primes-on-a-design.md
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Primes on a design
- 2026-09-06 [Proved] Primes on a design at
fill = base^dim - 1are primes with one restricted digit at basebase^dim: the Morton codex -> Sum_j (Sum_c base^(c-1) x_(c,j)) base^(Dj)mapsS_levelbijectively onto the integers at basebase^dimwhose digits lie in the image of the digit setF, the gasket base 4 missing 3 and the carpet base 9 missing 4; the gcd-prime reading is a positive-density count whenB(F) > 0and empty otherwise, base 32 on{0,4,...,28}^2havingfill = 64 > 32, (E), and every gcd divisible by 4; thex_1-prime reading is a sum-of-digits large deviation. Witness: coprime.md PRIMES ON A DESIGN. - 2026-09-06 [Proved] Lemma A' the window rate: for (E),
gcd(d,base) = 1and nonzerotin(Z/d)^dim,Prod_(l<level) f_l(t) <= c(base,fill)^floor(level/m_d)withm_d = max(1, floor(log(d/2)/log(base)) + 1), andord_d(base) >= m_dso it is never weaker than Lemma A; with a base parteandtnonzero mod the coprime partm, and|eta|_inf < base^(-2n/3)/(4 base dim (base-1)), the rate isc'(base,fill)^floor(2n/(3 m_d)), which is Maynard Lemma 8.2 in every dimension with an explicit constant and no consecutive-digit hypothesis; the hypothesis ontis sharp, the gasket atd = 6andt = (3,0)sitting at1/3at everylevel. Witness: lab/py/digit-transform-norms lemma, worst per-digit rate0.830915atd = 257overd <= 301against Lemma A's0.986514. - 2026-09-06 [Proved] The 2D Type I saves a power when
alpha_1* < dim/2, the dyadic blockd ~ Q_1costingfill^level (Q_1^(2 alpha_1* - dim) + Q_1^dim base^(level(alpha_1* - dim)))and the small moduli going to Lemma A': the carpet certified atalpha_1* < 0.8124givesSum_(d <= Q, gcd(d,3) = 1) |#{x in S_level : d | x} - fill^level/d^2| <<_A fill^level level^(-A)atQ = 3^(0.5938 level) level^(-C), and the gasket certified atalpha_1^- >= 1.0126,alpha_1^+ <= 1.1022closes the route,min_x Sigma_2 > 4.059204against 4 andmin_x Sigma_3 > 8.213932against 8 in interval arithmetic with directed rounding,Sigma_2(0) = (8 + 2 sqrt(5))/3exactly. Witness: lab/py/digit-transform-norms certify. - 2026-09-06 [Verified] The carpet misses the one-dimensional criterion at every order: base 9 missing 4 has
g(1) = 0.3437below27/77butg(3/2) = 0.1531,g(235/154) = 0.1457,g(1.6) = 0.1262,g(1.7) = 0.1031,g(1.8) = 0.0835against0.1473, 0.1397, 0.1179, 0.0884, 0.0589, a gap of0.0058on the printed pair ats = 3/2and0.005749in full, andg(3/2)moves0.154389, 0.153068, 0.152921over four, five and six digit-vectors, so windows do not close it. Witness: lab/py/digit-transform-norms moments. - 2026-09-06 [Verified] The gasket is out of reach at both numbers: base 4 missing 3 has
g(1) = 0.4820against27/77andg(235/154) = 0.3170against59/433, so no Type II range opens at any order computed. Witness: lab/py/digit-transform-norms moments. - 2026-09-06 [Verified] The componentwise route is closed at source: Chow, Varju and Yu Remark 6.1 puts the Fourier
l^1dimension below1/2for(b,a)in{(3,0),(3,1),(3,2),(4,1),(4,2)}by interval arithmetic atlevel = 2, so the base-3 design's coordinate marginals fall on the wrong side, while Proposition 2.4 puts base 4 missing 3, the base-2 gasket's Morton code, above1/2. Witness: arXiv:2402.18395v2 pp.25-26. - 2026-09-07 [Verified] The missing-digit criterion is unreachable for the carpet at every order: dividing by
2 - sthe criterion is the single inequalityg(s)/(2 - s) < (1/5)*(1 + c/2)on the transform's moment exponents, and for base 9 missing4the shift sandwich at a power certifiesg(3/2) > 0.149397andg(235/154) > 0.142274against the required0.147320and0.139667, with a monotone chain of orders anchored at the exactSigma_N^(2)(x) = (9/8)^Ncovering[3/2, 2)in 21 closed cells sharing endpoints and[1, 2)in 87; the pointwise deficit is at least0.001268over[3/2, 2)and the decisive cell re-derived independently atN = 5clears by0.000840. Witness: lab/py/digit-transform-norms criterion, with an independent recomputation by a digit-tree fold reproducing every printed digit. - 2026-09-07 [Proved] The two-missing-digit transform is
(base-2)^2 abs(hat F)^2 = K^2 + 2 + 2 cos(2 pi D t) - 4 K cos(pi S t) cos(pi D t)withK = sin(base pi t)/sin(pi t),D = a - c,S = a + c - (base-1), so a pair enters only throughabs(D)andabs(S); that implication does not run backwards,{0,2}and{0,8}atbase = 10reading(2,7)and(8,1)with equal transforms, and the collapse is generated instead by the reflectiond -> base-1-d, which flips both signs, together with the integer translation ofFavailable exactly when0orbase-1is excluded and identifying{0,c}with{0,base-c}, so the edge family is the one-missing-digit sets of a(base-1)-digit interval read at basebaseand the number of distinct transforms is(C(base-2,2) + floor((base-2)/2))/2 + floor(base/2). Witness: coprime.md PRIMES ON A DESIGN. - 2026-09-07 [Verified] That pair count reads
7, 16, 21, 31of the15, 36, 45, 66excluded pairs atbase = 6, 9, 10, 12, is reproduced by grouping every one of theC(base,2)pairs by its sampled transform at every base4 <= base <= 41, and sums to 2373 distinct sets over4 <= base <= 31. Witness: lab/py/digit-transform-norms pairs. - 2026-09-07 [Verified] The least base carrying a certified two-missing-digit set with
alpha_1 < 1/4isbase = 32at the interval class{0,1},alpha_1 in [0.2499087, 0.2499779]at four window digits, the same class atbase = 31reading[0.2518967, 0.2519717]; over4 <= base <= 31the machine certifiesalpha_1 > 1/4at 2363 of the 2373 distinct sets, closestbase = 26missing{2,23}at> 0.2502919, and the ten it cannot bracket from below all haveS = 0orD = base/2withbase/2odd, a shared shape and not a cause since the clearing headlinebase = 32missing{0,1}has a transform vanishing at all 29 pointst = j/30, with certified upper bounds0.2538899to0.2826357, above1/4. Witness: lab/py/digit-transform-norms pairs and pairfail. - 2026-09-07 [Verified] Against the bar
1/3a two-missing-digit set first clears atbase = 13, the interval class atalpha_1 < 0.3318819on three window digits withbase = 12above at all 31 of its sets to five, and the whole pair family clears frombase = 21on throughbase = 26, worstbase = 23missing{4,5}at< 0.3333284, every base4 <= base <= 20carrying a certified witness above1/3,base = 20by{3,11}at[0.3356579, 0.3356674]. Witness: lab/py/digit-transform-norms pairs pairclear pairsome. - 2026-09-07 [Proved] The digit-uniform bound holds at any excluded-digit count:
abs(hat F(t)) <= (abs(sin(base pi t)/sin(pi t)) + m)/(base - m), the level product expands with weightm^(N - card E)and telescopes to the same Dirichlet kernels, soa_N = m a_(N-1) + m Sum_(l<N) lambda_l a_(N-1-l) + lambda_Nand the growth root solves(z - m)(z - 1)^2 = m(c_1 (log base) z + gamma'(z - 1) + c_1 (z-1)^2/(base z - 1))on the exact Lebesgue inputlambda_l <= c_1 l log base + gamma' + c_1 base^(-l),gamma' = (2/pi)(gamma + log(8/pi)), givingalpha_1 < 1/4for everybase >= 649atm = 2with the chain failing at648, and125atm = 1and1873atm = 3, with32,105,230against1/3, certified at 120 bits; the coarserc_0 = 0.97form of the same chain needsbase^l >= 86and gives126atm = 1. Witness: lab/py/digit-uniform-bound pairs. - 2026-09-07 [Proved] The threshold
1/4is the Mertens bar: in the GRH chain steps 1, 2, 4 and 5 never name the digit set and only step 3 substitutes a digit-free kernel bound, so feeding the certifiedl^1exponent there givesabs(M_F(x)) <<_(base,eps) A_F(x) x^(alpha_1 - 1/4 + eps), that isA_F(x)^(1 - delta + eps)withdelta = (1/4 - alpha_1)/alpha_base > 0, and1 - b(a)in place of1/4under a zero-free half plane; steps 2 and 3 alone forcealpha_1 <= 1 - alpha_base + c_baseandgap_base(1) > 0is exactly1 - alpha_base + c_base < 1/4, so the old certificate implies the new condition and the wall can only fall. Witness: coprime.md PRIMES ON A DESIGN. - 2026-09-07 [Verified] That wall falls from
3690to34, on the interval certificates behind the one-missing-digit clearancealpha_1 < 1/4atbase = 34, at every35 <= base <= 125and by the uniform chain above. Witness: coprime.md PRIMES ON A DESIGN.