g: at mostrad(R)classes,d_1 <= d rad(R)dividing a power ofR; forpsiatg > 1only powers of the primes ofRcount, at mostomega(R) log u. Orthogonality bounds a class by the largestabs(M(v, chi))overchi mod d_1, and1/L(s, chi) = prod_(p) (1 - chi*(p) p^(-s))^(-1) / L(s, chi*)over the primespofd_1not dividing the conductorq*of the primitivechi*behindchi, soM(v, chi) = sum_w chi*(w) M(v/w, chi*)over thewbuilt from those primes, at most(1 + log_2 v)^(omega(R))of them; the terms withv/w < sqrt vare trivial and the rest havev/w >= x^(1/4)andq* <= rad(R) exp(sqrt(log x)/2). Chang and Martin 2019, read at source: Lemma 2.1 makesL(s, chi)zero-free insigma >= 1 - c/log(q (abs(tau) + 4))for everychi mod q,ceffective, except possibly for one real zero of a single character modq, withabs(log L) <= log log(q (abs(tau) + 4)) + O(1)in half that width for the others; Proposition 2.3 makes everyL(s, chi mod q)zero-free insigma >= 1 - c_0/(1 + log^+ abs(tau)),c_0 = eta/(q^(1/2) log^2 q), withabs(log L) <= (1/2) log q + 3 log log^+(q tau) + O(1)for the exceptional one; Lemma 2.4 turns a bound onabs(log L)into one onabs(1/L). The exceptional character is real, since a zero of a complexchi*is a zero of its conjugate, a second character modq*; a real primitive character has conductor2^etimes an odd squarefree number withe in {0, 2, 3}, so hereq*divides8 rad(R), a finite family fixed byR, andc_0 >= eta/((8 rad(R))^(1/2) log^2(8 rad(R))). Perron's formula at1 + 1/log v, heightT = exp(sqrt(log v)), and the segment moved to1 - (c/2)/log(q* (T + 4)), or to1 - c_0/(1 + log T)for the finite family, giveM(v, chi*) << v exp(-c_3 sqrt(log v))withc_3depending onRalone, sincelog(q* (T + 4)) <= 3 sqrt(log v); atq* = 1the same argument runs onL(s, chi_0 mod 4) = (1 - 2^(-s)) zeta(s), which has no real zero in(0, 1)and so no exceptional zero. Summing back overw,candggives the bound onM. Forpsithe same Perron integral runs on-L'/L, bounded by Cauchy's estimateabs(L'/L) <= max abs(log L)/radiuson discs that fit inside the regions wherelog Lis bounded, so the segment sits at1 - (c/4)/log(q* (T + 4)), a quarter of Lemma 2.1's width since its bound onlog Lholds in half of it, or at1 - c_0/(2(1 + log T)), half of Proposition 2.3's width, for the finite family; Proposition 2.3's region excludes the exceptional zero itself, so no termv^(beta_1)appears,psi(v, chi*) << v exp(-c_3 sqrt(log v))atq* > 1, the pole atq* = 1givesv, andpsi(v, chi) - psi(v, chi*)is at mostomega(R) (log v)^2; orthogonality then givespsi(v; d_1, c) = v/phi(d_1) + O(v exp(-c_3 sqrt(log v))). Siegel's theorem is never used: the exceptional zeros lie on the real primitive characters of conductor dividing8 rad(N b), the family of mobius with the primes ofNadded. The Mobius half is the proof of (M) on that page withrad(base)read asrad(N b)at each of its four uses: the classesc, the count ofw, the conductor bound and the exceptional family; nothing else in it readsbase. The von Mangoldt half is (M_Lambda) of coprime under the same swap, proved there through the exceptional termu^(beta_1)and its effective distance from1, and here through the region of Proposition 2.3, which excludes it; the two routes agree. - The von Mangoldt main term, through a model. Proved. Put
lambda_R(n) = (R/phi(R)) 1_(gcd(n, R) = 1). In each class modddividing a power ofR,lambda_Rsums to1_(gcd(r,d)=1) u/phi(d) + O(2^(omega(R)) R), becausen = r mod dcoprime toRis a class moddcut by the primes ofRoutsided, and(R/phi(R)) prod_(p | R, p not dividing d) (1 - 1/p) = d/phi(d); soLambda - lambda_Robeys the bound of (M_N) forpsiin every such class. Its exponential sum on a block isLambda's, bounded on A and B by Maynard 2022, Lemma 4.2, as on coprime, less(R/phi(R)) sum_(e | R) mu(e) sum_(n in block, e | n) e(n theta), each inner sum at mostmin(y/e + 1, 1/(2 norm(e theta))): ata'/y = l/d + eta,norm(e a'/y) >= 1/(2d)whenddoes not dividee, ase abs(eta) <= R y^(-3/5)/d, which gives at most2 d <= 2 y^(3/5), and whenddividese, sod <= R < Zand the residue is in B withh >= Z,norm(e a'/y) = e h/(d y)gives at mosty/h; both lie below the minor-arc bounds of A and B. C1'' paysLambda - lambda_Rthroughabs(S_P) <= y (log 2x + R). So the dissection givessum_(n in S_F, n <= x, n = r mod N) (Lambda(n) - lambda_R(n)) << A_F(x) exp(-c sqrt(log x)), and atgcd(r, N) = 1the model is(R/phi(R)) #{n in S_F, n <= x : n = r mod N, gcd(n, b) = 1}, coprimality toNbeing automatic. - The local constants split evenly. Proved. On a block
P y + D_kwithk >= 1,gcd(n, b) = 1reads the last digit, so withF*the digits ofFcoprime tob,#{t in D_k : gcd(t, b) = 1, P y + t = r mod N} = N^(-1) sum_(a mod N) e(-a (r - P y)/N) g_(F*)(a/N) prod_(1 <= j < k) g_F(a b^j/N). The terma = 0is#F* fill^(k-1)/N. Ata != 0,a b^jis nonzero modNbecausegcd(b, N) = 1, sonorm(a b^j/N) >= 1/Nand the pair form of the two-position lemma givesabs(g_F(a b^j/N)) <= fill rho_Nwithrho_N = 1 - 4 sin^2(pi/(2N))/fill. Over the at mostfill + 1blocks per scale the errors sum to<< (fill rho_N)^L << A_F(x) x^(-log(1/rho_N)/log b), and the blocks at scale0and the pointxtoO(b). So the count is(#F*/(fill N)) A_F(x)up to a power saving, and sinceR/phi(R) = (b/phi(b)) (N/phi(N))the model iskappa_F A_F(x)/phi(N) + O(A_F(x) x^(-delta_N)). The design is uniform modNin the limit whatever its digits share withN: the consecutive pair puts1among the digit differences, the condition of Saavedra-Araya 2024, Theorem A. AtN = b - 1the rate is exact:hat F_k(a/(b - 1)) = g_F(a/(b - 1))^k, sinceb^j = 1 mod b - 1. - Out of scope.
gcd(N, b) > 1: thenn mod gcd(N, b^j)is read on the last digits, the major arcs of the translated transform include denominators sharing primes withbin both factors, and this section does not carry it. - Gelfond at every modulus. Proved. Let
Fkeep two consecutive digits and satisfy (W) in its per-digit form, so that the theorem of The power saving and the theorem above both hold, at one missing digit frombase 92317. Letq >= 2,g = gcd(q, b - 1),N >= 1coprime tobandN' = lcm(N, g). Then for everyr_1 mod Nandr_2 mod q,sum_(n in S_F, n <= x, n = r_1 mod N, s_b(n) = r_2 mod q) Lambda(n) = (g/q) kappa_F A_F(x)/phi(N') + O(A_F(x) exp(-c sqrt(log x)))whenr_1andr_2agree modgcd(N, g)and the class modN'they define is prime toN', andO(A_F(x) exp(-c sqrt(log x)))otherwise, the implied constant andceffective and depending onb,F,Nandq. AtN = 1:s_b(p) mod qis uniform on theq phi(g)/gclasses prime tog, the classes compatible withp mod gsinces_b(p) = p mod g; atgcd(q, b - 1) = 1this is the corollary above. Proof: orthogonality modNand modqwrites the sum as(N q)^(-1) sum_(a mod N) sum_(c mod q) e(-a r_1/N - c r_2/q) sum_(n in S_F, n <= x) Lambda(n) e(a n/N + c s_b(n)/q). Whenq/gdoes not dividec,(b - 1) c/qis not an integer, sincegcd(q/g, (b - 1)/g) = 1, sonorm((b - 1) c/q) >= 1/q, and the theorem of The power saving with the frequency translated bya/NgivesO(A_F(x) x^(-delta)): the two-position lemma boundshat w_kat every frequency, the peel and the hybrid bound hold at every shift, and on a blocke(a (P y + t)/N) = e(a P y/N) e(a t/N), so its proof runs withhat w_k(a/N + a'/y)and nothing else changes. Whenc = (q/g) c',e(c s_b(n)/q) = e(c' n/g)becausegdividesb - 1, and these terms sum to(g/q) psi_F(x; N', R')over the classR'modN'withR' = r_1 mod NandR' = r_2 mod g, or to0when no such class exists;N'is coprime tob, and the theorem above gives the main term. The prime count follows by partial summation, as in the corollary: a prime dividingN'lies in no unit class modN', and the prime powers ofS_Fweigh at mostx^(1/2) (log x)^2. - The falsification. Verified. At base 10, below every wall and so a test of the shape, the primes of
S_Fabove30and below10^8,2079504missing7and3103338missing0, read against the law in units of the square root of the predicted count: on the lattice classes,p mod 9,s_10(p) mod 3and(p mod 7, s_10(p) mod 3), at most0.83and0.76from the law, and no prime in a class of law0. The off-lattice part moves slower. The share of evens_10(p), which the law puts at1/2, reads0.48942,0.49588and0.49464below10^6,10^7and10^8missing7, and0.48418,0.49576and0.49144missing0, sos_10(p) mod 2,mod 6andmod 18drift from the law by up to10.92and22.91units at10^8; the drift is not monotone inx, and it falls only at a fixed parity of the digit count. The drift is the prime11 = b + 1alone: on the8-digit strings of the design the even share is0.50000prime to30,0.49583prime to330and to2310,0.49996prime to390, and0.49576prime to30030missing7, and0.50000,0.49228,0.49228,0.50000and0.49229missing0, so7and13add nothing, and the primes sit within2.37units of the strings prime to30030in every class tested. On the strings, the share prime to330less the share prime to30reads-0.00769,-0.00248,-0.00417,-0.00210and-0.00103at6,7,8,10and12digits missing7, and-0.01385,-0.00295,-0.00772,-0.00433and-0.00243missing0: it oscillates with the parity of the digit count and, at even counts, falls by0.54,0.50,0.49and by0.56,0.56,0.56per two digits, againstabs(g_F(1/22))^2/fill^2 = 0.480and0.561. That the drift is not in the limit is argued by the mechanism below and read in that decay. The mechanism is the two-position lemma's own extremal point: atalpha = 1/2and the frequencyl/(b + 1)withl = b/2, the phasesb^j t + alphaalternate between+-1/(2(b + 1)), exactly thex_0 = beta/(b + 1)of the locating step, and the transform decays there only byabs(g_F(1/22))/fill,0.6927missing7and0.7491missing0per digit, against a prime weightmu(11)/phi(11)on that arc (verblattice). - Against the literature. Verified at source. Nath 2024, read at source in its abstract and Theorems 1-3: for
X = b^k,bsufficiently large in terms ofdelta(of order10^632atdelta = 1/100by its own remark),gcd(c, d) = gcd(r, b) = gcd(d, b) = 1, the errorE(X; d, c; b, r) = sum_(n < X, n = c mod d, n = r mod b) Lambda(n) 1_A(n) - (1/phi(d)) (b/phi(b)) sum_(n < X, n = r mod b) 1_A(n)summed overd <= X^(1/3 - delta)with the max overcis<< X^zeta (log X)^(-A). At one fixedd = Nthis is the prime count of the theorem above with its local constantkappa_F/phi(N)split evenly, at an unspecified large base, a log-power error andxa power ofb; the lattice case for primes is in print in that form. What is here is the shapeexp(-c sqrt(log x))at everyx, with an effective constant where that paper's depends onbanddeltaand is ineffective, through Bombieri-Vinogradov in its proof, frombase 584, the Mobius sum, which that paper never names, and the digit-sum law at everyqon a missing-digit set, which neither it nor Maynard 2019 (residue classes only through the set's Type I estimate, Proposition 7.1, moduli coprime to10, as REFS.md records at source) carries. Mauduit and Rivat 2010, Theorem 3, is the unrestricted form of the law atN = 1, with the main term(gcd(q, b - 1)/q) pi(x; r_2, gcd(q, b - 1)), the same split.
Open
- The pairing, which sets the exponent past about
10^5. The lemma books one deficit per two positions; the readings show close to one per position,0.718676per digit atalpha = 1/2against the proved0.921947. Sincesigmabinds from100084atbeta = 1/2and from93409atbeta = 0.2(the exponent bullet), the two-position constant, through regions B and C, limitsdelta_0at almost every admissible base, and a deficit per position would raise it there. - A lower base. The wall is the per-digit (W). A twisted chain would need, in place of the Lebesgue sums of
D_(b^l), the gridl^1norms of the full-digit twisted kernelprod_(j < l) D_b(b^j t + alpha), the discrete transform Mauduit and Rivat estimate; a twisted window would need a supremum over shift vectors. Either could bring the theorem toward the untwisted584or115. - The lattice at power strength. The section Progressions and every modulus carries every lattice
alphaand everyqatexp(-c sqrt(log x)), through (M_N) at the moduliN b^j; on the lattice the major arcs keep full mass, so a power saving there asks a zero-free strip for theL(s, chi)modN b^j, and the error term of the law at everyqstays root-log while the off-lattice part saves a power. The off-lattice rate at small base is set by the frequencyl/(b + 1), where the locating step of the two-position lemma is attained. - The untwisted C1 at a power, and with it whether the root-log ceiling of mobius has any source besides the zero-free region at C2.
- The exponent. Region A's
1/5 - alpha_1binds only on a window just above92317, and past itsigma, belowgamma/4, binds; either waydelta_0stays belowalpha_b/20, and nothing here touches the sparse columns or the exponenttheta(F)of mobius.