repunit-layer.md
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The repunit layer
- 2026-09-06 [Proved] The binary-weight floor on the repunits
w = R_k = (3^k - 1)/2in closed form:Phi_k = sum_{q | rad R_k} mu(q) q^(-1) sum_{t mod q} P_{q,t}^(k/ord_q 3)withP_{q,t} = prod_{r < d} (1 + e(t 3^r/q)), C-finite inkprime by prime,N_k(2) = 2^(k-1),N_k(p) = (2^k + p - 1)/pwhenever2is a power of3modp(p = 5, 7, 23), andPhi_k = 2^k - 2wheneverR_kis prime; values2, 6, 8, 30, 24, 126, 112, 450, 460, 1958, 1344, 8190, 8064, 27360atk = 2..15by three methods. Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT FLOOR EXACTLY. - 2026-09-06 [Proved] The repunit excess is a lift family and a deep tail: a binary
Kis a multiple ofR_kexactly when its column counts satisfysum_r c_r 3^r = 0 mod R_k; below3^(2k)the multiples areK_T = a_(T^c) + 3^k a_Twith multiplier1 + 2 a_TandR_(2k); each lift setOcc_Tis occupied and stable ink, soZ(R_k) >= |union_T Occ_T|, and at primeR_k(k >= 15, first atk = 71)Z(R_k) - Phi_k >= 2^k/7 - 4 F(k+1) - 126. Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT EXCESS. - 2026-09-06 [Verified] The repunit excess
Z(R_k) - Phi_kreads0, 0, 0, 0, 0, 6, 6, 50, 70, 402, 290, 2198, 2376, 8830atk = 2..15; the lift union equalsZ(R_k)atk <= 10and falls short by18, 16, 108, 162, 624atk = 11..15; minimal witnesses reach 436 digits with a column used 27 times atk = 13; the drift factorises exactly asZ(R_k)/R_k^(log 2/log 3) = 2^(log 2/log 3) (1 - 3^(-k))^(-log 2/log 3) delta_k (1 + X_k)withdelta_k = Phi_k/2^kandX_krising0.0476to0.3227overk = 7..15. Witness: lab/py/ratio-set-saving (ratio.py repunit). - 2026-09-06 [Conjecture] The repunit drift is unbounded:
X_k = (Z(R_k) - Phi_k)/Phi_krises at every step fromk = 8and beats the random-lift limitsum_T 1/m_T = 1.41atk = 13, so no pointwiseZ(w) <= C w^(log 2/log 3)holds on the repunits and every exponent abovelog 2/log 3survives; the blocking lemma is whether|union_T Occ_T|plus the deep tail isO(2^k). Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT DRIFT. - 2026-09-06 [Refuted] That
1.5975(the maximum ofZ(w)/w^(log 2/log 3)below8192, atw = 1093) bounds the layer: the repunits read1.7845and1.963681atk = 11, 13, so any pointwiseC w^(log 2/log 3)needsC >= 1.9636. Witness: lab/py/ratio-set-saving (ratio.py repunit). - 2026-09-07 [Verified] The deepest first return of the critical band automaton grows below the critical
sqrt(w)as a sign and not as an exclusion:log d_maxonlog wover 27 weights gives0.4055, 95 percent[0.3293, 0.4818], but one deletion moves the slope to0.4261and the interval to0.5034, covering1/2, so the leave-one-out range[0.3829, 0.4261]is what stands; the median has no single exponent,0.1802on every weight against0.2798atZ >= 8with 4 of 27 weights havingZ <= 2; and a two-predictor fit puts0.3385onlog wand0.1313onlog Z, so controlling for sample size lowers the exponent and the drift below1/2is understated. Witness: lab/py/band-return-times critical. - 2026-09-07 [Proved] The submasks of a binary
Kdivisible by a divisormof it are closed under complement insupp K, under disjoint union and under nested difference, soN_K(m)is even and every solution is a disjoint union of irreducible ones; the decomposition is not unique, soN_K(m)is the number of distinct unions of pairwise disjoint irreducibles and satisfiesN_K(m) <= #packings <= 2^iotafor the irreducible countiota, withN_K(m) = 2^iotaif and only if the irreducibles are pairwise disjoint, and then they partitionsupp K. Depth-free. The antipodal and run families of the repunit lift are the equality case, which is why their counts are exact powers of two, and the converse fails,k = 7with multiplier19having a power-of-two count and overlapping irreducibles. Witness: lab/py/band-return-times lift and check, the three closures asserted over every one of the2^(k-1)setsTat everyk = 2..9, and both witnesses pinned. - 2026-09-07 [Verified] The depth-2 lift census of the repunit reads
M_k = 2, 6, 14, 36, 68, 172, 306, 728, 1338, 2814, 5224, 11852, 20888, 43364, 84124, 172516, 327092atk = 1..17withM_k/2^kinside[1, 2.89356], and its Hankel matrix is9by9of full rank on all seventeen terms, so no linear recurrence of order at most 8; the irreducible supplySum_T iota_T / 2^ksits inside[0.738281, 0.890625]atk = 2..12, the even readings falling fromk = 6, whilemax_T iota_Tgrows2, 3, 4, 5, 6, 10, 14, 24, 31, 50, 68, and the equality case holds for1970of the2048multipliers atk = 12against1986whose count is a power of two. The sweep is exhaustive over everyTinside[1, k-1]; the multipliers meet the residue classes1and7mod9and never4, which is forced bya_T = Sum 3^iwithi >= 1and not a reading. Witness: lab/py/band-return-times lift. - 2026-09-07 [Verified] A column transfer for the submask count of the lift half needs at least 253 states where the return half needs
b/2: a machine reading thekcolumns with a state set free ofkis a linear representation of the count as a series over the column word, so its state count is at least that series' Hankel rank, and the rank reads3, 7, 14, 31, 62, 126, 253at word length1..7on each side against the full3, 7, 15, 31, 63, 127, 255, deficiency0, 0, 1, 0, 1, 1, 2. The words reach length 14, so the floor holds atk <= 15and is already worse than the2^(k/2)meet in the middle; whether the rank is unbounded is observed and not proved, and a rank levelling off would be a poly-time machine, so the route is blocked and not closed. The irreducible count has the same full-rank Hankel to word length 5. Witness: lab/py/band-return-times lift.