cocycle-joint-spectral-radius.md
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The cocycle's joint spectral radius
- 2026-09-06 [Proved] The component cocycle of mixed Kronecker words is simultaneously triangularizable over
Zand its joint spectral radius is the largest fill: in the frame(gamma, h, v, phi) = ((1,1,1,1), (1,1,2,2), (1,2,1,2), (1,2,2,4))of components, horizontal runs, vertical runs and fill, every class matrix is nonnegative, integer and lower triangular with column sums(comp(A_c), r(c), s(c), fill_c)and diagonals(0,0,0,1), (0,1,0,2), (0,0,1,2), (0,0,0,2), (1,1,1,3), (1,2,2,4), so the cross-polytopeP = conv{+/- gamma, +/- h, +/- v, +/- phi}satisfiesM_c P subset fill_c Pwith exact integer residuals and its gauge is an extremal norm; henceJSR(F) = max fillandLSR(F) = min fillon all2^15 - 1subfamilies, the finiteness property holds with a one-letter spectrum maximizing product, and every word over{3, 6}has spectral radius exactly2^level. Witness: connectivity.md THE JOINT SPECTRAL RADIUS OF THE COCYCLE, lab/py/jsr-schedules. - 2026-09-06 [Refuted] That the joint spectral radius of a component-cocycle pair is a nontrivial invariant of the pair: the JSR depends on the alphabet only through its largest fill and the LSR only through its smallest, both attained by one-letter words, so on the 78 of 105 letter pairs whose fills differ the JSR rate
log max_c k_cstrictly exceedschiat every interior frequency; an exhaustive scan of all2^levelwords tolevel = 16on{3, 6}and{3, 7}never improves on the one-letter rates2and3, and the Blondel-Nesterov lifting equals(fill_1^k + fill_2^k)^(1/k)exactly, terminating at no finitek. Witness: connectivity.md THE JOINT SPECTRAL RADIUS OF THE COCYCLE, lab/py/jsr-schedules.