

Discoveries
Every claim of the tree on one dated, tagged line with its witness, one section per topic, filtered by tag, topic and date.
Acoustic barrier
- Conjecture The level trend of the self-similar acoustic barrier is fineness, not self-similarity: a random tile at matched solid fraction and cell size, three seeds,
r = 4, also falls with level and blocks more at every L2 and L3 - random against self-similar at L2 / L3: carpet 0.264 / 0.074 against 0.390 / 0.128, net 0.229 / 0.099 against 0.467 / 0.215, tree 0.221 / 0.066 against 0.781 / 0.666, void 0.211 / 0.104 against 0.270 / 0.235 - with a seed spread of 0.006 to 0.037.
Atlas
- Verified mrlygame quests replay outside the engine: following the quest draw order through board, mask, rulebook, score and pivot options with a shift-and-add or FFT count reproduces
mrlygame::questcell for cell on seeds 1, 4, 7 and 9 under the default config, the four cheapest quests, each a single attempt at canvas climb 1 without the copy path; the other 60 quests, 37 of them re-attempts, rest on the same draw order and a stepper checked againstnext_gridon 24 random cases. Witness: lab/rs/still-hunt. - Verified Over 64 default quests and 4626 frames, 609 pass the ring cut (peak-ring share at least three times a random field share at the same ring, wavelength at most twice the mask side, peak ring at or below half the field): 426 of 1043 basic-path frames, 76 of 92 copy-path frames, 107 of 3491 side-3 frames; 3 of the 64 settled stills pass, all on side-3 masks; the cut also admits envelope peaks, 149 of the 562 hits past generation 0 peaking at ring 1 or 2 of their field, 34 at a wavelength longer than the crop, among them 66 of the 73 copy-path hits, the copy path being one quest whose masks are its own 45-cell canvas on a 64 field; none of the 176 resolved drawn-mask hits sit at ring 1 or 2; the full-square peak leaves the ring cut for a Fourier corner in 376 of 4561 frames. Witness: lab/rs/still-hunt.
- Verified At canvas cap 512 and mask cap 128, seeds 65 to 68, the copy path yields 40 ring-cut frames of 51 and the one drawn-mask still, seed 66, a copy mask of side 75 on a board of 5 by 5 tiles, peaks at ring 10 of field 512, wavelength 51 cells or 0.68 mask sides, inside the lobe 8 to 13; seed 67 with a copy mask of side 121 on a board of 3 by 3 tiles peaks at the tile fundamental ring 4, one ring below its lobe 5 to 8, in 11 of its 27 hits, at ring 13 in 5 and elsewhere from 8 to 93 in the rest. Witness: lab/rs/still-hunt.
- Proved Sublattice closure: when every mask offset lies in
dZ^2and zero is outside birth, every outer-totalistic rule carries a frameA (x) Bon thed sidetorus toA' (x) B, withA'one step of the same rule on thesidetorus under the mask divided byd, because the count at a cell in positionpof its tile isB(p)times the quotient count and a cell at an empty position reads count zero; verified frame by frame on 16 runs of the mini preset, all 16 rules, the carpet-tile seed at tessellation 3 under its copied-inverted mask of index 9. Witness: lab/rs/life-atlas. - Verified On the mini preset, 848 runs on canvas 27 to 64 generations, 103 settled frames (34 distinct up to the dihedral group and torus translation) tested at every torus shift and both cuts 3 and 9: in place 72 are confined to one block of the cut, 4 are full tilings, 1 is the board footprint and the 3 proper cuts are the settled runs of the index-9 sublattice mask, no index-1 frame cutting properly; after a torus shift 6 index-1 frames cut properly, all at cut 9 and tessellation 3, the 16-cell still of the corner seed (four 2x2 blocks at spacing 3, shift
(1, 1), outer fill 4) on Moore under B357/S357, B3/S3 and B3/S23 and on the two-bar and cross masks under B3/S23, and the 36-cell still of the two-bar seed on the cross mask under B3/S23 (shift(1, 0), outer fill 6); index-2 and index-3 masks cut properly nowhere. Witness: lab/rs/life-atlas. - Verified Mini fate table (dead, still, loop, timeout): number rules 106, 24, 56, 132; design rules 448, 2, 0, 27, the rolls off leaving at most one count of the nine design sequences inside budget 8, the budget of 45 of the 53 mask cells, the other 8 being tessellation-3 copy masks of budgets 26 to 80; B3/S23 31, 17, 4, 1; the 160 timeouts hold no mover, a timeout being a lower bound on the period and never a class. Witness: lab/rs/life-atlas.
- Verified The median level set of the visit counts cuts properly in 9 of 848 runs in place and 10 after every torus shift, eight of them sublattice-lemma runs and the others the cross-tile heat frame of one index-1 run and the two-bar seed under the cross mask and B3/S23; on the 103 settled runs the proper heat sets coincide with the proper frames, so the heatmap is a design no more often than the frame it summarises. Witness: lab/rs/life-atlas.
- Refuted The lobe law on the sequence rules of mrlygame: the peak ring sits in the mask first negative lobe in 52 of 176 resolved drawn-mask frames (crop at least four mask sides, generation above 0, 15 chapters of 13 quests, correlated frames); witness seed 3, chapter 1, generation 1, mask side 23, peak ring 11 against lobe 13 to 22; the lobe centre reads 0.64 mask sides at the median while the hits wavelength over mask side fills every quarter bin from 0 to 2, the cut itself; the copy path 35 of 73 is one quest whose lobes sit at rings 2 to 4 of a 64 field, the envelope scale of its 45-cell crop. Witness: lab/rs/still-hunt.
- Refuted The seed-comb product law: on the 176 resolved frames (15 chapters, comb spacing 1.08 to 5.69 rings, median 5.22, 22 rows on one-tile boards) the peak ring is within half a ring of a comb multiple in 77 against 52.9 by chance, the chance confirmed by a uniform-ring null at 52 and a permutation null at 53, and on both comb and lobe in 22; the 77 counts correlated frames, not independent trials; witness seed 3, chapter 1, generation 1, peak ring 11 against the multiple 10.04 of comb 5.02 and outside lobe 13 to 22. Witness: lab/rs/still-hunt.
- Refuted That a tessellated seed still peaks on the seed comb: of 21 stills from tessellation 3 on canvas 27 (comb 9), the 5 comb hits are two lattice-mask runs of index 3 and 9 and three four-cell frames of peak share 0.06 on the index-2 corner mask, while every Moore still peaks at ring 1, 4 or 6; the witness is the two-bar seed at tessellation 3 under Moore and B3/S23, still at generation 53, ring 4 against comb 9 and lobe 9. Witness: lab/rs/life-atlas.
Automata
- Proved Wolfram rule
Nand the designbang dim 3, code Nare one subset of{0,1}^3under(x0, x1, x2) = (l, c, r)with corneri = 4 x0 + 2 x1 + x2, so every design invariant is a rule invariant; recomputed on all 2048 rule cells. Witness: lab/rs/automata-census. - Verified The elementary rules fall into 160, 88, 22 and 14 classes under reflection, Wolfram equivalence, the cube group and the cube group with complement, by orbit walk and by Burnside alike; Wolfram equivalence and the cube group are incomparable inside the order-96 group and meet exactly in the reflection, rule 137 lying in the Wolfram class of 110 and outside its cube orbit. Witness: lab/rs/automata-census.
- Proved The cube group is not a dynamical symmetry of the elementary automata: surjectivity is not a cube invariant, exactly one of the 22 classes being mixed, the 24-rule orbit of 30 with 16 surjective rules and 54 among the 8 that are not, while reversibility is constant on all 22 classes, the six reversible rules 15, 51, 85, 170, 204, 240 being the orbit of the identity, and both properties are constant on all 88 Wolfram classes. Witness: lab/rs/automata-census.
- Verified The 24 rules in the cube orbit of 110 share popcount 5, degree 3, genus compound, the Walsh amplitude profile and non-surjectivity, only their single-seed diagrams separating all 24; the multiset of Walsh amplitudes by weight is a cube invariant on all 256 rules while the signed level sums are not. Witness: lab/rs/automata-census.
- Verified Rules 60 and 102 draw the plane designs
bang dim 2, code 13andbang dim 2, code 14cell for cell from one seed, and rule 90 drawsbang dim 2, code 13in the sheared framej = (t + i)/2, each unique among the fill-3 codes to level 8 by two renderers. Witness: lab/rs/automata-census. - Proved The single-seed diagram of rule 150 is an XOR substitution, row
2tbeing rowtspread by two and row2t + 1that row xor its two unit shifts, and its first2^krows holdP(k) = 2^k F(k+2)live cells withB(k)adjacent pairs underP' = 4P - 2BandB' = 2P - 2B, so the growth exponent islog2(1 + sqrt 5); the recurrence and closed form are already A087206's and A071053's and are re-derived here. Witness: lab/rs/automata-census, A087206, A071053. - Verified One live cell under the 256 rules gives 143 distinct space-time diagrams, 89 up to reflection, class sizes
{1: 118, 2: 13, 4: 4, 8: 4, 16: 4}, identical at padTand2TforT = 64, 128, 256; equal occurring key implies equal diagram with 0 failures over 65536 ordered pairs, the key measured on the padded line takes 152 values by a boundary artefact, and on the cropped window exactly 143. Witness: lab/rs/automata-census. - Proved In every dimension the level-1 side-3 tile of the design "not every coordinate odd" is the
3^dim - 1Moore neighbourhood and the tile of "at most one odd coordinate" fills2^(dim-1) (dim + 2); as popped masks the two agree iffdim <= 2, 20 against 26 cells atdim = 3, and in the plane the Moore mask isbang dim 2, code 7. Witness: lab/py/life-census, lab/py/sibling-census. - Verified
B3/S23is thedim = 9design of fill 140 of 512, so Langton's lambda is140/512by definition, withGF(2)degree 8 on 184 monomials, Walsh level sums140, 308, -224, -896, -168, 840, 448, -224, -196, -28on the 0/1 form and genus compound; over the2^18life-like rules the fill takes 479 of 513 values with 34 gaps, the genus splits 2044 isotropic, 4 axial only and 260096 compound, exactly 8 rules are affine, and the degree obeysdeg(B, S) = deg BwhenB = Sandmax(deg B, 1 + deg(B xor S))otherwise, giving2 * 4^drules of degree at mostd. Witness: lab/py/life-census. - Proved The nine-cell Moore XOR
B1357/S02468is rule 150 tensor rule 150, every time slice the outer product of two rule 150 rows and its population A071053 squared, which is A246035; the named replicatorB1357/S1357is the eight-cell XOR with kernel(1/x + 1 + x)(1/y + 1 + y) - 1, A160239, and equals the outer product with the centre copy removed only att = 2^j. Witness: lab/py/life-census, A246035, A160239. - Proved The decoupling lemma: an automaton whose dependency set, centre included, generates a sublattice of index
kiskinterleaved copies of the index-1 rescaled automaton under the same rule, so the 1D parity tile at side2r + 1decouples iffris even and the Cantor tower iff its level is even; over the base-2 masks atdim = 1, 2, sides 3 to 9 and levels 1 to 3, the 195 distinct masks split 95 of index 1, 70 of index 2, 18 of index 4 and 12 rank-deficient. Witness: lab/py/sibling-census. - Proved
B3/S23is not a rows-then-columns composite of two elementary rules in either order; the 65536 ordered pairs give 32260 distinct nine-input rules, none equal to Life, and exactly 10 life-like composites, all affine or thresholds at 0 or 9. Witness: lab/py/sibling-census. - Proved Cantor-Life,
B3/S23on the eight-cell level-3 Cantor mask at offsets+-5, +-7, +-11, +-13, has no still life under 4 cells at any width,{0, 5, 7, 12}being minimal, and its nine-cell XOR has period dividing 256 on the ring of 1024 by Frobenius, exactly 256 on generic soups; every seed of width at most 14 dies (6113), stills (2003) or oscillates (76, periods 2, 3, 4, 6), and no mover is found there. Witness: lab/py/sibling-census. - Proved Menger-Life,
B3/S23on the 20-cell Menger mask, leaks out of every plane holding a dead cell of Moore count 3, and a plane2 x 2block stacks as rule 90 along the normal with population4 * 2^popcount(t); over 101 outer-totalistic rules and 200 random5^3seeds each, no mover appears. Witness: lab/py/sibling-census. - Proved Under the composite
110.110the bounding box of every finite pattern grows without bound, its upper-left corner moving(-1, -1)each generation; the population growth itself is only recomputed, not proved. Witness: lab/py/sibling-census. - Refuted "Fredkin's replicator is the mod-2 sum of the nine Moore cells": the named replicator
B1357/S1357is the eight-cell sum with kernel(1/x + 1 + x)(1/y + 1 + y) - 1, A160239, while the nine-cell sum isB1357/S02468, A246035, and the two agree at no generation pastt = 0except through the removed centre copy att = 2^j. Witness: lab/py/life-census, A160239, A246035. - Verified Over the 195 base-2 masks at dim 1, 2, sides 3 to 9 and levels 1 to 3 the lattice index splits 16 of index 1, 11 of index 2 and one empty mask at dim 1 and 79, 59, 18 and 11 at dim 2, the both-even mask
bang dim 2, code 1at level 2 being an index-4 witness. Witness: lab/py/sibling-census. - Conjecture On the level-3 Cantor mask from soups of 1024 cells at three densities,
B36/S23behaves likeB3/S23with activity lingering at density 0.5,B2/Ssustains a soup near 0.18,B3/S012345678freezes near 0.65 at the densities 0.25 and 0.5, andB3678/S34678dies, fills the ring or holds a long period at a density between 0.3 and 0.9. Witness: the soup runs of lab/py/sibling-census, which carries no witness line for these four rules. - Verified Of the 101 Menger rules on a
32^3torus at 200 generations the 22 quiet in all four runs are every rule of birth{5}or{6}together withB4/S5andB4/S6. Witness: lab/py/sibling-census. - Verified Of the 69 still lifes among the 20200 Menger seed fates, 55 sit under
B5/S34,B6/S34andB56/S34. Witness: lab/py/sibling-census.
b-visibility
- Conjecture The gasket's
b-visible density is(1 - 2^(b-1)/3^b) Prod_{p odd}(1 - p^(-(b+1))), not(8/9)/zeta(b+1)for everyb >= 1: the local factor at 2 is2^(b-1)/3^b, exact to the integer atb = 1, 2, 3on every level3..12, and the ratio to1/zeta(b+1)is(1 - 2^(b-1)/3^b)/(1 - 2^(-(b+1))), which is8/9atb = 1((2/3)/(3/4)) and atb = 2((7/9)/(7/8)) only -368/405 = 0.9086420atb = 3,2336/2511 = 0.9303067atb = 4, climbing to 1; the two formulas part atb = 3,0.8395292against0.8212786, and exact enumeration reads0.8427119at level 12, falling about0.0022a level toward the former;b = 1is the proved16/(3 Pi^2).
Boolean complexity
- Verified Geometry under-determines Boolean complexity at
dim = 4:bang dim 4, code 27andbang dim 4, code 281share genus,GF(2)degree, popcount and the fill polynomial4k^4 - 4k^3 + k^2and split six of seven complexity measures; across the 424 classes (22 + 402) 92 groups hold two or more classes and 279 measure splits occur. Witness: lab/py/boolean-measures, mrlymath::bang::counting::sequence. - Verified Sensitivity and block sensitivity separate exactly once in the
dim <= 4catalog:s = bson all 22 classes atdim = 3and on 401 of 402 atdim = 4, the exceptionbang dim 4, code 7128withs = 2,bs = 3, orbit 24;C = bson all 424 classes; exactly two classes meetdeg = s^2,bang dim 4, code 855andbang dim 4, code 1911, the second the AND-of-ORs that Huang 2019 names tight fors(f) >= sqrt(deg(f)). Witness: lab/py/boolean-measures.
Carpet star
- Conjecture The carpet-star decay coefficient is not exactly
-1/8: it depends on the registration and band-normalization frame, the family frame throughL = 400giving slope-0.1242and the ideal frame through the sameL = 400giving-0.18to-0.19and still drifting; only the(log L)/Ldecay order survives the frame change.
Cobham
- Proved Multiplicative independence is a property of a pair and never of a triple: dependence is an equivalence relation on the integers
>= 2whose classes are the powers of one least member, so three bases that are pairwise dependent are jointly dependent and a third base adds no hypothesis a pair does not carry; the invariant is the dependence-class partition and not the tuple. The two degenerate readings are settled the same way: base1is not a base,k-recognizability being defined fork >= 2only, and bases2and4are one base, so Cobham's hypothesis fails there and so does its conclusion, the base-4 design{0, 1}being4-recognizable, hence2-recognizable, infinite and of density(1/2)^levelat levellevel, hence not ultimately periodic. Witness: cobham.md:9 to cobham.md:15, Durand and Rigo Definition 1.1 and Remark 1.2 read at source, Bes on Buchi read at source. - Proved Every proper one-dimensional design is base-locked, exactly. For
Finside{0, ..., base-1}with0 in Fand1 < card F < base, the setS_Fof integers whose digits all lie inFis infinite, sinced base^klies in it for every nonzerodinF, and has density(card F / base)^levelat levellevel, which tends to0; an infinite ultimately periodic set has positive density, soS_Fis not ultimately periodic, and Cobham's theorem forbids any base multiplicatively independent ofbase. The two hypotheses are the two exclusions and nothing else:card F > 1removesF = {0}andcard F < baseremoves the full digit set, and those are the only two semilinear designs atdim = 1. Witness: cobham.md:26, Bes Theorem 24 and Durand and Rigo Theorem 1.1 read at source. - Proved A necessary condition on the digit set, sharp enough to settle every gasket. If
S_Fis semilinear thencard F = base^dfor an integer0 <= d <= dim, andS_Flies in a finite union ofd-dimensional affine subspaces: a linear setv + N c_1 + ... + N c_rwhose generators span dimensionemeets[0, N)^diminTheta(N^e)points, so a semilinear set countsTheta(N^d)in the box withdthe largest span dimension among its constituents, while the design counts(card F)^levelexactly at sidebase^level, forcingcard F = base^d. Consequence with no geometry: the base-2 gasket{(0,0), (0,1), (1,0)}hascard F = 3, not a power of2, so it is not semilinear and not3-recognizable. Witness: cobham.md:32 and cobham.md:38. - Proved A sufficient condition, and the two conditions agree at
base = 2, dim = 2. CallFa block design when thedimcoordinates split into a zero setZanddblocks withF = {v : v_i = 0 on Z, and v_i = v_j whenever i and j share a block}; thencard F = base^dandS_F = N c_1 + ... + N c_dwithc_tthe0/1indicator of blockt, one linear set, hence semilinear and recognizable in every base. Atbase = 2, dim = 2the characterization is complete: of the eight designs containing0, the five of cardinality1, 2, 2, 2, 4are exactly the block designs and are semilinear, and the three of cardinality3are excluded by the count. Witness: cobham.md:33 and cobham.md:34. - Proved The base-3 gasket is not semilinear and so not
2-recognizable. Its box count is3^levelat side3^level, sod = 1and a semilinear version would lie in finitely many lines; but it containsP_t = (3^t, 3^(t^2))for everyt >= 2, whose consecutive slopes are exactlys_t = 3^(t^2 - t) (3^(2t+1) - 1)/2, strictly increasing, so theP_tsit in strictly convex position, no three are collinear, and coveringnof them costs at leastn/2lines. Hence no automaton reading base-2 digits enforces the base-3 gasket's digit rule. Witness: cobham.md:37. - Proved Five of this tree's instruments, checked one by one on the page that carries each, split as follows under a second independent base; the audit covers those five and asserts nothing about the instruments it did not check. Survives: the box bound of the coprimality sieve,
N*_level(m) <= (base+1)^dim fill^level m^(-alpha)withalpha = log(fill)/log(base), which is pure counting onS_leveland passes to any subset by monotonicity, the Chebyshev sum built on it still converging whenalpha > 1. Dies: the fill law ofmethod.md, an identity on a Kronecker power in one base; the transfer matrix and its Perron root, the vertex shift ofbeneath.md, the even slice matrixM_evenofcuts.mdand the Collatz-Wielandt brackets ofcrop.md, each a finite automaton over the digits of one base; the carry automaton ofcuts.md, finite only becausex -> (x + dim)/3contracts on integer carries inside one base, while a machine reading base-2 digits and tracking base-3 digits is base conversion; and the character contractionabs(Sum) <= fill - 2 + 2 cos(pi/(2 base)), which is the statement that the level-leveltransform factors over digit positions in one base. A sieve needs an upper bound and an equidistribution: two bases hand over the first and destroy the second. Witness: cobham.md:40 to cobham.md:46. - Proved The two-set transversality theorem does not iterate, for an elementary reason:
A cap Bneed not be invariant under either map. WithAthe middle-thirds set,T_3-invariant, andB = [0, 1),T_2-invariant, the intersection isA, which is notT_2-invariant, since1/4 = 0.020202..._3lies in it andT_2(1/4) = 1/2 = 0.1111..._3does not. Them-fold bound is proved instead by rewriting the intersection as one slice of the productA_1 x ... x A_dinsideT^d. Witness: cobham.md:52, Corso and Shmerkin 2024 Theorem 1.15 and Corollary 1.17 read at source. - Proved What product designs do give is one budget per axis, not one budget in total. If every
F_iis a productG_i^(1) x ... x G_i^(dim)across thedimaxes in pairwise independent bases, eachA_iis the product of its axis sets, the intersection is the coordinatewise intersection, upper box dimension is subadditive on products, and Corso and Shmerkin Corollary 1.17 applies on each axis, givingdim-upper_B(cap_i A_i) <= sum_(j=1)^dim max(0, sum_i dim_H A_i^(j) - (m-1)), upper box on the left and Hausdorff on the right. Witness: cobham.md:61. - Verified The joint census of the base-2 gasket
{(x, y) : x AND y = 0}against the base-3 gasket,C(N) = card(A cap B cap [0, N)^2), readsC(3^m) = 1, 3, 7, 19, 45, 111, 241, 467, 1175, 2443, 5285, 11939, 25281, 53477, 109001, 231737, 498083, 1077727, 2179165, 4372741, 9051805, 18107943, 37126191, 75050077, 151133095atm = 0..24. Each level is computed by a pruned walk over the base-3 exponents whose cut is a proved bit-length bound on the remaining addition, and rebuilt form <= 6by scanning every pair in the box against both digit rules with one shared membership routine; the two agree at every level and the axis bound is asserted at each. Witness: cobham.md:77,lab/py/two-base-gasketverbstermsandcontrol. - Proved
C(3^m) >= 2^(m+1) - 1, and that already breaks the naive planar budget. On the axisx = 0membership in the base-2 gasket is automatic and membership in the base-3 gasket asks the base-3 digits ofyto lie in{0, 1}, which2^mvalues below3^msatisfy; the axisy = 0gives another2^m; the origin is the only overlap. Hence the counting exponent is at leastlog_3 2 >= 0.630929, against a budgetlog_2 3 + 1 - 2 <= 0.584963, the lower bound truncated down and the budget rounded up. The real gaskets carry the same excess: the left edge lies in the real base-2 gasket and the real base-3 gasket meets it in a Cantor set of dimensionlog_3 2. Witness: cobham.md:78 and cobham.md:79,lab/py/two-base-gasketverbstermsandbudget. - Proved Budget zero is dimension zero and not finiteness:
{2^n}has counting exponent0, its count belowNbeing at mostlog_2 N + 1, and is infinite, so a transversality bound of zero never closes a question that asks for a finite list. Finiteness in two bases is reached only at the bounded-digit-sum corner, by Senge and Straus 1973 ineffectively through Thue-Siegel-Roth and by Stewart 1980 effectively through Baker; that corner is not a design, its set is not closed under changing one digit and its count belowb^kisO(k^c). Witness: cobham.md:67 and cobham.md:68, both statements read at source in the survey of Bugeaud, Cipu and Mignotte. - Proved The three-base thin set has real upper box dimension zero, by the three-set theorem and not by any pair. With
A_3, A_5, A_7the closed subsets of the circle whose base-3, base-5 and base-7 digits lie in{0,1},{0,1,2}and{0,1,2}, Corso and Shmerkin 2024 Corollary 1.17 atd = 3asks for pairwise multiplicatively independentp_j >= 2, closedT_(p_j)-invariantA_jand affineg_j, and givesdim-upper_B(g_1(A_1) cap g_2(A_2) cap g_3(A_3)) <= max{s - 2, 0}withs = sum_j dim_H A_j; the bases are distinct primes, each set is closed and invariant by its digit rule, theg_jare the identity, ands - 2 = -0.121889rounded up, so the bound is0and upper box dimension is nonnegative. The conclusion is about the three real sets and about upper box dimension, and it does not transfer to the integer set. Witness: cobham.md:90,lab/rs/three-base-thinverbbudget, Corso and Shmerkin 2024 Corollary 1.17 read at source. - Proved The third base is not redundant, and the redundancy is sharp in both directions. Upward, the three pair budgets
dim_i + dim_j - 1read0.313536at(3, 5),0.195505at(3, 7)and0.247182at(5, 7), each rounded up and each positive, so the two-set bound returns nothing on any pair. Downward, the pair(3, 5)alone is infinite: Erdos, Graham, Ruzsa and Straus 1975, quoted as Theorem 1.8 of Burrell and Yu 2021, give infinitely many integers with base-pdigits<= Aand base-qdigits<= BwheneverA/(p-1) + B/(q-1) >= 1, and1/(3-1) + 2/(5-1) = 1.000000exactly. The other two pairs miss the criterion by one digit each, both reading0.833333, and both reach1.000000when the base-7 bound rises from2to3; the criterion is sufficient and not necessary, so neither pair is claimed finite. Witness: cobham.md:88 and cobham.md:91 and cobham.md:92,lab/rs/three-base-thinverbbudget, Burrell and Yu 2021 Theorem 1.8 read at source. - Verified The members of the three-base thin set below
7^17 = 232630513987207are0, 1, 3186, 3187, 20007and nothing else, found in333nodes. The walk enumerates the base-3 side as subset sums of distinct powers of3from the top power down and cuts a branch by a proved bound: once the powers3^kand above are chosen the remaining addition is at most(3^k - 1)/2, so withjleast such that5^j > (3^k - 1)/2the high partfloor(n / 5^j)of every reachablenis one of two consecutive integers, and the branch dies when neither has all its base-5 digits<= 2; base7cuts the same way and membership in the base-3 set is never tested. Witness: cobham.md:94,lab/rs/three-base-thinverbseven 17. - Verified The same five members and no sixth below
3^80000, a height of38170decimal digits, in1710789nodes and61.48s on about3GB. The node count grows near21 levelat height3^leveland the stored powers costTheta(level^2)bits, so memory and not the clock is what stops the census. Witness: cobham.md:95,lab/rs/three-base-thinverbreach 80000. - Verified The pruned walk is checked against a direct scan of every integer below
10^8against all three digit rules, at base-7 bound2and again at base-7 bound3, and the two agree in both. Witness: cobham.md:96,lab/rs/three-base-thinverbcontrol. - Verified The budget changes sign one digit away, and on the far side it is a heuristic already in print. By Lucas's theorem
binomial(2k, k)is prime topexactly when every base-pdigit ofkis belowp/2, which reads<= 1at3,<= 2at5and<= 3at7, so raising the base-7 bound from2to3gives{k : binomial(2k, k) is prime to 105}, OEIS A030979, whose triple budgetlog_3 2 + log_5 3 + log_7 4 - 2reads0.025951rounded up against-0.121889for the thin set; A030979 read at source records a prize for settling whether it is finite, names it as Erdos problem 376, and quotes a heuristic of Pomerance giving aboutx^0.02595...terms up tox, which is the same number as the budget. The same walk at base-7 bound3rebuilds all23terms A030979 publishes, counts1374members below10^70, exactly the length of the table that entry calls complete to10^70, and counts216020below10^140; the effective exponentslog(count)/log(height)read0.044828and0.038103, truncated down, both above0.025951and falling. Witness: cobham.md:97 and cobham.md:98 and cobham.md:99,lab/rs/three-base-thinverbsbudget,control,ten 70andten 140, OEIS A030979 read at source. - Verified The twenty-five terms
C(3^m) = 1, 3, 7, 19, 45, 111, 241, 467, 1175, 2443, 5285, 11939, 25281, 53477, 109001, 231737, 498083, 1077727, 2179165, 4372741, 9051805, 18107943, 37126191, 75050077, 151133095atm = 0..24are printed from scratch in this run by the verbtermsand again by the verbhankel, which recomputes the census before its algebra, and the two agree term for term with each other and with the page. Both call the same pruned walk, so that agreement is determinism and not corroboration: the one independent rebuild is the verbcontrol, which tests every pair of[0, 3^m)^2against both digit rules with a separate routine and agrees at everym <= 6. Witness: lab/py/two-base-gasket verbsterms,hankel,control;cobham.md:77. - Verified No linear recurrence with constant coefficients of order
r <= 12fits all twenty-five terms ofC(3^m). Two exact tests over the rationals agree. The Hankel determinants of the matrix with entriesa[i+j], computed by fraction-free Bareiss overZ, are nonzero at every sizek = 1..13, reading1, -2, 4, 8, 5360, -1259267712, -5516990041856, 112485023878830080, 5697070341654551514880, -1283183611235610612560681984, 512735847124145678895522067154944, -30665906970422092677442692752788846592, -148892102950447887517893509783802772470337536; a recurrence of orderrwould force every Hankel determinant of size aboverto vanish, sodet H_13 != 0alone kills every order at most12. Independently, for each orderr = 1..12the linear systema(n) = c_1 a(n-1) + ... + c_r a(n-r)taken over every one of the25 - ravailable equations is inconsistent by Gauss-Jordan overQ, order by order with no order left consistent and none underdetermined. Order12is the largest the data can test: it leaves13equations against12unknowns, one spare, while order13leaves12equations against13unknowns, one short of determined, so that system is consistent for trivial reasons and tests nothing;12is exactly the bound twenty-five terms carry and not a choice. The two solvers behind the negative have their own generator: the verbselftestfits Fibonacci first at order2withx^2 - x - 1,2^n + 3^n + 1first at order3with dominant root3.0000000, andn^3 + 2^nat no order below5and at5with(x - 1)^4 (x - 2), and checksbareissagainst five determinants computed by hand, eleven checks in0.05s. Witness: lab/py/two-base-gasket verbshankel,3min15s atHI = 24, andselftest. - Verified The sequence
1, 3, 7, 19, 45, 111, 241, 467, ...is absent from the local OEIS dump, and so are eight simple transforms of it: the sequence from its second term, the first differences, the partial sums,a(n) - 1,a(n) + 1,(a(n) - 1)/2,2 a(n), and the halved first differences. Each was searched as its seven-term window starting at the second term. Witness: grep of the local dumpresearch/data/oeis/stripped, nine patterns, zero hits. - Verified The decision rule is calibrated on one-base counts before any two-base object is read, and neither one-base control is clean. The base-3 design
{0, 1}puts a maximum at5.719220against2 pi / ln 3 = 5.719202, error0.000%, at1.7e7times the median power of the band[0.5, 14]under the linear detrend and1.9e7under the cubic; the base-5 design{0, 1, 2}puts one at3.903959against2 pi / ln 5 = 3.903963, error0.000%, at4.0e6times the median. At3^44the base-3 control's nearest maximum to2 pi / ln 5sits at error1.115%and35.9times the median under the linear detrend and at0.966%and39.2under the cubic, which passes the rule at a frequency absent by construction; the base-5 control's nearest maximum to2 pi / ln 3sits at1.060%and2.21under the linear detrend and at0.963%and1.95under the cubic, inside the tolerance and held out by the power gate alone. Both control windows are longer than the cell's and give a prediction more room to be met by position alone: span38.05with11maxima above10xthe median covering0.113of the band, and span38.49with4covering0.048, against the cell's span27.41,4maxima and0.020. Witnesslab/py/two-base-instrumentverbcell 44. - Verified The multiplicatively dependent pair is a one-base control and not a two-base count. Base 3 digits
{0, 1}against base 9 digits{0, 1, 3}satisfies the zero-digit hypothesis of the collapse theorem ofbases.md,0lying in both digit sets, so the joint set is exactly the one-base designF(9, {0, 1, 3})of exponentlog_9 3 = 1/2; at the aligned height3^28 = 9^14its count is exactly3^14 - 1 = 4782968, the fitted exponent is0.497809, and its spectrum shows2 pi / ln 9 = 2.859601at2.859889, error0.010%, at886times the median, with the first harmonic2 pi / ln 3at error0.003%and2.5e3times the median, on a window of span17.47carrying4maxima above10xthe median covering0.042of the band. Witnesslab/py/two-base-instrumentverbcollapse 28. - Verified The two-frequency prediction is what the two band structures alone predict, and the cell does not meet it at their scale. A member of the base-3 design with
k+1digits lies in[3^k, (3^(k+1)-1)/2]and a member of the base-5 design withi+1digits in[5^i, (5^(i+1)-1)/2], so the designs occupyln(3/2)/ln 3 = 0.369070andln(5/2)/ln 5 = 0.569323of their own decades and the cell's count is exactly constant wherever the two bands miss: of the47decades[3^j, 3^(j+1))below3^47, the10withj = 1, 4, 17, 20, 23, 26, 36, 39, 42, 45carry no member at all, proved by the bands and witnessed by the ladder, whose new hits are0atlevel = 40, 43, 46. The block modelC3(N) C5(N) / N, the same two band structures multiplied with no joint arithmetic, shows2 pi / ln 3at error0.001%and1.33e6times the median and2 pi / ln 5at0.004%and9.79e5, on a window of span31.55with4loud maxima covering0.043; the cell's own count on a window of span30.70with the same4loud maxima and0.020reaches22.5and15.7. Witnesslab/py/two-base-instrumentverbsblocks 47andladder 38 47. - Verified The rule's verdict on the cell is not stable in height, so this run settles the two-frequency prediction neither way. On the full window under both detrends the ladder from
3^38to3^47returns both frequencies present atlevel = 38, 39, 40, 41,2 pi / ln 3at errors0.473%, 0.073%, 0.342%, 0.704%under the linear detrend and0.325%, 0.036%, 0.484%, 0.862%under the cubic at19to24times the median, and returns2 pi / ln 3absent fromlevel = 42up, at errors1.034%to1.574%and22to25times the median, while2 pi / ln 5is present at every one of the ten heights. The error at2 pi / ln 3rises monotonically fromlevel = 39tolevel = 46under both detrends as the window lengthens, which is a nearest maximum drifting away from the prediction rather than an estimate converging on it. On the upper half of the window at3^44the nearest maximum to2 pi / ln 3sits at error0.825%under the linear detrend and0.791%under the cubic, inside the tolerance and held out by the power gate alone at5.55and6.1times the median, and at3^47at2.430%and2.293%. No height rule is stated in advance, so no height is entitled to the verdict. Witnesslab/py/two-base-instrumentverbsladder 38 47,cell 44andcell 47. - Verified The cell's strongest maximum matches no small combination of the two lattice frequencies. It sits at
1.702087at3^44and1.697925at3^47, at57and68times the median on windows of span27.41and30.70carrying4maxima above10xthe median covering0.020of the band, and the nearestm 2 pi / ln 3 + n 2 pi / ln 5withabs(m), abs(n) <= 8is(1, -1) = 1.815239at errors6.233%and6.463%;2 pi / ln 15misses by3.750%and3.457%and the sum frequency by1.528%and1.977%at2.2and2.1times the median, while2 pi / ln 5is met at0.461%and0.594%. Block structure does not account for it: the block model's nearest maximum to1.815239sits at1.895843and0.588times the median at3^44and at1.697497and1.58at3^47. The same verbs read the local counting exponent falling through the budget0.313536,0.323301over the full window and0.295978over its upper half at3^44,0.318728and0.292184at3^47, which is a fit at finite height and decides nothing about the limit. Witnesslab/py/two-base-instrumentverbscell 44,cell 47andblocks 47. - Proved The dimension-one lane of coprime, Conjectures O, W and Z with the shelf lane
lemma-b-pincer, is a one-base problem whose automata come in families indexed by the object read, and never meets Cobham's hypothesis. Every object of the lane is read in base 3 alone: the gasketG_nis the base-3 digit pairs from{(0,0),(1,0),(0,1)}, the wordbinaryinside the lane means a base-3 expansion with digits in{0, 1}and never base 2, and the only other bases in the section are the general simplex corollary atcoprime.md:150and the base-4 and base-5 simplex probes atcoprime.md:253, each a separate design in its own single base and not a second base on one object. The machines are one automaton per primitive ray, per multiplier pairB(s,t), per band direction and per modulus3^k; the band family, whose states are the integers in[-(z_2-1)/2, (z_1-1)/2](coprime.md:233), and the digit-congruence family indexed by3^k(coprime.md:228) carry no uniform state bound, whileB(s,t)carries only the upper bound(s+1)(t+1)(coprime.md:214) and a measured 167 live states at(25,52)and(31,40)(coprime.md:197,gasket-ray-machine), and the ray automata grow likeabin the shelf lane's own words. Cobham asks one set recognized by a finite automaton in two multiplicatively independent bases, which the lane never presents, so the wall of cobham, that no transfer matrix over the digits of one base reads the constraint a second independent base imposes, does not touch the lane. Witness:coprime.md:187; the shelf lane README reading "counting the multiples of a ray inside the gasket is a finite automaton on the base-3 digits of the multiplier, with growth rate rho(a,b). There are infinitely many rays and the automata grow like ab, so no computation settles them";cobham.md:41. - Conjecture Block designs are the only semilinear designs, at every base and every dimension. The count alone is not enough, which is what makes the conjecture nontrivial: the base-3 gasket has
card F = 3 = 3^1and is not semilinear. Witness: cobham.md:35. - Conjecture The true counting exponent of the two-gasket intersection is unknown and twenty-five levels decide nothing.
log_3 C(3^m) / mreads0.754141, 0.749634, 0.746312, 0.743739, 0.738025, 0.732546, 0.729032, 0.724371, 0.721151, 0.717651, 0.714298atm = 14..24, falling by about0.004a level on the mean of those ten steps and still0.129above the budget at the last level, consistent with any limit from0.630929upward. The cheap falsifier is a linear recurrence for1, 3, 7, 19, 45, 111, 241, 467, ..., which would make the growth rate algebraic and put the object back inside this tree's machinery; it is not run here. Witness: cobham.md:81 and cobham.md:82,lab/py/two-base-gasketverbterms. - Conjecture The Schanuel wall. Every growth exponent this tree prints has the shape
log(algebraic)/log(base), the Perron root of a nonnegative integer matrix read in its own base, and every two-base budget has the shapesum_i log(k_i)/log(p_i) - (m-1) dim, aQ-linear combination of1and the ratioslog k_i / log p_i, the wall assuming that a realized two-base exponent has that shape too, which nothing here proves; those two families meet only where one side degenerates, and under Schanuel's conjecture they meet nowhere nontrivial, so no instrument of this tree ever outputs a two-base exponent. This is strictly stronger than Cobham, which forbids the set from being automatic while the wall forbids the number from being a Perron root, and neither implies the other. Witness: cobham.md:108, Burrell and Yu Theorem 1.6 and Theorem 1.11 read at source. - Conjecture The three-base thin set is exactly
{0, 1, 3186, 3187, 20007}. Finiteness is open and no theorem on the page gives it: the dimension bound is0and the page already proves that a budget of zero says nothing about finiteness, while the finiteness results in print, Senge and Straus 1973 and Stewart 1980, bound digit sums rather than digits, so applying either to the thin set would need a bound on the base-3 digit sum of a member, which is the finiteness in question. The falsifier is a sixth member and the census is where it would have shown. Witness: cobham.md:101 and cobham.md:102,lab/rs/three-base-thinverbreach 80000. - Conjecture
C(3^m)satisfies no linear recurrence with constant coefficients of any order, so the counting exponent of Object Y is notlog_3of a Perron root and the Schanuel wall holds in data for Object Y. What is proved is the order at most12case above; the step to every order is the conjecture, and nothing here rules out a recurrence of order13or more. Falsification: orderris testable once the terms leave its system a spare equation, which wants2r+1of them, so order13wants27terms, the two levelsm = 25andm = 26beyond what is run, about11min by the measured per-level factor; the same verb tests any order the census reaches. Witness: lab/py/two-base-gasket verbshankelandselftest, extrapolated from ther <= 12negative. - Conjecture The joint digit constraint destroys the oscillation that either design carries alone. The block model of the same two designs carries both lattice frequencies at
10^5to10^6times the median while at3^47the cell's own count carries2 pi / ln 5at15.7times the median and puts nothing nearer to2 pi / ln 3than a maximum1.488%away, so the intersection is not the product of its two band structures at the level the spectrum reads. A nonlattice Moran system has its complex dimensions off any arithmetic progression and its detrended count carries no sharp frequency, which is consistent with the cell's flat reading, and nothing in this run separates that reading from the height instability the ladder prints. A positive test has to read the spread of the complex dimensions rather than a comb, and that needs a zeta function for the joint object, which needs a gap structure, which is what Cobham denies. Witnesslab/py/two-base-instrumentverbscell 44,cell 47,ladder 38 47andblocks 47. - Refuted The sentence "no proper design is recognizable in two independent bases, in any
dim" is false. Atdim = 2andbase = 2the designF = {(0,0), (1,1)}hasS_F = {(n, n)}, the diagonal, which is definable in<N; =, +>and so recognizable in every base by the easy half of Cobham-Semenov. Proper designs recognizable in two independent bases exist as soon asdim >= 2, so thedim = 1lock does not generalize by itself and the theorem must be stated as Cobham-Semenov states it, with semilinear in place of ultimately periodic. Witness: cobham.md:31, Bes Theorem 25 read at source. - Refuted The global planar budget
dim(A cap B) <= max(0, dim A + dim B - dim)is false atdim = 2, in one line and with product designs. The base-2 designF_A = {(0,0), (0,1)}givesA = {0} x Tof dimension1, the base-3 designF_B = {(0,0), (0,1)}givesB = {0} x Cof dimensionlog_3 2,Bsits insideA, so the intersection has dimensionlog_3 2while the budget readsmax(0, 1 + log_3 2 - 2) = 0. Both sets lie in the line{0} x T, invariant under both maps, and that is exactly where the two codimensions refuse to add. Witness: cobham.md:60,lab/py/two-base-gasketverbbudget. - Refuted The global budget is not a corollary of the per-axis bound, and the step that fails is
sum_j max(0, x_j) >= max(0, sum_j x_j), which runs the wrong way. The one-line witness above is where it runs strictly wrong: the per-axis bound reads0 + log_3 2and is sharp there, while the global budget reads0. So indim >= 2the two-base budget is a theorem per axis for product designs and open for compounds, andcore.mdproves almost every design is a compound asdimgrows. Witness: cobham.md:62.
Complex dimensions
- Conjecture Every one-base design is lattice, so the Lapidus-Maier machinery is not out of reach but empty:
zeta_level(s) = 1/(1 - fill base^(-s))puts the complex dimensions on one vertical line of period2 pi/ln(base), and(ISP)_dim, the Riemann hypothesis in the language of fractal strings, has no content on the degenerate case, several incommensurable ratios being the change that gives it content; the lattice half is checked on this tree's own poles and folding tables, the(ISP)_dimhalf is a literature reading not yet checked at source, and the dichotomy is a theorem for strings only, so dimension two and above is open outside the pluriphase class, inside which the carpet and the interior-hole designs are settled. Witness: lab/py/complex-dimensions. - Proved The Sierpinski carpet is not Minkowski measurable: its complement in the open square is the disjoint union of
8^(m-1)open squares of side3^(-m)whose boundaries lie in the carpet, the tube is the exact hole sum, andeps^(log 8/log 3 - 2) V(eps) -> G(t)withG = t^(log 8/log 3 - 2)(1 + 4t/5 - 4t^2/7)on[1/3, 1/2)andt^(log 8/log 3 - 2)(9/8 + 3t/10 - t^2/14)on[1/2, 1),C^1at the seam,379/280at the ends, maximum1.35561708227att = 0.429638, minimum1.3506702097att = 0.692137, swing0.3662%; a corollary of Kombrink, Pearse and Winter 2016 Theorem 1.1(ii), whose hypotheses are verified for the carpet with the open square, the profile and the elementary proof being the addition. Witness: lab/py/complex-dimensions carpet_tube.py, dimensions.md measurability with its hypotheses. - Proved Every one-base design at
base >= 3indim >= 2removing at least one digit vector, all removed vectors interior and pairwise differing by at least 2 in a coordinate, is not Minkowski measurable:base^(dim-1) < fill < base^dimsolog(fill)/log(base)is never an integer,G(t) = t^(log(fill)/log(base) - dim) sum_j fill^(j-1) base^(-j dim) h(t base^j) > 0, andt^(dim - log(fill)/log(base)) Gis a polynomial on[1/base, 1/2); includes the parity carpets at every odd base and dimension. Witness: dimensions.md measurability with its hypotheses (proof), lab/py/complex-dimensions atbase = 3,dim = 2only. - Refuted The hole-sum route for the sponge: the level-1 plus hole's boundary is not in the sponge (
(1/2, 1/2, 1)at distance1/6,(2/3, 1/2, 5/6)at distance1/18), the tube inside the hole is not its parallel volume, and the pluriphase theorem does not reach the sponge with the open cube; the sponge stays Conjecture. Witness: dimensions.md measurability with its hypotheses, qualification 2, read off the digit rule.
Component counts
- Refuted The boundary state of a Kronecker word grows with level, so the component count is not a finite-state function of the code sequence - one failed trial state (the four-corner partition of the running product, exact at length 2 and wrong on 20 of 216 words at length 3) bounds nothing; a linear representation of rank 4 exists and is exact on all 54240 words of length at most 4; what is unbounded is the naive geometric state
kappa, which reaches2^(level-1). Witness: order-sensitivity-of-kronecker-words.
Conjecture S: even half
- Proved The reduction chain for Conjecture S runs at every odd
base, middle-digit design,dim >= 2: the digit polynomial is palindromic with strictly positive support; the transfer recursionhat u_(level+1)(psi) = (1/base) sum_r Phi(y_r) hat u_level(y_r)holds with exact phase cancellation (the palindromic centre is the carry offsetdim m); the step identity isW_k = (-1)^(dim-1)(dim-1) base^(k-1) V(k-1)withV(level) = base m0(level) - b(level); the carry core has reachable set exactly{|c| <= floor((dim-1)/2)}, is irreducible and aperiodic, and its Perron root isrho_dim; eventual contraction (V(level) >= 0for alllevel >= level_0, evendim) impliesrho_dim <= fill/base; anddet(fill I - base M_even) == fill^n mod pfor anyp | base, primality unused, gives strictness wheneverp nmid fill; the Perron-Frobenius asymptotic is unnecessary (b(level) >= (M^level)[0,0]suffices) and the base-3 contraction hypothesis weakens to its eventual form since the odd-leveldip is a finite transient. Witness: slice-sign-even-half. - Proved The exact two-step reduction
9 b(2j+2) - fill^2 b(2j) = -(dim-1)[fill V(2j) + 3 V(2j+1)], the two-step weight identityC_2(y) = g_5(2y)(the base-3 two-step symbol is the base-5 symbol, the comb constant having minimal polynomialx^3 - 9x - 9), and the orbit identitiesG(3t) = cos(t) G(t)andNtilde(3^a pi) = ((dim-2)/(dim+2))^a Ntilde(pi). Witness: slice-sign-even-half. - Proved The Collatz-Wielandt certificate closes the even half per dimension at any odd base, strictness included:
B >= 0,x > 0,Bx < theta xcomponentwise implyrho(B) < thetawith no irreducibility needed; withbeta_K = (M^T)^K 1 > 0(positive by column-sum positivity alone,colsum(c) = (fill + (-1)^(dim-1)(dim-1)(base[base|c]-1))/base > 0), ifbase beta_(K+1)(c) < fill beta_K(c)for every|c| <= (dim-1)//2thenrho_dim < fill/basestrictly, bypassing the mod-pdeterminant lemma and every exceptional class; the base-5 mass identity on the right Perron vector of the full core is5 rho_dim = fill - (dim-1)(5 p_dim - 1), so the even half isp_dim > 1/5, and the left-vector reading is false atdim = 8(p_LEFT = 0.1428 < 1/5);K = 2certificates are exact atdim = 16, 30, 44, 60. Witness: slice-sign-even-half. - Verified The row certificate
v^T M^t >= 0is sound -V(level) = sum_j (v^T M^t)_j u_(level-t)(j)with both factors nonnegative, so one integertwithv^T M^t >= 0entrywise plus the exact prefixV(0..t-1) >= 0provesV(level) >= 0for alllevel, monotone int- and at base 5 its minimal depth ist(dim) = max(1, ceil(log_5(2 dim - 3)) - 1), breakpoints exactly atR = (5^(k+1)-1)/4, checked to evendim = 400with fresh rows at 150, 250 and the boundary314|316; the782atk = 4is an extrapolation unobservable belowdim = 1566. Witness: slice-sign-even-half. - Proved The 2-adic strictness lemma, complementary to the mod-
plemma:det(fill I - base M_even) == (-base)^n det(M_even) (mod fill)by principal-minor expansion (everyk < nterm killed byfill^(n-k)), so a primep | fill,p nmid basewithv_p(det M_even) < v_p(fill)forcesdet(fill I - base M_even) != 0, that isrho_dim != fill/base, which upgrades a certificate's<=to<; the two lemmas' silent classes (p | baseagainstp | fill) are complementary; at base 5v_2(fill) = 2(dim-1) + v_2(dim+4)whilev_2(det M_even) <= 26out todim = 156, so the test holds everywhere including the exceptional classdim == 6 (mod 10)todim = 156, and at base 3 the classdim == 4 (mod 6)todim = 118; the 5-adic side is large and erratic and the mod-25 angle is dead; open: a uniform bound onv_2(det M_even),<= nsufficing for all evendim >= 4. Witness: slice-sign-even-half. - Proved The even half of Conjecture S at base 5 is a theorem entire: on the base-5 middle-digit solid
rho_dim < fill/5for every evendim >= 2, henceslice dimension < solid dimension - 1at every evendim- the Fourier formbeta_K(c) = 5^(-K) sum_n F_K(n) e^(2 pi i n c/5^K)(the product-formula phase cancellation iterated), the exact telescopingfill beta_K - 5 beta_(K+1) = 5^(-K)(dim-1) Sigma_K(c)with thefill-power leading terms cancelling identically, the frequency-separation lemmaQ_K(n)/Q_K(1) <= 0.768for everyn != +-1(three-branch residue analysis in rigorous intervals, maximum0.7679580, read0.7679541in an earlier check, thej >= 3branch exhaustive atj = 3, 4, 5), and the criterion at depthK(dim) = Theta(log dim), analytic for evendim >= 18(K(dim) >= 2fordim >= 34since4(dim-2) >= 128 > 25) with exact integer certificates below; the log depth is necessary, every fixedKdying atdim = 16, 66, 316forK = 1, 2, 3; the criterion holds directly at every evendim = 34..600and at every depth transition todim = 10^6; the death lawdim = 2 ceil(5^(K+1)/4) + 2is known at three depths only; with the odd-dimtheorem, Conjecture S at base 5 is settled everywhere except strictness at odddim == 1 mod 5, exact throughdim = 80. Witness: slice-sign-even-half. - Verified The even half at base 3 holds per dimension for every even
dim = 2..102and on the grid106, 110, ..., 178-rho_dim < fill/3with strictness at each, by the exact-integer Collatz-Wielandt certificate3 beta_(K+1)(c) < fill beta_K(c), no determinant lemma and no exceptional classdim == 4 mod 6needed;beta_K(0) = b(K)exactly, soK_min >= level*(dim) + 1withlevel*the last level withV(level) < 0, andK_min = level* + 1or+ 2at every testeddim; spot depthsK_min = 8, 50, 140, 291atdim = 12, 30, 50, 72; two implementations sharing no code reproduce all 36 rows to every digit, including the two non-monotone slack rows. Witness: slice-sign-even-half. - Verified The odd half's last gap narrows to the same 2-adic bound: at base 3 and odd
dim == 1 mod 3, where the mod-3 strictness lemma is silent,v_2(det M_even) < v_2(fill) = (dim-1) + v_2(dim+2)at everydim = 13, 19, ..., 241, silent only atdim = 7(v_2(det) = 7 >= 6, closed by the direct computationdet(fill I - 3M) != 0), sorho_dim != fill/3on13 <= dim <= 241and, withrho_dim >= fill/3at every odddim,rho_dim > fill/3strictly at every odddim <= 241; the referencev_2rows on the two other classes read1, 2, 3, 1, 4(base 3,dim == 4 mod 6) and2, 1, 2, 3, 2(base 5, even); both exceptional classes of Conjecture S reduce to one uniform statement, an upper bound onv_2(det M_even), andv_2(det M_even) <= n = (dim+1)/2at everydim = 13..241in the class, failing only atdim = 7, is exactly strong enough. Witness: slice-sign-even-half. - Proved The even half of Conjecture S at base 3 is a theorem entire:
rho_dim < fill/3for every evendim >= 2, henceslice dimension < solid dimension - 1at every evendim, base 3, middle-digit design, strictness included - by the Fourier/telescoping port tobase = 3(the exact phase cancellation load-bearing, off-centre variants failing with integer witnesses), four nested frequency tracks (+-1at angle 0, the half-points+-(3^(K+1)-1)/2at the tripling fixed pointpi; on-track prefixes nest, exits never return), exit-cost and window/subtree lemmas givingE_K(dim) <= [4(K-1)(0.7528157^(dim-1) + 0.7052518^(dim-1)) + 2 * 0.2266816^(dim-1)] exp(2(K+1) 0.8900159^(dim-1))for everything off the two leader pairs, and the criterion closing atK_1(dim) = K*(dim) + O(1), analytic for evendim >= 38(182 interval-certified inequalities todim = 400, monotone domination beyond, the margin term the true cosine deficitdelta(dim) = O(3^(-2 K_1)),< 4.1e-76atdim = 38, since an absolute1e-8term fails atdim = 399999998), exact certificates below; checks: Fourier form to9.4e-61, telescoping to2.6e-59, tracks exhaustive over all3 !| n < 3^10, the subtree bound never exceeded (worstsigma_5 = 1.023against8.97), the E-bound dominating exact enumeration at all 35(dim, K)points and at 28 fresh ones (dim in {10, 14, 22, 26} x K in {3..9}, worst ratio 19.74), class counts exact atK = 9, an exit-level sweep toj = 60,dim = 4000finding the caps asymptotically exact (worst attainment0.999121) but never breached, seven certified constants re-derived to 22 digits by exact interval arithmetic on a10^-90grid with outward rounding (a hand-rounded0.6696reads0.66966), and the theorem machine-checked in exact integers atdim = 38, 40, 42(the certificate holds at exactlyK_1, fails at0.8 K*,K_1 = K_min + 1at all three); the chain's single global safety factor is 2 and theh-exit(2)attainment (two of four residues reachC_H) is load-bearing. Witness: slice-sign-even-half. - Proved The base-3 transient is identified in closed form:
level*(dim)is the greatest odd integer<= K*(dim),K*(dim) = [(dim-1) ln R + s_dim]/ln((dim+2)/(dim-2)),R = prod_(i>=2) cos(pi/3^i)/cos(2 pi/3^i) = 1.2553249438...- the half-point frequency rides thepifixed point with per-level magnitude advantagecos(pi/3^i)/cos(2 pi/3^i) > 1against per-level amplitude cost about(dim-2)/(dim+2), its sign alternates as(-1)^K(that is the odd-leveldip), and the crossing is the transient - so the certificate depth constant isln(R)/4 = 0.0568486146...andK_min in [level* + 1, ceil(K*) + 2]for evendim >= 38; exact on 58 of 58level*rows, every evendim = 6..120, each one exhausted by proof and not by margin -M >= 0andu_level = M^level e_0 >= 0, so a singletwith(M^T)^t v >= 0entrywise forcesV(level) >= 0at everylevel >= tand no census window can truncate the answer - with towerslevel* = 79, 97, 107atdim = 38, 42, 44andlevel* = 811atdim = 120; a census carried only to a4 dim + cwindow is unsound pastdimabout 70 sincelevel*is quadratic, but no row ofdim = 6..120is in fact false; the column-sum identityfill - 3 colsum(c) = (dim-1) v_c, which isprop:massby root-of-unity filtering and needs no per-row check, makes that row certificate the even-half Collatz-Wielandt test itself, so the stopping level isK_minexactly,level* + 1on 36 rows andlevel* + 2on 22; scoped todim >= 6sincedim = 4has no dip; atdim = 10, 20the half-pair carries the largest magnitude in the spectrum, the dominant pair only third. Witness: slice-sign-even-half, lab/py/base3-transient-exhaustion. - Proved Base 3 is the unique hard base: the half-point track exists at strength
|A_base(-1)|/A_base(1)per level withA_base(-1) = 1 - (-1)^((base-1)/2), so the ratio is1exactly atbase = 3,0at everybase == 1 mod 4(the symbol dies atpi, the base-5 case) and2/(base-1) < 1at everybase == 3 mod 4,base >= 7. Witness: slice-sign-even-half. - Verified Exact Collatz-Wielandt certificates give
rho_dim < fill/9at every evendim = 2..56andrho_dim < fill/11at every evendim = 2..74(machine-pinned todim <= 42anddim <= 60),K_min <= 2,V(level) > 0everywhere, no transient, and base9 = 3^2inherits nothing from base 3; atbase = 7theK = 2 -> 3step lands at exactlydim = 174as the frontier-race law predicts, the frontierf_2 = 85converged fromdim = 160, the asymptotic death law landing there too; earliness (asymptotic death minus true death) is monotone down inKand up inbase- the depth-0 death isdim = 4at every base, so base 5 is one even step early atK = 0(4 against 6) and exact atK = 1, 2,K_0(5) = 1;base = 7: 1, 1, 0 steps;base = 9: 2, 1;base = 11: 2, 2 - the asymptotic law being exact for allK >= K_0(base); atbase = 9the window edge is immune whenh == 0 mod base(dim = 20, 38), so tightness must be stated modbase; the 12 printed constants of the base-3 chain are asserted against interval endpoints and printed by ceiling. Witness: slice-sign-even-half. - Conjecture The row certificate's sign law at base 5 is periodic, not one-sided:
(v^T M^k)_j >= 0iffdist(j, 5^(k+1) Z) <= (5^(k+1)-1)/4(witnessdim = 40, k = 1, j = 19positive), the threshold being the carry-drift radius around every multiple of5^(k+1), not just around 0. Witness: slice-sign-even-half. - Conjecture Three negatives on the base-5 even half: quintupling resummation is structurally empty, the two orbit relations of the base-5 tower summed over complete residue systems returning exactly the one-step identity
5 b(level+1) = fill b(level) - (dim-1) V(level), the nontrivial comb mapping into the trivial comb whose orbit factor is 1 and the correctly normalised scaling limit ofVbeing0 = 0; any envelope bounding numerator and denominator independently dies atpsi = 0, the cone having zero width at both census points2 pi/5and4 pi/5(both slack summands nonnegative with nonpositive sum), so only curvature-coupled envelopes remain; and the neutral Gaussian width of the transfer atpsi = 0is exactlya* = m2/(24 fill) = Var(digit sum)/24 = 5 dim (dim+3)/(48(dim+4)), not5 dim/48, which explains the measured upward drift ofsig2/dimtoward5/48. - Conjecture At every odd base
base >= 5the even half falls to the base-5 template at depthO(log dim)with no transient: V-towers atbase = 5, 7, 9, 11, 13, evendim = 8, 12,level <= 25show no dip anywhere off base 3. Witness: slice-sign-even-half. - Refuted The base-3 resummation mechanism built on those identities - the scaling limit
3^n f_n(psi)/fill^n -> Sigma(psi)is false, the exact tower falling geometrically to 0 as it must since a nonzero limit would contradictrho_dim < fill/3; the claimed absolute convergence is false, the per-decade absolute mass of|G(m pi)|^(dim-1) Ntilde(m pi)growing atdim = 4(block ratios 1.081 to 1.115 out tom = 2e7) and rising through 1 atdim = 6, 8; the tail-to-lead figures-0.1812/-0.0464/-0.0121are artifacts of them <= 199cutoff, still moving atm <= 2e5;Sigma(pi) > 0is unproved at everydim; the leader boundmax_(m>1) |G(m pi)| = |G(7 pi)| = 0.2520527holds tom <= 20001. Witness: slice-sign-even-half. - Refuted
V_(2j+1) < 0for every evendim >= 4- atdim = 4,V_level > 0for everylevel <= 40(V_1 = +4exactly) and atdim = 6,V_3 = +135092 > 0; the odd-leveldip is a transient of length about0.055 dim^2, anddim = 2, 4never dip. Witness: slice-sign-even-half. - Refuted Certificate depth
K = 2closes every evendimat base 5 -5 beta_3 < fill beta_2holds for even16 <= dim <= 64and fails at every evendim = 66..320, first atdim = 66at the edge carry|c| = 32 = (dim-2)/2, relative deficit-2.19e-43;beta_Khas Fourier support5^(-K) Z, the dominant frequencyn = +-1givesSigma_K(c) ~ 2 T_K(1) cos(2 pi c/5^(K+1)), so depthKsees only carries inside the quarter-period|c| < 5^(K+1)/4and dies atdim = 2 ceil(5^(K+1)/4) + 2- predicted deaths16, 66, 316, 1566atK = 1, 2, 3, 4, the first three exact - every fixed depth is finite,Theta(log dim)growth is necessary, and the minimalKequals the row certificate'st(dim)at every breakpoint tested (14|16,64|66,314|316). Witness: slice-sign-even-half. - Refuted The base-3 certificate depth is exactly
(9/160) dim^2- exact lower bounds put the residual at+2.00bydim = 120and+9.78atdim = 178;9/160 = 0.05625is the first two digits of the true constantln(R)/4 = 0.0568486146.... Witness: slice-sign-even-half.
Conjecture S: odd half
- Proved The slice census has the trigonometric product formula
P(e^(i psi)) = e^(i dim psi) (2 cos psi)^(dim-1)(dim + 2 cos psi), and the sheaf censusb(level)(coordinate sum== dim(3^level-1)/2 mod 3^level, equally the free-end carry count) isb(level) = 3^(-level) sum_(m<3^level) prod_(j<level) Phi(2 pi m 3^j/3^level)because the extraction phase is the accumulated palindromic phase; every unit tower ends at2 pi u/3with factor(-1)^(dim-1)(dim-1), so at odddimthe integrand is pointwise nonnegative,b(level) >= (fill/3)^levelandrho_dim >= fill/3, anddet(fill I - 3 M_even) == fill^n mod 3givesrho_dim > fill/3strictly at every odddim = 0, 2 mod 3and throughdim = 80in the class1 mod 3by exact determinants (Bareiss, three 61-bit primes and Berkowitz agreeing); the bijection is brute-forced atdim = 2..8,level <= 4and the phase cancellation matched to 50 digits atdim = 2..12. Witness: slice-recurrence-order. - Proved The pinning
|rho_dim - fill/3| <= 2(dim-1)/3holds unconditionally (evendimin[fill/3 - 2(dim-1)/3, fill/3 + (dim-1)/3], odddimmirrored) because the core's column sums take exactly the valuesfill/3 + 2 epsandfill/3 - eps; exactly3 rho_dim = fill + (-1)^(dim-1)(dim-1)(3 p_dim - 1)withp_dimthe Perron carry vector's mass on carries divisible by 3, well defined since the core is irreducible for alldim; soslice dimension - (solid dimension - 1) -> 0likedim^2 2^(-dim)regardless of sign, and Conjecture S entire is the parity-free inequalityp_dim > 1/3; checked by power iteration atdim = 2..20and entrywise column sums atdim = 2..80. Witness: slice-recurrence-order. - Verified The sign-law mechanism is universal: at every
base >= 3andu != 0 mod basethe design symbol hasg_base(2 pi u/base) = -1, the full digit sum vanishing at a nontrivialbase-th root of unity and the middle digit contributing 1, so the innermost tower factor is(-1)^(dim-1)(dim-1)at every odd base and the mechanism isbase-th-root evaluation, neverP(-1); the odd-diminequalityrho >= fill/basetravels with scopedim >= -min g_base(9/4atbase = 5,(34+14 sqrt 7)/27atbase = 7, growing like0.217 base), strict whendim != 1 mod pfor some primep | base; the sign law is exact by Sturm counts at base 5dim = 2..26, base 7dim = 2..18, bases 9, 11dim = 2..12and(base,dim) = (21,3), (31,5), (51,5), (101,3). Witness: slice-sign-even-half.
Conjecture S: the even-half transient
- Verified The two-step census contraction
9 b(2j+2) <= fill^2 b(2j)with3 b(2j+1) < fill b(2j)has zero violations through index 400 at every evendim <= 50, margin peaking near(dim-2)/(dim+2), and in exact integers at evendim = 2..30to index 40 the margin sits strictly below(dim-2)/(dim+2)and rises toward it,0.8704914against0.875atdim = 30; with irreducibility and nonvanishing it would close the even half. Witness: slice-recurrence-order. - Conjecture Every weighted-L2 certificate for the even half fails, the transfer norm being at least
sqrt(3) fillfor every positive weight, and two Abel pairings fail with it. - Refuted The even half's early
W_ksign alternation at base 3 persists, and a conjecture can be built on it - the alternation is a transient: over all evendimthe first break isdim = 6, k = 4, then(8,6),(10,8), the rulek = dim - 2dying atdim = 16where the first break isk = 16, then20, 24, 28, 34, 40atdim = 18..26and none throughk = 40fordim = 28..40(inside the window even12 <= dim <= 22the first break is(dim,k) = (12,10)); structurallyW_level ~ C 3^(level-1) rho^(level-1)(3 rho - fill)makes the eventualW-sign the even half itself; the pointwise route is dead too,V_2 < 0for evendim >= 6. Witness: slice-recurrence-order, slice-sign-even-half.
Coprimality at dimension one
- Conjecture No fixed modulus decides mixed-radix coprimality: the smallest moduli labelling coprimality exactly on the
n = 12sets are 27994 and 20736, at which all 4096 values occupy distinct residues, an encoding of the finite set rather than a transfer matrix; a prime not dividingMis invisible moduloM, so no fixed finite state space decides coprimality on an unbounded family, and a finite matrix tracks a fixed finite prime set exactly and nothing beyond, which is why the truncated Euler product through 13 misses by 0.008977 and -0.031676 on the two alternating schedules. - Refuted The universal pair-prefix transfer matrix is a route to Conjecture W - its Perron root is
k^2 = 4for everydimunder coupled digit vectors, or4^dimunder the scalar tensor reading, never 3; the 3 in W belongs to the shift multiplier-pair automata, wherelambda(1, 3^r) = 3exactly and every other coprime pair haslambda <= 2, with 2 attained at(1,4); the octave census that was fitted is the unweighted count, not W's weighted(3/2)^Ksum, its exponent on the stabilised octavesj = 0..3is 9.36, and the all-octave fitalpha = 2.956, CI[2.682, 3.257], leans on right-truncated high octaves with its constant driftingC = 1.042, 1.136, 1.244, 1.356atn = 13..16, residual Durbin-Watson 0.261. Witness: gasket-ray-machine. - Refuted Weil's theorem reaches the coprimality window - over
F_3[t]the restricted coprime count grows like4^n, a positive density among ordered pairs, sogamma = log_3(4) = 1.261860and the window analogue(gamma/2, 1/2]is empty,gamma/2 = 0.630930already above1/2; the quantity is positive-density counting with no zeta error term, so the framework is sound over a field where the Riemann hypothesis is a theorem while carrying no zeta content; the like-for-like test is theF_q[t]analogue at a prime powerqof the ray-multiplicity second moment, still undone. Witness: lab/py/function-field-density. - Proved At digit length
k = 2t+1the liftT = [t, 2t-1]has multiplierm_T = 3^(2t) - 3^t + 1 = Phi_6(3^t)dividing the binary3^(3t) + 1, soK_Tcarries at least2^tsubmasks divisible bym_Tagainst an equidistribution model below 1; no uniform bound of the shapeC 2^k / m_T^csurvivesc > log 2 / (2 log 3) = 0.3154649whileSum_T m_T^(-c)converges only forc > log 2 / log 3 = 0.6309297, so every exponent that would close the lift-union half is refuted for that shape. Witness: lab/py/ratio-set-saving, ratio.py check 2.5 s and ratio.py lifts --kmax 19 21 s. - Proved Antipodal lift family: for odd
p,0 <= s <= t,k = (p-1) t + s, the setT = Union_(i odd) [ti, ti + t - 1]hasm_T = (3^(pt) + 1)/(3^t + 1)and exactly2^(((p-1)/2)(t - s) + s)submasks ofK_Tdivisible bym_T, by antipodal pairs, blocks and balanced-ternary uniqueness. Witness: lab/py/ratio-set-saving, ratio.py agg asserts all 74 triples tok = 19, check atk <= 8. - Proved A binary
Kwith support inside[0, bk - 1],bblocks ofkdigits, is a multiple ofR_kexactly when its column counts satisfySum_r c_r 3^r = j R_k, and forb <= 3that forces the column vector constant, so the binary multiples ofR_kbelow3^(3k)are exactly2 * 3^k + 1lifts,3^kwith one position per column and multiplier1 + 2 a_(E_1) + 2 (3^k + 1) a_(E_2),3^kwith two, andR_(3k), which yields only submask directions; atb = 4the column vector branches, 24 non-constant vectors atk = 3. Witness: lab/py/ratio-set-saving, ratio.py tail and ratio.py check. - Verified
Occ_Tat the cyclotomicTis exactly the set{(3^t + 1) a_S}with its complements, of size2(2^(t-1) - 1)wheneverR_kis prime and2, 6, 12, 30, 62, 100, 254, 510att = 2..9, andmax_T |Occ_T| m_T / 2^kreads4.562to376843.283at oddk = 5..19at thatTevery time; an unconditional statement needs#{S in [1, t-1] : gcd(a_S, R_k) = 1} >= 2^t / poly(t), nowhere proved. Witness: lab/py/ratio-set-saving, ratio.py lifts --kmax 19 21 s. - Verified The lift union to
k = 19satisfiesU_k <= Sum_T |Occ_T| = agg_k L_k Phi_kwithL_k = Sum_T 1/m_T < 3/2Proved; overk = 11..19agg_ksits inside[1.01748, 1.11457]with no trend,L_kinside[1.41043, 1.41724]andU_k / Phi_krises monotonically across[1.19611, 1.36517], soU_k = O(2^k)is the boundedness ofagg_kalone. Witness: lab/py/ratio-set-saving, ratio.py lifts --kmax 19 --zmax 15 10 min 43 s. - Verified The absolute-value route on the
u != 0Fourier terms of the lift count is dead:Sum_T (1/m_T) Sum_(u != 0) |F_T(u)| / 2^kreads1.3839to7.9155atk = 5..11, step ratios all above1.26. Witness: lab/py/ratio-set-saving, ratio.py agg, the Abs column. - Verified The cut-free aggregate
agg'_k = Sum_T (N_T - 2)/(2^k L_k)sits inside[1.03919, 1.3403]andM_k / 2^kinside[2.47278, 2.89356]overk = 11..19, no upward trend. Witness: lab/py/ratio-set-saving, ratio.py agg, 20 s. - Verified Writing
b(z)for the number ofk-blocks the minimal witness liftm(z) R_kfills,U_k = #{b(z) <= 2}(Proved) and the depth-3 censusV_k = #{b(z) <= 3}gives(U_k, V_k, Z(R_k)) = (2342, 2350, 2360), (1618, 1624, 1634), (10280, 10310, 10388), (10278, 10310, 10440), (35566, 35630, 36190)atk = 11..15, so depth 3 captures8, 6, 30, 32, 64of the deep tail18, 16, 108, 162, 624, a share falling0.4444, 0.375, 0.2777, 0.1975, 0.1025, and the one-position lifts add nothing at anyk <= 13. Witness: lab/py/ratio-set-saving, ratio.py tail.
Coprimality density
- Proved The base-local coprimality factor is exact at every finite level:
#{x in S_level : e | x_i for all i} = fill_e * fill^(level-1)for every squarefreee | rad(base), holding on all 763 census lines; at composite base it does not factor over primes, the base-6 sample givingB(F) = 1/2for the code's digitsF(256 and 240 of 512) against the naive0.46875; the character contractionc(base,fill) = 1 - (2/fill)(1 - cos(pi/(2 base)))gives0.804738, 0.966506, 0.946410, 0.986603, 0.991481at(base,fill) = (2,3), (3,8), (3,5), (3,20), (6,8). Witness: coprime-density-above-dimension-one, lab/rs/design-census. - Verified Lemma B, the equidistribution estimate the coprimality programme needs, is a uniform equidistribution statement for digit-restricted sets across moduli growing with the level, the subject of Erdos, Mauduit and Sarkozy 1998, Konyagin 2001 and Maynard 2019, with Lemma A supplying the per-character input; it is proved for every design with
fill > baseby the dimension-above-one theorem and remains open only atfill <= base. Witness: coprime-density-above-dimension-one, REFS.md. - Proved Every digital design of fractal dimension above one has the classical coprimality density: for
dim >= 2, condition (E) andfill > base,A(level)/fill^level -> B(F) prod_{p not dividing base} (1 - p^(-dim)), by the box boundN*_level(m) <= (base+1)^dim fill^level m^(-log(fill)/log(base))driving a Chebyshev log-gcd sum and a fixed-zsieve; this settles the gasket16/(3 pi^2), the or-triangle8/pi^2, the carpet189/(32 pi^2), the Vicsek plus27/(4 pi^2)and the sponge(513/520)/zeta(3), and the finite levels approach with oscillating signed error: carpet gap-3.52e-07atlevel = 20, sponge-3.45e-05atlevel = 18(lab/rs/dimension-one-ladder), gasket0.539591against0.540380atlevel = 16(lab/rs/oeis-terms, A396934). Witness: coprime-density-above-dimension-one, lab/rs/dimension-one-ladder, lab/rs/oeis-terms, A396934. - Proved The 36 open dimension-one census lines are one problem: for any full-rank
base = 3,fill = 3design, collecting the corner-choice classes intoE_j = sum_{c_l = j} 3^lmapsS_levelbijectively through the gasket, and for everymcoprime to the design's difference determinant the two divisibility conditions become one shifted-target congruence on the gasket pair, so Lemma B stands or falls for the whole family at once, withT*vanishing atm >= 3^level; the same argument reduces every full-rankfill = dim + 1design at any base to the simplex at that base. Witness: lab/rs/design-census. - Verified Not every census collision is a shear: base-3 codes 11 and 161 have identical
A(level)at every level (2, 4, 12, 34, 108, 322, 992, 3006, 8924, ...throughlevel = 12, and equalT_efor everye <= 40atlevel <= 7) though 161 is alone in itsGL_2(Z)orbit over the exhaustive entry range[-8, 8]: both have zero cornerv_0 = 0hence gasket target 0, determinants with prime support{3}, and matching base-3 peel, so the finite Mobius sums agree termwise. Witness: lab/rs/design-census. - Proved
A(level)is not C-finite for any design meeting the dimension-above-one theorem withB(F) > 0anddimeven ordim = 3: a rational C-finite sequence withA(level)/fill^levelconvergent has a rational limit (roots abovefillhave zero coefficient, oscillatory roots on|z| = filldie by mean-square averaging, the remaining constant is fixed by every Galois automorphism), whiledeltais an irrational multiple of1/zeta(dim); all five eligible base-2 plane designs throughlevel = 12admit no rational constant-coefficient recurrence of order at most 6 and approach their irrational limits (the gasket-type designs read0.5378546at level 12 against0.5403796); the theorem says nothing at odddim >= 5, atB(F) = 0orfill <= base, or about polynomial-coefficient recurrences, which 2729 exact P-recursive fits with held-out terms exclude only empirically. Witness: coprime-density-above-dimension-one. - Proved The Menger sponge's pairwise coprimality density is
(13/20) prod_{p != 3} (1 - 3/p^2 + 2/p^3) = 0.251620868451255 = (351/400) C_3withC_3 = 0.286747428434479, so the sponge rule lowers the full-lattice benchmark by exactly12.25%: the three-modulus Mobius inversion over the three coordinate pairs does not collapse to one modulus, the base factor13/20is exact at every level (13 of the 20 legal digit vectors have at most one zero), each foreign prime contributes(1 - 1/p)^2 (1 + 2/p), and the tail closes on the pair-fibred box bound withkappa_I = 3andalpha = log_3(20/3) = 1.726833 > 1; the exact census0, 60, 1434, 32268, 721524, 15141288atlevel = 1..6gives0, 0.150000, 0.179250, 0.201675, 0.225476, 0.236583; the local factor is not1 - p^(-s), so no reciprocal zeta value is claimed and the coefficient in0.4138997384/zeta(2)carries no rationality claim. Witness: menger-pairwise-coprimality. - Proved The density theorem's spanning hypothesis retires to condition (E): a finite abelian quotient of order
mis killed bym, som Z^3sits inside the difference lattice, and a character moddvanishing onF - Fforcesm t = 0 mod dwithgcd(m, d) = 1, hencet = 0, the only step of Lemma A that used spanning; non-parity index-4 and index-8 designs at bases 4 and 6 measure0.105072, 0.035346, 0.936067against the widened predictions0.105639, 0.035261, 0.950751, converging; those three non-parity measurements have no generator in lab/, which computes parity codes only. Witness: coprime-density-above-dimension-one. - Proved Every parity code at every even
base >= 4hasdelta * zeta(3) = (8/7)(1 - W_0/|P|), nine values only and independent of the base, because multiples of an oddm | basesplit evenly by parity while multiples of2mare all even, so every odd base prime cancels its own Euler correction exactly; all 255 nonempty codes at every evenbase <= 40give exactly nine band values, every lattice index atbase = 4, 6, 8, 10lies in{1, 2, 4, 8}, enumerations reproduce0.712853, 0.951771, 0.709137, and indim = 2the parity carpet's band value8/9gives8/9 / zeta(2) = 0.5403796460924681 = 16/(3 pi^2), an even-base band constant rather than the gasket's own. Witness: lab/py/mrlybang-density-classes. - Proved Odd bases are self-similar across bases and the density trichotomy is exhaustive for odd
base >= 5:fill_e(base) = fill_P(base/e)for squarefreee | base, so the bracket is a Mobius convolution of the code's corner-count cubic; the 149 spanning codes converge to1/zeta(3)along the odds while frozen on their even band, the 43 codes inside their difference span take the corrected factor1 - 2^(-s2)at 2, and the 63 codes whose affine span avoids the origin have no density at all, with zero all-even points at every odd level and two subsequential limits in ratio1 - 2^(-s2); the even value equals the odd limit exactly on the 16 subgroup codes; checked for all codes at all oddbase <= 75, twelve measured cases to the printed digit including exact zeros at the even levels of{111}atbase = 5and the axes pair0.987338 / 0.739563against0.987319 / 0.740489. Witness: lab/py/mrlybang-density-classes. - Proved Slice coprimality is finite arithmetic of the height: on
x + y + z = sthe gcd dividess, soA_s = sum_{d | s} mu(d) N_s^(d)exactly with no tail and no Lemma B; prime slices are fully visible up to the three axis points (coordinates forced into{0, p}), the base prime peels the slice to the previous level one step off-centre, a code without the origin corner owes nothing at its base on any slice, and each foreign prime costs the slice1/p^2where it costs the solid1/p^3(aggregated locals0.040902against1/25,0.020446against1/49); the parity-walk factor at 2 is9121792/32002048on the integer, the net's immunity at 3 holds on all7^7points, and the tree dichotomy holds: even slices hold zero visible points, odd slices zero even gcds. Witness: lab/py/slice-coprimality. - Proved The central slice never converges and its bill is the repunit:
s* = (3(base-1)/2) R_level(base)owes 3 always, 2 exactly whenbase = 1 mod 4orlevelis even, and a foreign odd prime exactly whenord_p(base) | level, so the centre's visible density is a quasiperiodic function of the divisors oflevel; atbase = 3the two streams read0.892, 0.898against0.571, 0.611, 0.652, atlevel = 7the whole foreign bill is the Wieferich prime 1093 (2^1092 = 1 mod 1093^2), the central count isA299916(level)on the(9, -12)recurrence exact tolevel = 14, and the sixth peeled term is 83835 by a meet-in-the-middle count over all20^7level-7 points. Witness: lab/py/slice-coprimality, A299916. - Conjecture The visible density inside a design's
base-periodic pattern is exactlydelta:4/pi^2 = 0.405284734569for the base-2 gasket pattern,21/(4 pi^2) = 0.531936214122for the carpet,19/(26 zeta(3)) = 0.607932310732for the sponge, by coprime tuples splitting evenly over the nonzero residue classes ((2/3)(6/pi^2),(7/8)(6/pi^2), 19 of 26 classes over1/zeta(3)), with worst Mobius-count error6.05e-07atN = 10^6; designs differing only in the all-zero corner have identical visible density on 8579 pairs, since that class holds no visible points. - Conjecture Exhaustive endpoints at bases
2..6anddim = 2, 3agree with the predicteddeltawith no inferable rate: base-6 code 34376528265 reads0.454413against0.455945atlevel = 8, and the base-5dim = 3pair is the worst case at8.3e-03and1.5e-02. - Conjecture The central-slice peel ratio tends to
(sqrt(33) - 5)/8 = 0.0930703308, measured0.093070331, forced from the shared(9, -12)recurrence of the peeled streams, which itself stays Conjecture. Witness: lab/py/slice-coprimality.
Crop census
- Proved Crop partition and anti-crop complement:
classifyputs every cell in exactly one of Out, Cut, In, so the keep-cut and strict crops bracket the boundary, andShape::Antiflips In with Out fixing Cut, so the crop and the anti-crop under the complementary cut rule partition the filled set exactly; read off the definition and asserted both ways on all 118 printed configurations. Witness: mrlymath::shape, lab/rs/crop-counts. - Verified The inscribed sphere never enters the level-1 sponge:
censusreads cells[0, 26, 1], the one In cell the empty centre and all 20 filled cells Cut, so the keep-cut crop keeps everything and the strict crop nothing; the inscribed octahedron holds no filled sponge cell fully inside through level 2. Witness: mrlymath::shape, lab/rs/crop-counts. - Proved Exact dead zones of the inscribed crops: the carpet crop is empty for
r < 1/6under ball and diamond alike and the sponge diamond crop forr < 1/3, the central holes' inradii; the sponge ball's exact contact radius issqrt(2)/6 = 0.2357, witnessed by the filled level-3 cell[13/27, 14/27] x [8/27, 9/27] x [8/27, 9/27]whose nearest point to the centre is(1/2, 1/3, 1/3), so the 1/24 sweep reads empty throughr = 5/24and first cuts atr = 6/24. Witness: crop.md, lab/rs/crop-counts. - Verified Saturation and its one failure: the carpet ball crop holds all 4096 filled cells at level 4 from
r = 17/24, the first sweep radius past the circumradiussqrt(2)/2, the sponge ball all 8000 at level 3 fromr = 7/8, pastsqrt(3)/2, and the sponge diamond never saturates in the sweep, readingin = 5356, cut = 1332of 8000 atr = 1since the cube's corners sit atL1distance3/2. Witness: lab/rs/crop-counts. - Verified The strict inscribed diamond crop of the full side-
2mgrid holds exactly2m(m-1)cells. Witness: mrlymath::shape. - Proved A grid-aligned polytope crop is digit counting: walls on multiples of
3^-kkeep exactly the cells with coordinates in integer intervals at levelk, the count factors along digit positions as inmrlylab::press, and the crop adds nothing. Witness: crop.md. - Conjecture The curved-slice dimension: the
log_3cut-ratio exponents of the inscribed circle on the carpet read1.140, 0.909, 0.899, 0.951and of the sphere on the sponge2.166, 1.579, 1.705, hovering near the straight-slice yardsticks, the dimension minus one,0.8928and1.7268- yardsticks by analogy only, since Shmerkin 2019 and Wu 2019 cover intersections ofxp- andxq-invariant line sets withp, qmultiplicatively independent, not same-base carpet slices, straight or curved; five levels decide nothing. Witness: lab/rs/crop-counts, crop.md. - Proved Over any triadic window
r in [R, 3R)the mean of the crossing countC(r)isTheta(R^(log(fill)/log(base) - 1)), fromC(r) = A(r) - B(r), the step bound1 <= |x+1| - |x| <= sqrt(dim), the exact sandwichB(3R) - A(R) <= W(R) <= 2 (A(3R) - B(R))and the bracket lemmaB <= M <= A, with constants((m-1)/2) G_minand(m-1) G_max. Witness: lab/rs/circle-crop mean lines, carpetr = 2187..6560sum13758140inside[11019880, 22055720]. - Proved
C_full(r) = Theta(r^(dim-1)): the shell bound above, and belowC_full(r) >= (r/sqrt(dim-1))^(dim-1)from one crossing cell per orthant lattice point of the firstdim-1coordinates. Witness: lab/rs/circle-crop corner assert at every radius, band[2.000152, 2.037038]on the carpet atr = 27..6560. - Proved Pointwise
C(r) = Theta(r^(log(fill)/log(base) - 1))holds if and only ifPhi(r) = C(r) (3^dim/m)^level / C_full(r)is bounded above and below,levelthe least level withr < 3^level. Witness: lab/rs/circle-crop factor lines. - Proved The digit transform route's budget is
sum_(a != 0) |phi_level(a)| |S_r(a/3^level)| = O(r^(dim-1)), met term by term only if thel^1mass grows by at mostsqrt(3) = 1.7320508076per triadic step, and the transfer step at the lattice ish(u) = (m + 3^dim - 1)/m = 2atdim = 2. Witness: crop.md the transform route, and where it stops. - Proved At
dim = 2the crossing shell is exactly2r + 1cells at every integerr >= 1, by the telescopinglo_i = hi_(i+1)of the column intervals withhi_(r+1) := 0; the same count at real radius is2 floor(R) + 1, so the level-jboxes meeting the shell number at most2 floor(r/3^j) + 1and one holds at most2 * 3^jcrossing cells. Witness: lab/rs/circle-crop, asserted at every radius of every carpet level tor = 19682. - Proved The fraction
p_j(r)of crossing cells whose base-3 digit vector at positionjis one the design omits obeysp_j(r) <= 2 * 3^j (2 floor(r/3^(j+1)) + 1)/(2r + 1) < 2/3 + 3^j/ratdim = 2, capping every position with3^j <= r/30at0.7uniformly inr; it does not transfer toPhi, since the sharpest bound the marginals alone support is Frechet-Hoeffding,C >= C_full (1 - sum_j p_j), andsum_j p_jreaches1.349974atlevel = 8on the carpet and1.627693atlevel = 5on the sponge. Witness: lab/rs/circle-crop digits and digitrate lines, asserted in exact integers. - Verified The crossing shell's digits are equidistributed away from the top of the scale: carpet window means
0.111086, 0.111086, 0.111068, 0.111063, 0.111141, 0.109478, 0.109295, 0.166786atr = 2187..6560against1/9, the whole departure in the top three positions and locked tolevel - j, fine positions inside[0.108363, 0.111141]and the scaled drift(p_j - 1/9) 3^k/3^jinside[-0.111806, 0.063806]; sponge0.259211, 0.259237, 0.259663, 0.256864, 0.286061against7/27with fine positions inside[0.259103, 0.259237], wholly below the null on three readings. Witness: lab/rs/circle-crop digitrate and digittotal lines. - Verified Pairwise digit dependence in the crossing shell is bounded per pair and falls off with the gap: consecutive ratios
1.000165, 1.000219, 1.000521, 0.998543, 0.992613, 1.076698, 0.956158and gap-two1.000298, 1.000022, 1.000203, 1.000221, 1.003261, 1.005671on the carpet atlevel = 8, over every window[0.939130, 1.714286]and[0.988460, 1.126957], sponge[0.954573, 1.151415]and[0.997413, 1.019127]. Witness: lab/rs/circle-crop digitpair and digittotal lines. - Verified The pointwise factor widens with decelerating drift: carpet maxima rise
1.125000to1.518945by increments0.140625down to0.000808over eight windowsr = 1..6560, minima in[0.588115, 0.900000]; sponge maxima1.350000to1.673315over five windowsr = 1..242. Witness: lab/rs/circle-crop factor lines. - Verified The window multiplicity
kappa = W(R)/((m-1) M(R))brackets to[1.247746, 1.248322]on the carpet atr = 2187..6560and to[1.417534, 1.445977]on the sponge atr = 81..242, still climbing there; the[1, 2]bound is asymptotic, the exact slack being(C(3R) + C(R))/((m-1) M(R)). Witness: lab/rs/circle-crop mean lines,form_low = -4.744629atr = 1..2. - Verified The
l^1massLambda_levelreads1.000000, 3.585973, 9.637999, 23.736907, 56.547512, 132.884543atlevel = 1..6withlog_3step0.777708, forcing a term-by-term costr^1.277708against a budgetr^1and an error no better thanr^1.170497, worse than the exact floorLambda_level >= 2^level - 1gives; closing it needs|S_r| = O(r^0.222292), below the square-root floor. Witness: lab/rs/circle-crop transform mass lines. - Conjecture
Phi = ind * Psiexactly withind = prod_j (1 - p_j) (3^dim/m)^levelandPsithe dependence correction; carpet means settle at0.942104and1.005714while the global brackets[0.542697, 1.515753]and[0.793296, 1.374208]still widen with decelerating drift, soindandPsibounded is sufficient for the pointwiseC(r) = Theta(r^(d-1))and is the whole of what is left. Witness: lab/rs/circle-crop digits and digittotal lines over eight carpet and five sponge windows. - Refuted That two is the minimum of the transfer step
h:hat the level-5 triadic point(155/243, 155/243)is1.951261. Witness: lab/rs/circle-crop transform step line.
Density theorem boundary
- Verified The base-2
dim = 4design census is complete to level 4: 65536 designs close into 402 orbits under the 384 signed coordinate permutations, 400 withfill >= 2, 336 both spanningZ^4and carryingfill > 2so the dimension-above-one density theorem applies to them on its stated sufficient condition, and the 400 eligible canonical representatives realize 189 distinct coprimality sequences(A(1), A(2), A(3), A(4))with 87 collisions covering 298 classes, the largest being 10 classes on(4, 16, 88, 436)and 10 on(5, 25, 165, 985), by exhaustive enumeration with exact integer minors for spanning and an exact four-coordinate gcd at every point; four terms cannot separate an infinite collision from a short coincidence, and the distribution is over minimum-bitmask representatives rather than unoriented orbits, since coordinate complement moves the arithmetic origin and preserves neitherB(F)nordeltanorA(level). Witness: coprime-density-above-dimension-one. - Verified Exact sponge visible census without enumeration, three levels past the feasible: the hybrid
A(level) = Sum_(d <= G) mu(d) T*_d(level) - Sum_(gcd > G) S(gcd)with transfer matrixT_dand the big-gcd tail enumerated as multiples in abase^level/gbox costs aboutbase^(level(dim+1)/2)against enumeration'sfill^leveland givesA(7) = 1038074187,A(8) = 20860210527,A(9) = 418429711224(22.6 seconds against half a trillion points, the whole ladder in 84 seconds), anchored by the four census terms, direct enumeration atlevel = 5, 6, and cutoff independence (G = 100andG = 150split the work differently and agree onA(9)to the integer). Witness: lab/py/sponge-visible-census. - Conjecture Spanning is the wrong hypothesis for the density theorem and the sharp condition (E) is that
F - Fhas full rank andrad(m(F)) | rad(base): six census degenerate lines satisfying it obey the formula unchanged, a primep | m(F)not dividingbasereplaces the Euler factor atpby a coset-corrected one, andA(level)/fill^levelcan fail to converge at all (base 7,F = {v : v_1+v_2 = 1 mod 3},fill = 16, index 3, period-3 subsequential limits matched to3e-04), numerics at1e-04on five corrected designs plus seven null cases, provable-looking by the base-peel argument; the same failure shows at base 3,F = {0,2}^2,fill = 4 > 3withA(level) = 0at every level against a positive predicted density. Witness: coprime-density-above-dimension-one; A396934. - Conjecture The b-visible local factor of a design at a base prime is exact at every finite level: on the gasket
#{x in S_n : 2 | x_1 and 2^b | x_2} = (2^(b-1)/3^b) 3^nforn >= b, by the last-digit argument, exact to the integer atb = 1, 2, 3on every level3..12, thirty matches with ratios exactly1/3,2/9and4/27; the Euler-product assembly it feeds is unproved forb >= 2. - Conjecture Directional coprime profiles separate designs that the scalar density cannot: two base-3,
dim = 2,fill = 5designs with identicalB(F) = 4/5and identical predicted density0.5471344differ by up to0.0327in an eight-bin angular coprime profile at level 7 while their scalar pairwise densities differ by0.0001001809, by exact enumeration at levels 2 to 7 with displacement multiplicities validated againstN(N-1); the bin gap decays by a factor near0.6a level (0.375, 0.1461, 0.0946, 0.0492, 0.0327at levels 3 to 7), so a nonzero limit is open. - Conjecture The digit-restricted coprime density over
F_3[t]withS = {0,1}is9/16: measured0.564176, 0.563471, 0.562833atlevel = 10, 12, 14by exact enumeration against(2/3)(3/4)/(8/9) = 0.5625, the correction sitting entirely at the exceptional primetwherepi(t) = 1/2exactly against the unrestricted1/3, the other two linear primes measuring0.333984and0.333008; the finite Euler product is neither exact nor monotone, crossing9/16between degrees 3 and 4 and landing at0.560193through degree 5 while the exact no-shared-prime-below-degree-6 probability is592189/1048576 = 0.564755, a dependence gap of-0.004563, so the density is a theorem only under three hypotheses: existence ofpi_S(p), asymptotic independence over finite prime sets, and a vanishing high-degree tail. Witness: lab/py/function-field-density. - Conjecture Mixed-radix coprime density depends on the schedule through a mod-3 effect rather than parity: at
level = 12over 8386560 ordered pairs per schedule (4096 points each), alternating base-2/base-3 gives0.511135with digits{0,1}/{0,1}and0.672615with{0,1}/{0,2}, against pure base-20.607874(near1/zeta(2) = 0.607927) and pure base-30.514692; both alternating schedules are exactly half even, and the0.161480gap comes from the divisible-by-3 fraction falling from1/2to1/4, local factor3/4to15/16, log advantage0.223144, with prime 5 opposing at-0.014253and primes 2, 7, 11, 13 identical between them; the residue mechanism for{0,1}/{0,1}is exact (every place value from position 2 on is a multiple of 6, soa mod 6 = d_0 + 2 d_1and residues 0..5 are hit1024, 1024, 1024, 1024, 0, 0), but no limit is established and the aperiodic staircase is untouched. - Conjecture The sponge census gaps
delta 20^level - A(level)measure0.347, 0.349, 0.344in units of12^level, the subdominant parity-walk scale, soA(level) = delta 20^level - c 12^level + smaller. Witness: lab/py/sponge-visible-census. - Verified The sponge visible census to
level = 18by two engines: admissibility is pairwise disjointness of the digit-1 masks, soA(level) = W(level) - W(level-1)withW(level) = Sum_(m < 3^level, gcd(m,3) = 1) mu(m) (N_level(m) - 1)andN_level(m)a disjoint-triple count over at most2^levelmasks of the multiples ofm; the engine splits moduli by their multiples count into a closed-form tail, bitset rows,u16zeta rows and a rank-truncated ranked cube, about3^level (level 2^level)^(2/3)work,122.3 satlevel = 18on eight threads with level ratio4.32,3.8xits previous form, which it reproduces term for term fromA(10) = 8382927031902toA(18) = 215134797774716879278017, both matching the hybrid census throughA(9)and enumeration throughA(6); nine counters agree on every modulus to level 8, pinned counters with auto to level 8-11, 38 probed moduli at level 14 and two pinned probes at level 19 cover theu64cube gate and theu32rows branch; the new engine alone givesA(19) = 4302768326366633733102921in515 s, unwitnessed. Witness: lab/rs/coprime-terms. - Proved The tail of the sponge Mobius sum is closed and admits no hyperbola grouping: for
3^level/2 < m < 3^level,3not dividingm,N_level(m) - 1 = 3 + 4 [m has no base-3 digit 1], so the top band ofW(level)is three times the Mertens sum over the band's moduli coprime to 3 plus four times a Mertens sum over the base-3 Cantor set; theY = 3band is6 + 7 [mask(m) = 0] + 7 [mask(2m) = 0] + 6 [mask(m), mask(2m) disjoint], every band a Mobius sum over a digit-automatic condition onm, 2m, ..., (Y-1) m;N_level(m)depends on the digits ofm, not onfloor(3^level/m)(level = 2:m = 5, 8share the floor withN - 1 = 3, 7; atlevel = 6every floor band holding two admissible moduli is non-constant), verified exhaustively atlevel = 6, 7against a brute triple loop. Witness: lab/rs/coprime-terms.
Dependent bases
- Proved The collapse theorem: for one root
r >= 2, basesbase_i = r^(e_i)withi = 1..m, any dimensiondim >= 1and any digit setsA_iinside{0,...,base_i - 1}^dimeach containing0, putM = lcm(e_1,...,e_m)andB = r^M; thencap_i F(base_i, A_i) = F(B, A)exactly, whereA = (cap_i F(base_i, A_i)) cap [0, B)^dimis the joint set's own bottom block, the count law is exact atcard {n in [0, B^level)^dim : n in F(B, A)} = (card A)^levelfor everylevel >= 0, and the attractor of{x -> (x + a)/B : a in A}has Hausdorff and box dimensionlog card A / (M log r). Proof in four steps:e_idividingMmakes everye_i-group of base-rpositions sit inside oneM-group, so no group straddles andlcmis forced rather than chosen; each digit at basebase_iis then a function of one base-Bdigit, so the constraint is per base-Bdigit with nothing carried between them; the top base-Bdigit is read with its fullM / e_ibase-base_idigits while the base-base_iexpansion ofnstops at its top nonzero digit, so the two readings agree exactly when0 in A_i; and membership one digit at a time gives the count with no error term while the maps send the unit cube to boxes with disjoint interiors, so the open set condition gives the dimension. No step usesdim = 1and no step asksA_ito be a product across thedimaxes, sodim >= 2is covered with no extra hypothesis, compound designs included. Across two dependence classes the theorem says nothing. Witness: lab/py/base-collapse verbsblocks,dim,check;bases.md:92,bases.md:101-107. - Proved Multiplicative dependence is an equivalence relation on bases
>= 2and each class is the set of integer powers of its least member: reading a base by its vector of prime exponents turnsp^a = q^baseinto parallel vectors, so a class is the set of integer points on one ray through the origin, its least memberris the primitive vector on that ray and every member isr^efor one integere >= 1; transitivity is one line,p^a = q^baseandq^c = s^dgivep^(ac) = s^(bd). The half of the rule that follows is collapse first: partition the bases into dependence classes and replace each class by the single design the collapse theorem gives it, with its own baser^M, its own digit set and its exact dimension; a transversality budget inside a class is not allowed, by the Refuted row below. Witness: lab/py/base-collapse verbblocks;bases.md:88,bases.md:126. - Verified Four dependent cells rebuilt from their digit sets alone, root, exponents,
M, block set and exact dimension: base4on{0,1}with base8on{0,1,2,3}givesr = 2,M = 6,A = {0,1,16,17}and dimension exactly1/3; base4on{0,1}with base16on{0,1,4,5}givesM = 4,A = {0,1,4,5}and exactly1/2; base9on{0,1,2}with base27on{0,...,8}givesr = 3,M = 6, nine blocks and exactly1/3; bases4, 8, 16on{0,1},{0,1,2,3},{0,...,7}giveM = 12, sixteen blocks and exactly1/3. The block set is built twice per cell and asserted equal, once by sieving allr^Mbase-rwords against the per-group constraint and once by testing every integer belowr^Mfor membership in each original design. Witness: lab/py/base-collapse verbsblocks,dim;bases.md:115-120. - Verified The exact count law survives brute force to
10^13on all four cells, three checks each: every element ofF(B, A)below10^13passes a digit test in each original base; the joint count from enumerating the lowest-dimension original design (2^22 - 1elements at three cells,3^14 - 1at the base-9 cell) and filtering it by the others equals the count ofF(B, A)below10^13, which with the first check gives set equality, the four counts reading32767,4194303,19682,32767; and the joint count belowB^levelis exactly(card A)^levelat everylevelwithB^level <= 10^13, reachinglevel = 7and16384,level = 10and1048576,level = 4and6561,level = 3and4096. Witness: lab/py/base-collapse verbcheck;bases.md:124. - Verified A dependence class can give a block count that is not a power of its root, so the exact dimension can be irrational: base
4on{0,1,2}with base16on the full digit set givesr = 2, exponents2, 4,M = 4andcard A = 9, dimensionlog_2(9) / 4 = log_2(3) / 2. The dimension islog_r(card A) / Malways, and for the least baserof the class it is rational exactly whencard Ais a power ofr, since a primitiveris no perfect power. Witness: lab/py/base-collapse verbdimcellI;bases.md:107. - Verified The hypothesis
0 in A_iis sharp and not decoration: atr = 2withbase_1 = 2onA_1 = {1}andbase_2 = 4on the full digit set,M = 2and the bottom block isA = {0, 1, 3}, yetF(4, A)holds4,5,12and13, whose base-2 words carry a digit outsideA_1, so the collapse strictly over-counts the joint set. Witness: lab/py/base-collapse verbblocks;bases.md:105. - Conjecture Budgeting across the collapsed classes alone, with
mthe number of classes and not the number of bases, is the right second step: nothing here shows a collapsed class behaves in a cross-class budget like an ordinary design of the same dimension, so the step is assumed. Witness:bases.md:126; no proof and no lab verb. - Refuted The naive budget
sum_i dim A_i - (m - 1)is not an upper bound on a multiplicatively dependent cell and is low on every one tested: base4on{0,1}with base8on{0,1,2,3}has exact dimension1/3against a budget of1/2 + 2/3 - 1 = 1/6; base4on{0,1}with base16on{0,1,4,5}has exact dimension1/2against a budget of1/2 + 1/2 - 1 = 0; base9on{0,1,2}with base27on{0,...,8}reads1/3against1/6; and the three-base cell4, 8, 16reads1/3againstmax(0, 1/2 + 2/3 + 3/4 - 2) = 0, the budget being read at zero because no dimension is negative and the raw sum there is-1/12. The second cell is the clean failure:F(16, {0,1,4,5}) = F(4, {0,1})as sets, since a base-16 digit lies in{0,1,4,5}exactly when both of its base-4 digits lie in{0,1}, so the budget prices the intersection of a set with itself at dimension0while the truth is that set, of dimension1/2. A budget built on transversality cannot be applied inside a dependence class. Witness: lab/py/base-collapse verbsdim,check;bases.md:113,bases.md:115-120.
Design census
- Proved Designs up to cube symmetry are the NP-equivalence classes of Boolean functions: an equivariant bijection carries
B_dim(order2^dim * dim!) onto the NP group, so the class counts are3, 6, 22, 402, 1228158, 400507806843728atdim = 1..6, reproduced by orbit walk on designs, orbit walk on truth tables and Burnside, checked against the entry todim = 7; the NPN sibling gives2, 4, 14, 222atdim = 1..4. Witness: mrlymath::bang::counting::sequence, A000616, A000370. - Verified The design census at
dim = 2and any base is the toroidal binary array count: Burnside over one dihedral group per residue axis gives2, 6, 26, 805, 172112, 239123150, 1436120190288, 36028817512382026atbase = 1..8, with brute-force orbit closure agreeing atbase = 3, 4. Witness: mrlymath::bang::baseq::distinct_designs, A255016. - Proved The isotropic-class count is
A005418(dim+2)minus one at evendim: a level set's orbit is{F_S xor t}and the image depends ontonly through|t|, so the count is subsets of{0..dim}up to reversal with the even-dimmerge,3, 5, 10, 19, 36, 71, 136, 271, 528, 1055, 2080, 4159, 8256, 16511, 32896, 65791atdim = 1..16; nameable classes grow like2^dim, half the2^(dim+1)subsets. Witness: A005418. - Verified Census multiplicity in the base-2 census is a bounded perfect-power representation count: over the 16 two-dimensional and 256 three-dimensional designs at side 3 and levels
1..5, the 1360 design-level pairs give 119 distinct fill counts,M(N) = sum_{level=1}^5 sum_{fill=0}^27 c_fill [fill^level = N]withsum_fill c_fill x^fill = prod_{w in {1,2,4}} (1 + x^w) + prod_{w in {1,2,4,8}} (1 + x^w), maximumM(4096) = 29from4096 = 8^4 = 16^3(14 designs of base fill 8 plus 15 of base fill 16), support exactly{fill^level : 0 <= fill <= 27, 1 <= level <= 5}, so only 119 integers occur up to27^5 = 14348907, coverage8.29e-6, in 91 maximal missing runs, the longest11881377..14348906;Mis not multiplicative (M(2) = M(3) = 5,M(6) = 12), opens10, 10, 5, 5, 13, 8, 12, 12, 19, 19, 15, 15, 16, 16, 16, 16, and no classical arithmetic function is behind it: the raw Pearson signals againstsigmaandphi(-0.332,-0.315) are shared size dependence (MagainstNis-0.338), and partial rank correlations controlling forlog Nfall in-0.035..0.096ford, sigma, phi, omega, Omega. Witness: mrlymath::formulas::counting::fill. - Verified The census covers only a short prefix of the integers: through Kronecker level 6 the 256 three-dimensional designs produce 37 positive fill values in
1..262144, coverage0.01411%, contiguous only on1..9, becausefill(code, level) = f^levelwithfthe tile popcount in0..8; the nine named observables reach a union of 368 integers to1633932with 10 the first gap, the graph observablescore_edges,tips,junctionsextend it to 437 integers and the prefix to1..24;edgesis the broadest single observable (73 distinct positive values, 60 exclusive), thenfaces70,vertices67,surface66; design 23 reads fill 20, voids 7, surface 72, vertices 64, edges 144, faces 96, Euler-4at level 1 and fill 400, vertices 896, edges 2304, faces 1728, Euler-80at level 2, and every record obeyssurface = 6 fill - 2 core_edges,faces = 6 fill - core_edges,cycle_rank = core_edges - fill + components,euler = vertices - edges + faces - fill;voidsmeans every empty lattice site, 3Dedgesmeans cubical-complex unit edges andcore_edgesthe branch count of the face-adjacency graph; the 2D census gives 176 distinct positive integers to1064340, contiguous on1..10. Witness: mrlymath::formulas::counting::fill, mrlymath::three::census::census. - Verified Unbounded census observables cannot be automatic sequences and are at best regular in some base: an integer-valued automatic sequence has finite range, a finite-range regular sequence is automatic, so
d(n)andsigma(n)are automatic in no base and can enter only through unbounded regular representations, weighted substitutions, Dirichlet convolutions or a purpose-built geometric model; Cobham's theorem is the one general rigidity constraint, and substitution incidence matrices generate additive recurrences whiledandsigmaare multiplicative over primes, so self-similar census countsc_m = u^T A^m vare generically sparse in the integers. Witness: REFS.md.
Design counts at every base
- Refuted The per-base,
dim = 3count2, 22, 111618, 6005363762644688, 7089215977519836239803174210135872has no OEIS entry - it is A398348, toroidaln x n x nbinary arrays up to layer rotation, layer reflection and axis permutation, data verbatim with a b-file ton = 14and A255016 as the two-dimensional case; the null search ran against a dump older than the entry. Witness: A398348, lab/rs/oeis-terms.
Diagonal cuts of the parity solid
- Proved Every diagonal slice of
bang dim 3, code 126holds exactly3^levelpoints at every admissible height, by uniqueness of the binary expansion of the height offset; checked atlevel = 1..8by two enumerations sharing no code and tolevel = 14by a height recursion; the constancy separates it from the digit-scheduled slices of Nakajima and Watanabe, whose non-autonomous IFS usesA_c^(j) = {0}or{1,2,3}by the height digit, so their digit changes the number of maps and this one only the orientation. Witness: mrlymath::three::diagonal. - Verified The two central cuts of
bang dim 3, code 126decompose into six congruent Sierpinski gaskets of3^(level-1)points each tiling a hexagon with an order-12 symmetry group, checked atlevel = 2..8by rebuilding the pieces from the previous level (union, pairwise disjointness, sizes); the combined totals are6 * 3^(level-1) = 2 * 3^level:18, 54, 162, 486, 1458, 4374, 13122; the ambient object is the octahedron flake of dimensionlog(6)/log(2). Witness: mrlymath::three::diagonal.
Diagonal designs
- Refuted The diagonal designs are codes 98, 140 and 266 with
Z_F(level) = 3^level - 2- the identity fails atlevel = 0(sides0and-1) and holds for everylevel >= 1, and the list is short by one: of theC(9,3) = 84three-corner subsets of the3 x 3digit square, four are diagonal throughlevel = 6,{(0,1),(1,0),(2,2)}(266),{(0,1),(1,2),(2,0)}(98),{(0,2),(1,0),(2,1)}(140) and{(0,2),(1,1),(2,0)}, code 84 (the value 148 once quoted for it names{(0,2),(1,1),(2,1)}, not a permutation design); the three named codes hold tolevel = 11with every pair checked for collinearity atlevel = 7. Witness: gasket-ray-machine.
Diagonal slice ladder
- Verified The even half at base 7 carries exact Collatz-Wielandt certificates
rho_dim < fill/7at every evendim <= 26and atdim = 172, 174, anchored byP(1) = 6^(dim-1)(dim+6)and a brute-force digit enumeration ofP, with depthK_min = 0, 1, 2stepping atdim = 4anddim = 26(and 3 atdim = 174),V(level) > 0at every evendim = 2..40,level <= 25with no dip, andc == 0 mod 7immune at depth 0, soSigma_Kdepends onc mod 7^(K+1). Witness: slice-sign-even-half. - Verified An off-centre diagonal slice cannot break the alternation: a fixed target offset
kchanges only the initial vector, the transfer matrix commutes with carry reflection ande_0is even, soe_k^T M^level e_0 = (1/2)(e_k + e_(-k))^T M^level e_0and the odd component is annihilated, the off-centre slice seeing only the central even block; the boundary condition matches direct polynomial multiplication in 24 cases atdim = 2..7,level = 1..4, exact counts tolevel = 80obey minimal rational recurrences on every term, and the dominant root equals the central one at everydim = 2..12and offset|k| <= 2, the only movement being transient zero modes atdim = 4,|k| = 2anddim = 2,|k| = 1, 2that raise the order without touching the growth rate; offsets scaling with3^levelare untested. Witness: slice-recurrence-order. - Verified The anti-diagonal slice profile factors across the Kronecker product,
P_(A (x) B)(t) = P_A(t^(side_B)) P_B(t), sincer + c = side_B (r_A + c_A) + (r_B + c_B), giving the stationary productprod_(j<level) P(t^(base^j))and its mixed-radix form, so one identity covers fractal slices, mixed-product slices and the dimensional ladder; exact on all words of length 2 and 3 at base 2,dim = 2, zero mismatches. Witness: lab/py/slice-ladder-controls. - Verified The level-1 central diagonal slice of the base-3 Menger analog is the vertex set of the cube's central cross-section: the hypersimplex vertex counts
2, 6, 6, 30, 20, 140, 70atdim = 2..8matchC(dim, dim/2)for evendimandC(dim, (dim-1)/2)(dim+1)/2for odd, so the ladder starts on a polytope rather than on an analogy. Witness: lab/py/slice-ladder-controls. - Conjecture The 2-adic Smith form of
M_evenat base 3 and odddimhas elementary-divisor valuations0^r 1^p 2^e Awith exactly one divisor>= 2^3andsum a_i = v_2(det), sov_2 = nullity + #{a_i >= 2} + max(a_max - 2, 0)reduces the uniform boundv_2 <= nto the tent rank lawnullity_2(M_even) = min_(t in T) (|dim - t|/2 + 1),T = {2J(k)+1, 2J(k)+3 : k >= 2},J(k) = (2^k - (-1)^k)/3(exact 255/255 at odddim = 3..511, peaksJ(k-1)atdim = 2^k + 1, hencenullity <= ceil(n/3), troughs at the odddimwith3 dimnearest a power of 2, so the rank deficiency measures the 2-versus-3 carry mixing) plus a small-excess bound whose constants are domain-limited:max a_i <= 9and#{a_i >= 2} <= 5hold at odddim = 5..121, butmax a_i <= 9first fails atdim = 127(12 by 511),#{a_i >= 3} = 1atdim = 175(reaches 5) and#{a_i >= 2} <= 5atdim = 183(reaches 21); the mod-2 form isP == (1+t)^(2D-3)(1+t^3)with1 + Dt + t^2 == 1 + t + t^2irreducible,dim = 7is a tent trough with the whole valuation in the lone big divisor (a = {0,0,0,7},max a_i = 7 > n = 4, a size effect),dim = 5(a = {0,0,4}) is the only otherv_2 > nat odddim = 5..121, equality holds atdim = 9, 15, and the fold puts the 2-content in the even block because the palindromy rowc' = 0is2 P[dim+c]entrywise and atdim = 7the odd block is 2-adically unimodular. Witness: lab/py/smith-cascade; slice-sign-even-half. - Conjecture The base-7 certificate extends with logarithmic depth and no transient to every even
dim = 2..40, and the depth-death law is asymptotic rather than exact: both measured breakpoints land one even step early ofdim = 2 ceil(7^(K+1)/4) + 2because the depth-Kpositivity frontierf_K(dim)is still climbing when the window edge reaches it, so the corrected law readsK_min = min{K : (dim-2)/2 <= f_K(dim)}. - Conjecture The central diagonal slice census of the base-3
dim-dimensional Menger analog obeys a linear recurrence of order exactlyceil(dim/2): the digit polynomial factors asP(t) = (1 + t^2)^(dim-1)(1 + dim t + t^2), the carry mapc' = (c + dim - s)/3contracts to{|c| <= floor((dim-1)/2)}, the symmetryv -> (2,...,2) - vgivesP[s] = P[2 dim - s], so the Krylov subspace frome_0sits in the reflection's+1eigenspace of dimensionfloor((dim-1)/2) + 1 = ceil(dim/2)and the order bound holds at everydim; exactness is checked atdim = 2..14by distinct eigenvalues ofM_evenwith minimum gap above 6.9 and atdim = 2..24by nonzero Hankel determinants, and is open for generaldim(a square-free characteristic polynomial); controls:dim = 2gives2^levelat order 1,dim = 3gives6, 42, 306, 2250, 16578, 122202and A299916's9a(n-1) - 12a(n-2)at order 2 by a route that never mentions a hexagon,dim = 4gives6, 132, 1848, 29040, 441408, 6772128at order 2 with dominant root(11 + sqrt(385))/2,dim = 5gives30, 1000, 35700, 1321600, 49786200,dim = 6gives20, 4030, 242300, 24642700, and rational Hankel elimination on nine terms reads orders1, 2, 2, 3, 3atdim = 2..6. Witness: slice-recurrence-order; A299916. - Conjecture Conjecture S, the sign law
sgn(slice dimension - (solid dimension - 1)) = (-1)^(dim+1)at everydim: the even half at bases 3 and 5 and the odd classesdim != 1 mod 3are settled on the shelf, the odd classdim == 1 mod 3beyonddim = 80is open, and the route through a named lemma, an explicit positive vectorx_dimwithsgn((M_even x)_i - (fill/3) x_i) = (-1)^(dim+1)at every index, has only the Perron vector, which supplies it numerically at everydim <= 50with worst componentwise discrepancy9.15e-46at 90 digits, peaked at index 0 and non-increasing, with no closed form; its two silent hypotheses, a real spectrum (exact atdim <= 20, numerical atdim = 2..60) and no non-Perron eigenvalue crossingfill/3(checked atdim = 2..60against a 180-digit reference), are themselves unproved. Witness: slice-recurrence-order; slice-sign-even-half. - Conjecture The second eigenvalue of the even carry block tracks the digit polynomial at
-1:lambda_2 -> (-1)^(dim+1) 2^(dim-1)(dim-2)/3 = (-1)^dim P(-1)/3with exponential convergence but never exactly (the characteristic polynomial is nonzero at that value in exact arithmetic at everydim = 2..40, solambda_2 = -9007199254740992 = -2^53to 22 digits atdim = 50, which is2^49 * 48 / 3, is display rounding), hencerho/|lambda_2| -> (dim+2)/(dim-2) -> 1, measured13/12to2.58e-22atdim = 50and1.04081632653atdim = 100, with|lambda_2|/rho = (dim-2)/(dim+2)to nine digits bydim = 36, so the spectral gap closes and no argument may assume a fixed one; the asymptote must not be quoted at smalldim, wheredim = 4gives a truelambda_2 = -4.310708against-16/3, a 19% gap consistent with anO(2^(-dim))approach; measured at 420 to 650 digits. Witness: slice-recurrence-order. - Conjecture The base-5 middle-digit analog (keep a cell when at most one coordinate is the middle digit 2) has
P_5(t) = A(t)^(dim-1)(A(t) + dim t^2)withA(t) = 1 + t + t^3 + t^4,fill = 4^(dim-1)(dim+4)and carry rulec' = (c + 2 dim - s)/5, andsgn(slice dimension - (solid dimension - 1)) = (-1)^(dim+1)holds atdim = 2..15down to a smallest excess of1.055e-9atdim = 15(exact-integer sign sweep with 80-digit root refinement, agreeing with substitution-product convolution in all 16 cases atdim = 2..5,level = 1..4, thedim = 3fill112 of 125matching the middle-digit count), yetA(-1) = 0makesP_5(-1) = 0for everydim, so the alternating mass that carries the base-3 explanation is absent while the alternation survives, and no mechanism yet survives that. Witness: slice-sign-even-half. - Conjecture The alternation is universal across base-3 designs and its phase is not: over four families at
dim = 2..7, Menger with at most one middle digit andP(-1) < 0fordim > 2gives-+-+-+-, at most two middle digits withP(-1) > 0gives--+-+-+, Cantor with no middle digit andP(-1) = P(1)gives+-+-+-+, exactly one middle digit withP(-1) < 0gives+-+-+fromdim = 3, so the phase tracks the sign ofP(-1); the range stops atdim = 7and the four sign patterns rest on a prose table alone. - Conjecture The excess
rho_dim - fill/3decays at the rater_inf = 1/prod_(k>=2) cos(2pi/3^k) = 1.3461220067642173per dimension on the eigenvalue scale,2 r_inf = 2.6922450on the dimension scale, with a linear prefactor|delta_dim| ~ A (dim-1) r_inf^(-dim),A -> 2/(3 prod cos) = 0.89741, from the 3-adic angle-tower product formula, matched within1e-8by exact rational bisection atdim = 61; a third-order Richardson fit in1/dimoverdim >= 60at 320 digits gave the one-step ratio0.742874554813847413,r_inf = 1.34612251727283689(seven true digits, the rest fit residue), even and odd extrapolations4.5643e-8apart andA ~ 0.897520192686, and the shape check(6A/ln 3)(dim/(dim+2))(2 r_inf)^(-dim) = 1.47e-21atdim = 50against the measured1.42672e-21tests the form and not the constant. Witness: slice-recurrence-order. - Conjecture Conjecture S reduces to one separation lemma along an explicit chain: with
M_eventhe reflection-even block of the carry automatonM[c,c'] = P[c + dim - 3c'],P(t) = (1+t^2)^(dim-1)(1 + dim t + t^2)andfill = P(1), if every non-Perron eigenvalue ofM_evenhas modulus belowfill/3thensgn det(fill/3 I - M_even) = sgn(fill/3 - rho), and that determinant sign is(-1)^dim, exact in integer arithmetic atdim = 2..20and todim = 40, which is Conjecture S; the separation hypothesis is checked atdim = 2..60and not proved, the row-sum lemma feeding it holds for the full carry matrix on statesc = 0..dimand is false in the recurrent even basis (dim = 3row sums(12,4)against the formula's(8,6)), and the product formula settles the odd half without separation, so this chain is a route to the even half only. Witness: slice-recurrence-order; slice-sign-even-half. - Conjecture The balanced-mask homotopy reduces Conjecture S to a one-variable determinant inequality and owes two lemmas: with
a_dim = (-1)^(dim-1)(dim-1)andQ_dim = P_dim - a_dim t^dim, the root-of-unity identity forces1 + t + t^2 | Q_dim, andfill/3 I - M_dim = L_dim + a_dim K_dimexactly withK_dim = I/3 - E_dim,E_dimthe dilation1_(j=3i); thenf_dim(z) = det(L_dim + z K_dim) = z h_dim(z)and S becomesh_dim(a_dim) < 0, exact atdim = 2..30;det L_dim = 0is exact todim = 30but does not follow from residue balance, becauseN_dimlacks constant column sums in the unnormalised even basis after truncation and folding, and coefficient negativity ofh_dim, which settles every odddimsincea_dim > 0there, is useless at evendimwherea_dim = -(dim-1)is negative, so a uniform root bound is still missing.
Diagonal slice stack
- Verified The level-1 slice is exactly a lattice-plane object:
carpet_cut(n, 1)at odd scalenequals the setx + y + z = 6n - 2,zeven, in[0, 4n)^3, filled iff at most one offloor(x/4), floor(y/4), floor(z/4)is odd, with|slice| = 6n^2; two cell-for-cell reconstructions (n = 1..63andn = 1..13) show zero mismatches. Witness: walsh-spectrometer. - Proved The 1:6:1 three-plane law: every micro point of the slice lies in a macro cell with
i + j + lin{K, K-1, K-2}atK = (3n - 1)/2with multiplicities 1, 6, 1, sofill(n) = 6 F(K-1) + 2 F(K), a two-line derivation of the cut fill closed forms, exact for all oddn <= 21and holding atn = 1where the outer planes are empty. Witness: walsh-spectrometer. - Proved The slice's two mod-4 families are the Dirichlet character
chi_4: per-gram ink is exactly3/8 + 1/(2n) + 1/(8n^2)atn = 1 mod 4and5/8 + 1/(2n) - 1/(8n^2)atn = 3 mod 4, because the plane constraint pins the triple parity product to(-1)^K;14 + 14layers cancel it, so the stacked snowflake sits at background1/2while the flat carpet stack sits at3/4ink; the closed forms reproduce all 28 layers with zero error. Witness: walsh-spectrometer. - Verified The
chi_4twist kills the pair-resonance ray family: the average ofchi_4(n) T(nx)over oddn <= Nfalls like1/Nat everyx, rational or not (x = 0, 1/3, 2/3, 1/5, 1/7, 1/2, 1/4, 1/9and irrational), so the snowflake stack has no analogue of the carpet stack's bright main diagonal, itsA = Cexcess going-0.0036atN = 55to-0.000052atN = 5555; its visible rays are only the three single-wave crosshair families parallel to the hexagon's edge directions, one per lattice axis, at odd-denominator rational coordinates. Witness: lab/rs/hexagon-moire. - Verified The ghost star at the hexagon's centre is a finite-layer artifact: each layer's centre is entirely ink or entirely paper, flipping with
n mod 4, so 28 layers give exactly1/2, which is also the limiting background; the star-minus-background contrast decays as(ln L)/Lin the layer countL(-0.094at 5 layers,-0.031at 28,-0.018at 56;excess * Lrunning-0.7779to-1.2519in the ideal frame and-1.0212to-1.3645in the lattice frame fromL = 28toL = 400), and the exact rate constant is open and frame-dependent (-1/8perln Lin one frame,-0.18in another). Witness: lab/rs/hexagon-moire. Superseded in the cell frame: the decay coefficient is a closed form at every band width, see the width family rows under Diagonal slice stack in SETTLED. - Verified The three 60-degree crosshair families obey a limit law: the line at coordinate
a/qcarries strength1/(4q)for oddqand nothing for evenq, converging in the arithmetic model (1/3 -> -0.0837against-0.0833atN = 5555) and visible in the real render in registration-correct frames (theX + Z = 1.25line atN = 55:-0.045/+0.029; theX = 1/3one-sided bands+0.021/-0.058); the per-layer registration drift of1/(2n)in the slice plane is what a drifted scan raster misreads (1/7at-0.058against-0.036,1/2at-0.014in the coarse crosshair model), and a null claiming no rays above0.013was about the scan geometry, not the object. Witness: lab/rs/hexagon-moire. - Proved The Walsh spectrometer: the diagonal-slice ink of every 3D parity design is the exact quasipolynomial
ink(n) = Sig0 - (1/2) Sig3 s + [(2/3) Sig1 - (1/3) Sig2 s]/n + [(2/3) Sig2 - ((1/3) Sig1 + (1/2) Sig3) s]/n^2withs = (-1)^((3n-1)/2)andSig_jthe design's level-jWalsh coefficient sums: the background is the mean Walsh coefficient, the mod-4 blink is minus half the top coefficient, the1/norders read the middle levels; exact in rationals on all 256 codes at every oddn <= 55and at the cold sizes101, 555, 999, 9991; the attempt to break it recomputedP_nfrom the definitions for all 28 oddn <= 55independently of the lane's scripts and of the crate, found|P_n| = 6n^2, weight-only dependence with zero splits and zero law mismatches on all 256 codes. Witness: walsh-spectrometer, mrlydemo::walsh_spectrum. - Proved Nine of the 22 design classes never blink:
|b|takes exactly the values{0, 1/16, 1/8, 3/16, 1/4}, zero iff the top Walsh coefficient vanishes (tree and void among them), carpet and net blink at the middle rung1/8, the xor pair maximally at1/4;(a, |b|)is orbit-invariant on all 256 codes, the named codes are carpet 23, net 232, tree 3, void 129, and carpet and net are the same symmetry class (net is carpet with all parities flipped). Witness: walsh-spectrometer. - Verified The corrected law on the hexagon is dyadic: what breaks coprime independence is a hidden half-cell-shifted overtone at doubled frequency,
chi_4(n) s(2nX + 1/2)/8, that the plane constraint forces into every carpet slice, plus the hexagon's non-product tent marginal; together they couple layermto layers2m +- 1andm +- 2regardless of gcd, and the doubling sign lawsign r(m, 2m +- 1) = -chi_4(m) chi_4(2m +- 1)holds on 18 of 18 pairs from(3, 5)to(601, 1201)across all four residue branches. Witness: lab/rs/hexagon-moire. - Verified The breakage is rule-specific in the limit: the persistent doubling coupling is carpet and net only (void and tree doubling correlations die,
+0.001at(201, 401)), tree keeps a neighbour couplingr(m, m+2) -> -0.0704, void stays essentially independent (adjacent+0.008), and the gcd echo survives in all four (carpet(m, 3m) -> +0.2148, tree+0.1498, void+0.0772at(67, 201)); on the full hexagon the coprime pairs(5, 9)and(5, 7)read-0.142and-0.085, so any published number must pin the mask convention. Witness: lab/rs/hexagon-moire. - Verified Eisenstein is absent from the base-2 slice stack:
L(2, chi_-3) = 0.7813024129appears nowhere, the only character the slice generates ischi_4, and the hexagonal geometry contributes rational tent integrals. Witness: lab/rs/hexagon-moire. Superseded on the character claim: the arm of the ghost star carrieschi_8, see the width family rows under Diagonal slice stack in SETTLED. - Verified The quarter-line law: the strongest interior lines of the stacked hexagram sit at quarter-cell coordinates
a/4(generallya/(4b),bodd), an exact one-sided step of+-1/8that every layer votes for identically because the overtone'schi_4sign meets the layer's ownchi_4and squares away, converging0.1221, 0.1234, 0.1241, 0.1245atN = 151, 301, 601, 1201, the odd-fraction crosshairs at1/(4q)following behind; theX,Z,Wprofiles are numerically identical on the render by the slice's permutation symmetry, so "in five directions but never horizontal" is false and the missing-Z-overtone statement holds only in the rectangle-cell frame. Witness: lab/rs/hexagon-moire. - Verified The void slice stack keeps its star forever: six central lines at plateau ink
1/2against background1/4(ratio 2, the model-frameZarm weaker at3/8), every layer voting on all six, plus a centre dot that is ink at every oddnby a two-line parity proof; the carpet's star fades as log-corrected1/L, so the two snowflake stacks differ by a theorem. Witness: lab/rs/hexagon-moire. - Verified Void and carpet have complementary line spectra on the cut: void's lines sit at even-denominator twisted positions
X = a/(2b),bodd, where carpet is silent, and void is silent at carpet's odd rationals; tree carries the only untwisted crosshair family plus a permanent ratio-2 line atK = 3/2and ignores its free axis; net is the exact pixelwise complement of carpet, since "at most one odd" and "at least two odd" exhaust the cases. Witness: lab/rs/hexagon-moire. - Proved The cut ink laws of all four families are exact closed forms with
chi = (-1)^((3n-1)/2): carpet1/2 + chi/8 + 1/(2n) - chi/(8n^2), net1 - carpet, tree1/4 + (1/3 - chi/12)/n + (1 - chi)/(6n^2), void1/4 - chi/(4n) + 1/(2n^2), exact for all oddn <= 55in lab/rs/hexagon-moire; the wider rangen <= 101has no generator. Witness: lab/rs/hexagon-moire, walsh-spectrometer. - Proved The slice stacks' surviving constants are Leibniz, odd Basel and Catalan: the carpet split
M (I1 - I3 + 1/4) -> pi/4 + pi^2/32unconditionally at balanced layer counts (1.08267atM = 28against1.09382), the void background(pi + pi^2)/16 = 0.8131998159(a fourth-decimal near-collision with the flat-stackpi^2 ln 2/(7 zeta(3)) = 0.8130217042, explicitly separated), the tree backgroundpi/48 + pi^2/48 + G/6withGCatalan's constant, all character series over the exact ink laws, to 7 digits each. Witness: lab/rs/hexagon-moire. - Conjecture On rendered cut grams masked to the common hexagon, the 290 coprime layer pairs have Pearson mean
-0.037and range[-0.205, +0.147]with 85 of 290 beyond|0.05|, against a flat-stack coprime maximum of0.017on the same raster and exactly 0 in the continuum; the gcd echo survives with the(m, 3m)family topping the table at(17, 51) = +0.248; the two strongest coprime pairs,(5, 9) = -0.205with the same residue mod 4 and(5, 7) = -0.204with different residues, show the mod-4 alternation is not the mechanism; these half-mask values are superseded by the full-hexagon-0.142and-0.085below. - Conjecture The xor pair's
14 + 14stack is the flattest nontrivial field measured, carrying six eternal points at the permutations of(1/4, 1/4, 1), ink at all 28 layers for 105 and paper at all 28 for 150, by a one-line parity proof. - Conjecture The Catalan statement
M (mean ink - 1/2 - eps/2) -> G/8holds only alongN = 3 mod 4(0.1144757884atN = 55,0.11448atM = 28against0.11450); alongN = 1 mod 4the limit isG/8 - 1/8(-0.0104828892atN = 53). Witness: lab/rs/hexagon-moire. Superseded: the statement is Proved at both residue classes by the summed ink law, see the Catalan row under Diagonal slice stack in SETTLED. - Verified The xor pair blinks hardest: code 105 has
ink(n) = 1/2 - s/4 - s/(4n^2)and its complement code 150 the reflection1/2 + s/4 + s/(4n^2), both swinging1/4to3/4; the attempt to break it checkedn = 1, where 150 inks 0 of 6 cells against the 1 the shared formula would demand. Witness: walsh-spectrometer. - Verified The doubling magnitude reads between
0.11711630and0.11715991(Richardson extrapolation on sliding triples ofm = 157..601), and the two branch extrapolations in1/mland on0.1171270and0.1171274, so the exact rational-19/162 = -0.117284is dead at1.57e-4. Witness: lab/rs/hexagon-moire. - Conjecture The doubling magnitude is
253/2160 = 0.11712963, fitting both branches to1e-6. Witness: lab/rs/hexagon-moire. Superseded: the constant is exactly253/2160by the phase-map integral, see the layer-pair row under Diagonal slice stack in SETTLED. - Proved The ghost star's decay coefficient is a closed form at every band half-width, not just at the arm. Widen the star to the band
|x - y| <= Wcells;x - yis even on the cut, soWenters only throughK = floor(W/2). Withb = 1whenfloor(K/2)is even,chi = (-1)^((3n-1)/2)the ink law's character (-1atn = 1 mod 4),chi_8the real character mod 8 ofQ(sqrt 2), andE(K) = #{|j| <= K : j = 3, 4, 5 mod 8} + floor((K + 2)/4) - Kthe block tail'schi_8weight, the band's excess over the hexagon's ink law is exactlykappa chi + (m + q chi_8(n))/n + chi/(8 n^2)at every oddn >= K, withkappa = -(-1)^K/(8(2K + 1)),m = -(K + b)/(2(2K + 1))andq = (1 - 2E(K))/(2(2K + 1)); belown = Kthe band is clipped and the identity is false,W = 6atn = 1missing by2/7. The decay coefficient is therefore-(K + b)/(4(2K + 1)), the conjectured-(W + 2b)/(8(W + 1))at evenWand-(W - 1 + 2b)/(8W)at oddW, tending to-1/8.Eis 8-periodic because a block of eight adds6 + 2 - 8 = 0, matching the run0, -1, -1, 0, 1, 2, 2, 1at 201 of 201 valuesK = 0..200, and the identity matches the counted band in exact rationals 1354 of 1354 at 14 distinct half-widths, every oddnfromKto 201, with the four classesn = 1, 3, 5, 7 mod 8counted apart. Witness: lab/rs/hexagon-moire. - Proved The width family's constant and both its
1/L^2branches are closed forms at every width. At an even layer countLthe ladder isL * excess_L = (m/2) ln L + C_W + O(1/L^2)withC_W = m (ln 2 + gamma/2) + q L(1, chi_8) - G/8 + Delta_W, whereDelta_Wis the sum over oddn < Kof the counted excess less the identity, the exact rational the clipped layers contribute,0throughW = 5and2/7atW = 6. Thechi_4components cancel at the1/norder only, soL(1, chi_4) = pi/4is absent at every width whileL(2, chi_4) = Gsits in every one:C_Wcarriesgamma,ln 2,L(1, chi_8)and Catalan'sG. Three tails give the1/L^2coefficient: thechi_8tail over oddn > 2Lis-q/4atL = 0 mod 4and+q/4atL = 2 mod 4, since the sign pattern+--+on the four odd residues starts atn = 2L + 1; the Catalan tail of the background'schi/(8 n^2)gives+1/64blind to the residue; and the harmonic remainder ofm (H_{2L} - H_L/2)gives+m/48. So the coefficient is-q/4 + 1/64 + m/48against+q/4 + 1/64 + m/48, which atW = 0is-23/192and+25/192. The sliding-window slope the sweep reads cancels the oscillation only atL = 0 mod 4and converges tom/2 + kappa/ln 2atL = 2 mod 4: the generator reads-0.24999980atL = 1600againstm/2 = -1/4, and-0.43078703atL = 1602against the limit-0.43033688. Witness: lab/rs/hexagon-moire. - Proved For a fixed affine phase map
n = a m + cwithmgrowing inside one class mod 4, and on the mask this page always uses - the full hexagon of the common cut, area-weighted exactly - the layer-pair correlation limit is an exact rational; a general pair(m, n)has no limit theorem here. The cut cell obeyss_y = s_x + s_z + w mod 2withw = 1at exactly the phase cells(p, q) = (0, 0)and(3, 1)whenN = 1 mod 4and its complement whenN = 3 mod 4; the map sendsalpha = mX mod 2to(a alpha + c X) mod 2, and(mX mod 2, mZ mod 2)equidistributes on the fixed polygon atO(1/m), leaving a piecewise-constant integral with rational breakpoints. It returns the doubling constant exactly253/2160, covariance253/9216over variance15/64, at all four branches with the sign law's sign; the adjacent limit exactly-11/135and the gcd echo exactly29/135; the tree0,-61/864,4/27and the void0,+7/864,2/27, the two doubling zeros exact.19/162is refuted. Both residue classes converge:(301, 601)reads-0.11745304and(601, 1201)-0.11729091atm = 1 mod 4,(103, 205)reads+0.11914004and(203, 405)+0.11814528atm = 3 mod 4, gap timesmat-0.097,-0.097,+0.207and+0.206. Witness: lab/rs/hexagon-moire. - Proved Every constant of the stack's recentred one-layer cut ink is one character sum, and the layer count's parity is the only residue it reads. The hypothesis carries two limbs: the object is the cut ink of a 3D parity design, whose Walsh quasipolynomial carries only
chi_4and terminates at the1/n^2order by the Walsh spectrometer's ink theorem, and the quantity is the recentredM (mean - A - c eps). Writing a family's ink law asI(n) = A + B chi + (c + d chi)/n + (e + f chi)/n^2withchi = -chi_4(n), the average over the firstModd sides obeysM (mean - A - c eps) = -B S - d s_1 + e s_3 - f s_2exactly, withepsthe mean of1/n, threechi_4sums and the zeta tails_3 = sum 1/n^2over those layers, so the limit is-B [M odd] - d pi/4 + e pi^2/8 - f G:pienters only through the1/norder of the ink law, Catalan only through the1/n^2order, the residue class only throughB, and inside those two limbs no other constant can appear, soL(2, chi_-3)is absent by a theorem rather than by a search; outside them it is not, the ghost star's width family being a one-layer object of the same stack whose constant carriesgamma,ln 2andL(1, chi_8)because its character is mod 8 and its1/nlimb is not subtracted. The four families read(A, B, c, d, e, f)as(1/2, 1/8, 1/2, 0, 0, -1/8),(1/2, -1/8, -1/2, 0, 0, 1/8),(1/4, 0, 1/3, -1/12, 1/6, -1/6)and(1/4, 0, 0, -1/4, 1/2, 0), every row of the constants table is an instance, and the leading termA + B chiis the pair sections' own phase-map integral taken at the identity mapa = 1, c = 0. The generator holds the summed identity against the counted hexagons in exact rational arithmetic at every layer count toN = 55, all four families, the classesn = 1, 3, 5, 7 mod 8counted apart, 7 of 7 in each. Witness: lab/rs/hexagon-moire. - Proved The Catalan statement holds at both residue classes and neither one is a fit. The carpet is
B = 1/8,d = e = 0,f = -1/8, soM (mean ink - 1/2 - eps/2) -> G/8 = 0.1144956993alongN = 3 mod 4, measured0.1144757884atN = 55, and-> G/8 - 1/8 = -0.0105043007alongN = 1 mod 4, measured-0.0104828892atN = 53. The1/8step is the ink law's ownchiaveraged over an odd number of layers, the same parity term the ghost star's even-Lhypothesis carries, and Catalan enters only asL(2, chi_4), one order below thepithe tree and the void collect. This closes the Conjecture of the same name. Witness: lab/rs/hexagon-moire. - Proved The approach to every one-layer constant is a closed form. With
sigma = +1at evenMand-1at oddM, the three tails pasta = 2M + 1solveT(a) + T(a + 2) = a^-stwisted andT(a) - T(a + 2) = a^-suntwisted in powers of1/a, givingsigma/(4M),sigma/(8M^2)and1/(4M)with the1/M^2limb of each cancelling, so the gap to the limit is(sigma d - e)/(4M) + sigma f/(8 M^2) + O(1/M^3). Carpet and net read gap timesM^2as-1/64at evenMand+1/64at odd, the void gap timesMas-3/16and-1/16, the tree as-1/16 - 1/(48M)and-1/48 + 1/(48M), and the carpet split as-5/16at evenMonly. The generator's ladders atM = 400, 1600, 3200print all four classes ofM mod 4, so all four ofN mod 8, and match to eight decimals atM = 3200. Witness: lab/rs/hexagon-moire.
Digit designs and the Euler product
- Proved The indicator of
S_F, the integers whose base digits all lie in the digit setF, is multiplicative exactly at the full digit set.1 in Fis forced byf(1) = 1; if a digitc >= 2is missing take the least, andR_c R_(c+1)has no carry because itsbase^mcoefficient ismin(m+1, c, 2c-m) <= base-1, so its digit set is exactly{1..c}whilegcd(R_c, R_(c+1)) = R_1 = 1; if only0is missing then oddbasegives the coprime pair(2, (base^2+1)/2)with productbase^2 + 1 = 101, and evenbasegives(base^2-1, base^2+1), coprime and odd, whose productbase^4 - 1has every digitbase-1whilebase^2+1does not lie in the set. Over all 8177 sets with2 <= base <= 12the constructed witness is asserted at each of the 4083 sets that passf(1) = 1and are not full, and an independent search finds a minimal witness for every one, hardestbase = 12,F = {1}, pair(5, 377). No design outside the full set carries an Euler product over primes;0excluded and a single digit both fail. Witness: lab/py/mrly-euler verb wall. - Proved For every
Fstrictly inside{0..base-1}the design zeta and the design Mobius series obey a disjunction and not a universal: if1is outsideFthe constant coefficient ofzeta_F M_Fis0; if a primepofS_Fhasp^2outsideS_Fthe coefficient atp^2is-1, since(p,p)is the only admissible factorisation; and otherwisezeta_F M_F = 1forces the least elementg > 1ofS_Fto be prime with every powerg^jinS_F, a necessary condition on an escapee and not a contradiction. At the full digit set the two are inverse,zeta_F = zetaandM_F = 1/zeta. Over 257 sets the leastn > 1with a nonzero coefficient is at most50, first atn = 4for base 3{0,1}andn = 9for base 10 missing9, while the eight full sets have none below4000. Witness: lab/py/mrly-euler verb pair. - Proved The position product. With
G_level(t) = prod_(i<level) sum_(d in F) e(d base^i t) = fill^level hat F_level(t), uniqueness of the digit expansion givesint_0^1 G_level(t) e(-nt) dt = 1_(D_level)(n)for every integern, hencesum_(n in D_level, n >= 1) a(n) n^(-s) = int_0^1 G_level(t) A(s,t) dtfor every absolutely convergent Dirichlet series, withA(s,t) = sum_(n >= 1) a(n) e(-nt) n^(-s);a = 1is the periodic zeta of DLMF 25.13.1 anda = muthe Lerch-Mobius series, sozeta_FandM_Fare pairings of one set-only product against one arithmetic-only kernel. The set enters through the digit positions and never through the primes. Checked to1.95e-16and2.04e-16at base 10 missing9,level = 3andlevel = 4, and2.9e-16at base 3{0,1},level = 3, 4, 5. Witness: lab/py/mrly-euler verb position. - Proved The tree's pair route is Holder on the position identity. When
0is inF, atx = base^levelthe identity is finite on both sides,M_F(base^level) = int_0^1 G_level(t) S_level(t) dtwithS_level(t) = sum_(n < base^level) mu(n) e(-nt), soabs(M_F(base^level)) <= (int_0^1 abs(G_level)) max_t abs(S_level)is at mostfill^level base^(level(alpha_1 - 1)) x^b = x^(alpha + alpha_1 - 1 + b); when0is outsideFthe same upper bound holds after summing the levels, a geometric sum of ratiobase^(alpha + alpha_1 - 1 + b) > 1by the flooralpha + alpha_1 >= 1of mobius.md. It sits under the trivialx^alphaexactly whenalpha_1 < 1 - b, which is the bar of coprime.md and mobius.md derived rather than posited, withb = 3/4 + epsunder GRH from Baker and Harman 1991. Witness: lab/py/mrly-euler verb position. - Proved The fibres of the Lerch-Mobius series are inverse Dirichlet L-functions. Splitting
nbyg = gcd(n,Q)and expanding on the characters of(Z/(Q/g))^*givesM(s, a/Q) = sum_(g divides Q) mu(g) g^(-s) phi(Q/g)^(-1) sum_(chi mod Q/g) tau_a(chi) L(s,chi)^(-1) prod_(p divides Q not Q/g) (1 - chi(p) p^(-s))^(-1), soM(s, a/Q)continues toCwith singularities inRe s > 0only at zeros ofL(s,chi)of modulus dividingQ, andM(s,0) = 1/zeta(s). SinceG_level(a/base^j) = fill^(level-j) G_j(a/base^j)are the largest values the position product takes, the design's major arcs are thebase-power rationals, and on that family holomorphy inRe s > 1/2is exactly GRH forbase-power modulus. Coefficient identity checked to2.6e-12at eleven pairs(Q,a)includingQ = 3, 9, 27, 100, the Euler-factor step to7.4e-16. Witness: lab/py/mrly-euler verb fibre. - Proved The reflection moves the kernel and not the design. Solving Hurwitz's formula DLMF 25.13.3 at
x = tandx = 1-tgivesZ(s,t) = ((2 pi)^s Gamma(1-s)/(2 pi i))(e^(pi i s/2) zeta(1-s,t) - e^(-pi i s/2) zeta(1-s,1-t))forsnot a positive integer, the derivation dividing by2i sin(pi s); this is DLMF 25.13.2 recovered, the gain being the rangeRe s > 0in place ofRe s > 1. The position identity turns it into a dual integral of the sameG_levelagainst Hurwitz zetas at1-s, never a relation betweenzeta_F(s)andzeta_F(1-s); the design's own symmetry is thebase-adic scalingG_level(t) = g(t) G_(level-1)(qt), whose transfer eigenvaluefill base^(-s)is what makes the vertical pole lattice. Formula checked to2.1e-30ats = 3.3,2.7 + 1.9iand0.6 + 4.1i. Witness: lab/py/mrly-euler verb dual. - Proved The design's multiplicative shadow is a Lyndon Euler product with no RH content. On the free monoid over
Fwith normN(w) = base^(abs(w)),sum_w N(w)^(-s) = 1/(1 - fill base^(-s)) = prod_(level>=1) (1 - base^(-level s))^(-c_fill(level))withc_fill(level)the Lyndon count, by Chen-Fox-Lyndon: every word factors uniquely as a non-increasing product of Lyndon words, so the free monoid onFis equinumerous by norm with the free abelian monoid on Lyndon words and is not equal to it. The primes are the Lyndon words, the zeta is zero-free, its Mobius is supported on the empty word and the letters so its Mertens is1 - fillbeyond norm1, and its poles are exactlys = alpha + 2 pi i m / log base, the design pole lattice. All RH content ofzeta_Ftherefore sits in the cofactorzeta_F(s)(1 - fill base^(-s)). Expansion verified throughu^16atfill = 2, 3, 4, 9, 10,c_2(level)being A001037. Witness: lab/py/mrly-euler verb word, A001037. - Proved The Beurling system of a design with non-unit digit gcd is finitely generated, on two branches. If
gcd(F) = a > 1every element ofS_Fis a multiple ofa; whenais prime the primes of the design are{a},N_Fis the powers ofaandM_B(x) = 0forx >= a, and whenais compositeS_Fholds no prime at all,N_F = {1}andM_Bis identically1, witnessbase = 10,F = {0,4,8}. Either way the eight scaled census families of mobius.md are exactly the columns the Beurling route cannot see, while the scaling transfer reads them exactly. Witness: lab/py/mrly-euler verb beurling. - Verified The Beurling census on the primes of a design, to
x = 10^6. Base 3{0,2}has the single prime2andM_Bidentically zero past2; base 3{0,1}has525primes,N_F(920483) = 2198, runningmax abs(M_B) = 98and exponent0.3339againstalpha/2 = 0.3155; base 10 missing9has35139primes,N_F(10^6) = 488864againstx^alpha = 531441,M_B(10^6) = 1860, running max1866, and exponentlog(running max)/log xreading0.4203, 0.4882, 0.5452at10^4, 10^5, 10^6againstalpha/2 = 0.4771, where full base 10 as control reads0.4084, 0.4241, 0.4276at the same points against its ownalpha/2 = 0.5. What the census reads is the level and not a trend:+0.068overalpha/2for the design against-0.072for the control, a running maximum climbing in both. There is cancellation,0.545against the trivialalpha = 0.954, and it is abovealpha/2, so the census supports cancellation and does not support the square-root conjecture onN_F;N_Fis notS_F. Full base 10 reproduces-23, -48, 212at10^4, 10^5, 10^6, A084237. Witness: lab/py/mrly-euler verb beurling, A084237. - Proved The identity that replaces
zeta M = 1on a design. For every(base,F)with1 in Fthe indicator1_(S_F)has a Dirichlet inversenu_F, given bynu_F(1) = 1andnu_F(n) = -sum_(d divides n, d > 1, d in S_F) nu_F(n/d), sozeta_F(s) N_F(s) = 1withN_F(s) = sum nu_F(n) n^(-s); the support ofnu_Flies inside the multiplicative semigroup generated byS_Fand strictly inside it, since9,27and36lie in the semigroup withnu_F = 0while16,48and52lie in the semigroup and outsideS_F, so the semigroup is a third set besideS_Fand the Beurling integers on the primes of the design and the support is a fourth, andnu_Fismuexactly at the full digit set, where the classical identity is the special case. Ifrhois a zero ofzeta_FwithRe rho > alphathensigma_c(N_F) >= Re rho, by the identity theorem on the connected pole-free half planeRe s > max(sigma_c(N_F), alpha), sosum_(n <= x) nu_F(n)is notO(x^(Re rho - eps))for anyeps > 0; the converse boundsigma_c(N_F) <= sup Re rhois not claimed. Checked againstmuterm for term on the full digit set ton = 131072atbase = 2andn = 177147atbase = 3, and the partial sums ofN_F(sigma)meet1/zeta_F(sigma)to1.60e-3atsigma = Re rho + 0.08 = 0.8008and1.96e-4atsigma = Re rho + 0.20 = 0.9208at base 3{0,1}, and to1.72e-2atsigma = 1.0816and2.39e-3atsigma = 1.2016at base 10 missing9, both offsets sitting aboveRe rho. Witness: lab/py/mrly-pairing verb inverse, lab/py/design-zeta. - Proved The design's own Mobius has anti-cancellation, and that is what makes the decoupling a blessing. Winding boxes on
zeta_Fby the argument principle certify one zero each and pinRe rhoto the box edges: winding1onRe in [0.72074, 0.72084],Im in [28.60563, 28.60573]at base 3F = {0,1}with contour minimumabs(zeta_F) = 8.298e-4against the engine bound6.284e-30, and winding1onRe in [1.00150, 1.00168],Im in [2.73915, 2.73925]at base 10 missing9with contour minimum6.865e-4against2.798e-23, while the control rectangleRe in [0.99900, 1.00050],Im in [2.73810, 2.74030]there returns winding0. Both boxes lie strictly right ofalpha = 0.6309297536and0.9542425094, sosum_(n <= x) nu_F(n)is notO(x^(0.72074 - eps))and notO(x^(1.00150 - eps))respectively: the limsup of the design's own Mertens function exceeds the design's own massA_F(x), and at base 10 missing9exceedsxitself, the box lying right ofRe s = 1. The square-root conjecture in thealpha/2shape is therefore false fornu_Fand can only be carried bymurestricted toS_F; the sibling's decoupling theorem is what protects it. Pointwise the census is far below both limsups,max/A_F = 0.0738at base 3level = 16andmax/x = 0.0847at base 10level = 7: the running maximum ofsum nu_F(n)grows by9.4474, 11.5000, 10.2220, 10.0354per level at base 10 missing9,level = 4..7, againstbase^(Re rho) = 10.036661and the trivialfill = 9, only the last of the four landing on the predicted rate, withmax/A_F(base^level)rising0.1043, 0.1094, 0.1398, 0.1588, 0.1771; at base 3{0,1}the geometric mean of the four stepslevel = 12..16is2.059against2.207512and2while the arithmetic mean of the five printed level ratios is1.9972, below the trivial2, a census too short to separate them. Witness: lab/py/mrly-pairing verbs box and inverse, lab/py/design-zeta. - Verified The pair
zeta_F M_F = 1 + D_Fgains nothing:D_Fhas abscissa exactlyalpha. Absolute convergence ofzeta_F^2putssigma_a(D_F) <= alphaand that half is proved; for the other half, ifsigma_c(D_F)were belowalphathenM_F(sigma) = (1 + D_F(sigma))/zeta_F(sigma)would tend to0assigma -> alpha+, sincezeta_Fhas nonnegative coefficients and is singular at its abscissa by Landau, sozeta_F(sigma) -> +infinity, and there is no circularity in the argument becauseM_Fis dominated termwise byzeta_Fand so converges absolutely at everysigma > alphawith no hypothesis ontheta(F). That half rests on a measurement, unconditional in shape sincesigma_c(D_F) < alphawould forceP(x) = o(x^alpha):P(x) = sum_(n <= x) c_F(n)divided byx^alphais bounded away from0and from infinity, reading0.493767, 0.699235, 0.758519, 0.587055at four sampling phases at base 3{0,1}, the four phases being needed becauseP(x)/x^alphais log-periodic and sampling only atx = base^levelaliases every Fourier mode onto one number. TheM_F(sigma) -> 0limit test is not a witness here: the tail the generator prints beside it isbase^(-level alpha/2), which assumes the square-root conjecture, and against the unconditional tail(fill-1) base^(-level eps)/(1 - base^(-eps))fromA_F(base^l) = fill^lno printedM_Fvalue at base 10 missing9is distinguishable from0. SinceM_F = (1 + D_F) N_Fandsigma_c(N_F) > alpha, the glue is not neutral but lossy. Witness: lab/py/mrly-pairing verb glue. - Proved The position pairing is exact on the grid and its
l^1mass sits at the top level, which kills the per-denominator split. For0 in F,M_F(base^level) = base^(-level) sum_(a mod base^level) G_level(a/base^level) S_level(a/base^level)exactly, both factors being trigonometric polynomials of degree belowbase^level; writinga = base^v a'withbasenot dividinga'andj = level - vgivesG_level(a/base^level) = fill^(level-j) G_j(a'/base^j)and the exact level decompositionC_level = sum_(j=0)^level fill^(level-j) c_jof thel^1mass, withC_j = fill C_(j-1) + c_j. Thel^1floorC_j >= base C_(j-1)forces the top-level sharec_level/C_level >= 1 - fill/base = m/baseat every base and digit set, measured0.485846, 0.602606, 0.687994, 0.510055against floors0.333333, 0.500000, 0.600000, 0.100000, with levelsj >= level/2carrying0.995116, 0.996061, 0.997043, 0.942350. Since the Baker-Harman Proposition beats the uniformx^(3/4)only belowj = level/2, weighting the Mobius input per denominator saves exactlylog(C_level/c_level)/(level log base), a constant factor capped bybase/m: the numerator is0.657068at base 3{0,1}, identical at everylevel = 6..14. The split exponents are0.988106, 0.912502, 0.905006, 1.012881uniform and0.941173, 0.879287, 0.879188, 0.964150per denominator againstalpha = 0.630930, 0.500000, 0.430677, 0.954243, while the Cauchy-Schwarz split is(alpha+1)/2exactly sinceint abs(G_level)^2 = fill^level; the base 2 and base 3 full-set controls return0.500000, the classical RH exponent. Witness: lab/py/mrly-pairing verb split. - Proved The principal fibre of the grid pairing has exponent
alpha - 1/2under RH, below the conjecturedalpha/2, and that is an asymptotic statement only. Thea = 0term of the grid pairing isbase^(-level) fill^level M(base^level), of exponentalpha - 1/2under RH, andalpha - 1/2 < alpha/2for everyalpha < 1, so in the limit the classical Mertens function cannot carry the conjectured size of the design meter. At finite depth it carries a great deal: thea = 0term reads-0.31857of11,0.11133of6,-0.05924of9and112.66549of276at base 3{0,1}level = 14, base 4{0,1}level = 11, base 5{0,1}level = 9and base 10 missing9level = 6, shares-0.028961, 0.018555, -0.006583, 0.408208, and exactly all of the meter on the two full-set controls. So at base 10 missing9the principal fibre carries40.8percent of the meter at the only measuredlevel, which refutes any claim that the square-root conjecture lives entirely off the principal fibre at finite depth: the exponent gap there is0.454243against0.477121, and a factor of10between them needsx = 10^44. Witness: lab/py/mrly-pairing verb split. - Proved The one-step constant of the digit transform never exceeds the triangle-split bound, and is strictly below it at every family measured beyond
level = 1. WithH(t) = sum_(r mod base) abs(g_F((t+r)/base))andB_base(F) = sup_t H(t), the identityC_level = sum_(a mod base^(level-1)) abs(G_(level-1)(a/base^(level-1))) H(a/base^level)givesC_level <= B_base(F) C_(level-1), soC_level/C_(level-1) <= B_base(F)at everyleveland every family with no computation at all; the inequality is not strict in general and equality is attained,C_1/C_0 = 4 = B_base(F)exactly at base 3{0,1}, so strictness needslevel >= 2. Verified there:C_level/C_(level-1)reads3.889888518, 5.032783116, 6.410132461, 18.369402635at base 3{0,1}, base 4{0,1}, base 5{0,1}(alllevel = 9) and base 10 missing9(level = 6), againstB_base(F) = 4.000000000, 5.226251860, 6.472135955, 19.888543820, and the ratio agrees between the two consecutivelevelthe generator prints to8.5, 7.4, 10, 5.0digits by family, so the stability is family by family and two values oflevelare all that is measured. Witness: lab/py/mrly-pairing verb split. - Proved The design Mobius of the two-digit design is base-free. Let
S*be the nonzero0/1polynomials ofZ[x],M*the monoid they generate,nu*the Dirichlet inverse of1_(S*). ForF = {0,1}at everybase >= 2,nu_F(n) = sum over P in M* with P(base) = n of nu*(P). Evaluation is a bijectionS* -> S_F, a monoid homomorphism, and of finite fibres, since an element ofM*has nonnegative coefficients soP(base) = ncaps every coefficient bynanddeg Pbylog(n)/log(base); the pushforwardgtherefore exists,g(1) = 1because1is the only element ofM*of value1, and grouping the pairs(D, Q)inS* x M*withD(base) Q(base) = nbyP = DQturns1_(S*) * nu* = deltainto1_(S_F) * g = delta, where the Dirichlet inverse is unique. Hencesum_(n <= x) nu_F(n) = sum over P in M* with P(base) <= x of nu*(P)at everyx: the base enters only as the order in which one base-free function is summed, and atbase = 2the classicalmuis that pushforward. Checked term for term with 0 mismatches ton <= 2^15,3^10,4^8and5^7, where 108978 elements ofM*collapse onto 32768 integers at base 2. Witness: lab/rs/carry-free-mobius verb lemma. - Proved The degree-graded mass of the base-free design Mobius is
1 - 2texactly. Degree is a monoid homomorphismM* -> Nwith finite fibres because1is the only constant inM*, which holds forF = {0,1}and for no design carrying a digit at least 2, where a constantc >= 2makes the degree-zero fibre{c^k}infinite; pushing1_(S*) * nu* = deltaalong it with2^dpolynomials of degreedgivesA(t)/(1 - 2t) = 1, so the graded sums are1, -2, 0, 0, ...andsum over deg P < level of nu*(P) = -1for everylevel >= 2. The design Mertens function is therefore pinned to-1at every level boundarylevel >= 2inside the carry-free window, and reads0atlevel = 1. Witness: lab/rs/carry-free-mobius verb sequence. - Proved The design zeta has an explicit zero free half plane, and it closes the census right of the abscissa. Let
a_minbe the least nonzero digit ofF, hence the least element ofS_F, every element of two digits or more exceedingbase. If a realsigma > alphasatisfiesa_min^sigma zeta_F(sigma) < 2thenzeta_Fhas no zero inRe s >= sigma: the coefficients are nonnegative and the series converges forsigma > alpha, so forRe s = sigma' >= sigmaone hasabs(a_min^s zeta_F(s) - 1) = abs(sum_(n in S_F, n > a_min) (n/a_min)^(-s)) <= sum_(n > a_min) (n/a_min)^(-sigma) = a_min^sigma zeta_F(sigma) - 1 < 1. The hypothesissigma > alphais load bearing and the test is one real evaluation carrying the ladder's own error bound. On the gridalpha + 0.05 nthe edgesigma_1reads0.5at base 4{1}to1.75at the three full digit sets over twenty-four designs, witha_min^sigma zeta_F(sigma)in[1.8635, 1.9995]and largestsigma_1 - alphaequal to0.95, so a census of the zeros right ofalphaneeds no hand chosen right edge and thealpha + 3.02strip of the locus sweep is three times wider than the zeros need. Witness: lab/py/transport-census verb census. - Verified The transport census: every proper design censused carries zeros right of its abscissa, the full digit set alone carries none, and each rightmost is certified by a winding box. On the box
alpha + 1e-6 < Re s < sigma_1, where the cofactorZ = zeta_F(s)(1 - fill base^(-s))is analytic and its zeros right ofalphaare exactly those ofzeta_F, the transfer failing only at residue null poles which sit on the lineRe s = alpha, the argument principle counts157zeros right ofalphabelowIm s = 40over twenty-three designs, all157located, plus2at base 50 missing one digit belowIm s = 4. The count is exact on the box and a lower bound for the half plane, since the sliveralpha < Re s <= alpha + 1e-6, the band0 < Im s < 0.02, everything above the census height and the conjugate half plane are uncounted. Twenty-one of the twenty-four designs carry such a zero; the three that do not are the base 2, 3 and 4 full digit sets, whose windings read-1.97e-33,1.73e-33and1.53e-33. Every rightmost carries the height it is read below, because the teeth of the level zero comb drift right with the pole index: base 20 missing one digit reads1.000285484146atIm s = 2.0988,1.000549674321at4.1971and1.002685494779at14.6920. BelowIm s = 40the rightmost real parts run0.441505537191at base 5{0,1}to1.002685494780at base 20 missing one digit, each certified by a winding1box onzeta_Fof half width5e-5inRe sand inIm swhose sampled contour minimum,1.2e-4to6.1e-3, beats the engine's error bound by at least eight orders of magnitude and whose distance to the pole lattices_(i,j) = alpha - i + 2 pi i j/log baseis at least0.00517845, four hundred box half widths. The two published boxes of lab/py/mrly-pairing reproduce at their own edges, winding1and1with contour minima8.298e-4and6.865e-4, and its control rectangle returns winding0. Witness: lab/py/transport-census verb census. - Proved A certified zero right of the abscissa refutes every square-root-shaped bound for the design's own Mobius, and the digit
1is the hypothesis that bites. Let1 in F, letrhobe a zero ofzeta_Fcertified by a winding1box with left edgex_0 > alphacontaining no pole, and letnu_Fbe the Dirichlet inverse of1_(S_F). The transport theorem givessigma_c(N_F) >= Re rho >= x_0 > alpha, sosum_(n <= x) nu_F(n)is notO(x^(x_0 - eps))for anyeps > 0; sinceA_F(x)has exponentalphathe square-root exponent isalpha/2 <= alpha < x_0, so the design's own Mobius satisfies no square-root-shaped bound and misses even the trivialO(x^(alpha - eps)), the first inequality failing to be strict only at the two designs withalpha = 0, whereA_F(x)grows likelog x. Nineteen of the twenty-four designs censused meet all three hypotheses and get a bound, and seventeen of the twenty-two the locus and family sweeps censused, the bounds runningtheta(nu_F) >= 0.4414555at base 5{0,1}totheta(nu_F) >= 1.0026354at base 20 missing one digit. Four designs haveRe rho > 1, so their own Mobius outruns the count of all integers belowx: base 10 missing two digits, base 10 missing the digit9, base 20 missing one digit and base 50 missing one digit, atfill/base = 0.8, 0.9, 0.95, 0.98andalpha = 0.9030900, 0.9542425, 0.9828779, 0.9948357; only the SIGN ofRe rho - 1is read and never its size, three of the four being censused toIm s = 40and base 50 toIm s = 4. Thefill/basereading dies on its control, base 5{0,1,2,3}at the samefill/base = 0.8with rightmost0.989748105861. Two designs carry a zero right ofalphaand no bound: base 4{2,3}and base 4{0,2,3}omit the digit1, so1is outsideS_F, the indicator vanishes there andnu_Fdoes not exist. Witness: lab/py/transport-census verb law. - Refuted The gain of a design's rightmost zero over its abscissa is not a function of
alphaandfill/base. The refuted functional is new: the locus row already refutes a law for the POSITION of the zeros, this refutes one for the single statistic the transport theorem reads, the rightmost real part lessalpha. Four equal key families, one base and one digit count each soalphaandfill/baseagree exactly and not to a rounding, read unequal gains: atalpha = 1/2,fill/base = 1/2the four base 4 two digit designs give0.0853043873,0.4400124317,0.2706238545,0.3439264581, a spread of0.35470804; base 5 atalpha = 0.4306766,fill/base = 0.4spreads0.37474232; base 3 two digit atalpha = 0.6309298spreads0.17605693; base 4 three digit atalpha = 0.7924813spreads0.060972003, which is still six hundred box widths. The two columns disagree in direction: the gain is largest at the sparsest designs,0.5291214025and0.4485242462atalpha = 0, while the rightmost real part itself is smallest there. What rises withalphais the floor, the least rightmost real part at eachalphareading0.4485242462, 0.4415055372, 0.5853043873, 0.7207876015, 0.9126562295, 0.9897481059, 1.0015143877, 1.0015892753, 1.0026854948, 1.0000614750up ten rungsalpha = 0, 0.4307, 0.5, 0.6309, 0.7925, 0.8614, 0.9031, 0.9542, 0.9829, 0.9948, rising at every step but the first and the last, the last being where the census height drops from40to4; one design per rung abovealpha = 0.86against six atalpha = 0.5, and no fit is taken. Witness: lab/py/transport-census verb law. - Proved
nu*vanishes at every polynomial divisible byx^2, andnu*(x b) = -nu*(b)at everybof nonzero constant term. The convolution runs overZ[x]divisors andM*is not divisor-closed,1 + x^2 + x^4 = (1 + x + x^2)(1 - x + x^2), so the claim lives onA, the nonzero polynomials mod units, wherenu*vanishes offM*by induction.Asplits asN x R,Rthe classes of nonzero constant term and divisor-closed;x^k blies inS*exactly whenblies inS*_odd, so1_(S*)is the outer product of the all-ones function onNwith1_(S*_odd), inversion factors, and the inverse of the all-ones function onNis1 - t. Witness: lab/rs/carry-free-mobius verb ladder. - Proved Every element of
M*of degreedhas its coefficient ofx^iat mostbinomial(d, i), so the maximum coefficient at degreedis exactlybinomial(d, floor(d/2)), A001405, attained by(1+x)^d. A product of0/1polynomials of degrees summing todis dominated coefficientwise byprod_k (1 + x + ... + x^(d_k)), each factor by(1 + x)^(d_k), and domination survives products of nonnegative polynomials, so the product is under(1 + x)^d, itself inM*. This retires the measured clause and the crude cap2^(L-1)of the carry-bound row. Checked at every degree to 22, maximum 705432. Witness: lab/rs/carry-free-mobius verb ladder. - Proved On
R, the classes of nonzero constant term among the nonzero polynomials up to units,nu*is fixed by the reciprocalb -> x^(deg b) b(1/x). There the reciprocal is degree-preserving, multiplicative and involutive, hence a monoid automorphism, and it carriesS*_oddonto itself by reversing the bitmask, so it preserves1_(S*_odd)and its Dirichlet inverse. It is no invariance on all ofZ[x]: the reciprocal drops thexpower andnu*(x) = -1againstnu*(1) = 1. Checked with 0 mismatches over the 35121747 classes of degree 1 to 21. Witness: lab/rs/carry-free-mobius verb ladder. - Proved The carry-free window of a two-digit design is
(base+1)^(level-1) < base^level. A0/1polynomial of degreedhasP(base) <= (1+base)^dand degrees add over a product, so the maximum ofP(base)overM*at degree belowlevelis exactly(base+1)^(level-1), attained by(1+x)^(level-1), and the least base holding every such element underbase^levelis the leastbasewith(base+1)^(level-1) < base^level. Verified by enumeration atlevel = 3..14, reading 3, 3, 4, 4, 4, 5, 5, 6, 6, 6, 7, 7. The windows are 4, 7, 9, 12 and 15 at bases 3 to 7, andsum_(n <= base^level) nu_F(n)leaves-1at level 5, 8 and 10, one level past the window each time. Witness: lab/rs/carry-free-mobius verb lemma. - Conjecture The base-free Mertens maximum of the two-digit design gains on the design's mass without reaching it. The running maximum of
sum nu*over degree belowlevelreads 1, 1, 2, 3, 4, 7, 15, 23, 45, 86, 162, 331, 741, 1665, 3173, 7508, 17753, 36147, 79645, 182432, 427806, 858703, 2026147 atlevel = 1..23, and the ratiomax/2^levelbottoms at 0.079102 atlevel = 11, falls for the last time atlevel = 15, and rises at every step from there to 0.241536 atlevel = 23. A turn-down at a deeper level kills the trend and none is seen to 23. Witness: lab/rs/carry-free-mobius verb ladder. - Conjecture The rate of that maximum exceeds the design's mass rate 2, and its estimate is window-unstable. At depth 23 the geometric mean step reads 2.245836, 2.202419, 2.242075, 2.206405 over the last 4, 6, 8, 10 levels but 2.194975, 2.149760, 2.092480, 2.074545, 1.996559 over the last 12 to 20, a hull of [1.996559, 2.245836] straddling 2, the long windows opening inside the levels where the ratio still fell. Every short-window reading at depths 20 to 23 sits above 2.18 and above its depth-18 value. No constant is claimed;
log_2(max)/levelreaches 0.910883 atlevel = 23unsettled. Witness: lab/rs/carry-free-mobius verb ladder. - Proved Weil's theorem reaches a design zeta along no evaluation bridge:
P -> P(base)on polynomials with coefficients in{0..base-1}is a bijection onto the nonnegative integers and additive only where no carry occurs, a coefficient of the polynomial productP Rreaching(base-1)^2 (min(deg P, deg R) + 1)against the digit capbase - 1, so an integer product's digit string is the carry reduction of the polynomial product andR_c R_(c+1)is the shortest coprime pair whose carry-free product shows the missing digitc. Witness: lab/py/mrly-euler verb wall. - Proved Under the hypothesis
alpha < 1the large sieve does not rescue the per-denominator split on the major arcs: writinga = base^v a'withbasenot dividinga'andj = level - v, thel^2mass of the grid pairing over the levelsj <= Jis exactlyfill^(2 level - J) base^J, and the spacing form of the large sieve on thosebase^(-J)spaced points gives(base^level + base^J) base^level, so the levels belowJ = u levelcostx^(alpha + u(1-alpha)/2), strictly abovealphaat everyu > 0and equal toalphaonly atu = 0. Witness: lab/py/mrly-pairing verb split, Montgomery and Vaughan 1973.
Digit strings across divisors
- Proved Orthogonality for digit strings against a divisor:
N_F(level; d, r) = (1/d) sum_{a mod d} e(-a r/d) prod_{j < level} g_F(a base^j/d)withg_F(t) = sum_{f in F} e(f t), by expanding the divisibility indicator in additive characters modd, the digits being independent so the character sum factors over positions, thea = 0term givingfill^level/d; the attempt to break it rebuilds the whole residue vector by dynamic programming against brute-force string enumeration at four bases and checks its total againstfill^levelat every census cell, with no mismatch. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The uniform geometric equidistribution bound: for
fill >= 2,d >= 2,(d, base) = 1andgcd(d, Delta_F) = 1withDelta_Fthe digit-difference gcd,|N_F(level; d, r) - fill^level/d| <= ((d-1)/d) fill^level (1 - 8/(fill^2 d^2))^level <= fill^level exp(-8 level/(fill^2 d^2))for everyrandlevel >= 1, since|g_F(a/d)|^2 = fill^2 - 4 sum_{f < f'} sin^2(pi a (f' - f)/d)andd | a(f' - f)at every pair would forced/gcd(a, d) | Delta_Fhenced | a; the attempt to break it asserts the weaker form as an exact integer inequality at every census cell where the hypotheses hold, five bases and depths tolevel = 96, with no failure and largest observed-to-bound ratio0.187atbase = 100,F = {0,1},level = 16, and the hypothesis edged = 2,fill = 2holds at bound factor(1 - 1/2)^level; thed^(-2)in the exponent is sharp in shape, sinced | base - 1withFan arithmetic progression of differencem'anda m' = 1 mod dgives|g_F(a/d)|/fill = sin(pi fill/d)/(fill sin(pi/d)) = 1 - Theta(fill^2/d^2). Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The dense-digit bound: for
F = {0..base-1}minusEwithm = |E|,fill = base - mand(d, base) = 1,gamma_F(d) <= (d/2 + m)/fillbecauseg_Fis the full Dirichlet kernel lessg_E,|D_base(a/d)| <= 1/(2||a/d||) <= d/2and|g_E| <= m, so ford/2 + m < fillthe error is at mostfill^level ((d/2 + m)/fill)^leveluniformly inr; the attempt to break it looks for the gain at fixed digit count, where the bound is vacuous and stays vacuous - atd = 7the per-digit rate falls0.4869, 0.3312, 0.2484, 0.1104, 0.0167asfillruns2, 3, 4, 9, 99but reads0.4992forF = {0,1}atbase = 100, against the same ceiling0.9010thatF = {0,1}carries atbase = 3. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved A power saving over a whole level for dense digit sets: for
eps in (0,1),base >= 4^(1/eps),m <= base^(1-eps)/2andlevel >= 4/eps, every2 <= d <= base^(1-eps)coprime tobasehas per-digit factor(d/2 + m)/fill <= base^(-eps/2), sosum over those d of |N_F(level; d) - fill^level/d| <= fill^level base^(1 - eps level/2) <= fill^level x^(-eps/4)atx = base^level, a level of distributionbase^(1-eps)with no conditional input; the attempt to break it pushes the level past a constant power of the base and fails, since summing the geometric bound alone caps the level atd ~ sqrt(level)/fill, and the census argmax at every family's deepest level is a divisor ofbase^t - 1witht <= 8, where no per-factor bound decays. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The exact split across the base's own divisors: for
d = d1 d2withd1 | base^m,m <= level, and(d2, base) = 1, the lowmdigits fix the value modd1and reach the rest only through the invertible multiplierbase^m mod d2, soN_F(level; d) = sum over w in F^m with d1 | val(w) of N_F(level - m; d2, r_w)withr_w = -val(w) (base^m)^(-1) mod d2, and the density splits asrho_F(d1 d2) = (N_F(m; d1)/fill^m)(1/d2); the attempt to break it tests the natural guess1/d1for the base part and refutes it, the base part being a digit-string count, with the identity itself pinned against direct enumeration atbase = 6,d = 10. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The digit-gcd hypothesis is a wall: if
gcd(d, Delta_F) > 1there is no equidistribution, witnessbase = 3,F = {0,2},d = 2, where every value is even,N_F(level; 2) = fill^leveland the normalized errord |N_F(level; d) - fill^level/d| / fill^levelis exactly1at everylevel; the attempt to break the wall by sweeping the whole range instead of one divisor leaves it standing, the unrestricted worst error overd <= 200reading1.0483atlevel = 32pinned atd = 164against0.019166oncedis required coprime toDelta_F, and such families reduce to a primitive one through the scaling bijectionS_(aF') = a S_(F'). Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The second moment across residue classes:
sum_{r mod d} (N_F(level; d, r) - fill^level/d)^2 = (1/d) sum_{a not 0 mod d} prod_{j < level} |g_F(a base^j/d)|^2, by Parseval moddon the orthogonality identity, the mean being thea = 0term and no cross terms surviving; the attempt to break it looks for a hidden hypothesis and finds none, the identity holding for everyd >= 1and everyF, including the walls where the supremum bound is worthless, which is what makes it the one handle left at a pinned divisor. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Verified The divisor census of digit strings: exact dynamic-programming counts of
N_F(level; d)over2 <= d <= Dfor ten families atbase = 3, 4, 5, 10, 100, depths tolevel = 96andDto500, printing the worst normalized error, the multiplicative order ofbaseat the argmax, the per-factor ceilinggamma_F(d)and the slack against the proved bound; the counts are pinned against brute-force string enumeration at four bases, the residue vector totalsfill^level, and the argmax is a pinned divisor ofbase^t - 1witht <= 8at every family's deepest level,d = 164atbase = 3,d = 143atbase = 10,d = 101, 303atbase = 100, with shallow depths straying (d = 199,ord = 99, atbase = 10,level = 6). The slow column is the sparse one:F = {0,1}atbase = 100reads worst normalized error28.593, 14.590, 9.0340, 7.2034atlevel = 16, 32, 64, 96, per-digit factor0.9929. Witness: lab/rs/rho-decoupling, mobius.md digit strings across divisors. - Conjecture The orbit-mean law at a pinned divisor: for
F = {0..base-1}minus one digit andd = base^t - 1, the worst orbit-mean damping isfill^(-1/t) (1 + o(1)), the orbita base^j mod dcarryingt - 1undamped points and one damped by~ 1/fill; atbase = 100,level = 12the single-divisor probes read orbit mean0.1059atd = base^2 - 1againstfill^(-1/2)and0.2369atd = base^3 - 1againstfill^(-1/3), with the proper divisord = 3367 | base^3 - 1better at0.0549andd = 101 | base + 1pinned but harmless at0.0261, the kernel being flat across that whole orbit. Two values ofton one base with one dominant character are a check and not a law, and theo(1)is untested;t = 4needs the orbit product analysed rather than counted, the exact count atd = base^4 - 1being out of reach of the census. Witness: lab/rs/rho-decoupling, mobius.md digit strings across divisors. - Verified The signed pinned sum against its absolute sum: over the squarefree moduli
e = (base^t - 1)/g,g | base - 1,e >= 2,t <= level <= 40, withT_level(e) = N_F(level; e) - fill^level/e, the ratiosum mu(e) T_level(e) / sum |T_level(e)|reads-0.211, -0.123, +0.069, -0.498atlevel = 10, 20, 30, 40forF = {0,1},base = 3, and+0.812, -0.495, -0.127, -0.192for one excluded digit atbase = 10, swinging across[-1, 1]with no decay,Abs_level/fill^levelat2.1 * 10^-4and3.9 * 10^-12atlevel = 40; counts exact by the carry DP pinned against brute force and the residue DP at every reachablee <= 30000,mufrom a complete certified factorisation with zero unknown cofactors. Witness: mobius.md digit strings across divisors; lab/rs/rho-decoupling, the carry sweep and its five pinned tests. - Refuted The adversarial pass on the divisor census: the geometric bound was attacked as an exact integer inequality at every census cell where its hypotheses hold, five bases and depths to
level = 96, with zero failures and the closest cell at observed-to-bound ratio0.187; the hypothesis edges were attacked one at a time,d = 2withk = 2holding at bound factor(1 - 1/2)^level, the digit-gcd hypothesis breaking exactly where the proof says it must (base = 3,F = {0,2},d = 2, normalized error1at everylevel, sweep worst1.0483atlevel = 32), and the base-coprimality hypothesis handled by the exact split rather than dropped; the search for decay at fixed digit count failed and is recorded as the slow column rather than smoothed away. The printed floats truncate at forty decimal digits, so every claim-bearing comparison runs in exact integers or fractions and no rate is quoted past what the exact columns carry. Witness: lab/rs/rho-decoupling. - Proved The pinned-orbit law, two-sided at one excluded digit. For
t >= 1, everyddividingbase^t - 1withd >= 2and everyanonzero modd, the full Dirichlet kernel's orbit product telescopes toProd_(j < t) abs(D_base(a base^j/d)) = 1exactly, sincea base^t = a mod dand no factor degenerates, so a closed shift orbit is invisible to the full digit set and every damping comes from the excluded digits. Withabs(g_F) <= abs(D_base) + mandabs(D_base(a base^j/d)) <= B = min(base, d/2), convexity oflog(e^y + m)puts the maximum at a vertex of{Sum_j log D_j = 0, log D_j <= log B}and givesProd_(j < t) abs(g_F(a base^j/d)) <= (B + m)^(t-1) (m + B^(1-t)). At one excluded digit that is sharp both ways: ford = base^t - 1,t >= 2,base >= 10and any single excluded digit,fill^(-1/t) (1 - 9/base) <= max_(a not 0 mod d) (Prod_(j < t) abs(g_F(a base^j/d))/fill^t)^(1/t) <= fill^(-1/t) (1 + 3/(base-1))uniformly int, the lower bound witnessed bya = 1. Sot - 1undamped positions and one damped by~ 1/fillis the truth and the1 + o(1)is a two-sidedO(1/base)that does not grow witht; the constants9/baseand3/(base-1)are stated atbase >= 10. This supersedes the orbit-mean Conjecture row in OPEN, whosebase = 100,level = 12probes0.1059and0.2369read the finite-depth error rate(abs(N_F(level; d) - fill^level/d)/fill^level)^(1/level) d^(1/level)and not the orbit maximum. Witness: mobius.md digit strings across divisors, lab/rs/rho-decoupling. - Proved The
a-average at a full pinned modulus is exact at every digit set and every number of excluded digits: ford = base^t - 1,Sum_(a mod d) Prod_(j < t) abs(g_F(a base^j/d))^2 = d (fill^t + 2w)withw = 1when both0andbase - 1lie inFandw = 0otherwise, sincevalis injective on length-tstrings with range[0, d], so the congruent pairs are the diagonal plus the single wraparound pair of the all-0and all-(base-1)strings when both lie overF. Under the pinned-orbit law's hypotheses, one excluded digit andbase >= 10, the worst orbit exceeds the average over alla, which isfill^t + 2w, byfill^(t-2) e^(O(t/base)); most of that average is its owna = 0termfill^(2t)/d,970299/101of9803atbase = 100,t = 2, so the average a second moment sees, overanonzero, is(d (fill^t + 2w) - fill^(2t))/(d - 1), smaller again by~ t/baseand980298/4999at the same cell, and the spread is wider than the exponent states rather than narrower. Fromt = 3on at most afill^(2-t)fraction of residues sits near the worst orbit: the bad mass at a pinned divisor is spread, which is what the supremum overrgives up and an average overabuys. Witness: mobius.md digit strings across divisors. - Proved The bisection bound and a level of distribution
x^(alpha/2)for digit strings, up to one factor. For everyFwithfill >= 1, everyd >= 2coprime tobase, everylevel >= 1and uniformly inr,abs(N_F(level; d, r) - fill^level/d) <= fill^(level/2) (1 + 2 base^((level+1)/2)/d): cut the string in the middle and bound each half's variance byfill^b (1 + 2 base^b/d), an off-diagonal congruent pair of length-bstrings needingval(f) - val(f') = j dwith0 < abs(j) <= (base^b - 1)/dand each pair(f', j)fixing at most onef. Summed againstSum_(d <= D) 1/d <= 1 + log Dthis givesSum_(2 <= d <= D, (d,base) = 1) max_r abs(N_F(level; d, r) - fill^level/d) <= fill^level (D fill^(-level/2) + 2 sqrt(base) (1 + log D) (base/fill)^(level/2))at everybase >= 3,level >= 1andD >= 2, everydand not only the squarefree ones, supremum over the target residue and not only the residue0. AtD = x^thetawiththeta <= alpha/2andm = base - fillexcluded digits the whole sum is at most3 sqrt(base) (1 + log x) fill^level x^(m/(2 fill log base)): a levelx^(alpha/2 - o(1))at everythetaup toalpha/2at once, with a defect sub-power inbaseand a positive power inx, the exponent1/(2(base-1) log base)at one excluded digit sitting under0.0011atbase = 100. Atd >= sqrt(base x)the same bound readsmax_r abs(N_F(level; d, r) - fill^level/d) <= 3 fill^level x^(-alpha/2), asking nothing ofFat all. The defect is the pair count's own overshoot2 (base/fill)^bover its meanfill^(2b)/dat the balanced depthb = level/2, and no cut point removes it. Witness: mobius.md digit strings across divisors. - Proved The assembled level-of-distribution theorem for digit strings, and the one family it leaves. Fix
eps in (0,1)and an integerT_0 >= 2and putbase_0(eps, T_0) = max(4^(1/eps), base_1)withbase_1any base satisfying3 base_1^(-eps)/log base_1 <= eps/(16 T_0). For everybase >= base_0, everyF = {0..base-1}minusEwith1 <= m <= base^(1-eps)/2, everylevel >= max(6 T_0, 4/eps)andx = base^level: at every levelD <= xthe sum ofmax_r abs(N_F(level; d, r) - fill^level/d)over2 <= d <= Dcoprime tobasewithd <= base^(1-eps)orord_d(base) <= T_0is at most(T_0 + 2)(1 + log x) fill^level x^(-eps/(8 T_0)); at levelx^(alpha/2)the full sum is at most3 sqrt(base) (1 + log x) fill^level x^(m/(2 fill log base)); everydcoprime tobasewithsqrt(base x) <= d <= xhasmax_r abs(N_F(level; d, r) - fill^level/d) <= 3 fill^level x^(-alpha/2); and at one excluded digit the full pinned moduli are damped together bylevel fill^(2 - sqrt(2 level)) e^(4 level/base) fill^level, superpolynomial inlevel, worst att ~ sqrt(2 level), and never a fixed power ofx. No clause asksdsquarefree and every clause is a supremum over the target residue. One family survives at a fixed level, the generic-order middle modulibase^(1-eps) < d <= x^thetacoprime tobasewithord_d(base) > T_0, where only the level-alpha/2clause applies and its single factorx^(m/(2 fill log base))is the whole distance to a fixed power; that factor is the wraparound overshoot shared by the pair-count certificate, the orbit moment and the additive large sieve over the Farey points, and no rearrangement of cuts, Cauchy-Schwarz or divisor bookkeeping tried here removes it. Witness: mobius.md digit strings across divisors. - Proved The uniform geometric bound summed over a divisor range is microscopic:
D exp(-8 level/(fill^2 D^2)) < 1fails pastD ~ sqrt(level)/fill, so it certifies a level of that size and nothing like a power ofx. Witness: exact arithmetic on the geometric bound of mobius.md DIGIT STRINGS ACROSS DIVISORS. - Proved No moment past the second helps at a pinned divisor: at
d = base^t - 1the2r-th orbit moment isdtimes an additive energy of length-tstrings, and the pair-count certificate places it a factor4 (base/fill)^(r t)above its own meanfill^(2 r t)/d, a loss growing inr. Witness: the orthogonality and bisection bullets of mobius.md DIGIT STRINGS ACROSS DIVISORS, lab/rs/rho-decoupling. - Proved The signed Type I weight is itself a Mertens-type sum: with
T_level(d) = N_F(level; d) - fill^level/dandP_level(e)the primitive frequency sum,sum_{d <= U} mu(d) T_level(d) = sum_{e >= 2} (mu(e)/e) M_e(U/e) P_level(e)withM_e(y) = sum_{f <= y, (f,e) = 1} mu(f)/f, somu(e)fixes only the sign and the signed route restates the wall one layer down. Witness: Mobius inversion over reduced denominators, carried out in the sentence that prints it. - Refuted Any bound on
M_e(y)uniform ineand tending to zero iny: at the primorialeof all primes up toPandy = Pthe onlyf <= ycoprime toeisf = 1, soM_e(P) = 1exactly. Witness: that witness, exact. - Proved No clause in the supremum norm is a fixed power of
x, and clause (iv) is not slack: at one excluded digit andbase >= 10,d = base^t - 1witht = ceil(sqrt(level))carriesmax_r abs(N_F(level; d, r) - fill^level/d) >= fill^level x^(-O(1/sqrt(level)))by the two-sided orbit law and the second moment across residues, so the sum over2 <= d <= x^thetais at least that at every fixedtheta > 0and everylevel >= max(9, 4/theta^2). Witness: the two-sided pinned orbit law of mobius.md DIGIT STRINGS ACROSS DIVISORS, lab/rs/rho-decoupling. - Proved The wraparound defect is circular and not loose: with the pair-count certificate alone both halves of a cut need
base^b <= d, sob <= 2 log_base dand the certificate reads3 d^(1 - alpha) > 1, while winning asks the depthb ~ (2/alpha) log_base dat whichfill^b ~ d^2strings meetdclasses and equidistribution there is the statement being proved. Witness: the bisection certificate of mobius.md DIGIT STRINGS ACROSS DIVISORS.
Dimension one
- Proved The burst certificate moves the pincer's top edge to
0.6402122unconditionally: when3^kdivides a ray coordinate (div) or the coordinate sum (opp), the branching type of a carry state is predeterminedksteps ahead and the two digits of a 2-branching state force distinct types exactlyksteps downstream, so admissible paths inject into the subsets of{1..w}avoiding distance exactlyk, a Fibonacci product bounded byphi^(w+k)and attained on the shifts(9,1)and(27,1), hencerho <= phifor every primitive ray, one certificate for the infinite family with no computation; the opp designation rule at states whose predetermined window hits the dead type is fixed by a digit-order tie rule never consulted in the argument, the div ray count is per orientation with constant 61.6 rather than 600, and the edge rounding0.640212sits1.9e-7on the unsafe side. Witness: lemma-b-pincer. - Proved Theorem R: the second moment
Z(n) = sum_y M_n(y)^2over primitive rays satisfyingZ <= C 3^(gamma n)closes everybeta > gamma/2, with1/2the method's own wall since the diagonal alone forcesZ >= 3^n;Z(n)decomposes exactly as diagonal plus multiplier triples(s, t, z)withQ_n(1, 3^j)in closed form,Z/3^npeaks at2.676455atn = 10and falls monotonically to2.226210atn = 18(limit 2 conjectured, which would shrink the window to(0.4475978, 1/2]); directions are reduced from the origin per point, never as pairwise displacements, the six-digitx_j + y_j <= 2construction is a different6^ngasket and notG_n, and the 1D coprime pairs of the{0,1}base-3 Cantor set (Z/4^n -> 0.513358) are a different object. Witness: lemma-b-pincer. - Proved Two named ways past
0.6402122are shut: keeping the exact Fibonacci burst productD_k(w) = prod_r F_(m_r + 2)cannot lower the octave exponent, since atk = 1alreadyD_1(w) = F_(w+2) = Theta(phi^w)while the depth-one octave-jcensus is at most a constant times3^(2j-1), reproducingpsi_phi(c) = 2c + (1 - c) log_3 phiandbeta = 1/(2 - log_3 phi); and averaging spectral radii cannot replace the supremum, since ray mass is governed byrho^wand Jensen givesint rho^w dnu >= (int rho dnu)^w; the height-40 catalogue (486 primitive non-shift rays plus the shifts(1,3), (1,9), (1,27)) has meanrho = 1.0228285, median 1, standard deviation0.0907378, inverse-square-weighted mean1.0639086(a34.25%deficit belowphi,1.0481989if(1,1)were wrongly counted as a shift) and certified weighted upper mean1.0997454, and substituting them into(2 - log_3 lambda)^(-1)yields0.5145062, which is not a coprimality bound and must never be quoted as one; the inverse-square weight is a probability measure only after a height cutoff sincesum 1/(a^2 + b^2)diverges logarithmically, and the shifts are removable because their count isO(1)per octave. Witness: lemma-b-pincer. - Verified Paley-Zygmund, Bonferroni and Cauchy-Schwarz on the first two Fourier moments are structurally unavailable for the dimension-one lower edge: Paley-Zygmund lower-bounds the heavy rays while the proof needs an upper bound on the total bad mass
sum_y M_n(y); Bonferroni needs the signed intersection countsT*_pq, T*_pqr, ...with no uniform estimate over the exponentially growing modulus range; and(sum_t F_a(t))^2 <= p^2 sum_t F_a(t)^2is an upper bound on the first absolute moment, the direction the ladder already uses, soM_1^2/M_2cannot improve0.4479; the cap0.447930987882is purely the absolute-Fourier-moment wall from the low-frequency peakE_2K >= 3^((2K-2)a)/K^2, forcingkappa_2K < 2at every finiteK, not a Cauchy-Schwarz artifact and not Mobius truncation (which needs the separate tail controlA_z(n) - A(n) <= G(n)/log z, divergent at dimension one); no universal cap holds for "any moment-based method", since a complete moment sequence determines the distribution. Witness: lemma-b-pincer. - Verified Higher Fourier moments cost polynomial time in the moment order: once the carry transfer matrix is built,
E_2K(G_a) = (M_K^a)_{0,0}, polynomial in the levelaby matrix powering; the bounded carry radius is aboutK/2, givingS_K = (2 c_K + 1)^2 = O(K^2)states, and the naive construction is aboutO(K^6)operations before bit complexity, with9, 25, 25, 49, 49, 81states at orders6, 8, 10, 12, 14, 16; exact characteristic-polynomial algebra still grows with integer size, and a numerical Perron root is not a master inequality. Witness: lab/rs/dimension-one-ladder. - Verified The multiplier pairs have a spectral gap at 2:
lambda(s,t) = 3only on the shift pairs(1, 3^j)and their reverses, every other coprime pair obeysP_w <= (3/2)^K 2^wat every state withK = v_3(st) + v_3(t' - s'), and the interval(2, 3)is empty over the certified domainmax(s,t) <= 52only, universality being the lane's open con:gap and no theorem; aligned 3-way splits land their penalty exactlyksteps later, givingG_m = G_(m-1) + 2 G_(m-2)with Perron root exactly 2 at(1,4)(P_w = (2^(w+2) + (-1)^(w+1))/3, characteristic polynomiallambda (lambda - 2)(lambda + 1)); over all 829 coprime unordered pairs withmax(s,t) <= 52, 20 non-shift pairs attain 2 and the largest non-shift radius below 2 is1.6956207695598for the gasket-digit automatonAbut1.8488475886485for the free-digitBthe census actually needs, on(4,13), (4,39), (12,13), (13,36); the 9-divisible classes(9,2), (2,9), (18,1), (1,18)havelambda = 1; the closest ratios to the bound are0.8888893at(3,4),(3,7),(1,12)and0.8888887at(1,4),(1,7); the gap means no radius strictly between 2 and 3, not a gap below 2, and alone gives onlyE <= C 9^n. Witness: gasket-ray-machine. - Verified The heavy gasket rays carry named run-length counts:
M_n(3,1) = F(n+1) - 1, the Fibonacci productprod_r F(m_r + 2) - 1at(3^j, 1), Narayana's cowsA000930(n) - 1at the supergolden ray(1, 12), andc(n-3) - 1withc(m) = c(m-1) + c(m-4)at(7, 3), exact ton = 140(M_140(3,1) = 131151201344081895336534324865,M_140(1,12) = 106502839316458556100416,M_140(7,3) = 21561294536157802712);M_14(7,3) = 49 = 7^2is a coincidence,x^4 = x^3 + 1being irreducible and the quartic sequence square only atn = 4, 7, 9, 12, 14(1, 4, 9, 25, 49) throughn = 140;max M_13 = 376 = F(14) - 1. Witness: gasket-ray-machine, A000930. - Proved Codes 98, 140, 266 and the fourth permutation design
{(0,2),(1,1),(2,0)}(code 84 under the3a + bindexing) are diagonal:Z_F(n) = 3^n - 2for everyn >= 1(the identity fails atn = 0, where the sides are 0 and-1), no two distinct points ever collinear with the origin, by a 3-adic cross lemma: weights all in one unit residue class mod 3 against weights injective mod 3 pin the cross determinant's valuation to the first differing digit position; the three named codes are the permutation graphsj -> j+1,j -> j+2and the swap of 0 and 1, so the lemma has instances and not separate proofs; for these designs ray mass is ray occupancy and the window problem is pure divisor rarity. Witness: gasket-ray-machine. - Conjecture Occupancy is the one door left in the
1/2wall: the Cauchy-Schwarz bound saturates atbeta = 1/2against the trivial ray count, but occupied rays number only3^(0.5416 n)to3^(0.5798 n)at the critical band against the trivial3^nunder the pinned threshold reading,n = 10..18(the earlier band0.543to0.557does not reproduce), every occupied ray has exactly one coordinate divisible by 3, and Theorem R+ closes the entire window under Conjectures Z and O while every bootstrap from Z to O collapses to the trivial fixed point; minimal witnesses are not unique (four tied rays atn = 12, repaired by a least-multiplier tie-break) and prefix-newness is necessary but not sufficient, overcounting occupied rays by a stable1.51x. Witness: gasket-ray-machine, lab/rs/dimension-one-ladder. - Conjecture Higher ray-mass moments make the Holder conversion strictly worse, capping the ray power-moment route at the second-moment edge
1/2: atn = 12the 345318 occupied rays haveS_1 = 523250,S_2 = 1374038,S_3 = 46380938,S_4 = 8145428822, maxM = 232, and the Holder boundS_1 <= N^(1 - 1/r) S_r^(1/r)overshoots by factors1.316, 3.380, 8.179atr = 2, 3, 4, because Fibonacci-heavy shift rays dominate the high moments (phi > 3^(1/(2K))at the critical half-scale); the laddern = 8..12lists occupied rays3904, 12170, 37298, 113836, 345318with maxM33, 54, 88, 143, 232. - Proved The pincer at dimension one: Lemma G, the gasket case of Lemma B, hence all 36 lines by the reduction above, holds at level
nfor every prime exponentbeta = log_3(p)/nbelow0.4475978and above0.6402122: below by exact gasket moment identities (carry-free additive energy exactly15^a, 6th, 8th and 10th moment growths the exact algebraic numbers57 + 6 sqrt(46),456 + 3 sqrt(11017)and the largest root ofx^4 - 7833x^3 + 7916949x^2 - 850684437x + 13054946580from nine- and twenty-five-state transfer matrices) fed through a Holder ladder that never usesord_p(3), above by the ray decomposition (fibres2^(n+1) - 2, shift rays at most2n phi^n, every carry state of every primitive ray at most 2 admissible digits) with the regime bookkeeping on the trichotomy ofnagainst3aand4a,a = floor(log_3(p/2)), which closes the belt of primes nearp ~ 3^(n/3); the ladder saturates at2/(3 + log_3 5) = 0.447931 < 1/2and per-ray-maximum methods stop at1/2; the master bounds hold against exactL_n(p)for every prime5 <= p <= 199; the eighth rung0.446717is the row the shelf lane still imports and is now one row stale. Witness: lemma-b-pincer, lab/rs/dimension-one-ladder. - Proved The tenth rung of the moment ladder moves the bottom edge to
0.4475978(beta_0^(10) = 0.4475978134...), leaving the standing window(0.4475978, 0.6402122]with both edges unconditional; the eighth rung at0.446717is now only a table row. Witness: lab/rs/dimension-one-ladder. - Proved Conjecture O has no content below
alpha = 1/2- the rays of height at most3^(alpha n), occupied or not, number at most3^(2 alpha n)under the threshold reading and9 * 3^(2 alpha n)under the octave cut, so the box alone givesdelta = 1 - 2 alphawith no occupancy input, and the whole conjecture lives inalpha in [1/2, 0.5533]. Witness: lab/py/occupancy-decay. - Proved The first moment of occupancy is the window itself, so no proof of O may pass through it - with
F(n, X)the non-fibre gasket points of primitive height at mostX,Sum_{p > 3^(beta n)} N_n(p) <= (F(n, 3^((1-beta) n)) + 2^(n+1)) / betaat target zero, each suchxcarrying at most1/betaprimes above3^(beta n); a first-moment bound atalpha > 0.3597878moves the standing window and atalpha >= 0.5524022closes it with no Conjecture Z, and the inequality holds with ratio0.0846to0.1517against the sieved prime sum atn = 10, 12, 14,beta = 0.45, 0.5, 0.6. Witness: lab/py/occupancy-decay. - Verified Occupancy pays no exponent for the multiplicity, so O carries the full weight of the window and is no cheap half of Theorem R+ -
F/Aatalpha = 0.5533reads5.41, 5.20, 5.52, 5.64, 5.63, 5.86, 5.79, 6.08, 5.92atn = 10..18whilelog_3 F / nfalls0.7645to0.7201againstlog_3 A / ninside[0.6109, 0.6345], the exponents converging atlog(F/A)/(n log 3); only at fixed height do the shift rays split them,A(n, 3^5) = 384 .. 474againstF(n, 3^5) = 2728 .. 51694. Witness: lab/py/occupancy-decay. - Verified The digit-congruence seed is measured out as a route to O - the proved bound
A(n, X) <= 2 sigma_k X^2 + 2 sigma_k 3^k X + 2 X^2 3^(-k) + 3^k + 2 Xfor3^k <= Xcollects every digit-class constraint, the mod-3 dichotomy beingk = 1, butsigma_k = |R_k|/3^kfalls only polynomially throughk = 18,|R_k| = 73440, 206149, 580920, 1643545, 4663382, 13272515atk = 13..18with growth rising2.794to2.8461andk(1 - log_3 growth)inside[0.8418, 0.8628], so the route buysn^(-0.86)and no exponent; on the measured hypothesisM_2(k) = O(4^k)(M_2/4^k = 0.4098, 0.4077, 0.4071, 0.4029atk = 13..16, still falling) Cauchy-Schwarz caps any congruence-only decay atc = 0.2618596,alpha = 0.575328, excluding neither0.5533nor0.5524022, and no exponential floor is proved either way. Witness: lab/py/occupancy-decay. - Verified Occupied non-fibre ray totals
1044840, 3151656, 9491964, 28545340atn = 13, 14, 15, 16from a second builder, two below the earlier totals at every level, exactly the two fibre rays. Witness: lab/py/occupancy-decay, lab/rs/dimension-one-ladder. - Proved The golden ceiling
M_n(z) <= F(n+1) - 1holds for every direction of the 13158-box at every level, promoted from an enumeration ton <= 40- in the direction coordinate a multiplier word is a word over the increments{0, z_2, -z_1}summing to zero, its carry automaton has out-degree at most 2 with the branch states in one residue class mod 3, and the two successors of a branch state differ byq/3for the uniqueqin{z_1, z_2, z_1+z_2}divisible by 3, so when no branch state has two branching successors (in particular whenv_3(q) = 1) the state maximum obeysG(n) <= G(n-1) + G(n-2)and the ceiling follows; that settles 206 of the 218 occupied directions, 107 byv_3(q) = 1, three of the twelve left are shift rays closed byF(p+2) F(q+2) = F(p+q+3) - F(p+1) F(q+1), and nine carry rational Fibonacci certificates of denominators 18, 40, 381, 18, 2013, 18, 40, 2013, 34. The hypothesisz_1, z_2 >= 1is load-bearing: on the fibre ray(0,1)two digits share the increment0, a set-valued reading sees no branch state, andM_6(0,1) = 63againstF(7) - 1 = 12. Refutation attempt: ground truth rebuilt independently from the ray definition for 20 directions including all twelve hard ones, zero mismatch; all nine certificates re-verified in exact rational arithmetic with domination checked ton = 60; the box census, the renewal criterion, the(1,9)profile, the weight bound and the-1path accounting all recomputed exact. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved The whole case list collapses into one algebraic inequality per direction. Weight the first returns of the direction automaton by
phi^-1a step: withg(c,m)the paths from a live statecto the start meeting it only at the end,u(c) = Sum_m g(c,m) phi^-mandU(z) = Sum u(c')over the start's successors other than itself, soSum_{j>=2} f_j phi^-j = phi^-1 U; anypi > 0withSum_succ pi <= phi pi(c)at every livec != 0andSum_(c' != 0 succ 0) pi(c') <= phi^-2 pi(0)forcesU(z) <= phi^-2by a maximum principle on the truncated sums, and thenM_n(z) <= F(n+1) - 1at everynby renewal against the envelopephi^(m-2) <= F(m) <= phi^(m-1), withpi = uadmissible as soon asU(z) <= phi^-2. It proves 45 directions no earlier case reached, the nine hand-tuned rational certificates and the 36 that rested on enumeration alone;3 nmid z_1 z_2givesM_n = 0outright, settling 6566 box directions on residues against 3284 before;f_1 = 1always andf_2 = 1only at{a,b} = {1,3}, both from the increments. Refutation attempt, briefed to break it: the proof read line by line for convergence, normalisation,S = phi^-1 Uand both envelopes; an independentQ(sqrt5)rebuild reproduced every count (218 occupied and 214 passing in the box with the four shift-ray failures, 647 and 644 outside it with three, 865 and 858 in total with seven, 57 distinctUvalues, the exact attainers); a600 x 1800box census with 3866 occupied directions, 4.5 times the shipped range, plus 19681 stressors including 52 in the openv_3(q) >= 2ground, found failures only at shift rays; and every shipped solve is confirmed strictly positive and against both criterion inequalities, not merely against the linear system. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Verified The golden potential misses exactly the shift rays and, on every censused range, nothing else:
U(1,3^j) = phi^-1exactly because the shift mass grows at ratephi,U = phi^-2only on the supergolden(1,12),(3,10),(4,9), and no direction of any range censused hasUin the open interval(phi^-2, phi^-1)- the box, the six adversarial families, a 36037-direction lab sweep with high-v_3stressors, and the independent600 x 1800recompute. The gap is empirical only: a legal-looking first-return profilef_3 = f_5 = 1givesS = 0.3262inside it, so nothing arithmetic excludes the interval and the observation is never a theorem. The open conjecture isU(a,b) <= phi^-2for every non-shift primitive direction, which with the theorem and the Fibonacci product identity is the whole golden ceiling. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved
M_n(z) <= D_n(z_1 + z_2), Conjecture W's owed first move, in one line - disjoint binary supports makem(z_1+z_2)binary below3^nandm -> m(z_1+z_2)injective - and it is the wrong half:D_n(w)grows at rate 2, notphi, reading4196351, 1683971, 613817, 228519atn = 24,w = 4, 10, 28, 82against the ceilingF(25) - 1 = 75024, so the weight enters only through the constant. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved
gasket-ray-machinestatedM_n(a,b) = (T^n)_{00}where its own proof givesM_n(a,b) + 1closed paths; corrected to(T^n)_{00} - 1, and the carry bound|c| <= max(a,b)sharpened tocin[-a/2, b/2], which ties the live state count to the witness weight atfloor(a/2) + floor(b/2) + 1. Witness: gasket-ray-machine. - Refuted The occupancy band
3^(0.543 n)to3^(0.557 n)atc = 1/2- it reproduces under no cut convention atn = 12..15, the threshold reading giving[0.5416, 0.5798]overn = 10..18and the integer octave cut giving the paired readings0.5249 / 0.6052atn = 13; the band was stale, not a convention difference, and the adversarial pass that killed it also killed a pruning bug in the new census,A(9, 3^7) = 1176printed where the truth is2818, the tracked-direction cut sitting below the requested threshold, now pinned as a regression. Witness: lab/py/occupancy-decay, lab/rs/dimension-one-ladder. - Refuted The state maximum
G(n) = max_c N(c,n)does not obeyG(n) <= G(n-1) + G(n-2), so the branch argument does not extend tov_3(q) >= 2- at(1,9)the profile runs1, 1, 1, 2, 4, 6, 9andG(4) = 4 > G(3) + G(2) = 3, and 8 directions of the box break it, every one withv_3(q) >= 2; the sharp reformulation is the renewal criterionSum_{j>=2} f_j F(n+1-j) <= F(n-1)on first-return counts, withf_1 = 1always andf_2 = 1only at(1,3), holding on all 218 occupied directions ton = 46, bothffacts now proved from the increments and the whole criterion subsumed by the golden potential throughSum_{j>=2} f_j phi^-j = phi^-1 U. Witness: lab/py/gasket-witness-weights. - Refuted The ceiling's adversarial family census double-counted: the six families overlap, the no-adjacent-ones family sitting inside the binary one, so the shelf's
11369coprime members are10862distinct directions,717already in the box and10145genuinely further, of which9498carry no mass,608fall to the branch argument and3are shift rays, leaving36on the enumeration alone and not the70first claimed; the same overlap inflated the lab's widened sweep from23435distinct to24088with multiplicity. The36hold ton = 60, worst ratio below0.1516, and are now proved outright by the golden potential, so no direction of the six families rests on enumeration alone. Witness: gasket-ray-machine, lab/py/gasket-witness-weights.
Divisor avatars
- Proved The Avatar Theorem: for
x = prod p_i^(a_i)withp_1 < ... < p_dimand everya_i >= 1, thedim-axis design withf_w = e_w(a_1 - 1, ..., a_dim - 1)hasP(n) = d(x^n)at everyn >= 0, by the substitutiona_i n + 1 = b_i n + (n + 1)andprod (b_i t + 1) = sum_w e_w(b) t^watt = n/(n+1); the map is injective by Newton's identities and surjective onto thef_0 = 1signatures whose fill splits completely into linear factors overQ, and a design exists iffsum_i (a_i - 1) <= dim; the first ten colossally abundant numbers2, 6, 12, 60, 120, 360, 2520, 5040, 55440, 720720have avatars while the first without one is21621600; on the sevendim = 3laddersx = 30, 60, 120, 180, 240, 360, 900ton = 20, all 131 of the 140 powers exceeding 5040 satisfy Robin's inequality, the largest ratioR(14400) = 1.5732599059againste^gamma = 1.7810724180, margin0.2078125121, strictly decreasing innon every ladder, which proves nothing about Robin beyond them;sigma(m)/m < sigma(N)/Nfor everym < Ndefines a superabundant number, not a highly abundant one. Witness: divisor-avatars. - Proved The sigma-hunt is closed negatively for polynomial census laws: no census law of a design at odd side
2n + 1equalssigma_k(x^n)fork >= 1,x > 1, since that grows at least likex^(kn)while every such law is a polynomial innof degree at mostdim, and none equalssigma(x^n)/x^n, strictly increasing and bounded hence not constant; atx = 1both collapse to the nine constant identitiesO(n) = 1 = d(1^n); over the nine observables (fill, voids, surface, touched vertices, edges, faces, Euler characteristic, components, cycle rank) on all 22 least-mask representatives of the 256 base-2 3D designs counted through side 21, exactly eight non-fill strict divisor avatars survive, only for voids, Euler characteristic and components;EandRvanish atn = 0whiled(x^0) = 1, so they are never strict identities, and the four graph laws for codes 30 and 126 hold only forn >= 1; ifsigmais a design observable at all it lives among geometrically growing counts. Witness: divisor-avatars. - Verified The eight non-fill divisor avatars come from topology, not measure: the empty design's voids
(2n+1)^3 = d(900^n); Euler characteristic and components both(n+1)^3 = d(30^n)for{000}; both(n+1)^2 = d(6^n)for{000, 100}; componentsn + 1 = d(2^n)for the three-corner path{000, 100, 010}; bothn + 1 = d(2^n)for the square face{000, 100, 010, 110}; plus nine constant identitiesO(n) = 1 = d(1^n), components for codes23, 27, 31, 61, 63, 111, 127, 255and Euler for 255; the statement is for the canonical least-mask representatives, since cube symmetry does not preserve the odd/even origin under coordinate reversal; codes 15 and 27 share a weight signature and a fill law, so eight orbits carry seven weight signatures. Witness: divisor-avatars.
Exposure
- Proved The exposed faces of a design's level power obey
V(level + 1) = occ V(level) - 2 sum over the axes of P S^level, withoccthe tile's filled cells,Pits adjacent filled pairs along the axis andSthe cross positions whose two end cells are both filled, because two adjacent blocks bury one face per spanning position and the spanning positions multiply bySa level; soV(level)is a sum of the powersocc^levelandS^levelin every dimension, the carpet perimeter closes as(4*8^level + 16*3^level)/5(A381517) and the sponge surface as2*20^level + 4*8^level(A332705), and all four counts fold from the residue corners without rendering the tile. Witness: mrlymath::formulas::surfaceprediction_matches_census_on_every_cube_codeandthe_corners_fold_what_the_tile_shows, sequences.
Farey stack
- Verified The odd-carpet stack renders an RH-equivalent object and no route to a proof: the lit nodes are exactly the Farey fractions, each scale
ncontributingphi(n)new nodes, their discrepancy is the object of the Franel and Landau 1924 theorems, and the measuredS2 * Qflattens near0.656(0.6560at 2000,0.6564at 8000) with the local exponent walking to-1. Witness: mrlynum::lattice::new_nodes, lab/rs/farey-discrepancy. - Proved The stack is an address, not a construction: the odd-carpet stack's brightness at
x = (a_1/q, a_2/q)is the residue countB_N(x) = ceil(N/2) - sum_{r in S(x), r <= N} (floor((N - r)/(2q)) + 1)over the bad residues mod2q, per-point cost independent ofN, and the line stack's isfloor(N/b); a stack of5 * 10^17layers,N = 10^18, evaluates exactly in a tenth of a second, and atN = 55the Farey table holds 940 nodes summing to1540 = N(N+1)/2; the closed form's proved boundaries are per-point only (anR x Rraster costsR^2), exact representations only (a real-oracle input is undecidable on{n x integer}, irrationals with known continued fractions stay computable via Ostrowski), finiteNonly (infinite-depth membership is undecidable) and unweighted only. Witness: lab/py/carpet-stack-address, mrlynum::lattice::farey. - Verified Immediacy buys no RH content: the Mobius-weighted node is the Mertens-type sum
Sum_{k <= N/b} mu(kb), equal toM(N)atb = 1and toM(floor(N/b))at only 64 of 200 denominators atN = 200, with no polynomial-time algorithm for the Mertens function at binary input and the best known nearx^(2/3); the rank closed formsum_d mu(d) sum_e floor(x e)re-imports Mobius, the meter's global readout collapses tosum_{n <= N} M(floor(N/n)) = 1identically (checked exactly toN = 20000), the divisibility incidence array is the Redheffer matrix up to its first column, and Franel 1924 is already the symbolic all-Qreduction, so the route ends at Mertens. Witness: lab/py/mertens-meter. - Verified The stack's complexity frontier is the sharing of its scales: per-pixel brightness with binary inputs is in P by fixed-dimension lattice-point counting (Barvinok 1994, two parity branches summed), destroying the shared scales makes "does any point reach maximum brightness" NP-complete (Simultaneous Incongruences, Garey and Johnson SP3), and making the ambient dimension part of the input makes "is any layer lit at this fixed point" NP-complete (Lagarias 1985) while polynomial at every fixed dimension, so a no-shortcut theorem for this stack could never separate P from NP;
d(n)is not factoring-hard by thesigmaroute (sigma(pq) = pq + p + q + 1recovers the factors whiled(pq) = 4carries nothing), and theO(q)residue sweep is polynomial in the denominatorq, hence a unary-input algorithm. Witness: REFS.md. - Conjecture The Baez-Duarte coefficients
c_k = sum_n mu(n) n^{-2} (1 - n^{-2})^k = sum_{j=0}^k (-1)^j C(k,j)/zeta(2j+2)from an independent Mobius sieve ton = 10,000read-0.316011506atk = 1to-1.68003e-5atk = 1000against a 450-digit reference-1.65958e-5, difference2.04521e-7; the sieve agrees with the test vector[1,-1,-1,0,-1,1,-1,0,0,1]and with a second linear sieve at every integer through 10,000, counts3053minus-ones,3917zeros,3030plus-ones; consistent with the criterion and evidence for the Riemann hypothesis of exactly nothing. - Conjecture
S_N = sum_{k=1}^N (-1)^k C(N,k)/zeta(2k)is not a Riemann-hypothesis criterion tending to zero: it has the wrong zeta shift, omits thej = 0term and tends to 2 -S_100 = 1.843329,S_500 = 1.967518,S_1000 = 1.983699; the sequential Baez-Duarte coefficient isc_k = sum_{j=0}^k (-1)^j C(k,j)/zeta(2j+2), the Nyman-Beurling distanced_N = inf ||1 - D_N||^2is not the coefficient sequence and needs its own basis and Gram matrix,sum_{j | k} mu(j)is the Mobius inversion identity (1atk = 1,0after), and direct binomial evaluation at 80 digits is nonsense byk = 500, so 450-digit arithmetic or the Mobius series is required. - Conjecture Under the convention
Q = 3^levelthe Landau discrepancy reads0.166667, 0.549206, 1.150760, 2.118500, 3.187070atQ = 3, 9, 27, 81, 243, computed in exact rationals by two routes that agree;D_Q/sqrt(Q)stays in[0.0962, 0.2354]and the last-three log-log slope is0.464, consistent withO(Q^{1/2+eps})and discriminating nothing, since five nested deterministic points cannot test a statement quantified over every positive epsilon. - Refuted Stack brightness encodes the Mobius function, so a Baez-Duarte meter can replace the Franel table - neither brightness carries factorization data: the Farey stack gives
B_Q(a/b) = floor(Q/b), 199 distinct values for the 10,000 denominators atQ = 10,000, every denominator from 5,001 to 10,000 sharing brightness 1 whilemuruns-1, 0, +1; the gramstack gives1 + K(a/b)withK = (-1)^a/b^2for oddbandK = 0for every evenb, so all even denominators coincide; joining a node to a factorization through its denominator puts the arithmetic in the factorization. Witness: lab/py/carpet-stack-address. - Refuted A design's Farey order is determined by its fill count - the stack of grid scales
n = 1..Qlights exactlyF_Q = {a/b : 1 <= a <= b <= Q, gcd(a,b) = 1}with brightnessfloor(Q/b), a boundary coordinatek/nreducing toa/band recurring at every scale divisible byb, checked by literal stacking atQ = 30on all 278 lit fractions; Farey order isQ, fill count plays no part, and every design gives the same sequence at fixedQ. Witness: lab/py/carpet-stack-address. - Proved The Farey sequence restricted to a digit design counts without enumerating a fraction: with
S_Fthe whole numbers whose every base digit lies in the digit set,card {a/b reduced : 0 < a <= b <= Q, b in S_F} = sum_{b in S_F, b <= Q} phi(b)andcard {a/b reduced : 0 < a <= b <= Q, a and b in S_F} = sum_{b in S_F, b <= Q} sum over d dividing b of mu(d) #{multiples of d in S_F up to b}, the second by inclusion-exclusion on the divisors ofb. Witness: lab/rs/farey-discrepancy. - Verified Both restricted counts agree with a Stern-Brocot enumeration at every rung of both ladders, base 3
{0,1}toQ = 3^11 = 177147and base 10 without the digit 9 toQ = 10^5, 45 checks and no failure, the largest being 9538759028 nodes on the full-set control. Witness: lab/rs/farey-discrepancy. - Verified On the strict convention the discrepancy sums ride the node count instead of cancelling against it: the local exponents
e_2ande_1, single ratios between consecutive rungs, agree with the mass exponent to two decimals at both designs,+1.259and+1.262against+1.263at base 3{0,1}and+1.904and+1.906against+1.908at base 10 without 9, while the same lane'sS1/cardholds two figures fromQ = 2187(card4286 to 1080458) at base 3 and fromQ = 10000(card11890654 to 963170938) at base 10, at9.4e-2and5.2e-3, andS2/cardlikewise at1.3e-2and3.6e-5, the base 10 rung below moving the first figure ofS2/cardfrom4.1e-5. Witness: lab/rs/farey-discrepancy. - Proved The strict digit-restricted Farey sequence at base 3
{0,1}misses the closed interval[1/2, 2/3]at everyQ, so it does not equidistribute: a denominator with leading digit at positionLsatisfies3^L <= b <= (3^(L+1) - 1)/2, a numerator with leading digit at the same position givesa/b >= 2*3^L/(3^(L+1) - 1) > 2/3, and one with leading digit atL - 1or below givesa <= (3^L - 1)/2 < b/2, hencea/b < 1/2; the measured widest gap contains that interval at every finiteQand shrinks onto it from outside,0.16827, 0.16720, 0.16684, 0.16673, 0.16669, 0.16667atQ = 3^6 .. 3^11from left endpoints0.49931, 0.49977, 0.49992, 0.49997, 0.49999, 0.50000. Witness: lab/rs/farey-discrepancy. - Conjecture The strict digit-restricted Farey sequence at base 10 without the digit 9 does not equidistribute either, on the settled constants alone and with no interval to argue from: its widest gap falls like
1/Q,0.01136, 0.00113, 0.00011, 0.00001atQ = 10^2 .. 10^5against the control's0.01000, 0.00100, 0.00010, 0.00001, so the base 3 emptiness argument does not transfer. Witness: lab/rs/farey-discrepancy. - Conjecture Restricting only the denominator to a digit design keeps the square-root shape transplanted to that design: with
D_Q = #{b in S_F, b <= Q} ~ Q^alphaandcard ~ Q^(1+alpha), a node-count error of ordersqrt(D_Q)putse_2at-1and capse_1atalpha/2, and the measurede_2reads-0.959and-0.899whileS2*Qreads0.8926and0.8536against the control's0.6782and0.6684andS1/Q^(alpha/2)reads0.243, 0.281, 0.267, 0.268, 0.274atQ = 3^7 .. 3^11and0.213, 0.222, 0.207, 0.265atQ = 10^2 .. 10^5, flat where the control'sS1/sqrt(Q)falls, so the reading isS2 = O(Q^(-1+eps))andS1 = O(Q^(alpha/2+eps)). Witness: lab/rs/farey-discrepancy. - Proved The stack is the Farey resonance diagram up to the floor: normalising the brightness law gives the node
a/bthe heightfloor(Q/b)/Q, which lies in(1/b - 1/Q, 1/b]at every depth and equals1/bexactly whenbdividesQ. Witness: lab/rs/farey-discrepancy.
Fill polynomials
- Conjecture The discriminant staircase is gapless and counts
2(dim-1)new discriminants per dimension: the negative fundamental discriminants (d = 0or1 mod 4) carried by the irreducible quadratic factors of fill polynomials at dimensiondimform a gapless initial segment of lengthdim(dim-1),dim = 2giving-3, -4,dim = 3adding-7, -8, -11, -12for 6,dim = 4adding-15, -16, -19, -20, -23, -24for 12, with 20 atdim = 5, exhaustive over 17424 signatures, gapless to-40; atdim = 6, exhaustive over 1053696 signatures, the peeled-remainder reading is gapless from-3to-63with length 31 and the reading over every irreducible quadratic factor gives length 80 to-160, deepest-899, so thedim(dim-1)count law predicting 30 is Refuted atdim = 6under both readings while the run stays gapless; gapless and unbounded forces every imaginary quadratic order to appear at some finitedim, the geometric content of the imaginary completeness conjecture; exhaustive atdim = 2..6by exact factorization. Witness: lab/py/fill-polynomials. - Refuted Seven
dim = 4fill-polynomial remainders labelled irreducible overQof degree 4 - palindromic signatures(1,0,1,0,1),(1,0,2,0,1),(1,1,2,1,1),(1,2,3,2,1),(1,3,2,3,1),(1,4,2,4,1),(1,4,5,4,1)- split overQinto two centered-polygonal quadraticsk n^2 + k n + 1; rational-root peeling proves irreducibility only through degree 3, and no qualify/fail verdict moves since no factor is linear. Witness: lab/py/fill-polynomials. - Proved The odd-side fill is a product of norm forms, one per irreducible factor of the weight enumerator
W(t) = sum_j s_j t^j: withm = deg WandW = cont(W) prod_i g_i^(e_i)overZ, primitive irreducibleg_i, the fillP(n) = (n+1)^dim W(n/(n+1))is(n+1)^(dim-m) cont(W) prod_i g_i*(n)^(e_i)withg*(n) = (n+1)^(deg g) g(n/(n+1)) = lc(g) prod_theta ((1-theta) n - theta), the norm form ofQ(theta); the constant is the content, never the leading coefficient, and is 1 on the origin-filled box. Exact on all 16, 256 and 65536 designs atdim = 2, 3, 4, in the factored and the resultant form. Witness: lab/py/field-ladder. - Proved The norm form of a factor has the discriminant of the factor: the map
t = n/(n+1)is the Mobius map of[[1,0],[1,1]]inSL_2(Z), soQ(theta/(1-theta)) = Q(theta)anddisc(g*) = disc(g)for every factor withg(1) != 0, which isdeg g* = deg gand is automatic for an irreducible factor of degree at least 2; checked over the 6, 32 and 350 origin-filled signatures atdim = 2, 3, 4, 0 mismatches on the 2, 25 and 343 factor slots of degree at least 2. Witness: lab/py/field-ladder. - Proved The bare product form
P = s_dim prod_theta ((1-theta) n - theta)needs the lift(n+1)^(dim - deg W)on exactly half the designs:deg W < dimiffs_dim = 0iff the all-odd corner is empty, and the complement in that corner is a fixed-point-free involution, so the count is2^(2^dim - 1), which is 8 of 16, 128 of 256 and 32768 of 65536 atdim = 2, 3, 4. Witness: lab/py/field-ladder. - Proved With the origin filled every rational root of
Wis-1/kand every linear factor of the fill is(a n + 1):Whas nonnegative coefficients andW(0) = 1so no factor has a positive real root,Wis primitive with constant term 1 so every irreducible factor hasg(0) = 1, and(1 + k t)* = (k+1) n + 1; this is why the divisor tribe is the all-rational floor and why its factors are never(a n + b)withb > 1, and with the origin empty the law fails, signature(0,2,1)atdim = 2havingW = t^2 + 2tand filln(3n + 2). Witness: lab/py/field-ladder. - Proved The pure quadratic layer realizes exactly the imaginary quadratic fields of discriminant at least
-2 dim (dim-1): the pure signature(1, b, c)with0 <= b <= dimand0 <= c <= C(dim, 2)hasW = 1 + b t + c t^2, fill(n+1)^(dim-2)((1+b+c) n^2 + (b+2) n + 1)and discriminantb^2 - 4con both sides, everyd = 0or1 mod 4in[-4C(dim,2), -1]occurs atb = 0orb = 1and nothing deeper occurs, and dividing out the conductor leaves exactly the fundamental discriminants of absolute value at most4C(dim,2) = 2 dim (dim-1), which is 2, 5, 10, 14, 21 fields atdim = 2..6. Witness: lab/py/field-ladder. - Verified The whole origin-filled box adds no further imaginary quadratic field at
dim <= 6: the imaginary quadratic field discriminants carried by every irreducible factor of every signature are exactly the fundamental discriminants of absolute value at most2 dim (dim-1), so the run is gapless and its first gap is the next fundamental discriminant, 7, 15, 31, 43, 67 atdim = 2..6, exhaustive over 6, 32, 350, 8712 and 526848 signatures. Witness: lab/py/field-ladder. - Proved Amendment to the discriminant staircase row: its
dim(dim-1)count law is exact under the order reading on the origin-filled box, and what needs amending is the gloss "fundamental", since-12 = -3 * 2^2,-16,-20and-24are discriminants of orders and not fundamental. The pure layer gives exactly thedim(dim-1)values0or1 mod 4in[-4C(dim,2), -1], and exactly2, 5, 10, 14, 21fields atdim = 2..6. The two rows sweep different boxes, 1053696 signatures withs_0free against 526848 withs_0 = 1, so-63,-160,-899and-60do not meet:-899sits at the origin-empty(0,0,15,1,15,0,0),W = t^2 (15t^2 + t + 15). Witness: lab/py/field-ladder. - Proved Imaginary completeness holds for the origin-filled box: every imaginary quadratic order of discriminant
dand every imaginary quadratic field of discriminantdoccurs as a quadratic factor of a fill polynomial at everydimwith2D(dim-1) >= abs(d), so at everydimat least(1 + sqrt(1 + 2 abs(d)))/2. Witness: lab/py/field-ladder. - Verified Positive-disc completeness does not follow the imaginary law: the pure layer reaches only
d = b^2 - 4c <= dim^2 - 4on the real side, the census atdim = 6runs 5, 8, 12, 13, 17, 21, 24, 28, 29, 33 and stops at 37 with the last two values coming from signatures of degree above 2, and the real quadratic run is the binding constraint on the degree-2 Hunter bound at every dimension. Witness: lab/py/field-ladder. - Verified The ladder by degree over the origin-filled box: signatures by the top degree of the irreducible factors of
Ware 4 rational and 2 quadratic atdim = 2, 7, 13, 12 atdim = 3, 12, 62, 130, 146 atdim = 4, 19, 266, 955, 3522, 3950 atdim = 5, and 30, 1173, 7305, 45292, 222437, 250611 atdim = 6, exhaustive over the 6, 32, 350, 8712 and 526848 signatures of the box, the last carrying2^63oriented designs; counted by oriented design thedim = 4row is 504 rational, 6884 quadratic, 13241 cubic and 12139 quartic of 32768. Witness: lab/py/field-ladder. - Verified Cubic ownership: every cubic field of absolute discriminant at most 307 is a norm form of a fill polynomial at
dim = 6, the signature(1,1)run being the whole 100-entry table 23 to 815 with no gap and the totally real run 49, 81, 148, 169, 229, 257 stopping at 316, against(1,1)runs stopping at 44, 244 and 652 atdim = 3, 4, 5. Witness: lab/py/field-ladder. - Verified The field-discriminant run of the box stops at a first gap per degree and field signature, reading
dim = 3, 4, 5, 6where the class is nonempty: degree 2 at 15, 31, 43, 67 for(0,1)and 8, 13, 24, 37 for(2,0); degree 3 at 44, 244, 652 and past 815 for(1,1)and 81, 316 for(3,0); degree 4 at 225, 981, past 2156 for(0,2), 400, 1423, 3275 for(2,1)and 1125 for(4,0); degree 5 at 7684 and past 12752 for(1,2), 5783 and past 13883 for(3,1), and nothing at all for(5,0). Witness: lab/py/field-ladder. - Verified The Hunter-type bound of the box: with
B(d, dim)the largest bound such that every field of degreedand absolute discriminant at mostBis reached,B(2, dim) = 7, 12, 23, 35,B(3, dim) = 31, 44, 76, 307,B(4, dim) = none, 189, 697, 1107andB(5, dim) = none, none, 5753withB(5, 6)at least 12752 atdim = 3, 4, 5, 6, the first miss atdim = 6being 37 at signature(2,0), 316 at(3,0)and 1125 at(4,0), while the box heightmax_j C(dim, j)is only 3, 6, 10, 20. The merge is by field:8is two fields and only-8is reached atdim = 3, and a discriminant the table lists twice is credited only on two non-isomorphic factors. Witness: lab/py/field-ladder. - Proved No field signature is excluded by the sign condition: no irreducible factor of
Whas a positive real root, and for any fieldKwith generatorgammathe elementtheta = -1/(gamma + N)withNabove every real conjugate generatesK, has all real conjugates negative and has1/thetaan algebraic integer, so its primitive minimal polynomial meets both conditions a factor ofWmeets. Witness: lab/py/field-ladder. - Verified The totally real classes are the sparse side of the ladder: signature
(3,0)first occurs atdim = 5with the single field 49,(4,0)atdim = 6with the single field 725, and(5,0)does not occur atdim <= 6, the smallest totally real quintic field being 14641. Witness: lab/py/field-ladder. - Verified Every field discriminant of the census is computed by PARI
nfdiscon the reversed monic model and guarded against the polynomial discriminant, which must be a square multiple of it, and against0or1 mod 4: all 256179 distinct irreducible factors of degree 2 to 5 overdim = 2..6pass, so no run rests on an unchecked value and no factor is unresolved. A run counts discriminants, since two fields can share one, the first repeat inside a printed run being 576 twice in degree 4 signature(0,2); the Hunter bounds are lifted to fields bynfisisom. Witness: lab/py/field-ladder. - Conjecture Every number field appears at some finite
dimand its discriminants arrive in order: the boxs_0 = 1,0 <= s_j <= C(dim, j)reaches every field of degree 2, 3, 4 of absolute discriminant at most 35, 307, 1107 atdim = 6and every quintic field of the tables read, to 12752, each a gapless initial run, and the two necessary conditions on a factor, constant term 1 and no positive real root, are met by a generator of every field. Witness: lab/py/field-ladder. - Refuted The swap clause, that when one side factors completely over
Qthe other carries an irreducible factor, forbids theP+ V+cell alone, and that cell is not empty: over origin-filled oriented designs the table by fill split and void-core split reads 17, 4, 67, 40 atdim = 3and 413, 91, 4994, 27270 atdim = 4, so0.13of the designs atdim = 3sit in the forbidden cell, the smallest on corners000and001with fill(n+1)^2 (2n+1)and void core(2n+1)(3n+2). The exception class was already named with the clause; the count is the news, and theP- V-cell is not forbidden. Witness: lab/py/field-ladder. - Proved The sponge rule, keep a cell with at most one odd coordinate, is the signature
(1, dim, 0, ..., 0)and fills(n+1)^dim + dim n (n+1)^(dim-1) = (n+1)^(dim-1)((dim+1) n + 1)at odd side2n+1, a product ofdimlinear factors of exponent pattern(dim+1, 1, ..., 1), henced(x^n)forx = 2^(dim+1) 3 * 5 * ... * p_dim, the tower4, 24, 240, 3360atdim 1..4, withn = 1column(dim+2) 2^(dim-1)= A001792. Witness: lab/py/field-ladder, divisor-avatars. Claims heading: Divisor avatars. - Verified The
Qcolumn of the ladder over the origin-filled box,4, 7, 12signatures atdim 2, 3, 4, is in bijection with the exponent patterns ofprod_i (a_i n + 1)under the avatar map, so the rational floor is named integer by integer:30, 60, 120, 180, 240, 360, 900atdim 3and210, 420, 840, 1260, 1680, 2520, 3360, 5040, 6300, 7560, 12600, 44100atdim 4, and it is closed under products. Witness: lab/py/field-ladder. Claims heading: Divisor avatars. - Verified At
dim 3the signature(1,3,1,0), the sponge with one weight-2 corner added, hasW = 1 + 3 t + t^2of discriminant5and fill(n+1)(5 n^2 + 5 n + 1), the norm form of the real quadratic field of discriminant5. Witness: lab/py/field-ladder. Claims heading: Fill polynomials. - Verified Over the 350 origin-filled signatures of the box at dim 4 the 6884 quadratic oriented designs split into 6518 imaginary, 105 real and 261 mixed, carried by 55, 4 and 3 signatures. Witness: lab/py/field-ladder verb ladder.
- Verified Over the 8712 origin-filled signatures of the box at dim 5 the 2147483648 oriented designs read 1209703 rational, 102969641 quadratic (92090824 imaginary, 85372 real, 10793445 mixed), 213022933 cubic, 956166567 quartic and 874114804 quintic by top irreducible factor degree. Witness: lab/py/field-ladder verb ladder.
Flake band gap
- Verified The base-2 flake's Laplacian has an interior band gap whose upper edge is exactly 4: on the
bang dim 3, code 23flake (4^levelnodes,4^level - 1edges, connected), exact rational elimination ofLap - 4Ihas a single zero pivot,3 * 4^(level-1)eigenvalues lie below 2 and none in[2, 4), the lower edge climbs1.000000, 1.827520, 1.975680, 1.996862, 1.999605, 1.999950atlevel = 1..6, and the top eigenvalue is3 + sqrt(5) = 5.2360679775atlevel = 2climbing to5.7090316570atlevel = 6. Witness: lab/py/flake-band-gap. - Conjecture The lower edge closes at a fitted
c * 8^(-level)withcnear 12.9868 over ten levels,(2 - lo) * 8^levelreaching12.984807and12.986289atlevel = 7, 8, a fit with no mechanism. Witness: lab/py/flake-band-gap.
Flat carpet stack
- Proved The moire correlation law: for odd
m, nthe mean ofs(mu) s(nu)withs(x) = (-1)^floor(x)is exactlygcd(m,n)^2/(mn)(for general integers it needsm/gandn/gboth odd, else the integral is 0), and the Pearson correlation of the 1D parity indicators is exactly(gcd^2 - 1)/sqrt((m^2 - 1)(n^2 - 1)), so the correlation is exactly 0 if and only if the scales are coprime, and zero covariance is independence for Bernoulli pictures; exact rational integration over all odd pairs to 99 matches the closed forms to5.6e-17. Witness: moire-correlation-laws. - Proved The stack is an exact prime detector: an odd
n >= 3is prime exactly when its carpet is uncorrelated with every earlier carpet; over odd3..199all 45 primes sit at exactly 0 and all 54 composites strictly positive, minimum0.0517383atn = 169 = 13^2; the finite-window corollary "the zero-redundancy layers of the1..55stack are the primes above55/3" is a window artifact and not the statement. Witness: moire-correlation-laws. - Proved Pi cancels out of every visible brightness of the stack: ray strengths, crosshair steps, hot-spot values, layer correlations and per-layer means are all rational, because the square wave's
(4/pi)^2meets the odd Basel sumpi^2/8; the diagonal is exactly twice the background in paper coverage in the limit, and the anti-diagonal is its pixel-for-pixel copy by the palindrome symmetry. Witness: moire-correlation-laws. - Proved The moire rays obey a 2-adic law, not a Farey law: the slope-one family at offset
a/bcarries(-1)^a/b^2for oddband exactly nothing for evenb, and the slopeq/pray through the origin carries exactly1/(pq), the same number as the correlation of gramspandq. Witness: moire-correlation-laws. - Verified The stack fades at the random rate in
L^2: RMS contrast falls asc/sqrt(L)in the layer countLwithc^2 = lim L * Var,c = 0.522, a constant factor1.2054above independent layers, so "does not fade like random noise" is false inL^2; the exact variance is a finite rational sum at everyL. Witness: moire-correlation-laws. - Proved Coprime independence holds exactly in all four flat families: carpet, net, tree and void layer pairs have covariance identically 0 at every coprime odd pair, checked exhaustively to 201 and in exact rationals at
(3,5),(5,7). Witness: moire-correlation-laws. - Proved The void flat stack obeys a gcd-to-the-fourth law,
Pearson_void(m,n) = (g^4 - 1)/sqrt((m^4 - 1)(n^4 - 1))(void being the pure pair field(1 + s(mu) s(mv))/2), tree obeys(g^2 - 1)/sqrt((m^2 - 1)(n^2 - 1)), net's closed form is carpet's underm, n -> -m, -nwith slightly larger correlations, and the gcd echo orders tree > net > carpet > void; all four match exact lcm-grid counting on(3,9),(5,15),(9,15)with zero error. Witness: moire-correlation-laws. - Verified The flat variance constants reduce to two gcd sums,
S2(N) = sum g^2/(mn)andS4(N) = sum g^4/(m^2 n^2)over odd pairs:lim L * Varis theS2/(2N)limit for tree, theS4/(2N)limit for void (0.2768062) andS2/(4N) + S4/(8N)for carpet and net (their difference dying likeln^2 N / N), with the identityVar_L(carpet) = Var_L(tree)/2 + Var_L(void)/4, measured to 5 digits. Witness: moire-correlation-laws. - Proved The
S4limit is a theorem:lim S4(N)/N = (16/31) T/zeta(5)withT = sum_{k,l odd} 1/(k^2 l^2 max(k,l)) = 1.1122336970, value0.5536124372, measured0.5536124482atN = 3 * 10^6, by a bounded coprime tail plus Mobius over odd moduli, with an independent Jordan-totient recomputation. Witness: moire-correlation-laws. - Conjecture The rendered diagonal-to-background ratio reads
2.1189atN = 55walking to2.0000252atN = 10^6, and the rendered grey ratio is16/9because ink is 17. - Conjecture A primitive integer line
alpha u + beta v = gammais a ray iffalphaandbetaare both odd, and the crosshairs atu = a/bcarry1/(4b), a factorbstronger than the diagonal family. - Conjecture Pi survives only in the census and the decay arithmetic: distinct rays are indexed by odd-denominator reduced fractions, counted by
sum phi(b) ~ (2/pi^2) B^2through the odd-prime Euler product8/pi^2, and the pairwise gcd sum obeysS2(N)/N -> pi^2 ln 2/(7 zeta(3)) = 0.8130217(6 digits atN = 10^6two ways), whence the tree constantlim L * Var = pi^2 ln 2/(14 zeta(3)) = 0.4065108521and the carpet and net constant0.2724570. - Conjecture The sup-norm never fades: diagonal, crosshairs and the four brightest points (paper
9/14at the inner-thirds crossings, grey exactly 170) hold their values forever while their width shrinks like2/(N + 1)on an exactly triangular profile. - Conjecture Chaining 27 8-bit blends and truncating each step shifts the rendered stack by six grey levels, the saved image's mean
61.9against the true67.8and its brightest pixel163against170; quote paper-coverage fractions, never absolute greys. - Conjecture The 2D ray law transfers to the void flat stack at double contrast: void has no crosshairs (no single-wave terms) but carries the full odd/odd 2-adic diagonal web at twice the carpet's strength (offset
a/b:(-1)^a/(2b^2); slopeq/pthrough the origin:1/(2pq)), withu = vandu + v = 1solid ink, a black X on mid-grey, the negative of the carpet's paper X.
Franel on a digit design
- Proved At frequency 1 the exponential sum of the denominator-restricted Farey set IS the design's Mertens meter: with
S_Fthe whole numbers whose every digit lies in a digit set,sum of e(r) over r in {a/b reduced, b in S_F, b <= Q, 1 <= a <= b}equalsM_F(Q) = sum of mu(b) over b in S_F, b <= Q, sincesum over a mod b coprime to b of e(a/b) = mu(b)by Mobius inversion against the complete sums; every denominator inS_Fup toQ = 10^5has its literal sum ofphi(b)roots of unity equal tomu(b), worst deviation1.09e-11atb = 86293(base 3 digits{0,1}) and1.36e-12atb = 7247(base 10 without 9), 0 wrong roundings. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelladder_check) - Proved At frequency
mthe same sum issum over d dividing m of d M_F(Q/d; d), whereM_F(x; d) = sum of mu(c) over c <= x with dc in S_Fis the Mertens function of the DILATED designd^{-1} S_F; the classical divisor-shifted Mertens sums are the caseS_F = Z, where every dilate isZand all of them collapse toM, while for a digit designd^{-1} S_Fis notS_F, is not a digit design and carries no digit test, so eachd > 1brings a new function; checked atm = 1, 2, 3, 4, 5, 6, 12on base 3{0,1}atQ = 2187, base 10 without 9 atQ = 1000and the full-set control atQ = 300, exact integer against literal sum at every cell. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_denominator) - Proved The digit-restricted Franel identity, Fourier form:
sum over k nonzero of abs(S_F(k,Q))^2 / k^2 = (pi^2/3) G_F(Q)withG_F(Q) = sum over d, e of (gcd(d,e)^2/(d e)) M_F(Q/d; d) M_F(Q/e; e), a finite sum of exact rationals; the kernel is the Smith gcd matrix that already carries the moire correlation law and the Gaussian identity, so digit restriction moves the entries and never the kernel; checked against the literal Fourier side truncated atabs(k) <= 200000with the printed tail bound2 m^2/K, gap inside bound at base 3Q = 81and243, base 10Q = 40and the controlQ = 40. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelkernel_sumandfourier_side) - Proved The digit-restricted Franel identity, rank form: if the node set has top node
1and mean valuesum of rho_r = (m_F(Q)+1)/2, thenG_F(Q) - 1 = 12 m_F(Q) sum_j delta_j^2as exact rationals, withm_F(Q) = sum of phi(b) over b in S_F, b <= Qanddelta_j = rho_j - j/m_F(Q); closure underr -> 1 - raway from the node1is one sufficient condition for that mean value, holding for every denominator-restricted set and failing for every proper strict set; the proof is Parseval plus piecewise integration of(A(v) - m v)^2;Trueat base 3Q = 81, 243, base 10Q = 40and the controlQ = 40, which regenerates Edwards section 12.2. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelfarey_delta_square) - Proved The denominator lane's CONJECTURED shape implies the square-root ceiling for the design's Mertens meter: dropping every term but
k = 1andk = -1from a sum of nonnegative terms gives2 M_F(Q)^2 <= (pi^2/3) G_F(Q), which by the rank form is4 pi^2 m_F(Q) sum_j delta_j^2 + pi^2/3; withA_F(Q) << Q^alpha(the block count) andm_F(Q) <= Q A_F(Q) << Q^(1+alpha), the conjecturesum_j delta_j^2 = O(Q^(-1+eps))forcesabs(M_F(Q)) = O(Q^(alpha/2+eps)), the constant absorbed and no unproved input entering; the measured exponent is-0.959and-0.899, not-1, so only the conjecture yields the ceiling. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelscan_backward) - Proved The strict set's frequency-1 sum has an exact divisor form: it equals
sum over b in S_F, b <= Q of sum over d dividing b of mu(d) times sum of e(a/(b/d)) over a <= b/d with da in S_F, by Mobius inversion of the coprimality condition followed bya -> da; the inner sum is a digit-restricted exponential sum over an arithmetic progression, the Type II object with no bound on the tree, so the identity is exact and inert; literal summation against the divisor route agrees to6.28e-15over the 64 denominators of base 3{0,1}below 729 and to1.95e-14over the 162 of base 10 without 9 below 200. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelstrict_ramanujan_divisor) - Verified Literal enumeration of the strict digit-restricted Farey set reaches the counts the sieve prints without enumerating a fraction:
278, 4286, 67561, 1080458atQ = 3^5, 3^7, 3^9, 3^11on base 3{0,1}and1830, 147096, 11890654atQ = 10^2, 10^3, 10^4on base 10 without 9, 7 rungs and no disagreement. (witness:lab/py/restricted-franelstrict_literalagainstlab/rs/farey-discrepancydesign) - Proved For a design carrying the digit
0the dilated^(-1) S_F = {c : dc in S_F}is a regular language recognised least-significant-digit-first by a deterministic automaton whosedstates are the carries of long multiplication byd: reading digitefrom carryrwrites the output digit(de + r) mod base, which must lie inF, and moves to carryfloor((de + r)/base), which stays belowdby induction, and afterleveldigitsdcis theleveloutput digits with the terminal carryr_levelwritten above them, so acceptance is exactly thatr_levelhas all its digits inF; the accepting set isAcc_d = {0} union (S_F intersect [1, d)), of sizeA_F(d-1) + 1. The hypothesis0 in Fis load-bearing and not cosmetic: without it the run tests alllevelPADDED output digits, a leading output digit0is not a digit ofdc, and the automaton recognises the padded set of the Mobius page instead, reading8at base 3 withF = {1,2},d = 1andlevel = 3where the true count is14. Regularity of the dilate itself survives without the hypothesis; the count identity does not. So the dilated Mertens sums of the restricted Franel identity run over regular sets, not over digit designs. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franeldilate_matrix,verb_converse0mismatches of840) - Proved The dilate's transfer matrix
T_d(r, r') = #{e < base : (de + r) mod base in F, floor((de + r)/base) = r'}counts it,#{c < base^level : dc in S_F} = e_0 T_d^level 1_(Acc_d)for a design carrying0, and EVERY column ofT_dsums to exactly#F, in every base, at every digit set and everyd, with no hypothesis at all: the pairs(e, r)in[0,base) x [0,d)are in bijection withv = de + rin[0, dq)by the division algorithm, the column atr'counts thevwithv - base r'inF, and the window[base r', base r' + base)lies inside[0, dq)for everyr' < d, so exactly#Fof them qualify. Hence the all-ones vector is a positive left eigenvector and the spectral radius ofT_dis#Ffor everyd: the dilate carries the design's own mass exponent as its Perron root. The rows sum togtimes#(F intersect (r + gZ))withg = gcd(d, base), so they equal#Fwhenevergcd(d, base) = 1, giving#{c < base^level : dc in S_F} <= (#F)^levelat thosedwith constant1, again only for a design carrying0: base 3 withF = {1,2}andd = 1reads14atlevel = 3against(#F)^level = 8. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate,verb_converse) - Verified The dilate automaton and its transfer matrix are checked against brute-force enumeration: over
d <= 64at base 3{0,1}and base 10 without 9 no column ofT_dis off#F, while rows are off#Fat 21 and 38 of the 64 respectively, every one of them at adsharing a factor with the base; at base 3{0,1}withd = 2the transfer matrix[[1,1],[1,1]]with both carries accepting counts2^level - 1at everylevel <= 12, agreeing with literal enumeration of{c : 2c in S_F}at every rung and reading4095atx = 3^12 = 531441; and the count identity's scope is exact on the sweep overbase = 3, 4, 5, everyF, everyd <= 6and everylevel <= 5, with0mismatches in the840cases carrying the digit0and399in the750without it. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate,verb_converse) - Proved The dilated meter is blind to the base's own powers: if
0 in FthenM_F(x; base^j d) = M_F(x; d)for everyj >= 0and everyd, since appendingjzero digits neither leaves nor entersS_F, so the dilates repeat along every base-power ladder and only the base-prime part ofdcan move them. At base 3{0,1}thed = 3column reproduces thed = 1column exactly,M_F(3^12; 3) = M_F(3^12) = 56with both peaks61. It is the lever that fixes the rate in the converse's hypothesis and that refutes the mass saving uniformly ind. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Proved The digit transform of a dilate is the transfer matrix in place of the digit symbol: for a design carrying
0,sum of e(ct) over c < base^level with dc in S_Fequalse_0 M(t) M(qt) ... M(base^(level-1) t) 1_(Acc_d)withM(t)(r, r') = sum of e(et)over the digitsecarryingrtor', andM(0) = T_d, by decomposing over automaton paths. That is the ladder of the Mobius page with the scalar symbolg_F(base^j t)replaced by a matrix, and the replacement is exactly what the route costs: the product no longer factors, so the sup-over-shiftl^1exponent that carries a Type I estimate for a digit design has no scalar analogue here. The matrix form gives the exact count att = 0and exact evaluation at anyt, and gives no cancellation inmu; the Type II wall stands where it stands atd = 1. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Proved The converse of the restricted Franel identity, from (U') and with the dependence on
dexplicit. (U') givesG_F(Q) = O_eps(Q^(alpha + eps))and hencesum_j delta_j^2 = O_eps(Q^(-1+eps))on the denominator-restricted set, which is the denominator lane's conjecture. Writed = a d_baseande = b e_basewithaandbsupported on the primes dividingbase; the two parts have disjoint prime support, sogcd(d,e) = gcd(a,b) gcd(d_base,e_base)and the kernel sum FACTORS. Each term is at mostgcd(d,e)^2 (de)^(-1-alpha/2-eps) (d_base e_base)^((alpha-1)/2) Q^(alpha+2eps); the coprime factor carries exponent-3/2-epsand, writingd_base = g uande_base = g vwithgcd(u,v) = 1, is at mostzeta(1 + 2eps) zeta(3/2 + eps)^2; the base factor is the product overpdividingbaseofsum over i, j >= 0 of p^(2 min(i,j) - (i+j)s)withs = 1 + alpha/2 + eps, which sums in closed form to the product of(1 + p^(-s))/((1 - p^(-s))(1 - p^(-alpha-2eps)))and is FINITE becausealpha > 0. Thenm_F(Q) >> Q^(1+alpha)/log log Q, the>> Q^alphamembers ofS_Fin the top block belowQeach exceedingQ/basewithphi(b) >> b/log log b, so the rank form divides the bound down toQ^(-1+3eps). The exponent(alpha-1)/2ond_baseis critical, not chosen: at(alpha-1)/2 + deltaond_basethe same argument gives onlyG_F(Q) = O(Q^(alpha + 2delta + eps))and no threshold, the coprimegsum becomingsum of g^(-1+2delta)of sizeQ^(2delta), and atdelta = 0it is the harmonic sum, convergent only through theeps; the base factor never sees the exponent. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Verified The raw exponent readings on the dilates separate nothing and are not exponents: over base 3
{0,1}tox = 3^12 = 531441the readinglog max abs M_F(x;d)overlog xis0.311823atd = 1and at most0.292046overd = 2, 4, 5, 7, 8, 11, 13, 16, 22, 31, thed = 3row being thed = 1row by the free base powers rather than an independent reading; over base 10 without 9 tox = 10^7the reading is0.484570atd = 1against0.489199atd = 7and0.472377atd = 2, and the crossing seen atx = 10^6,0.495982atd = 2against0.444731atd = 1, reverses byx = 10^7, peaks2026against2466. The local exponents between consecutive rungs swing over0.24to0.845, so none of these readings is an exponent and none of them tests the converse's hypothesis, which is a statement about the ratio tod_base^((alpha-1)/2) x^(alpha/2)and is metered separately. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Conjecture The denominator-restricted set's Franel analogue is
sum_j delta_j^2 = O(Q^(-1+eps)), equivalentlyG_F(Q) = O(Q^(alpha+eps)); the forward half of an equivalence with the square-root conjecture forM_Fis open and needs the dilated sumsM_F(x; d)ford > 1, for which the desk has no bound, so only the implication above is proved and no exponent is claimed here. (witness: farey.md, The restricted Franel identity) - Conjecture The strict set's frequency-1 sum divided by its node count converges to the first Fourier coefficient of a limit measure of the strict set, nonzero; the readings are
0.335693, 0.343837, 0.345905, 0.346338atQ = 3^5, 3^7, 3^9, 3^11and0.015138, 0.012250, 0.011561atQ = 10^2, 10^3, 10^4, four and three nested rungs and no exponent claimed; that limit measure has no definition on the tree, and until it is named there is no Franel-type equivalence to state on the strict set. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_strict) - Conjecture (U'), the surviving hypothesis with the dilate's true mass:
abs M_F(x; d) = O_eps(d_base^((alpha-1)/2) x^(alpha/2 + eps))uniform ind >= 1andx >= 1, withd_basethe part ofdcoprime to the base. It is square-root cancellation in each dilate's own mass read correctly, sinced_base^((alpha-1)/2)is the square root of the accepting-set constant atd_baseand the base-smooth inflation is bounded; it is consistent with the free base powers by construction because(base^j d)_base = d_base; and itsd = 1case is exactly the square-root ceiling the forward implication already delivers. Metered as a ratio it does not fire:max abs M_F(y;d)overy <= xdivided byd_base^((alpha-1)/2) x^(alpha/2)reads0.9531, 0.7991, 0.9531, 0.6054, 0.9883, 0.3580, 0.5504, 0.8269, 1.0535, 0.4431, 0.5528, 0.3828atd = 1, 2, 3, 4, 5, 7, 8, 11, 13, 16, 22, 31on base 3{0,1}atx = 3^12, and1.1276, 0.9264, 0.5523, 0.6173, 0.8583, 1.2702, 0.4594atd = 1, 2, 3, 4, 5, 7, 11on base 10 without 9 atx = 10^7, while the refuted exponent puts1.1673atd = 3against1.0535as the coprime maximum. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Conjecture The dilate's mass constant is read off the automaton's accepting set under a SECOND coprimality: writing
Delta_Ffor the gcd of the differences of the digits inF, forgcd(d, base Delta_F) = 1the matrixT_dover#Fis doubly stochastic, the carry chain is irreducible, its stationary law is uniform, andA_d(base^level)/(#F)^levelconverges to#Acc_d/d = (A_F(d-1) + 1)/d, which isO(d^(alpha-1))and is exactly the saving a level of distribution forS_Fat the modulusdwould give. Verified to three decimals atlevel = 24at every printeddcoprime to the base, both metered designs havingDelta_F = 1: base 3{0,1}reads1.0000, 1.0000, 0.7501, 0.8000, 0.5714, 0.5001, 0.5455, 0.5394, 0.5001, 0.3636, 0.3548atd = 1, 2, 4, 5, 7, 8, 11, 13, 16, 22, 31against1, 1, 0.75, 0.8, 0.571429, 0.5, 0.545455, 0.538462, 0.5, 0.363636, 0.354839, and base 10 without 9 reads1.0000, 1.0000, 1.0000, 0.9091, 0.9231, 0.8264, 0.8272, 0.8148atd = 1, 3, 7, 11, 13, 121, 243, 729against1, 1, 1, 0.909091, 0.923077, 0.826446, 0.827160, 0.814815. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate) - Conjecture The converse's hypothesis has a Mobius-free surrogate the lab can meter: square-root cancellation in each dilate's own mass is
abs M_F(Q/d; d) <= N_F(Q; d)^(1/2+eps)withN_F(Q; d) = #{m in S_F : m <= Q, d divides m}, since the sum forM_F(Q/d; d)runs over exactly thosem, so under that hypothesis the converse reduces to the divisor statement thatB(Q) = sum over d, e of gcd(d,e)^2/(de) times sqrt(N_F(Q;d) N_F(Q;e))isO(Q^(alpha+eps)), which mentions no Mobius function at all. This form stays consistent where thed-uniform bound above does not, readingabs M_F(Q/base^j) <= A_F(Q/base^j)^(1/2+eps)atd = base^j, which is thed = 1ceiling again. Measured at base 3{0,1}:B(Q)/Q^alphareads12.5146, 17.8640, 24.7369, 31.5935, 39.0671atQ = 3^4to3^8with local exponents0.955, 0.927, 0.854, 0.824falling towardalpha = 0.630930, andB(Q)overQ^alpha (ln Q)^2falls0.6480, 0.5920, 0.5693, 0.5342, 0.5058, so the range is consistent withQ^alphatimes a power of a logarithm and no exponent is claimed. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelsmith_bilinear) - Refuted No Mertens-type sum over
S_Fequals the strict set's frequency-1 sum, because that sum is not real: at base 3{0,1}andQ = 3it is1 + e(1/3) = 0.5 + (sqrt 3/2) iand at base 10 without 9 andQ = 10it is-1.809016994 + 0.587785252 i, both exact algebraic sums evaluated past1e-9, whileM_F(Q), the count-weightedsum of mu(b) phi_F(b)and the normalisedsum of mu(b) phi_F(b)/phi(b)are all real; the two witnesses carry the refutation alone; beside them sits an observation and not a mechanism, that the strict set also fails the pairinga -> b - a, failure of which is not shown to force a non-real sum. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_strict) - Refuted (U), the
d-uniform dilated boundabs M_F(x; d) = O_eps(d^((alpha-1)/2) x^(alpha/2 + eps)), holds for NO design carrying both0and1, so it cannot be the hypothesis of the converse. Base powers being free givesM_F(x; base^j) = M_F(x), so (U) atd = base^jdemandsabs M_F(x) <= C_eps base^(j(alpha-1)/2) x^(alpha/2+eps)at everyj >= 0, andalpha < 1drives the right side to0at fixedx, forcingM_Fidentically zero againstM_F(1) = mu(1) = 1. Base 3{0,1}atx = 3^12: the left side is56at everyj = 0to12whiled^((alpha-1)/2) x^(alpha/2)falls64.0000, 52.2558, 42.6667, 34.8372, 28.4444, 23.2248, 18.9630, 15.4832, 12.6420, 10.3221, 8.4280, 6.8814, 5.6187overd = 3^0to3^12and the ratio climbs0.875, 1.072, 1.313, 1.607, 1.969, 2.411, 2.953, 3.617, 4.430, 5.425, 6.645, 8.138, 9.967, unbounded inj. The cause is that(alpha-1)/2is the square root of the dilate's mass constant only where that constant isd^(alpha-1), and on the base-power ladder the constant is1. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_converse) - Refuted The converse is one implication and not an equivalence: the threshold does not give (U') by the natural route. From
G_F(Q) = O(Q^(alpha+eps))the Fourier form gives termwiseabs S_F(fill,Q) <= fill (pi^2 G_F(Q)/6)^(1/2), and Mobius inversion ofS_F(m,Q) = sum over d dividing m of d M_F(Q/d;d)givesd M_F(Q/d;d) = sum over c dividing d of mu(d/c) S_F(c,Q), hence onlyabs M_F(Q/d;d) <= (sigma(d)/d)(pi^2 G_F(Q)/6)^(1/2), which is<< log log dtimesQ^(alpha/2+eps)and GROWS indwhere (U') needsd_base^(-1/2-eps)decay. So no biconditional is available, and none is claimed. (witness: farey.md, The restricted Franel identity) - Refuted Coprimality to the base alone does NOT give the accepting-set constant. At base 3 with
F = {0,2}, whereDelta_F = 2, the dilated = 2is coprime to the base and carriesT_2 = [[2,0],[0,2]], so carry1is unreachable from carry0, the closed class is{0}and the uniform stationary law is read on the wrong class: exhaustive counts are2, 4, 8, 16, 32, 64, 128, 256atlevel = 1to8, exactly(#F)^level, so the constant is1against#Acc_2/2 = 1/2. The split is exact where it is swept, over everybase <= 7, everyFcarrying0and every2 <= d <= 24coprime tobase, read atlevel = 400:1747agreements and0failures atgcd(d, Delta_F) = 1,0agreements and148failures atgcd(d, Delta_F) > 1. That same constant1sits at adcoprime to the base, so it also killsO(d^(alpha-1))there,1against2^(alpha-1) = 0.6444, and the base-smooth mechanism is therefore one cause and not the only one. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_converse) - Refuted The mass saving
A_d(x) = O(d^(alpha-1) x^alpha)does not hold uniformly ind, and the base-power ladder is what refutes it: with0 in Fthe dilate atd = base^jisS_Fitself, soK_d = 1exactly at everyjwhile the ceilingbase^(j(alpha-1))tends to0, andA_d(x)/(d^(alpha-1) x^alpha)is at leastbase^(j(1-alpha)), UNBOUNDED. Off the ladder the base-smooth dilates are denser than the design in the same way: at base 10 without 9K_d = A_d(base^level)/(#F)^levelreads1.1111, 1.1358, 1.1111, 1.1413, 1.0700, 1.0343atd = 2, 4, 5, 8, 16, 32against the claimed ceilings0.968781, 0.938537, 0.929003, 0.909237, 0.880851, 0.853352, and the accepting-set law fails there too, those samedcarrying#Acc_d/d = 1, 1, 1, 1, 0.9375, 0.90625. The dilate is denser because the last digit of an element ofS_Fis uniform onFandFis not balanced modulo a prime dividing the base, so no equidistribution ofS_Fmodulodis available at base-smoothd. What it costs is the converse's first hypothesis and not its conclusion, the repaired hypothesis asking the rate on the coprime part only: over the29base-smoothd <= 1000at base 10 without 9 the constant lies in[0.9273atd = 512,1.1637atd = 625]and over everyd <= 200its inflation over the value at the coprime part ofdlies in[0.9375atd = 112,1.1413atd = 88], bounded on the metered range and unmeasured past it. (witness: farey.md, The restricted Franel identity;lab/py/restricted-franelverb_dilate,verb_converse)
Franel one field up
- Proved Kluyver's identity in
Z[i]: the Gaussian Ramanujan sum obeysc_d(lambda) = sum_{e | gcd(d, lambda)} mu_G(d/e) N(e)over ideal divisors, so the exponential sum of the Gaussian Farey set isS_N(lambda) = sum_{[e] | lambda, N(e) <= N} N(e) M_G(N/N(e))withM_Gthe Gaussian Mertens function over associate classes; 2720 exact sums at norm bound 50 with 0 mismatches, 68 literal node sums agreeing to1.281e-13, and the node set identified with the complex Farey set of the literature atT = 2to6(4, 24, 64, 176, 320 points). Witness: lab/py/gaussian-franelcheck_theorem_1,check_sayous. - Proved Franel's identity one field up: the Fourier
L^2discrepancy of the Gaussian Farey set onC/Z[i]ism^2 D_2(N)^2 = 4 zeta_K(2) sum_{[a],[b]} N(gcd(a,b))^2/(N(a) N(b)) M_G(N/N(a)) M_G(N/N(b)), a finite gcd-weighted quadratic form in Gaussian Mertens sums whose kernel is the Smith gcd matrix of the layer Gram; checked against the Fourier side truncated atN(lambda) <= 200000with gaps0.001883and0.010546inside the printed tail bounds0.226192and7.093392at norm bounds 20 and 50; the same identity regenerates the classical Farey discrepancy with no Farey enumeration,C(Q) - 1 = 12 Phi(Q) sum delta_v^2exactly atQ = 40andS2 Qreading0.5395, 0.5848, 0.6241, 0.6387, 0.6560, 0.6538, 0.6564atQ = 125to8000, the Farey page's table digit for digit; the Gaussian global readout collapses like the rational one,sum_{N(a) <= x} M_G(x/N(a)) = 1at everyxto 2000. Witness: lab/py/gaussian-franelcheck_theorem_2,classical_exact,franel_form,readout. - Proved
F(N) = O(N^{1+eps})for everyeps > 0, equivalentlyD_2(N) = O(N^{-3/2+eps}), is equivalent to the Riemann hypothesis forzeta_{Q(i)}(s) = zeta(s) L(s, chi_-4): backward, the four units giveM_G(N)^2 <= zeta_K(2) F(N)and partial summation makes1/zeta_Kanalytic right of the critical line; forward, by divisor splitting from Littlewood's bound onM_Gtranscribed tozeta_Kby Perron with the bounds of Hu, Kaneko, Martin and Schildkraut (Lemma 5.4 and Lemma 2.4), the biconditional being assembled here and written in neither source; the rational template is Huxley 1971 Lemma 10 and Huxley 2012 Theorem 1 overQ, the announced number-field part abandoned by its author's account, and the Gaussian identity not found in the sources read; an equivalence is exactly as hard as the hypothesis it names and the meter renders, it does not measure. Witness: lab/py/gaussian-franelmain(the backward inequality alone, ratio at most 0.017 over norm bounds 100 to 64000), REFS.md.
Gasket rays and the window
- Verified Occupied-ray totals differ by exactly 2 between the two counting conventions at every level,
1044842against1044840atn = 13, because one counts the two fibre rays(1,0)and(0,1)and the other does not; nothing else in either table moves, so any occupancy total must say which convention it uses. Witness: lab/rs/dimension-one-ladder; gasket-ray-machine. - Verified The multiplier-count census of the gasket at
n = 13: over all 1,044,840 occupied non-fibre rays, 699,508 carryM_n = 1(17% ofZ), 339,530 carryM_nin[2,5](55% ofZ), the ten heaviest rays are exactly the shifts(1, 3^j)and their reverses forj = 1..5and carry 14% ofZ,sum M_n = 1,577,940 = 3^13 - 2^14 + 1exactly, andmax M_13 = 376 = F(14) - 1reproduces the mass lawM_n(3,1) = F(n+1) - 1from a generator that never mentions Fibonacci, all by exact exhaustive enumeration of the3^13gasket points with gcd reduction into a hash table. Witness: lab/rs/dimension-one-ladder; gasket-ray-machine. - Conjecture Conjecture N: every primitive ray automaton of the gasket has spectral radius at most the golden ratio with equality exactly on the shift rays
(3^j, 1), and the supremum off them is the supergolden ratio1.4655713, the root ofx^3 = x^2 + 1; the bound half holds for every primitive ray by the burst certificate (top edge0.6402122unconditionally, from0.730424), and what stays open is strictnessrho < phioff shifts and the supergolden supremum that would move the edge to0.605303, measured on all 490 primitive rays of height<= 40plus a fixed 766-ray sample to height 200 where every observed radius is a root ofx^k = x^(k-1) + 1orx^k = x + 1. Witness: lemma-b-pincer. - Conjecture Shear class 26 carries a flat mid-octave Chebyshev residue near
1.5e-4atn = 14, roughly 40 times its peers 98, 176 and 416, with no degenerate fibre to blame, being the class that is a graph of nothing, parametrized by the balanced-ternary integerx_2 - x_1; the excess is collinear shift-ray mass Mertens-smeared flat: code 26 builds its points asc_nminus a disjoint-support binary pair, so the golden shift family survives withM_n(3,1) = F_(n-1)exactly where its peers carry zero, and the deep excess atn = 14is 65.7% shift rays plus 2.9% supergolden against a Mertens-predicted flat height676 ln 3 / 3^14 = 1.55e-4versus the recorded1.5e-4, the carriers flat across octavesj = 7..12including inside the proved top range, so the window-mass-in-disguise reading is dead; the "3995 points" of the first count are 3993 non-fibre plus 2 axis points. - Conjecture Conjecture W and its ray twin Conjecture O: the weighted active multiplier census per octave is
C 3^j, measuredC ~ 120atn = 14, unimodal inj, with activity concentrated at 3-adic depth (attainer families(3^a, 3^b +- 1), per-pair activity decaying like0.65^Kagainst the weight1.5^K, so per-octave convergence is delicate); W implies Conjecture Z, hence the window(0.4475978, 1/2], and W with O closes the window entirely, both implications exact; the precursorA_(j,K) <= C 3^(j-K)fails on the deep-Kfamilies, the universal pair-prefix transfer matrix has Perron root 4, not 3, and the unweighted octave censusC = 1.042, 1.136, 1.244, 1.356atn = 13..16is a different quantity from the weighted(3/2)^Ksum W names, so W is neither supported nor damaged by it. - Conjecture Statement (A) is the exact averaged theorem the ray machine needs: for primitive non-shift
(a,b)with3^j <= max(a,b) < 3^(j+1),sum M_n(a,b) <= C 3^(2j) lambda^(n-j) poly(n)withlambda < phiinserts into the octave sum and givesbeta > 1/(2 - log_3 lambda); it is weaker than a uniform non-shift spectral gap and far stronger than any average ofrho, and its tail form requires the octave-jcount of rays withrho >= tto be at most3^(2j - I(t)j + o(j))followed by an optimization overt; two routes are named, a large sieve on a bounded local deficit observable Fourier-expanded over the ray's residue modulus and a finite-state fractional-moment operator, with three obstructions to the sieve (varying state spaces with no common separated frequency family, the Cauchy-Schwarz loss of the square root of the ray count in passing from anL^2average toL^1octave mass, and an unweighted octave count the sieve's measure must match), and Turan power sums are ruled out, since they lower-bound maxima where an upper bound for a positive sum over many nonnegative matrices of varying dimension is needed. Witness: lemma-b-pincer. - Conjecture The weighted active multiplier census
W_j(n) <= C 3^jis not numerically stable across the two known levels: atn = 9the exhaustive active-pair census givesA_j/3^j = 4.000, 6.667, 6.370, 4.025, 1.794, 1.141, 0.368andW_j/3^j = 7.500, 17.750, 23.719, 25.041, 12.841, 12.097, 5.837forj = 1..7, a peak of25.0, while then = 14summary reports a peak near113, so one level supports a constant and the two together do not, and then = 14tally is not in this tree; this weakens but does not refute Conjecture W, since W and O together closing the window is exact and W and O themselves remain untested. - Conjecture The 3-power family of the second moment sums in closed form:
S(n) = 2 Sum_(j=1..n-1) Q_n(1, 3^j) = 3^n - 4*2^n + 2n + 3fromQ_n(1, 3^j) = 3^(n-j) - 2^(n-j+1) + 1, soE(n) = T(n) + S(n) + R(n)withT + S = 2*3^n - 6*2^n + 2n + 4exactly and the whole of Conjecture Z's constant 2 is accounted for before any residual is measured, leaving one statement aboutR; the identity is machine-checked atn = 3..17andR = Z - T - Sre-subtracted against theElist atn = 13, 14, 16agrees. - Conjecture The Pair Census Bound
R(n) = o(3^n)over ordered collinear non-fibre gasket pairs whose multiplier ratio is not a power of 3 is the only unproved step toE(n) = O(3^n), hence to Conjecture Z and the window(0.4475978, 1/2]; the dominant carrier is the shift-ray family pairing with itself, now closed at((13 + 5 sqrt5)/11) phi^(2n)and carrying only0.65to0.84ofR, every other ray having spectral radius belowphi, and any proof must use the multiplier-specific automata, since the universal pair-prefix transfer matrix has Perron root 4 and not 3. Witness: lemma-b-pincer. - Conjecture Per-octave occupied ray counts by exact exhaustive enumeration at
n = 14, 15, 16total 3,151,658, 9,491,966 and 28,545,342, withocc(j,n)/3^jpeaking atj = 8in all three at2.217,2.492and2.740and low octavesj <= 4identical at all three levels; the table cannot be joined to then = 13per-octave table under the half-open convention3^(j-1) <= max(a,b) < 3^j, the discrepancy not being a uniform label shift (4 rays withmax = 3placed at octave 1 where the interval forces octave 2; 336 against a recomputed 294 in the next bin), and the fibre-ray convention (1,044,842with the two axes,1,044,840without) is not part of this mismatch. - Proved The gasket residual changes coordinate. Every off-diagonal collinear pair of the level-
ngasketG_nis(sz, tz)for a unique coprime(s,t)and a unique witnessz, soR(n) = Sum_z P_n(z)whereP_n(z)counts the coprime non-shift pairs one witness realises; the per-pair route needed a constant summable against an active-pair count growing2.77a level and is dead by construction, while the per-witness route has its constant. No witness weighs less than 4, hencemax(s,t) <= (3^n-1)/8, sharp: the largest multiplier is exactlyfloor(3^n/8)atn = 4..13. Weight layers scale exactly,R_(3w)(n) = R_w(n-1), because3 | z_1+z_2with3dividing neither coordinate forcesv_3(m z_1) = v_3(m z_2)and the supports collide; checked on all 1869 layers atn = 5..13. Every pair above(3^n-1)/10carries exactly 4 ordered pairs, its only witnesses being(1,3)and(3,1), verified on all 30028 such pairs atn = 6..13. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved The weight-four layer is closed in Fibonacci, the second layer of the residual to close after the shift family. With
F_n = {m : (m,3m) in G_n}the no-adjacent-ones set,#F_n = F(n+1) - 1andR_4(n) = 2 #{(a,b) in F_n^2 : a != b, gcd(a,b) = 1, b/a != 3^j} < 1.0473 phi^(2n), so the whole 3-power orbit obeysSum_j R_4(n-j) < 1.6945 phi^(2n); exact atn = 4..12whereR_4(n) = 12, 36, 108, 336, 988, 2596, 6672, 17480, 45720, carrying194096ofR(13) = 863848. Constants safe:2 phi^2/5 = 1.0472136and2 phi^3/5 = 1.6944272. Witness: gasket-ray-machine. - Verified The golden ceiling:
M_n(z) <= M_n(1,3) = F(n+1) - 1for every direction, so the shift ray(1,3)is the heaviest ray of the gasket at every level, and this is the per-witness constant the per-pair route never had. Refutation attempt, briefed to break it: 13158 coprime directions withz_1 <= 120andz_1 <= z_2 <= 240at everyn <= 40,(1,3)the sole attainer atn = 40; plus six families chosen to favour a breach at everyn <= 45- all binary base-3 pairs below3^7(4221 coprime), all no-adjacent-ones pairs below3^7(253), all(1,t)witht < 3000(2998), all consecutive below 1500 (1499),(s,3s-1)(1199) and(s,3s+1)(1199) withs < 1200, 11369 directions in the shelf script and 24088 with the binary family widened to3^8in the lab; plus an independent enumeration on a larger box. Zero breaches anywhere. Next rate down is the supergolden1.4655, the root ofx^3 = x^2 + 1, at(1,12),(3,10),(4,9). Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved Two cheap constructions for the free-digit automaton
B(s,t), which used to blow up at large multipliers. It is a constrained tensor squareT = S (x) S - U (x) U - V (x) V + W (x) Wof a one-coordinate carry automaton with at most(s+1)(t+1)states, so the four-tuple state graph is never built: 729 carry states against 26931 reachable at(365,1094), 81 against 835 at(41,122), agreeing on all 473 coprime pairs below 40 at every level to 9. And at large multipliers the witness boxz_1 + z_2 <= floor((3^n-1)/(2 max(s,t)))replaces the automaton entirely inO(W^2 n)digit tests, agreeing on 812 coprime pairs atn = 9- cheapest exactly where a forward build is most expensive. Witness: gasket-ray-machine. - Verified Conjecture Z evidence to level 17:
R(n) = 863848, 2211960, 5549452, 14100688, 35354824atn = 13..17.R/3^npeaks at0.8401158atn = 8and falls at every level to0.2737709;R/phi^(2n)peaks at3.2378233atn = 12and falls at five consecutive levels to2.7724831; the level ratioR(n+1)/R(n)reads2.5073119atn = 17, belowphi^2 = 2.6180339. Witness: lab/py/gasket-witness-weights. - Proved The golden partition bound
U(z) <= phi^-2is proved outright on an infinite arithmetic family, not checked direction by direction. Writeq = 3^k q_1for the coordinate divisible by 3 andpfor the other. Fork = 1andt = v_3(q_1 - p):U(z) <= phi^-1 (1 - phi^-max(t,2)), soU <= phi^-2on the whole classk = 1,t <= 2- 261 of the 360 occupiedk = 1directions of the census - sharply at(1,12)wheret = 1and(3,10)wheret = 2, andU < phi^-1for every such ray but(1,3), the first proof that a whole family of gasket rays grows strictly slower thanphi. Refutation attempt: 5422 occupiedk = 1directions picked in the hard corners (deept,q_1 - p = +-m 3^efore <= 7,2q <= pso the far predecessor is live) gave zero violations with equality only at(1,12)and(3,10), the independent first-return series was dominated by the exact solve at 5420 of 5420 checked, and an independent adversary sweep of 910 stratifiedk = 1directions in exactQ(sqrt5)found zero violations with equality again only at(1,12)and(3,10); a globalUhunt over 17624 occupied directions to weight 6000 found only shift rays abovephi^-2. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved Occupancy of a gasket ray is a congruence before it is anything else:
M_n(z) > 0for somenforcesq_1 = p mod 3, by two lines on last digits with no automaton built - a multiplierm = 3^s m'makesm' pandm' q_1binary in base 3 and prime to 3, so both end in digit 1. It empties 4588 of the 11691 census directions with3 | z_1 z_2, and it is only necessary: just 865 of the 7103 matching directions carry mass. Refutation attempt: zero violations over a 400 x 2500 sweep and over both censuses, 1995 occupied directions in the lab universe and 865 on the shelf. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved The short first returns of a ray automaton are classified. No first return has length between 2 and
v_3(q);f_2 != 0only at{1,3}andf_3 != 0only at{1,9},{1,12},{3,10},{4,9}, each equal to 1. HenceU = phi^-2 Sum_(j>=3) f_j phi^(3-j), soU <= phi^-2says exactlySum_(j>=3) f_j phi^(3-j) <= 1and forcesf_4 <= 1; the supergolden trio is exactlyf_3 = 1with every laterf_jzero. Refutation attempt: a 420 x 2600 sweep over 5281 occupied directions returned exactly those five directions and zero burst failures, and the adversary's exhaustive check to weight 12000 found no fifthf_3direction. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved A two-valued potential read off the out-degrees replaces the exact linear solve:
pi = 1where a live state branches,phi^-1where it does not,pi(0) = 1, is a super-solution of the golden criterion whenever no branch state has two branching successors, and sweeping it under the same operator gives a decreasing chain of exactQ(sqrt5)upper bounds onU. It settles 849 of the 865 occupied shelf directions - least sweep depth 1 on 760, 3 on 48, 4 on 31, 5 on 7, 6 on 3 - and 1966 of the lab's 1995, reaching 37 and 66 directions outside the branch case. What is left is the 7 shift rays and(1,756),(1,2196),(1,2214),(1,2268),(1,2430),(13,1080),(27,730),(28,729),(40,1053). Refutation attempt: an earlier depth split of760, 48, 31, 10was wrong because the sweep skipped depth 5 and the expected tuple had been fitted to that grid, a circular self-check that stayed green; the sweep now runs consecutive depths and the split is the least depth that works. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Proved The golden partition bound restated twice with no automaton in it:
Sum_n (M_n(z) + 1) phi^-n <= phi^4 = 3 phi + 2, and equivalentlySum_m phi^-l(m) <= phiover the multipliersmofz, wherel(m)is the number of base-3 digits of(z_1 + z_2) m. And the obstruction beyondv_3(q) = 1is now exact rather than heuristic: the burst forcesphi^-2 >= pi(c_0) >= phi^-(k-1) Sum_m pi(q_1 m)over2^(k-1)burst-floor states of valuation 0 whilepi(p) >= phi^-1at the valuation-0 statep, so any valid potential must separate states of equal valuation byphi^2 (2/phi)^(k-1), which grows without bound - no potential constant on the level sets ofv_3, and none constant on the out-degree classes, can work oncek >= 2. Refutation attempt: both restatements checked exactly against the linear solve on 111 directions, and the burst identity together withu(p) = phi^-1checked exactly on all 865 shelf and 1995 lab occupied directions. Witness: gasket-ray-machine, lab/py/gasket-witness-weights. - Conjecture Conjecture Z,
E(n)/3^n -> 2exactly for the second momentE(n) = Sum_y M_n(y)^2, writtenEto keep it clear of the lane's ray countZ_F(n):E = T + S + RwithT = 3^n - 2^(n+1) + 1andS = 3^n - 4*2^n + 2n + 3in closed form, so the constant 2 is exact before measurement and onlyRis open;Ratn = 8..16grows at about2.54per level, belowphi^2 = 2.618, soR/phi^(2n)peaks at3.238atn = 12and decays thereafter, three generators agree ton = 18, and no counterexample is known; the limit 2 has no proof and the residual's exact rate is undecided. Witness: lemma-b-pincer. - Proved The shift-ray family of the gasket second moment is closed in exact form:
M_n(3^j,1) = M_n(1,3^j) = prod_(r<j) F(m_r+2) - 1withm_r = #{i in [0,n-j) : i == r mod j}, becausez(3^j,1) in G_nsays exactly thatzis a binary string of lengthn-jwith no two ones at distancej, which factors intojindependent no-two-adjacent chains; fromF(k) <= 2 phi^(k-3)fork >= 2, a two-step induction with equality atk = 3, followM_n(3^j,1) < (3-sqrt5)^j phi^nandSh(n) < ((4+12 sqrt5)/11) phi^(2n) < 2.803 phi^(2n)at every level, withSh(n)/phi^(2n) -> (13+5 sqrt5)/11 = 2.198212717by dominated convergence; the break attempt ran the family in exactZ[sqrt5]arithmetic ton = 160and against literal enumeration of all3^npoints ton = 12, where the shift-ray share matched the closed form at every level, and an independent re-enumeration reproduced the closed form with no mismatch ton = 13at everyjand the constants to 80 digits. Witness: gasket-ray-machine. - Proved The gasket ray mass laws are theorems at every level, not checks to a finite range: the live carry automata of
(3,1),(1,12)and(7,3)have 2, 3 and 4 states with characteristic polynomialsx^2-x-1,x^3-x^2-1andx^4-x^3-1, so Cayley-Hamilton gives each recurrence and the first 2, 3 and 4 return counts pin it; the break attempt exhibited every reachable state by hand and by script, found the dead state-1at(7,3)that makes reachable 5 against live 4, and confirmed the annihilator residuals vanish well beyond the automaton order. Witness: gasket-ray-machine. - Proved The shelf pair automaton is not the multiplier-decomposition summand:
A(s,t)counts#{z in G_n : sz, tz in G_n}whileQ_n(s,t)inE(n) = T(n) + Sum Q_n(s,t)counts#{z : sz, tz in G_n}, andmin(s,t) = 1forces the two to agree, sinces = 1makes the first carry stay zero and drives every admissible digit intoG; an exhaustive census atn = 9of all 33552 ordered off-diagonal collinear pairs shows 482 of the 2656 active ordered multiplier pairs disagree, 2540 pairs (7.57%) having a witness off the gasket, the extremes(41,122),(122,41),(122,123),(123,122)with 50 witnesses each and none inside; independent re-enumeration reproduced the census from scratch. Witness: gasket-ray-machine. - Verified The spectral gap survives that correction but its ceiling below 2 does not: the free-digit automaton
B(s,t), readingzover all of{0,1,2}^2, has radius 3 on exactly(1,3),(1,9),(1,27), nothing in(2,3), and exactly 2 on the same twenty pairs over all 829 coprime pairs withmax(s,t) <= 52, by the same exact Faddeev-LeVerrier charpoly and nonnegative-shift certificates; its largest radius strictly below 2 is1.8488475886485on(4,13),(4,39),(12,13),(13,36), against theAceilingtheta = 1.6956207695598, the real root ofx^3 - x^2 - 2, which 44 strictly-sub-2 pairs reach or beat in the sharp split 19 strictly abovethetaand 25 exactly at it, the latter carryingx^3 - x^2 - 2as a charpoly factor and the former never, with live sets reaching 167 states at both(25,52)and(31,40)against 33, so the claim thatBmatchesAitem for item is Refuted; the eigenvalue-free witness isB(4,13)having 4583352807133551 closed paths atn = 60against1.6956207695598^60 < 5.76e13. Witness: gasket-ray-machine. - Verified The
n = 9active-pair census, previously claimed with no generator on disk, is 2656 ordered coprime multiplier pairs and 1328 unordered, 14 ordered of them the shift pairs(1,3^j)and(3^j,1)forj = 1..7;E(9) = 52212,T(9) = 18660,S(9) = 17656,R(9) = 15896, on 12170 occupied non-fibre rays carrying 18660 points, largest multiplier2460 = floor(3^9/8), andA(s,t)return counts agree with brute force on all 1328 unordered pairs;E(n)andR(n)are regenerated forn = 1..12, filling the skipped levelsR(9) = 15896andR(11) = 124928, and an independent re-enumeration reproduced both lists. Witness: gasket-ray-machine. - Conjecture The blocking lemma for the Pair Census Bound is
Sum over non-shift primitive rays M_n(a,b)^2 = o(3^n): the shift rays are closed at((13+5 sqrt5)/11) phi^(2n)and carry between0.65and0.84ofR(n)atn = 6..12, so between a sixth and0.35ofRis untouched; on the multiplier side that residue is a sum over non-shift active pairs numbering10, 30, 106, 332, 1010, 2642, 7564, 20934, 57858atn = 4..12, growth about2.77a level with largest multiplier exactlyfloor(3^n/8), solambda <= 2per pair buys nothing without a constantC(s,t)summable against that count. That per-pair summability is now Proved dead by construction and the door is restated in the witness coordinate as Conjecture W sharp,R(n) = O(phi^(2n)), with the weight-four orbit and the shift family both closed and only summability over the witness weight owed. Witness: gasket-ray-machine.
Half-ball chords
- Verified The half-disk chord constant (Zerr) decomposes into an integer and an area:
P(the chord through two uniform points of the upper unit half-disk crosses the diameter) = I_diam/(3 Area(H)^2)by Blaschke-Petkantschin, the flat-face chord-cube integral is the integerI_diam = 4andArea(H)^2 = Pi^2/4, giving16/(3 Pi^2); the whole computation collapses toIntegral_(-1)^(1) (-a u + sqrt(1 - a^2 + a^2 u^2))^3 du = 2for everya, the even part of the cube being the exact derivatived/du [u (1 - a^2 + a^2 u^2)^(3/2)]withR(+-1) = 1, checked by the exact derivative, by differentiation under the integral ina, at 50 digits on 50 values ofa, and with a symbolic residual of exactly zero at every step. Witness: lab/py/half-ball-mismatch. - Conjecture The mismatch theorem: a design's coprime density equals a half-ball flat-face probability at
dim = d = 2and nowhere else, since design densities are rational multiples of1/zeta(dim)while Version level givesrational/Pi^2at evendand a pure rational at odddand Version H givesQ + Q/Pi^2at evendandQ + Q Piat oddd, so evendim >= 4is blocked by Lindemann anddim = 3against Version level by Apery, both unconditionally;dim = 3against Version H is conditional onzeta(3)not being algebraic overQ(Pi), odddim >= 5onzeta(dim)irrational (Rivoal and Zudilin give it only for infinitely many odddim), and thedim = 2uniqueness half is numerical, 11 base-2 and 502 base-3 designs against every Version level value tod = 24, base-2 numerators4, 16/3, 6, 8, exactly one match,16/3atd = 2carried by 3 designs. Witness: lab/py/half-ball-mismatch; coprime-density-above-dimension-one; A395134. - Conjecture The Version H half-ball family,
duniform points and the hyperplane through them, has exact values4 - 19845 Pi/16384atd = 3,4 - 549978112/(14189175 Pi^2)atd = 4and16 - 178919214166875 Pi/35184372088832atd = 5, so odddcarriesPi^1where Version L carries a pure rational, by an unoriented-normal Blaschke-Petkantschin reduction integrated in closed form, quadrature at 60 against 80 digits agreeing to2.3e-62,7.2e-64and1.5e-63, and an independent10^8-sample random-point estimate whose deviations2.39e-6,-6.74e-6,-3.55e-6sit inside one sigma of3.96e-5,2.6e-5,1.54e-5;d = 6andd = 7are exact too,16 - 10363195833496113250304/(65656392092180764875 Pi^2) = 0.0074784083and64 - 403492347953923610203877211975 Pi/19807040628566084398385987584 = 0.0021206659, so the parity law "evendgivesQ + Q/Pi^2, odddgivesQ + Q Pi" rests on six terms and no proof. Witness: lab/py/half-ball-mismatch. - Conjecture No Euclidean body reproduces the bracket: a sweep of composite bases finds
B(F)taking1/2, 5/8, 3/4, 7/8, 1across twenty-five base-4 designs of identical dimension1.5, soB(F)is where a design's geometry lives, but no body whose chord-power integral reproducesB(F)was found, and the mismatch theorem makes the search futile abovedim = 2; a failed search, not a proof of nonexistence, and the base-4 sweep has no generator in lab/. Witness: lab/py/half-ball-mismatch for the futility only.
Hexagram provenance
- Verified The hexagon-triangle substitution matrix
[[6,1],[6,3]](an encoding of published prose, "replace each hexagon with 6 hexagons and 6 triangles, and replace each triangle with 1 hexagon and 3 triangles", not a published matrix) iterated from(1,0)gives1, 6, 42, 306, 2250, 16578, the A299916 row term for term, by matrix iteration and by the(9,-12)recurrence alike; one side counts tiles and the other holes, so the shared row is not by itself an identity of objects. Witness: A299916; slice-recurrence-order. - Conjecture No peer-reviewed source states the hexagram count: the upstream is a photograph, a video, three blog posts and one OEIS comment, and the one peer-reviewed item upstream, the Bridges proceedings paper on three-dimensional diagonal cross-sections of four-dimensional sponges, states the cut and the star-of-David holes but gives no count and no sequence (its full text searched for
hexagram,A299916,306,2250and1.8184). - Conjecture The hexagram slice is not scooped at any base but 3: the adjacent published work generalises the cut along dimension
nand a type-khole parameterM^n_kor draws it on a different solid, fixed to the base-three expansion throughout, and none of it treats base 5, 7 or 9; the sequel on pentagon, dodecahedron and 120-cell slices frames the Menger slice as a two-tile closed fractal family and names the directed-graph iterated function system, the same structural reading atbase = 3, so the correct statement is "generalises along dimension and hole type rather than base". - Conjecture The seed's anchor is self-confirming and cannot falsify anything: "regenerate the A299916 row from two independent generators" holds whether or not the slice's object is A299916's object, since two generators of the same tile census agree by construction (matrix iteration and the
(9,-12)recurrence agree exactly so); the real cold check is reproducing the matrix[[6,1],[6,3]]from the published prose.
Integer census and avatars
- Conjecture No geometric observable beyond dimension tracks Robin's inequality along the colossally abundant numbers: over the first 50 the Robin ratio is governed by
dimalone (Spearmanrho = 0.9906on indices 13-50, adjustedp = 2.93e-32) while the fill polynomial adds nothing (normalized-fill coefficient 0.0190,p = 0.649, AIC worsening from-116.34to-114.56), because every exponent equal to 1 contributes zero to(a_i - 1), so a new largest prime raisesdimand doubleskwhile fixing every nonzero coefficient, the maximum nonzero degree being 6 whiledimreaches 34; 38 dependent points over6 <= dim <= 34are a corridor, the fit1 - R = 0.03611 exp(-0.03089 dim)atR2 = 0.960is descriptive only, the ratio is not monotone (minimum0.964531at index 13,n = 21621600, 5 of 37 later transitions non-increasing), and nothing here bears on the Riemann hypothesis. - Conjecture 10 is the smallest positive integer that never occurs as a base-2 design fill count at side number 2, the fill counts through 1000 being
1, 2, 3, 4, 5, 6, 7, 8, 9, 16, 25, 27, 32, 36, 49, 64, 81, 125, 128, 216, 243, 256, 343, 512, 625, 729; fill 10 does occur at side 4 for a base-3 2D design; the catalog behind the original count had no generator. - Refuted The
dim = 4integer census has 350 qualifying signatures among 65536 designs - there are 12 distinct qualifying signatures,A000070(4), realized by 504 oriented designs of which 503 havek >= 2, meeting 33 fullB_4classes; 350 is none of 12, 504, 503, 402 or 33 and has no recoverable definition. Witness: divisor-avatars, A000070. - Refuted The census lock predicate identifies 13 designs - it identifies 14: 9 on the P5 clause (62, 94, 110, 118, 122, 124, 188, 218, 230) and 5 on the edgeless clause (128, 134, 146, 148, 150), the recount to 13 dropping code 128,
F = {111}, origin-free, edgeless, containing 111, of size 1. Witness: lab/py/fill-polynomials.
Kronecker word order
- Verified Boundary is order-blind at word length 2 and order-sensitive from length 3: on the
4 x 4grid only the four central cells can be interior and their requirements pair up under the factor swap,(S_1, S_4)against(S_4, S_1)and(S_2, S_3)against(S_3, S_2), so interior and hence boundary is symmetric in the two factors, exact on all 256 code pairs with the interior formula matching direct computation on all 256; at length 3 it fails on 36 of 210 multisets over the ten-code library of every code of fill 2 or 3. Witness: lab/rs/magic-words. - Verified Connected components of a mixed Kronecker word are order-sensitive, with minimal witness the multiset
{3, 6}:comp(A_3 (x) A_6) = 4againstcomp(A_6 (x) A_3) = 2, both factors of fill 2, because the inner tile's contacts decide whether adjacent outer copies merge (A_6is two isolated cells with no boundary contact, so four cells stay apart, whileA_3is a connected vertical pair sitting in two non-adjacent outer copies), enumerated by two independently written renderers, the study's substitution pass and the crate's Kronecker factory, agreeing cell for cell. Witness: lab/rs/magic-words. - Proved The
fill = 2designs at base 2,dim = 2split into adjacent (codes 3, 5, 10, 12) and diagonal (codes 6, 9), and commutativity of the component count follows the split: adjacent times adjacent commutes, diagonal times diagonal gives 4 in both orders, and adjacent times diagonal never commutes, always 4 against 2, by contact geometry, the diagonal pair having neither a face-adjacent cell nor a contact in either direction, and on all 15 pairs among the six codes with zero violations. Witness: connectivity.md, lab/rs/magic-words. - Verified Any two designs with
fill >= 3at base 2,dim = 2commute and give exactly one component in either order, since every such tile is connected and carries both a top-bottom and a left-right contact, so every pair of adjacent outer copies merges through the inner tile and connectedness of the outer tile merges them all; exhaustive over the fourfill = 3tiles plus the full tile, all 10 pairs among codes 7, 11, 13, 14, 15. Witness: lab/rs/magic-words. - Proved Block reduction: every periodic schedule
(c_1, ..., c_p)^levelequals thelevel-fold self-similar product of its one-period composite tileA_(c_1) (x) ... (x) A_(c_p), of baseprod_i side_iand fillprod_i fill_i, by associativity of the Kronecker product alone, so periodic mixed words carry no new theory and the first genuinely non-stationary behaviour requires an aperiodic word; cell for cell on six test cases at periods 2 and 3 and lengths to 6, the study's flat rendering againstTensor::fractalof the composite. Witness: dimensions.md, lab/rs/magic-words. - Verified Contact counts of a mixed Kronecker word are exactly multiplicative,
h(A_w) = prod_i h(A_(c_i))andv(A_w) = prod_i v(A_(c_i))for the row and column contact counts, becauseL(A (x) B) = L(A) (x) L(B)on outer columns and rows and the inner product of Kronecker products is the product of inner products, so whether adjacent copies touch is order-blind and decided factor by factor even where the component count is not; induction on length, exact on all15^3words with zero mismatches, the correct strengthening of the length-2 boundary theorem. Witness: lab/rs/magic-words. - Verified The naive geometric transfer state for mixed products is unbounded:
kappa(A_w), the number of components meeting a contact position and so still able to merge with a neighbouring copy, reaches2^(level-1)on the familyw_level = (15^(level-1), 3), whose product is2^(level-1)disjoint full-width rows each meeting both the left and right column, from the full-tile Kronecker power, exact atlevel = 2..10, with exhaustive search over all 15 codes showingw_levelis a maximiser atlevel <= 4with maxima 1, 2, 4, 8; the same family's component count is exactly2^(level-1)too. Witness: lab/rs/magic-words. - Verified Order sensitivity of mixed products is exactly the noncommutation of the cocycle matrices: 14 of the 15 pairs of component-matrix classes fail to commute, the only commuting pair being the two zero-contact classes,
fill = 1and the diagonal pairs, whose matrices have rank 1 withM_(6,9) = 2 M_(1,2,4,8); the vertical and horizontal domino classes carry different matrices, so the representation sees more than the square's full symmetry group; checked on all 15 class pairs. Witness: lab/rs/magic-words. - Proved The scale dimension of a magic word over a finite alphabet is a frequency functional: log side and log fill of a prefix are sums of per-letter values from a finite set, so whenever each letter's frequency exists the ratio
log fill / log sideconverges to the frequency-weighted average, and in particular every uniquely ergodic word (Thue-Morse, period-doubling, Fibonacci) has a scale dimension equal to that average; open are finite alphabets without letter frequencies and all unbounded alphabets, where frequencies can exist while the dimension oscillates. Witness: magic.md. - Proved The fill assumption
lab/py/slice-ladder-controlsstates before printing its five staircase dimensions is discharged: the parity-carpet code at odd sidesidefillsE^2 + 2EO = side^2 - ((side-1)/2)^2withE = (side+1)/2andO = (side-1)/2, the octagonal fill3k^2 - 2katside = 2k - 1already on this ledger for the same rule, so the staircase dimensions stand without the assumption. Witness: magic.md, sequences.md. - Proved The hyperoctahedral group acts diagonally through the Kronecker product,
g . (A (x) B) = (g . A) (x) (g . B), because reflecting a mixed-radix coordinate reflects every digit at once, so a magic word canonicalises under one shared symmetry applied to all letters and never letter by letter. Witness: magic.md. - Proved Every value in
[0, log 8 / log 3]is the scale dimension of some word over the two letterscarpet(3)andc8(3): rational carpet frequencies by periodic words, irrational by Sturmian words, endpoints by constant words, all through the frequency functional. Witness: magic.md. - Proved The component count of a mixed Kronecker word is a rational series of Hankel rank 4: with
lambda = (1,0,0,0),gamma = (1,1,1,1)^Tand one4 x 4integer matrix per code in six classes,comp(A_w) = lambda M_(c_1) ... M_(c_level) gammaat every word, by the four transfer laws in the observable frame(gamma, h, v, phi)and induction from(comp, H, V, fill)(A_e) = (1,1,1,1); the same induction readsH,Vand the fill off the same matrices. Witness: connectivity.md THE JOINT SPECTRAL RADIUS OF THE COCYCLE, lab/py/jsr-schedules. - Verified Euler characteristic, boundary and holes of a mixed Kronecker word are rational series in the word, of Hankel rank 4, 8 and 11: there are
lambda,gammaand one matrix per code withphi(A_w) = lambda M_(c_1) ... M_(c_level) gamma, exhaustive on all 54240 words of length at most 4 over the 15 non-empty codes plus 120 seeded words of length 5 to 7, all four observables, zero mismatches, built by Hankel-basis elimination in exact rational arithmetic; the rank is unexplained, staying 4 while the geometric state grows like2^(level-1)and the component count reaches2 * 4^(level-1)on(15^(level-1), 6), the checkerboard and the largest component count any subset of the2^levelgrid can carry. Witness: lab/rs/magic-words. - Proved Only a trailing solid letter is a magnification:
A (x) full(n)replaces each filled cell ofAby a solid block whilefull(n) (x) Alaysn^dimcopies ofAin a grid, soc15(2), carpet(3)andcarpet(3), c15(2)differ cell for cell at equal side and equal fill. Witness: magic.md, mrlymath::bang::magic. - Proved A count along a periodic word satisfies a linear recurrence, being a fixed vector times the powers of one integer matrix in the rank-4 representation, so a match against a table of sequences is a recurrence and never an arithmetic fact. Witness: lab/rs/magic-words, connectivity.md.
Kronecker words
- Proved Fill, side, density and the main-diagonal count of a mixed Kronecker word are order-blind at every word length, the first three as products of per-factor quantities and the diagonal by
diag(A (x) B) = diag(A) (x) diag(B), exhaustive on all15^3words of length 3 at base 2,dim = 2; the whole anti-diagonal profile is order-sensitive on 99 of 105 multisets at length 2 over the 15 non-empty codes and on 204 of 210 at length 3 over the ten-code library of every code of fill 2 or 3, its peak on 23 of 105 and its support on 27 of 105, minimal witness the one-cell codes 1 and 2 with profiles(0,1,0,0,0,0,0)against(0,0,1,0,0,0,0); take the whole profile, never one coefficient. An earlier length-3 reading of 110 of 112 is withdrawn, not confirmed: 112 is the multiset count of an eight-code library that was never recorded, so the figure names no sweep anyone can rerun. Witness: lab/rs/magic-words. - Proved A decoration on a letter folds into a code: the fill swap renders the complementary code at every base and side, and at base 2 and odd
sidethe half turn of the rendered tile is the identity and a quarter turn is the render of the transposed corner rule, becauseside - 1is even. Witness: magic.md. - Proved A unit letter is a property of the code and the side together: at odd side
2k - 1a base-2 letter fillssum over its corners of k^(zeros) (k - 1)^(ones), so fill 1 forces one corner with every coordinate odd andk = 2, givingc8as the only letter of fill 1 at side 3 and a smallest fill of 4 at side 5. Witness: mrlymath::formulas::counting, magic.md. - Proved No periodic word carries irrational letter frequencies, a word of period
phaving every letter frequency in(1/p)Z, so at an irrational frequency vector the control for a schedule is the value of the frequency functional and never a periodic word. Witness: magic.md. - Proved A mosaic whose palette is the empty cell and one design is a magic pair
M (x) c, since the block at a mask site is the palette cell the mask value indexes, so a census over both families counts it once on the word side. Witness: mrlycore::cell::mosaic, mrlymath::bang::magic. - Proved Magic meets special at a plain tiling and nowhere else: every mask site of a special carries a block, so a special is a magic pair exactly when all its blocks agree, which is
full(f) (x) cat a constant mask or at a designcfixed by the quarter turn. Witness: mrlymath::two::geometry::special, mrlymath::bang::magic. - Proved The fill of a mosaic is linear in the mask histogram,
fill = sum_i h_i(M) fill(P_i)over disjoint blocks, collapsing to the product law of a word only at a palette of the empty cell and one design, so block reduction and the Kronecker law are given up the moment a palette holds two designs. Witness: mrlycore::cell::mosaic. - Proved A special is fill-invariant,
fill(special(M, c)) = f^dim fill(c)at a mask of sidefin any dimension: an orientation permutes the entries of a cell, so every palette copy carries the fill ofc, and the mask laysf^dimdisjoint blocks. Witness: magic.md, spot-checked by mrlymath::two::geometry test special_rotations_preserve_sum and mrlymath::three::geometry test orientations_preserve_sum_and_shape.
Levels and designs
- Proved The product law: for 1-periodic
f, gthe mean off(mx) g(nx)over the unit interval issum_j hat f(j n') hat g(-j m')withg = gcd(m,n),m' = m/g,n' = n/g, and the covariance is the same sum overj != 0; the parity specialisation returns1/15, 1/3, 1/3at(3,5), (3,9), (5,15)andgcd^2/(mn)at all 820 pairs to 40. Witness: lab/py/stack-levelscheck_parity. - Proved The base-3 carpet stack correlates 3-adically, not by gcd: the shadow at level
levelhashat f_level(k) = (-1)^k 2^level sin(pi k/3^level) prod_{i <= level} cos(2 pi k/3^i)/(pi k), zero exactly when3^level | k, soCov(f_level(mx), f_level(nx)) = G_level(m' mod 3^level, n' mod 3^level)/(m' n')withG_level(a, 3^level - b) = -G_level(a, b)andG_level(0, b) = 0; at level 1 the closed form is(2/9) chi(m') chi(n')/(m' n')withchithe character mod 3, exact at all 1600 ordered pairs to 40; the covariance vanishes whenever|v_3(m) - v_3(n)| >= level, and the 2D field carries the same zero set throughCov_2D = Cov_1D (M + (2/3)^(2 level)). Witness: lab/py/stack-levelscarpet_law_level1,carpet_kernel. - Proved Levels are products, not layers:
f_level(x) = prod_{i < level} f_1(3^i x), so a layer at levelleveland scalenis the product of level-1 layers atn, 3n, ..., 3^(level-1) n, withf_level(nx) <= f_{level-1}(3nx)pointwise and gap measure(2/3)^(level-1)/3; levellevel-1at scale3nis not redundant against levellevelat scalen,Cov(f_2(x), f_1(3x)) = 4/27againstCov(f_1(x), f_2(3x)) = 0. Witness: lab/py/stack-levelscheck_levels. - Proved Coprime independence is the half period's: the 1-periodic odd strip
p(x) = 1ifffloor(2x)odd carries covarianceg^2/(4mn), nonzero at 159 of the 490 coprime pairs to 40 and1/60at(3, 5), while the tree'schi_nat oddncarries(g^2 - 1)/(4mn), zero at every coprime pair;p(nx) = chi_{2n}(x), so this is the landed law read at even scales, a sharpening and not a break, and the prime detector is a statement about odd scales under the half-period sampling. Witness: lab/py/stack-levelscheck_parity. - Proved Design pairs at level 1: two base-3 one-digit-removed shadows correlate by
c/(27 m' n')withcin-6, -3, 3, 6, zero exactly when 3 dividesm' n', so no two base-3 designs are coprime-independent; a base-2 strip against a base-3 shadow correlates byc/(18 m' n')withcin-3, 0, 3, and the odd strip against the Sierpinski shadow is exactly zero at all 1600 scale pairs, because the centred middle-thirds indicator is even and the centred strip odd underx -> -x. Witness: lab/py/stack-levelsdesign_law_33,design_law_23. - Proved The parity layers are linearly independent: the Gram matrix
gcd(m,n)^2/(mn)over oddm, n <= 2K + 1has determinantprod_{k odd <= 2K+1} J_2(k)/k^2 = prod_{k odd} prod_{p | k} (1 - p^-2), fromk^2 = sum_{d | k} J_2(d)and a unitriangular incidence factorisation on the factor-closed odd set, exact atK = 1..12,11399736556781568/21994507608198125atK = 12, positive. Witness: lab/py/stack-levelscheck_gram. - Conjecture The carpet zero law is exact at every level,
Cov(f_level(mx), f_level(nx)) = 0iff3^level | m' n', and the cross-level lawCov(f_level(mx), f_{level'}(nx)) = 0iff3^level | n'or3^{level'} | m'likewise: Proved atlevel = 1from the closed form, Verified only overm, n <= 40andlevel <= 3, 14400 ordered triples with zero breaches and zero unpredicted zeros. Witness: lab/py/stack-levelscarpet_kernel,check_levels. - Refuted The gcd law and coprime independence hold outside the parity family: at base 3 level 1 coprime layers carry
(2/9) chi(m') chi(n')/(m' n'), witnessCov(f_1(x), f_1(2x)) = -1/9, a coprime pair, anticorrelated; the zero set isv_3(m) != v_3(n), not coprimality. Witness: lab/py/stack-levelscarpet_law_level1. - Refuted The carpet kernel is separable above level 1:
G_2(1,1) G_2(4,4) - G_2(1,4)^2 = 76/729, so notheta(a) theta(b)form exists atlevel >= 2and the level-1 character law does not lift. Witness: lab/py/stack-levelscheck_carpet.
Matched random control
- Conjecture A self-similar slab is not a better acoustic barrier than an equally sparse random one: at levels 2 and 3 the matched random mask blocks more in every comparison, four filled-cell counts per level, 96 of 96 at 12 seeds per cell with margins of 4 to 31 sd (tree
L3fractal0.3720against a random mean0.1446, sd0.0074), every fractal value reproducing exactly (carpetL2 0.3120 / L3 0.2548, net0.2999 / 0.2619, tree0.3023 / 0.3720, void0.3122 / 0.3642), so the suppression is carried by fineness and sparsity rather than by self-similarity; the repeat reused the same simulator and so tests seed-fragility rather than the physics.
Menger slice sources
- Verified Cook's 2011 slice code is a point-sampled raster, not an array-free predicate: the listing allocates a
side x sideinteger array, fills it by sampling the digit predicate and renders it, so the exact-census method is this tree's and not Cook's; its prose puts the normal through(1, 1, 1)while the listing sets(1, 1, 0.5). Witness: REFS.md. - Verified Hart 2012 is an exact citation for the diagonal Menger slice: the Simons Foundation page carries his byline, the title "Mathematical Impressions: The Surprising Menger Sponge Slice" and a photograph credit. Witness: REFS.md.
- Verified "The Marstrand value is the dimension minus one" is the wrong attribution for a plane cutting a solid in
R^3: Marstrand 1954 concerns plane sets and lines inR^2, and the hyperplane generalisation is Mattila 1975; both are almost-everywhere statements, so one maximally arithmetic plane landing above or below that value contradicts neither. Witness: REFS.md. - Verified A299916's Menger reading is not its definition: the entry's name is
a(n) = A299914(2n+1), offset 0, signature(9, -12), terms1, 6, 42, 306, 2250, 16578, its reference is number theory with no sponge in it, and the hexagram-hole geometry lives in one comment with one uploaded picture, which Wikipedia sources onward beside a newspaper article; it must be cited as a comment, never as the sequence's definition. Witness: A299916. - Verified Abel 2012 claims no proof of the base-3 slice dimension, only a computation, naming mass distributions and similarity graphs as routes to one, so every generalised dimension inherits that status. Witness: REFS.md.
Mertens stack
- Verified Weighting the Farey stack by
mu(n)renders a Mertens-type sum at every node,Sum_{k <= N/b} mu(kb)ata/bandM(N)atb = 1, and the log-space power spectrum ofM(x)/sqrt(x)shows the first eight nontrivial zeta zeros, detected at13.94, 20.90, 24.97, 30.19, 32.52, 37.74, 40.64, 42.97against14.1347, 21.0220, 25.0109, 30.4249, 32.9351, 37.5862, 40.9187, 43.3271, errors0.04to0.42inside one bin of width0.5806; the zeros are known to far beyond any precision a moire can reach, so this is a rendering and not a measurement. Witness: lab/py/mertens-meter.
Moment ladder and Lemma B
- Conjecture The moment ladder's rows above the tenth approach the wall and stop:
beta_0^(2K)reads0.447838092, 0.447904613, 0.447923402, 0.447928788, 0.447930346at2K = 12, 14, 16, 18, 20from Perron roots59307.487289, 532101.317617, 4784678.13057, 43051182.4466, 387432198.159, the twentieth row lying only6.42e-7below the universal wall2/(3 + log_3 5) = 0.447930987882; these are floating eigenvalues of exact integer matrices, not interval-certified, and the wall above them is separately settled and unaffected. Witness: lab/rs/dimension-one-ladder. - Proved The energy cap
E_2K(G_a) <= lambda_2K^aholds at every order with constant exactly 1, which is what turns a ladder rung from a growth rate into a master inequality: the carry box{-r,...,r}^2withr = floor((K-1)/2)is closed because a digit difference lies in[-K, K]andfloor((r+K)/3) <= rfor everyK >= 1, every walk from the zero state back to itself stays insideS, the strongly connected component of that state,M_Sis irreducible by the definition of a component and carries a self-loop at the zero state, hence is primitive with Perron rootlambda_2Kand positive right eigenvectoru, ande_0 <= u/u_0componentwise withM_S >= 0gives(M_S^a)_(0,0) <= lambda_2K^a; the attempt to break it looked for the constantC > 1a reducible matrix would force and found none, since the reduction to the component is free andlambda_2K = lim E_2K(G_a)^(1/a)is the component's own root, checked equal to the full matrix's Perron root at2K = 4, 6, 8, 10with the component sizes1, 7, 7, 19inside1, 9, 9, 25states and the ratiosE_2K(G_a)/lambda_2K^afalling monotonically to1, 0.942327, 0.790590, 0.643725ata = 6. Witness: lab/rs/dimension-one-ladder. - Proved The master bound at order
2Kis one formula for every rung: witha = floor(log_3(p/2)),d_K = ceil(log_3(K/2)), a digit window ofndigits withn >= 2aandb = min(a - d_K, n - 2a), Hoelder over three blocks of the digit window of lengthsa, a, bat exponents4K/(2K-1), 4K/(2K-1), 2KgivesL_n(p) <= p^2 3^(-((2K-2+kappa)a + kappa_2K b)/(2K)), the outer blocks interpolated between the exactL^2andL^4identities and the inner block supplied by the energy cap, both admissible sinceK 3^(a-d_K) <= 2*3^a <= p; the exponent gain exceedsaexactly whenbeta < kappa_2K/Lambda_2KwithLambda_2K = 2 - kappa + 2 kappa_2K, which is the rung formula, and the seam3aagainstnis the same at every order with the two branches agreeing atn = 3a - d_K, so the feared order-10 crossing does not exist; the adversarial pass tried to break it by hunting a violation over every prime5 <= p <= 199and2 <= n <= 24, running the order-10 block alone in its 833 applicable cases as well as the min over all orders, and found none, worst ratio0.7839at(p, n) = (11, 2)for the order-10 block alone and0.8755at(13, 4)for the min, and by hunting an uncovered or negative-gain case in the main range3a > noveretain0.001..0.1andn = 6..400, finding none, worst geometric sum over cap0.8630. Witness: lab/rs/dimension-one-ladder. - Proved The order-10 rung is unconditional and the exponent needs no root-finding to be trusted: with
Lambda_10 = 4.436585106, main-range decayLambda_10/10 = 0.443658511and geometric constant2/(1 - 3^(-Lambda_10/10)) = 5.1842rounded to6, the ladder readsSum_(z < p <= 3^((beta_0^(10) - eta) n)) T*_p(n)/3^n <= 2/z + 35 z^(1-kappa) + 40 * 3^(-(kappa-1)n/8) + 6 * 3^(-0.443658511 eta n)foreta in (0, beta_0^(10)),z >= 5,n >= 1, the first three terms being the unchanged order-4 bookkeeping; a Sturm count on the exact quarticx^4 - 7833x^3 + 7916949x^2 - 850684437x + 13054946580places no root above66641136626/10^7and exactly one root in the bracket of width10^-7below it, solambda_10 < 6664.1136626,kappa_10 > 1.985805792698andbeta_0^(10) > 0.447597813453, every digit truncated down, never rounded, so the short form printed everywhere is0.4475978; rows 12 through 20 stay Conjecture for a different reason, theirlambda_2Kbeing floating eigenvalues and not certified algebraic numbers, so the energy cap alone does not promote them. Witness: lab/rs/dimension-one-ladder. - Proved The dimension-one moment ladder has a tenth rung and the lower wall is
0.4475978, not0.446717: the exact 25-by-25 integer carry matrixM_10on the box{-2,-1,0,1,2}^2satisfiesE_10(G_a) = (M_10^a)_((0,0),(0,0))with first energies1, 4653, 28967859, 190911254427, 1270015973323281, 8461182216374750493(matched by direct convolution of the digit set ata = 1, 2, 3), its characteristic polynomial factors symbolically asx^6 (x-120)(x^2-450x+12231)(x^3-2190x^2+282096x-5186835)^2 (x^3-990x^2+116154x-2569725)^2 (x^4-7833x^3+7916949x^2-850684437x+13054946580), the Perron root is the largest root of the quarticlambda_10 = 6664.113662506, sokappa_10 = 1.985805792712andbeta_0^(10) = kappa_10/(2 kappa_10 + 2 - (3 - log_3 5)) = 0.447597813454, above the eighth rung by0.000880502992, with Holder block exponents20/9, 20/9, 10; "dimension one" means the similarity conditionlog(fill)/log(base) = 1at base 3 and not the base-2 gasket of density16/(3 Pi^2), and the order-10 three-block master bound with explicit constants and checked regime seams is now written, so the rung is a theorem and a re-proof of target-uniform Lemma B at that edge. Witness: lab/rs/dimension-one-ladder; lemma-b-pincer.
Odd-base slice grammar
- Verified The odd-base generalisation rests on a choice of solid: Cook's predicate "at most one coordinate in the middle third" and the
bang dim 3, code 23rule "at most one odd coordinate" agree atbase = 3(20 of 27) and nowhere else, atbase = 5filling4^3 + 3 * 4^2 = 112of 125 against3^3 + 3 * 2 * 3^2 = 81 = 4k^3 - 3k^2atk = 3, and there is no canonical base-5 Menger sponge. Witness: lab/py/odd-base-slice-grammar. - Verified In the comparison of the slice dimension against the dimension minus one, the dimension is the solid's own
log(fill)/log(base)and never the ambient 3: at the ambient 3 the value3 - 1 = 2exceeds all four slice dimensions1.8184, 1.6869, 1.8026, 1.7204and the mod-4 split collapses. Witness: lab/py/odd-base-slice-grammar. - Verified The four printed dimensions are consistent with the four printed rules and this is not evidence for either: the dominant roots
(9 + sqrt(33))/2 = 7.37228,(11 + sqrt(369))/2 = 15.1047,(42 + sqrt(612))/2 = 33.3693,(28 + sqrt(3556))/2 = 43.8161givelog(root)/log(base)of1.8183, 1.6870, 1.8026, 1.7204atbase = 3, 5, 7, 9, while4k^3 - 3k^2atk = 2..5gives20, 81, 208, 425and dimension minus one1.7268, 1.7304, 1.7430, 1.7544; a rule and its own dimension cannot cross-check each other. Witness: lab/py/odd-base-slice-grammar. - Proved The middle diagonal layer sits at coordinate sum
3(base-1)/2, odd exactly whenbase = 3 mod 4(3, 6, 9, 12atbase = 3, 5, 7, 9). Witness: lab/py/odd-base-slice-grammar. - Conjecture No definition of a "blow-up of 4" for the slice exists in this tree, so the phrase carries no claim.
- Conjecture The two-tile grammar closes at ten odd bases with a
2 x 2substitution matrix rational inbasewithin each class ofbase mod 4. - Conjecture That parity forces structurally different cells into the middle layer in each residue class, which is the mechanism of the mod-4 split.
Odd-side fills
- Proved At odd side
n = 2k - 1the residue split of an axis hasklow positions andk - 1high, so a base-2 flat design fillssum over its corners of k^(zeros) (k - 1)^(ones), and the six designs of the plane read as the polygonal numbers ink: low cornerk^2(A000290), treek(2k - 1)hexagonal (A000384), carpetk(3k - 2)octagonal (A000567), void2k^2 - 2k + 1centered square (A001844), corner and centre3k^2 - 3k + 1centered hexagonal (A003215), solid(2k - 1)^2odd squares (A016754);two_censusat sides 3 to 11 returns8, 21, 40, 65, 96for the carpet and6, 15, 28, 45, 66for the tree. Witness: mrlymath::formulas::counting fill polynomial, mrlydemo two_census, A000567, A000384.
Primes on a design
- Proved Primes on a design at
fill = base^dim - 1are primes with one restricted digit at basebase^dim: the Morton codex -> Sum_j (Sum_c base^(c-1) x_(c,j)) base^(Dj)mapsS_levelbijectively onto the integers at basebase^dimwhose digits lie in the image of the digit setF, the gasket base 4 missing 3 and the carpet base 9 missing 4; the gcd-prime reading is a positive-density count whenB(F) > 0and empty otherwise, base 32 on{0,4,...,28}^2havingfill = 64 > 32, (E), and every gcd divisible by 4; thex_1-prime reading is a sum-of-digits large deviation. Witness: coprime.md PRIMES ON A DESIGN. - Proved Lemma A' the window rate: for (E),
gcd(d,base) = 1and nonzerotin(Z/d)^dim,Prod_(l<level) f_l(t) <= c(base,fill)^floor(level/m_d)withm_d = max(1, floor(log(d/2)/log(base)) + 1), andord_d(base) >= m_dso it is never weaker than Lemma A; with a base parteandtnonzero mod the coprime partm, and|eta|_inf < base^(-2n/3)/(4 base dim (base-1)), the rate isc'(base,fill)^floor(2n/(3 m_d)), which is Maynard Lemma 8.2 in every dimension with an explicit constant and no consecutive-digit hypothesis; the hypothesis ontis sharp, the gasket atd = 6andt = (3,0)sitting at1/3at everylevel. Witness: lab/py/digit-transform-norms lemma, worst per-digit rate0.830915atd = 257overd <= 301against Lemma A's0.986514. - Proved The 2D Type I saves a power when
alpha_1* < dim/2, the dyadic blockd ~ Q_1costingfill^level (Q_1^(2 alpha_1* - dim) + Q_1^dim base^(level(alpha_1* - dim)))and the small moduli going to Lemma A': the carpet certified atalpha_1* < 0.8124givesSum_(d <= Q, gcd(d,3) = 1) |#{x in S_level : d | x} - fill^level/d^2| <<_A fill^level level^(-A)atQ = 3^(0.5938 level) level^(-C), and the gasket certified atalpha_1^- >= 1.0126,alpha_1^+ <= 1.1022closes the route,min_x Sigma_2 > 4.059204against 4 andmin_x Sigma_3 > 8.213932against 8 in interval arithmetic with directed rounding,Sigma_2(0) = (8 + 2 sqrt(5))/3exactly. Witness: lab/py/digit-transform-norms certify. - Verified The carpet misses the one-dimensional criterion at every order: base 9 missing 4 has
g(1) = 0.3437below27/77butg(3/2) = 0.1531,g(235/154) = 0.1457,g(1.6) = 0.1262,g(1.7) = 0.1031,g(1.8) = 0.0835against0.1473, 0.1397, 0.1179, 0.0884, 0.0589, a gap of0.0058on the printed pair ats = 3/2and0.005749in full, andg(3/2)moves0.154389, 0.153068, 0.152921over four, five and six digit-vectors, so windows do not close it. Witness: lab/py/digit-transform-norms moments. - Verified The gasket is out of reach at both numbers: base 4 missing 3 has
g(1) = 0.4820against27/77andg(235/154) = 0.3170against59/433, so no Type II range opens at any order computed. Witness: lab/py/digit-transform-norms moments. - Verified The componentwise route is closed at source: Chow, Varju and Yu Remark 6.1 puts the Fourier
l^1dimension below1/2for(b,a)in{(3,0),(3,1),(3,2),(4,1),(4,2)}by interval arithmetic atlevel = 2, so the base-3 design's coordinate marginals fall on the wrong side, while Proposition 2.4 puts base 4 missing 3, the base-2 gasket's Morton code, above1/2. Witness: arXiv:2402.18395v2 pp.25-26. - Verified The missing-digit criterion is unreachable for the carpet at every order: dividing by
2 - sthe criterion is the single inequalityg(s)/(2 - s) < (1/5)*(1 + c/2)on the transform's moment exponents, and for base 9 missing4the shift sandwich at a power certifiesg(3/2) > 0.149397andg(235/154) > 0.142274against the required0.147320and0.139667, with a monotone chain of orders anchored at the exactSigma_N^(2)(x) = (9/8)^Ncovering[3/2, 2)in 21 closed cells sharing endpoints and[1, 2)in 87; the pointwise deficit is at least0.001268over[3/2, 2)and the decisive cell re-derived independently atN = 5clears by0.000840. Witness: lab/py/digit-transform-norms criterion, with an independent recomputation by a digit-tree fold reproducing every printed digit. - Proved The two-missing-digit transform is
(base-2)^2 abs(hat F)^2 = K^2 + 2 + 2 cos(2 pi D t) - 4 K cos(pi S t) cos(pi D t)withK = sin(base pi t)/sin(pi t),D = a - c,S = a + c - (base-1), so a pair enters only throughabs(D)andabs(S); that implication does not run backwards,{0,2}and{0,8}atbase = 10reading(2,7)and(8,1)with equal transforms, and the collapse is generated instead by the reflectiond -> base-1-d, which flips both signs, together with the integer translation ofFavailable exactly when0orbase-1is excluded and identifying{0,c}with{0,base-c}, so the edge family is the one-missing-digit sets of a(base-1)-digit interval read at basebaseand the number of distinct transforms is(C(base-2,2) + floor((base-2)/2))/2 + floor(base/2). Witness: coprime.md PRIMES ON A DESIGN. - Verified That pair count reads
7, 16, 21, 31of the15, 36, 45, 66excluded pairs atbase = 6, 9, 10, 12, is reproduced by grouping every one of theC(base,2)pairs by its sampled transform at every base4 <= base <= 41, and sums to 2373 distinct sets over4 <= base <= 31. Witness: lab/py/digit-transform-norms pairs. - Verified The least base carrying a certified two-missing-digit set with
alpha_1 < 1/4isbase = 32at the interval class{0,1},alpha_1 in [0.2499087, 0.2499779]at four window digits, the same class atbase = 31reading[0.2518967, 0.2519717]; over4 <= base <= 31the machine certifiesalpha_1 > 1/4at 2363 of the 2373 distinct sets, closestbase = 26missing{2,23}at> 0.2502919, and the ten it cannot bracket from below all haveS = 0orD = base/2withbase/2odd, a shared shape and not a cause since the clearing headlinebase = 32missing{0,1}has a transform vanishing at all 29 pointst = j/30, with certified upper bounds0.2538899to0.2826357, above1/4. Witness: lab/py/digit-transform-norms pairs and pairfail. - Verified Against the bar
1/3a two-missing-digit set first clears atbase = 13, the interval class atalpha_1 < 0.3318819on three window digits withbase = 12above at all 31 of its sets to five, and the whole pair family clears frombase = 21on throughbase = 26, worstbase = 23missing{4,5}at< 0.3333284, every base4 <= base <= 20carrying a certified witness above1/3,base = 20by{3,11}at[0.3356579, 0.3356674]. Witness: lab/py/digit-transform-norms pairs pairclear pairsome. - Proved The digit-uniform bound holds at any excluded-digit count:
abs(hat F(t)) <= (abs(sin(base pi t)/sin(pi t)) + m)/(base - m), the level product expands with weightm^(N - card E)and telescopes to the same Dirichlet kernels, soa_N = m a_(N-1) + m Sum_(l<N) lambda_l a_(N-1-l) + lambda_Nand the growth root solves(z - m)(z - 1)^2 = m(c_1 (log base) z + gamma'(z - 1) + c_1 (z-1)^2/(base z - 1))on the exact Lebesgue inputlambda_l <= c_1 l log base + gamma' + c_1 base^(-l),gamma' = (2/pi)(gamma + log(8/pi)), givingalpha_1 < 1/4for everybase >= 649atm = 2with the chain failing at648, and125atm = 1and1873atm = 3, with32,105,230against1/3, certified at 120 bits; the coarserc_0 = 0.97form of the same chain needsbase^l >= 86and gives126atm = 1. Witness: lab/py/digit-uniform-bound pairs. - Proved The threshold
1/4is the Mertens bar: in the GRH chain steps 1, 2, 4 and 5 never name the digit set and only step 3 substitutes a digit-free kernel bound, so feeding the certifiedl^1exponent there givesabs(M_F(x)) <<_(base,eps) A_F(x) x^(alpha_1 - 1/4 + eps), that isA_F(x)^(1 - delta + eps)withdelta = (1/4 - alpha_1)/alpha_base > 0, and1 - b(a)in place of1/4under a zero-free half plane; steps 2 and 3 alone forcealpha_1 <= 1 - alpha_base + c_baseandgap_base(1) > 0is exactly1 - alpha_base + c_base < 1/4, so the old certificate implies the new condition and the wall can only fall. Witness: coprime.md PRIMES ON A DESIGN. - Verified That wall falls from
3690to34, on the interval certificates behind the one-missing-digit clearancealpha_1 < 1/4atbase = 34, at every35 <= base <= 125and by the uniform chain above. Witness: coprime.md PRIMES ON A DESIGN.
Robin corridor
- Conjecture The Robin corridor is orthogonal to Robin's difficulty, not merely hard: a design of dimension
dimis an integer of exactlydimprime factors and level raises the exponents, so the tree varies exponents at fixed prime support, while all of Robin's difficulty lives at growing supportomega(n) -> infinity; fixed support is the classical easy half, settled byprod p/(p-1)bounded against a divergentlog log, an obstruction read off the definitions. Witness: divisor-avatars.
Slice sign law in every dimension
- Verified The slice sign law holds on every computed range: the central diagonal slice of the
dim-axis base-3 Menger analog hassgn(slice dimension - (solid dimension - 1)) = (-1)^(dim+1)fordim = 2..50at 180 to 210 digits by two generators sharing no code, fordim = 2..100at 320 digits with 99 of 99 signs, and in exact rational arithmetic through the determinant formsgn det((fill/3) I - M_even) = (-1)^dimfordim = 2..40, withfill = 2^(dim-1)(dim+2)andM_eventhe reflection-even carry block of sizeceil(dim/2); base 5 alternates fordim = 2..15, all four tested non-Menger families alternate, off-centre heights keep the dominant eigenvalue;dim = 3givesx^2 - 9x + 12withrho_3 = (9 + sqrt(33))/2 = 7.372281againstfill/3 = 20/3,dim = 4givesx^2 - 11x - 66withrho_4 = 15.310708against 16 anddet = 14; the even half and the odddim != 1 mod 3half are proved on the shelf, and the classdim = 1 mod 3beyond the computed range stays open. Witness: slice-sign-even-half, slice-recurrence-order. - Verified The
dim = 3rung is the base-3 slice dimension: the carry automatonM[c, c'] = P[c + dim - 3c']printsM_even = [[6, 6], [1, 3]], trace 9, determinant18 - 6 = 12, characteristic polynomialx^2 - 9x + 12, exactly A299916's signature(9, -12), Perron root(9 + sqrt(33))/2andlog_3of it1.818410, against the dimension minus onelog_3(20) - 1 = 1.726833withfill = 20the sponge's surviving-subcube count; the anchor cuts one way only, saying nothing about higher rungs. Witness: slice-recurrence-order, A299916. - Proved The digit polynomial
P(t) = (1 + t^2)^(dim-1) (1 + dim t + t^2)hasB_dim(2k) = C(dim, k)andB_dim(2k+1) = dim C(dim-1, k),P(1) = 2^(dim-1)(dim+2),P(-1) = 2^(dim-1)(2 - dim),P(omega) = (-1)^(dim-1) (dim-1) omega^dim, and root-of-unity filtering gives the full carry matrix's exact row sumssigma(c) = fill/3 + (2/3)(-1)^(dim-1)(dim-1) cos(2 pi c/3); the row-sum identity holds in the carry orientationc -> (c + dim - s)/3and fails in the transposed even-basis orientationM_even[i,j] = B_dim(dim + j - 3i) + B_dim(dim - j - 3i)for everydim = 3..50, thedim = 3row sums being(12, 4)against the formula's(8, 6); the coefficient formulas hold atdim = 1..10three positions past both polynomial endpoints. Witness: slice-recurrence-order. - Proved The trace of the even carry block is
tr(M_even) = 3 dim 2^(dim-3)at odddimand3 * 2^(dim-2) - 1at evendim, reading2, 9, 11, 60, 47, 336atdim = 2..7; the even case's-1is real, starting atdim = 2where the matrix is[2]. Witness: slice-recurrence-order. - Verified There is no uniform spectral gap in the slice transfer matrix, so no fixed-epsilon proof of spectral separation can exist:
lambda_1/|lambda_2| = (dim+2)/(dim-2) + O(dim^-3), tending to 1, reaching1.068966atdim = 60and1.04081632653atdim = 100,1.0833...atdim = 50against13/12to2.58e-22, withlambda_1 ~ fill/3 = 2^(dim-1)(dim+2)/3and|lambda_2| ~ |P(-1)|/3 = 2^(dim-1)(dim-2)/3; the double-precision spectrum agrees with a 180-digit reference overdim = 2..50to worst relative Perron discrepancy2.3e-15, median4.7e-16, every eigenvalue numerically real overdim = 2..60, so any proof of separation must be uniform in a margin of order4/dim. Witness: slice-recurrence-order.
Spectral spacings
- Conjecture Every mrly fractal spectrum tested clusters rather than repels, excluding GOE and GUE, and the claim is "more clustered than Poisson", not "Poisson": two unfolding maps, both Laplacians and two independent pipelines to 4096 nodes, with random-graph and square-lattice controls separating first; a from-scratch rebuild on the Menger sponge
level = 2cell graph (400 nodes), Sierpinskilevel = 5andlevel = 6, normalised Laplacian, a degree-12 polynomial unfolder and a20 x 20square-lattice control givesP(s<0.5) = 0.689for the sponge against GOE's1 - exp(-pi/16) = 0.17828,0.830for Sierpinskilevel = 6and0.594for the square lattice; the band0.44to0.57under one unfolder does not reproduce under a third, and the sponge spectrum is 61.25% repeated eigenvalues at1e-9, soP(s<0.5) >= 0.61is forced by degeneracy and GOE exclusion is a corollary of degeneracy rather than an independent measurement. Witness: lab/rs/spectral-spacings.
Spin
- Proved The average of a picture over the
qrotations by2 pi / qkeeps exactly the circular harmonics of order divisible byq, the average over all rotations keeps order zero only, and a design of rotation ordergshowslcm(q, g)petals under a screen that turns itp/qof a turn per frame. Witness: mrlynum::spinthe_harmonics_read_the_rotation_order, spin. - Proved The rings of a spun square-lattice picture sit at
sqrt(n)forna sum of two squares with weightr2(n) = 4 (d1 - d3), silent exactly where a prime3 (mod 4)dividesnto an odd power, and their Dirichlet series is4 zeta(s) L(s, chi_4); the hexagonal rings carry6 zeta(s) L(s, chi_-3); the mass of a spun lattice is the Gauss circle count and Hardy's Bessel series for its error is the ring expansion. Witness: A001481, A004018, A003136, A004016, Hardy 1915, spin. - Proved The exact ring profile of a raster integrates to its fill,
int 2 pi r F(r) dr = fill,512.0at level 3 of the carpet; the carpet's profile is zero toside/6. Witness: mrlynum::spinthe_mass_of_the_profile_is_the_fill, mrlydemo fixture. - Refuted The coprime law survives the spin - flat layers at coprime odd scales are exactly uncorrelated, but their ring profiles over the inscribed disc correlate at
+0.38for(3, 5),-0.33for(5, 7)and+0.38for(9, 13), no better thangcdpairs; the cancellation is separable inxandyand the spin discards the angle. Witness: mrlylab testthe_coprime_law_dies_under_the_spin. - Proved The spin mass about the fixed point
p_d = d/(base-1)of a filled digitdobeysM(r/base) = M(r)/fillexactly, sinceS(x) = (x+d)/basecarries the design onto itsdpiece and divides the self-similar measure by the fill, soM(r) = r^dim G(log(r)/log(base))withGof period exactlylog base- the ripple's period is an identity and not a fit, valid forr/basebelow the distance fromp_dto the other filled cells, that isr <= sideat the corner digit andr <= side/2at the centre. Witness: mrlynum::spin::mass_within, the_spin_mass_scales_by_the_fill_about_a_filled_corner. - Verified The spin dimension read about the corner fixed point at level 6 over the window
27 <= r <= 729, three whole periods oflog 3, gives slopes1.465054, 1.649432, 1.783588, 1.761814, 1.897854, 1.879522, 2.000100for codes79, 95, 127, 239, 255, 495, 511against the exactlog(fill)/log 3, every gap at or below1.9e-2and the discretisation of the identity,max |M(3r)/(fill M(r)) - 1|, running5.3e-3to1.8e-2; the exact integer shell histogram and the crate profile integral agree to1.7e-6on the total and0.5%at partial radii. Witness: lab/rs/spin-census. - Verified The corner ripple separates both equal-dimension pairs of the census where every density reading is identical: at level 7,
127against239gives ripple gap0.11984on drift bar0.04126and255against the carpet495gives0.12042on bar0.01461, with the solid square as the rippleless control at swing0.00277under its own bar0.00578and a code against its mirror at gap0.00e0. Witness: lab/rs/spin-census. - Verified The spin spectrum
P_m,m = 0..12, read at levels 1 and 2 over all 511 nonempty base-3 plane codes, splits them into exactly 101 spectra, the number of nonempty orbits of the square group, with no pair outside one orbit agreeing to1e-9: within the family it is a complete invariant of the dihedral class and no spin-isospectral witness exists. Witness: lab/rs/spin-census. - Verified The ring-averaged powder of a design is not Porod: every sliding three-period window slope, over every fractal code at level 7 and at both pad 4096 and pad 8192, stays above
-2.28and so at least0.72from the-3of a sharp interface, while the solid square control slides from-2.75781to-2.35759, within0.25of-3and never near its own-dim = -2. Witness: lab/rs/spin-census. - Proved The Menger sponge at level
levelblocks every lattice line down its space diagonal that meets its bounding cube: the shadow obeysS_(level+1) = union_d (3 S_level + proj d), and along(1,1,1)the 27 cube digits and the 20 sponge digits project onto the same 19 classes, so the induction gives equality at every level, the count3^(2 level + 1) - 3^(level+1) + 1=19, 217, 2107, 19441, 176419. Witness: lab/rs/spin-census, A220978, A003215. - Proved The sponge's axis shadow is exactly the Sierpinski carpet,
8^levelagainst the cube's9^level, dimensionlog 8 / log 3 = 1.892789: the 20 sponge digits project along an axis onto the 8 carpet digits, disjoint modulo 3. Witness: lab/rs/spin-census. - Verified No direction other than the axis is deficient in the searched window - over the 13 directions with
0 <= a <= b <= c <= 3, read to level 4 against the cube, the axis is the only share that falls with the level, every other rising,(1,1,2)to0.98568and(0,1,2)to0.97090atlevel = 4. Witness: lab/rs/spin-census. - Proved A radius
sqrt(k)/nof the spun scale-nsquare lattice, read inside the disc of radiussqrt 2, is new atnexactly when no primep | nhasp^2 | k- the sum-of-two-squares condition at the smaller scale is automatic by a parity argument, so only integrality binds - and hencenew(n) = sum_(d | rad n) mu(d) B(2n^2/d^2)withBthe counting function of A001481, giving2, 3, 9, 11, 22, 18, 40, 38, 55, 52, 91, 64, 123, 97, 128, 126, 199, 136, 243, 180, the rule, the identity and a direct union agreeing at everynto 64. Witness: lab/rs/spin-census, A001481. - Proved The Gaussian Farey's local factor is the Jordan totient
J_2(n)/n^2 = prod_(p | n) (1 - 1/p^2), the square-lattice analogue of Farey'sphi(n)/n, approached from below at rate1/ln nbecauseB(X) ~ K X / sqrt(ln X): the radical-6 family climbs0.56250, 0.59813, 0.61126, 0.62594, 0.63276, 0.63801atn = 6, 12, 24, 48, 96, 192toward2/3. Witness: lab/rs/spin-census, A064533. - Proved The spin dimension about the raster centre is undefined for a design with an empty centre digit - the empty digit removes the open square of side
side/3about the centre and hence its inscribed disc, soM(r) = 0for everyr <= side/6and the centre-spun mass carries neither power law nor ripple over a whole factor ofbase. The bound is attained, in exact integer arithmetic on doubled coordinates rather than cell centres, which would returnhole + 1/2whatever the hole: the squared distance to the nearest filled cell is(side/3)^2 = 6561at level 5 for bothbang dim 2, base 3, code 239and the carpet495, that isside/6 = 40.5exactly, while79empties out to56.572962. Witness: lab/rs/spin-census. - Conjecture The near-degenerate corner ripples beyond the segment case: de-duplicated to transpose classes, the equal-fill class pairs sitting inside their own drift bar number 13 at level 6 and 6 at level 7, at gap-to-bar ratios
0.71to0.95, the tightest287against315at fill 6, gap0.03574on bar0.04543, two designs that differ by moving one cell from(0,2)to(1,2); six survive both levels,287-315,63-123,123-187,31-59,437-485,37-261, and the count moves with the level and the estimator, so the list is a phenomenon and not a census. The ripple's Fourier coefficient at frequency2 pi / log 3should be a linear functional of the digit set whose kernel is what collides. Witness: lab/rs/spin-census. - Conjecture The powder falls as
k^-dim- at level 7 with pad 4096 the slopes-1.37986, -1.51762, -1.73012, -1.83071, -1.97886, -2.00433sit within0.24of-dimover both pads, but the agreement is inside the instrument's own spread: sliding a three-period window a quarter period at a time moves the slope by0.16to0.45, and doubling the pad to 8192 moves127from-1.73012to-1.81607,255from-1.97886to-2.03225and the carpet from-2.00433to-2.12289, with no monotone approach to-dim. The log-periodic ripple is not resolved either, the folded residual swinging1.5to4.4inlnpower because the ring average of a lattice point set is spiked on the norms of A001481. Witness: lab/rs/spin-census. - Conjecture The axes are the sponge's only deficient shadow directions; the window checked is
|v| <= 3. Witness: lab/rs/spin-census. - Conjecture
new(n) sqrt(ln n) / n^2converges tosqrt 2 K prod_(p | n) (1 - 1/p^2)along each radical class,Kthe Landau-Ramanujan constant; the Mobius sum is proved butBhas no closed form, so the Gaussian Farey carries a transcendental constant where the Farey carries none. Witness: lab/rs/spin-census, A064533. - Refuted The corner ripple as a complete invariant of the transpose class - a design that is a solid segment has
M(r) = c rexactly about a fixed point on it, so its ripple vanishes identically, and code7, the solid row, and code273, the solid diagonal, are two such designs of dimension exactly 1 in different transpose classes carrying the same zero ripple; the census reads them at swings0.01114and0.01217and mutual gap0.01371, all discretisation, and no bar is needed for the conclusion. It does separate both named equal-mass pairs, at2.9and8.2times the drift bar. Witness: lab/rs/spin-census. - Refuted The Gaussian Farey counted by primitive representations in
Z[i]modulo units - the norms below2n^2with a primitive representation run2, 3, 6, 9, 13, 17, 23, 29, 35, 44againstnew(n) = 2, 3, 9, 11, 22, 18, 40, 38, 55, 52, agreeing only atn = 1, 2; primitivity is the wrong condition, since(3,4)is primitive and25is a square, sosqrt(25)/5 = 1is old at 5. The correct criterion is freedom from the squares of the primes ofn. Witness: lab/rs/spin-census. - Refuted The disc and the box read the same Gaussian Farey - restricting to
0 <= a, b <= ninstead of the disc of radiussqrt 2breaks the criterion atn = 3, witness the radius4/3:16is free of9and4/3 < sqrt 2, but16 = 4^2 + 0^2needs a coordinate above 3, and the box counts2, 3, 7, 9, 17, 14, 31, 27, 41, 38part from the disc counts fromn = 3on. Witness: lab/rs/spin-census. - Proved The spin spectrum reads a pair census and nothing else: for a constant-valued
0/1render on a raster of sidebase^level, everyP_mis a quadratic form in the cell indicators whose Gram matrix is constant on the orbits of the raster's symmetry group acting on pairs, because turning a pair bythetamultiplies both harmonic coefficients bye^(-i m theta)while a mirror atalphasendsc_mtoe^(-2 i m alpha) conj(c_m)and the phase cancels in the real part; soP_mis a linear functional of the pair censusPhi_leveland equal censuses force equalP_mat every order, ring count and truncation, the base-3 plane carrying 11 pair classes at level 1 and 461 at level 2 and the level-1 coefficients solved from 11 independent censuses reproducingmrlynum::spin::harmonicsat 1024 rings andm = 0..12on all 511 codes at worst relative residual1.14e-14. In dimension 3 the covariant object is the degree-lpower summed over its orders, not a single(l, m). Witness: lab/rs/spin-census shape, spin.md the spin spectrum is a quadratic form. - Proved The 101 spectra need level 2:
Phi_1takes exactly 97 values on the 101 nonempty base-3 plane orbits, four pairs lying in distinct square-group orbits with all 11 class counts equal, so each pair's level-1 spectrum coincides identically at every order and resolution; readingP_mat level 1 alone and bucketing greedily at1e-9returns 97 buckets, with45-105at gap1.30e-16and level-2 gap0.151,61-121at1.03e-17and0.0689,78-102at6.51e-17and0.253, and94-118at1.64e-16and0.105. Witness: lab/rs/spin-census shape, spin.md level 1 alone is not complete. - Verified The 13 orders see 9 of the 11 level-1 census directions, and the odd cap of 3 is exact: the half turn
rhois itself in the square group and acts trivially on classes, but half-turning one member,tau: {j, k} -> {rho j, k}, is well defined on classes becauserhois central inD4, andg_(m, rho j) = (-1)^m g_(m, j)givesQ_m . tau = (-1)^m Q_m;taufixes 5 of the 11 classes, so the antisymmetric part has dimension(11 - 5)/2 = 3and no number of odd orders can exceed rank 3, which the six odd orders reach exactly while the seven even orders reach the proved cap of 6. The level-1 spectrum is strictly coarser than the census it factors through and splits it into the same 97 classes anyway. Witness: lab/rs/spin-census shape, spin.md the 13 orders see 9 of the 11 census directions. - Verified The completeness is not about base 3, as a statement about the census: over all
2^25base-5 plane codes the level-1 pair census takes3993511values on the4211743nonempty square-group orbits with204856ties over423088orbits and largest tie 8, and over all2^27base-3dim = 3codes it takes1461693values on the2852287nonempty orbits of the order-48 cube group with757066ties over2147660orbits and largest tie 32, and every tie breaks at level 2, the budget-capped weight window failing to bind and covering every group, all204856out to weight 21 and all757066out to weight 24 against level-2 censuses of 24805 and 6325 classes, with the canonical counts matching the Burnside averages4211744and2852288computed from the cycle index in the same pass. Witness: lab/rs/spin-census shape, spin.md the completeness is not about base 3. - Proved The level-1 rank cap is 9 overall, 6 even and 3 odd; the odd cap of 3 is the known
tauargument, the even cap of 6 and the total of 9 are new and supersede the earlier even bound of6 of a possible 8. The common kernel of the coefficient vectorsQ_mon the 11 base-3 pair classes holds the corner-centre basis vector, since the centre cell's farthest point and a corner cell's nearest point are both atr = sqrt2/6, so the two radial supports meet only in that null set and the integral vanishes at every order; and it holds(4, 16, 8, 8, 16, 4, 4, 8, 8, 4, 1)less9in the centre-centre slot, since the raster is similar to its own centre cell at ratio1/3andP_m(S/3) = P_m(S)/9. Both aretau-symmetric, so odd caps at3and even at6. Witness: paper spin-harmonics Theorem 5.4, scripts/verify.py blocks 6 and 7. - Verified The three caps are attained, on closed-form cell arcs and tanh-sinh quadrature rather than the 1024-ring discrete transform of the tree:
5and19exactly located radial segments at113nodes give rank9, even6, odd3atm = 0..12, stable from1e-9to1e-13, smallest pivot1.878e-4against largest coefficient9.806e-2; the Gram matrix is constant on the 11 classes to1.44e-17and on the 461 level-2 classes to1.52e-18under both generators of the square group, a quarter turn and a reflection; the same pass returns97level-1 and101level-2 spectra over all 511 codes, every level-2 bucket one orbit. Witness: paper spin-harmonics scripts/verify.py blocks 5, 7, 9 and 10. - Proved The four base-3 homometric pairs are two pairs and their centre augmentations, and homometry alone forces it: classes 0, 6 and 10 of the level-1 census are the self-pairs of a corner, an edge cell and the centre, so homometric designs already share their corner count, their edge count and their centre occupancy, and adjoining the centre to two that avoid it adds the corner count to the corner-centre class, the edge count to the edge-centre class and
1to the centre-centre class:61 = 45 + centre,121 = 105 + centre,94 = 78 + centre,118 = 102 + centre, the augmented censuses reading2, 2, 1there against0, 0, 0before. Witness: paper spin-harmonics Lemma 4.4, scripts/verify.py block 3. - Verified The 13 orders are a genuine truncation, and the solid square is the design the truncation flatters most: at level 1 the orders
m = 0..12hold0.977541of the solid square's angular energy against the exact Parseval total1, the largest share over all 511 codes, tied only by the lone centre cell code16whereP_m(S/3) = P_m(S)/9forces it, while the smallest is0.899436at the four one-corner codes1, 4, 64, 256, so every design spills at least2.2percent into the unread orders and some spill10. Witness: paper spin-harmonics Fact 6.3, scripts/verify.py block 11.
Stacked hexagon moire
- Verified The Walsh law's
1/nand1/n^2coefficients follow from plane counting: the planex + y + z = 6n - 2,zeven,0 <= x,y,z < 4nat odd scalensplits by macro parity into counts that depend only on the weightk,N_k(2h+1) = [t^(3h+1)](1 + 6t + t^2) E_h(t)^(3-k) O_h(t)^kwithE_h = 1 + t^2 + ... + t^(2h)andO_h = t + t^3 + ... + t^(2h-1)extracts all four exact quadratic quasipolynomials by finite binomial calculation, and ink is linear in the eight counts, so only the constant,1/nand1/n^2orders survive the normalization; exact by direct enumeration of the plane at every oddn <= 55, all eight macro-parity triples, 28 layers, zero discrepancies; the crate rebuilds only the ink, at codes 23 and 11 overn = 1..11, wherem_3 = 0leavesN_3(n)unexercised, so the eight-triple split stays the lane's. Witness: walsh-spectrometer, mrlydemo::walsh_spectrum. - Conjecture Layer alignment of the hexagon stack is imperfect by construction: the transparent grid fraction of the common box grows from
0.000atn = 1to0.245atn = 55, so 24.5% of the box differs between the smallest and largest silhouettes, and ray scans on the triangular lattice are aliasing-limited below band half-width~0.01. - Conjecture The adjacent-pair limit is
-11/135 = -0.0814815(lab/rs/hexagon-moire measures-0.08116at(199, 201)and-0.08150at(249, 251), with residue oscillation) and the gcd-echo limit is29/135 = 0.2148148(lab/rs/hexagon-moire measures+0.21473at(67, 201)and+0.21476at(99, 297)); both are numerology-grade fits and each needs its lattice integral. Witness: lab/rs/hexagon-moire. Superseded:-11/135and29/135are exact by the phase-map integral, see the layer-pair row under Diagonal slice stack in SETTLED. - Conjecture The carpet star's exact decay rate, the coefficient on
(ln L)/L, is open: one frame measures-1/8and another-0.18. - Conjecture The exact doubling constant of the stack is
253/2160, matching the two independent branch extrapolations to2.6e-6and2.2e-6where19/162fails at1.57e-4; a derivation is missing. Witness: lab/rs/hexagon-moire. Superseded: the constant is exactly253/2160by the phase-map integral, see the layer-pair row under Diagonal slice stack in SETTLED.
The 2-adic Smith cascade
- Verified The Smith layers are a Jacobsthal cascade and the excess anticorrelates with the tent: full 2-adic profiles at every odd
dim = 5..511(254 rows) - octave maxima ofL_2 = #{a_i >= 2}are exactly the Jacobsthal numbersJ(k-2)(aboutn/6) and ofa_maxexactlyfloor(log_2 dim) + 4on octaves 3 to 8, octave 2 (dim = 5, 7) readingL_2 = 1againstJ(0) = 0anda_max = 7against 6,L_4 <= 1and every non-spike divisor hasa_i <= 3(L_5 = 1at 233 of 254 rows, the spike alone), and the min-of-cones consequences of per-layer tents (interior local minima 1, 1-Lipschitz in steps of 2, no plateaus off 1) hold at layers 1, 2, 3; the excessX = v_2 - nullitygrows linearly (octave maxima6, 6, 7, 8, 10, 17, 28, driven byL_2) but peaks at the tent troughs, so the sum stays small:v_2 <= ceil(n/3) + 9at every odddim = 5..511(per-octave slack5, 5, 5, 7, 7, 9, 9, growing likelog_2 dim, extremaldim = 255, 257, 511),v_2 <= nat every odddim >= 9(equality only at9, 15, the only violationsdim = 5, 7), and in the classdim == 1 mod 6(84 rows,13..511)v_2 <= n - 3 < dim - 1everywhere (max ratiov_2/(dim-1) = 7/18atdim = 19only,1/3atdim = 13), hencerho_dim > fill/3strictly at every odddim <= 511; the reading "v_2 <= ceil(n/3) + 13fails atdim = 511" is arithmetically false (95 < 99), what died is the tent-plus-excess split, the object to bound being the sum; growth laws beyonddim = 511are unproved. Witness: lab/py/smith-cascade. - Verified The layer-2 window law: the second 2-adic Smith layer of
M_even(base 3, odddim = 2R+1) is a divisor-plus-ceiling window on the kernel family - withH_i = x^s(1+x^3)^i(1+x)^(2^b),b = ceil(log_2(3R-1)), and kernel elements as coefficient polynomialsc(z), the mod-2 kernel vectors that lift mod 4 formV_2 = {c : g_dim | c, deg c <= C_dim},L_2 = C_dim - deg g_dim + 1, with generatorg_dim = z^m c_t(z^(2^e))(c_ttheF_2Fibonacci polynomials),N = 2t+1 = J(k)Jacobsthal,k + e = b - 1; via the dictionaryu^t c_t((1+u)^2/u) = 1 + u + ... + u^(2t)the x-side generator block is the odd-length repunitRep(N, 2^e)(x^3)of zero(1+x)-valuation, which is why a pure valuation threshold (31/49) and a one-sided ideal (41/49) both fail; Law E givesg = |2R - 2^(b-1) - 1|,e = min{e >= 1 : J(e) >= (g+1)/2},m = max(0, 2w - c(e)),L_2 = min(w+1, c(e)+1-w)withw = C_dim - t 2^e,c(e) = 2J(e-2) - 1, deriving theL_2min-of-cones tent of heightJ(e-2)with octave peaksJ(b-4); the explicit elementH_2 = x^s(1+x^3)^(i_0+2m)(1+x^(2^b))Rep(N,2^e)(x^3)is derived from the Frobenius identitypsi^(2^e) = (1+u^(2^e))^2/u^(2^e)and lifts mod 4 at every row; the mod-4 symbol isP == [(1+t^4)^R + 2Rt^2(1+t^4)^(R-1)](1+Dt+t^2);C_dim = Kat 174/199 rows with deficits in2J({2..5})constant per(b,e)slot, two trial ceiling laws failing atdim = 249andb = 9; 199/199 at odddim = 5..401and 60/60 atdim = 403..521, withN = 43 = J(7)appearing atdim = 257, 259andN = 85 = J(8)at theb = 10peakdim = 513; a peak staircase breaks atdim = 237(nontrivialRep(3,32)atb = 9, invisible below by theJ(1) = J(2) = 1collapse), the block-size identity3J(k) = 2^k - (-1)^kis a tautology, and the family exponentfloor(log_2(4R-1))is wrong at 57/99 rows. Witness: slice-sign-even-half, smith-window. - Verified
det(m_full) = det(m_even) * det(m_odd)exactly, at every base and both parities (the core commutes with carry reflection by palindromy, the symmetric and antisymmetric blocks are the even and odd conventions, conjugation preserves determinants; by Bareiss todim = 101), sov_2(det m_even) <= v_2(det m_full)and the strictness targetv_2 < dim - 1can be attacked on the core, whose mod-2 kernel is the one-generator shift module; the core is the coefficient-extraction mapE: X -> ([x^(3j+1)](PX))ondeg X <= 2R, in polyphase coordinates the striped Sylvester matrix of(P_1, P_0, yP_2)(exact overZatdim = 5..13), so the window module is a bounded syzygy module, rank-2 free by Hilbert-Burch, anddelta_1 + delta_2 = 12R + 5is the syzygy degree identity, which is why it holds at 400 random symbols. Witness: slice-sign-even-half. - Verified The cascade holds across
[512, 2048)with two fresh octaves attained on the nose:max L_2 = J(k-2)at exactlydim = 3*2^(k-1) + {1,3}(43 at 769/771, 85 at 1537/1539),max L_3 = J(k-4)(11 at 705/707 and 833/835, 21 at 1409/1411),a_max = floor(log_2 dim) + 4(13 at 1023, 14 at 2047),L_1 = tent(dim)at every row through 2047,v_2 <= neverywhere (worst 0.37); at anL_jmaximiser the profile is a flat blocka_i = jplus onea_maxspike, maximiser sites scaledim -> 2 dim - 1, and the cascade stacks at tent troughs (L_1 = L_2at 767/769,L_1 = L_2 = L_3at 701..707), soXpeaks at stacking sites (51 at 767/769), not at the tent troughs (X = 7, 3at 683/685); at2^k - 1sitesX = v_2 - L_1 = a_max - 1, whilev_2 - ceil(n/3)extends5,5,5,7,7,9,9,11as...,11,11, not...,11,13(they part at 2047 whereL_1 = 340 < 342, tail[1^339, 14]); hencerho_dim > fill/3strictly at every odddim <= 583plus685, 703, 769, 1021; all 42 adjudicated rows agree between two eliminators sharing no code,dim = 1409at precision 512. Witness: slice-sign-even-half. - Verified Base-5 exceptional-class strictness is exact to
dim = 511:v_2(det M_even) < 2(dim-1) <= v_2(fill)at everydim == 1 mod 5- odd classdim = 11..511complete (51 values,v_2running 2..105 against thresholds 20..1020, smallest margin 143), even classdim = 166..506joining6..156(35 values, smallest margin 307) - sorho_dim != fill/5throughout, the range extended from 80; 10 spot rows spanning both classes agree with an independent eliminator onv_2and full profiles, and the matrix builder agrees entrywise with the graph-search construction at all 10dim. Witness: slice-sign-even-half. - Verified The ceiling law: with Law E's slot data (
b = ceil(log_2(3R-1)),g = |2R - 2^(b-1) - 1|,e = min{e >= 1 : J(e) >= (g+1)/2},k = b-1-e) the ceiling deficit isK - C_dim = 2J(e-1)iffkis even, else0-k >= 1for everyR(slot-endpoint identityg_max = 2J(b-2) - 1, exact forb = 4..60, nok <= 0row toR = 60000), so ak >= 2guard is vacuous, the rowsdim = 23, 87once read ask = 0aree = 3, 5withk = 1(deficit 0 by parity), anddim = 1367isb = 11, e = 9, k = 1, deficit 0;e = 2never occurs; 259/259 at odddim = 5..521and 643/643 atb = 3..13,dim <= 4779(the fullb = 11octave of 342 rows plus theb = 12, 13boundary slots), by a Smith-free extraction with no precision parameter; never-seen deficits predicted and attained:42 = 2J(6)on the whole slotdim = 429..471, 10 on493..503, 2 at511, 517, 0 at the peak,86 = 2J(7)on all 84 rows of theb = 11slot(e,k) = (8,2),170 = 2J(9)atb = 12,342atb = 13; realised deficits{0, 2, 6, 10, 22, 42, 86, 170, 342}, 152 of 212 nonzero-deficit rows nondegenerate (L_2 > 1), theb = 12peak givingN = 341 = J(10); soL_2(dim)is a closed function ofRalone through Law E plus the ceiling law. Witness: slice-sign-even-half, smith-window. - Verified The arithmetic amplitude law:
max L_jin octave[2^k, 2^(k+1))equalsJ(k + 2 - 2j), attained atdim = 2J(k+1) + 3 + 2(J(k+2-2j) - 1)with the flat-block-plus-spike profile[j x (J(k+2-2j)-1), spike]- 13/13 atk = 6..10,j = 1..4, includingdim = 689(octave 9,L_4 = 3, tail[4,4,6]) anddim = 1377(L_4 = 5 = J(4), block4x4+7); each octave carries two block towers, amplitudesJ(k-2j+2)at the upper trough andJ(k-2j+1)at the lower; thek = 10, j = 4edgedim = 1379, 1381, 1383readsL_4 = 5, 4, 3, somax L_4 = J(4) = 5sits on a length-2 plateau1377/1379and is never exceeded; octave 8 (dim = 343..365) givesmax L_4 = J(2) = 1andmax L_3 = J(4) = 5atdim = 353;L_1 = tent(dim)andv_2 <= nhold at all 31 new rows (worst ratio 0.14). Witness: slice-sign-even-half. - Verified The window-module machinery is classical: the carry core is a generalized (mosaic) Sylvester map of a
1 x 3polynomial row ("striped Sylvester" is not a term of art), its kernel the truncated first syzygy module, rank-2 freeness is Hilbert-Burch, anddelta_1 + delta_2 = 12R + 5is the mu-basis degree identitymu_1 + mu_2 = n - deg(gcd)(Cox, Sederberg and Chen 1998; the Index Sum Theorem), so neither the identity nor the freeness is claimable and the 400-random-symbol generalisation reproves a 1998 theorem; the one-generator window step is two lines from Forney's predictable-degree property, leaving in-house only the evaluation12R + 5for this symbol, which needs the grading stated and polyphase coprimality asserted; claimable after nine recorded empty searches: Lemma M (the closest neighbours bound degrees, never a(1+x)-adic valuation), the Jacobsthal tent rank law (the Jacobsthal literature never uses the sequence as a rank formula's breakpoint set), the 2-adic Smith-layer/window structure (nearest miss: Smith forms overF[y], algebraically closed, no modular treatment), the Bockstein pairing as a layer-2 reader, andF_2Fibonacci/Dickson kernel generators; three leads open - the full Beckermann-Labahn text,F_2polyphase filter-bank Bezout twins, and mu-bases in positive characteristic, the last the only plausible threat to Lemma M. Witness: slice-sign-even-half. - Proved Lemma W, the ceiling mechanism: on family coordinates multiplication by
zis multiplication bypsi = (1+x^3)^2/x^3 = x^(-3) + 2 + x^3overZ, so the mod-4 obstruction class obeysob(zc) = Lambda ob(c) mod im(E mod 2)withLambda = S + S^(-1)folded at the centre (the raw vector identity fails atdim = 29; only the class is intertwined); hence ifY_0corrects the generator (E(Y_0) = obraw(g)) with x-valuationcmin, thenpsi^i Y_0correctsz^i gwhilecmin + 3i <= R, soC - deg g >= min(K - deg g, floor(a_0/3))witha_0 = R - cminthe maximal correction reach andcminthe corrector's half-support extent from the centre, not a valuation; the uncappedC - deg g >= floor(a_0/3)is false atdim = 25and at 29 of the 115 rowsdim = 23..251, exactly the cap-strict rows, and equalityL_2 - 1 = C - deg g = floor((R - cmin)/3)holds at the other 86, replacing the fitted ceiling by one linear-algebra invariant of the row; escaper independence is equivalent to ceiling exactness, andrank(phi) <= K - Cfollows from membership alone; the mod-2 family element's degree does not set the ceiling (dim = 115: alls_j >= 0yetC = 3) anda_0has no affine closed form inC - deg g(dim = 47against115,a_0 mod 3varying, the floor load-bearing), so the ceiling law waits on a closed form fora_0satisfyingfloor(a_0/3) = K - deg g - 2J(e-1)[k even]plus the single-element membership proof. Witness: slice-sign-even-half. - Conjecture Layer 2 is read by the Bockstein pairing
B(z,w) = (1/2) z^T M w-hat mod 2withL_2 = nullity - rank(B)and the closed coefficient form(1/2)[x^(6R+1)](P What Zetahat)(49/49 at odddim = 5..101, the coefficient identity exact at about 1.3k pairs, a corollary of the extraction form), and the layer flagV_k = red_2(ker(M mod 2^k))is a contiguous step-3 degree run for allk <= 9atdim <= 201(99/99), not always top-anchored (witnessdim = 29: mod-4 corrections pinned at the window top break shift-closure). - Conjecture
Smith(core) = Smith(even) ∪ Smith(odd)as multisets at base 3 (dim = 5..91); it fails at base 5,dim = 31: even{1,3,4}+ odd{1,2,2}against full{1,1,1,2,3,5}. - Conjecture The base-5 nullity has no bounded tent: the mod-2 nullity valley floors rise linearly,
1, 2, 2, 4, 8, 14atdim ~ 19 * 2^k, aboutdim/38, with peaks about0.1 dim, so the Jacobsthal tent with floor 1 is a base-3 phenomenon; at large odd class-dimthe profile is rigidly[1] + [2]^(L_1-2)plus two tail terms, almost all 2-torsion in one layer, a parity split with no mechanism. - Conjecture Off a maximiser the profile is two-tier,
[(j-1)^p, j^q, spike]withp(i) = 2i - 1marching in from the site and plateau length 2 in the site's ownL_j(5 sites, 23 rows;dim = 1379..1383mirrorsdim = 689..693),dim = 1449(L_2 = 41, tail[2^39, 4, 7]) is an ordinaryj = 2flank row with a one-unit tier-height excess atq = 1, and spikeless rows exist -dim = 1373is a pure flat block, tail[4,4,4],L_5 = 0, double-sourced at a different precision and Smith-free. - Conjecture The cascade recursion: the layer-3 law is the layer-2 window law one level down - in the quotient coordinate
u = c/g_2(the layer-2 window isdeg u in [0, L_2 - 1]),V_3is again a divisor-plus-ceiling window with tent parameter two Jacobsthal indices down,c_3 = 2J(e-4) - 1,delta = C_2 - C_3,P = C_3 - deg g_2,j = deg g_3 - deg g_2 = max(0, 2P - c_3),L_3 = min(P + 1, c_3 + 1 - P), tower ladder(delta, c_3) = (0, 2J(e-4)-1)whileL_2 <= 2J(e-4)then(2J(e-4), 2J(e-5)-1); 40/40 on rows withL_3 >= 2(odddim = 175..401complete plus701..707,735..741,363, 365, with window, dimension and nesting exact and no contiguity break), six rows predicted before computation (dim = 735..741with a never-seendelta = 22, seam rows363withj = 9and365);jis always 0 or odd, the layer-jtent height isJ(e - 2(j-1)), which on thek = 1slot isJ(k_oct + 2 - 2j)- the amplitude law derived forj <= 3- sites tie to the octave troughs (K = (dim - t_k)/2at 38/38), andc_4 = 2J(e-6) - 1puts the firstL_4 >= 2at exactly689;g_3/g_2is not always a monomial nor Fibonacci-shaped (dim = 481:c_2(z^2);dim = 497:(1+z)^2); further,t > 0 => L_3 = 1on all 22 rows of thet > 0region of octaveb = 10; unswept:403..471,517..699,709..733,743+, and the layer-4 window at689..693. Witness: slice-sign-even-half. - Refuted The unified amplitude law
max L_j = J(k - 1 - T(j-1))withTtriangular - fitted atj = 2, 3where triangular and arithmetic indices coincide, it fails atj = 1(true indexk) and atj = 4, witnessesdim = 689anddim = 1377. Witness: slice-sign-even-half. - Proved Lemma S, the symbol reading of the carry core holds at every 2-adic layer: for odd
dim = 2R + 1, withP = (1 + t^2)^(dim-1)(1 + dim t + t^2)andH_x = x_0 t^R + sum_(j >= 1) x_j (t^(R+j) + t^(R-j)), the row atc'ofM_even xis the coefficient oft^(3 nu + 1)inH_x Patnu = R - c', andH_x Pis palindromic about3R + 1, so theR + 1rows are exactly the exponent class1 mod 3on[0, 6R + 2]; hence for everyr >= 1,M_even x == 0 mod 2^riffH_x Plies in theZ_2[t^3]-module generated by1,2^r tandt^2, equivalently, withu = t^3,H = H_0(u) + t H_1(u) + t^2 H_2(u)andP = P_0 + t P_1 + t^2 P_2, iffH_0 P_1 + H_1 P_0 + u H_2 P_2 == 0 mod 2^r; ther = 1case is the mosaic Sylvester row already recorded as classical and the mod-4 symbol is already recorded, so what is added is the one row(P_1, P_0, u P_2)carrying every layer, checked as sets and not only as dimensions atdim = 5..13,r = 1, 2, 3. The layers are not truncated-syzygy dimensions of that row overZ_2[u]: the syzygy module of the row is the kernel ofM_full, not ofM_even, and the two nullities differ by the already-proved halvingnullity_even = ceil(nullity_full/2), becauseu = t^3does not preserve palindromy; the operator that does ispsi = u + u^(-1), as Lemma W states. Witness: smith-window. - Proved Lemma Lambda, the family shift is intertwined on the nose: write
psi = t^3 + 2 + t^(-3), the integer multiplier(1 + t^3)^2/t^3of Lemma W, andob(H)(nu) = ((H P)[3 nu + 1] mod 4)/2on 0/1 palindromic coefficient vectors of the mod-2 kernel; then(psi H P)[3 nu + 1] = (H P)[3 nu - 2] + 2 (H P)[3 nu + 1] + (H P)[3 nu + 4]and(H P)[3 nu + 1]is even, being a mod-2 kernel row, so its doubled term dies mod 4 andob(psi H) = Lambda ob(H)holds as raw vectors withLambda = S + S^(-1)folded bynu <-> 2R - nu; the family satisfiesH^(j+1) = psi H^(j) - 2 Z_jwithZ_j = H^(j) + (t^3 H^(j) AND t^(-3) H^(j)), andZ_jis palindromic and inside the coefficient box becausedeg H^(K) <= 2R(fromi <= (6R + 2 - 2^b)/3) and the overlap sits in[val + 3, deg - 3], soob(X_(j+1)) = Lambda ob(X_j) + A(Z_j)withA(Z_j)in the image of the mod-2 symbol and the class identity of Lemma W holds at every row with its raw defect named; the pair moves together, andpsi = t^3 + t^(-3)withZ_j = H^(j) + ANDmakes the lift identity false atdim = 29, 31, 47, 115, 251. Witness: smith-window. - Verified The layer-2 window is a window, and its generator and ceiling regenerate from the symbol:
V_2 = g_dim F_2[z]_(<= C_dim - deg g_dim),g_dim = z^m c_t(z^(2^e))withc_ttheF_2Fibonacci polynomialsc_0 = 1,c_1 = 1 + y,c_t = y c_(t-1) + c_(t-2), andC_dim = K - 2J(e-1)at evenk,Kat oddk, at 199/199 rows of odddim = 5..401and 100/100 of odddim = 403..601; the slot, the window bounds and the closed forms are the shelf lane's arithmetic line for line and only the object side is independent - the kernel family, the mod-4 symbol, the obstruction and the extraction ofV_2- so what this adds is a committed generator forg_dimandC_dim, which the lane's own scripts do not compute, pinningL_1andL_2alone. The ceiling is a corrector length:C_dim - deg g_dim = min(K - deg g_dim, floor(reach/3))withreach = R - jmax,jmaxthe least index whose mod-2 symbol columns span the generator's obstruction, andreachitself Lemma W'sa_0; theminwas chosen after the5..401overshoot, so honest support is the 100 fresh rows403..601, where the floor binds strictly at 60, the cap at 38 and they tie at 2, against 108, 99, 92 over all 299 rows, and the floor-strict rows are exactly theC_dim < Krows, both ways. Remark: taking the corrector out of the coefficient box leaves an image of corank exactly 1 inF_2^(R+1)at 129/129 rows of odddim = 5..261, every family obstruction meeting it, so the unboxed layer-2 window is the whole mod-2 kernel and an argument living in the untruncated module cannot seeg_dimorC_dim. Witness: smith-window. - Verified The reach law, the last unknown of Law E's ceiling: with Law E's slot data (
b = ceil(log_2(3R-1)),g = abs(2R - 2^(b-1) - 1),e = min{e >= 1 : J(e) >= (g+1)/2},k = b - 1 - e) give the slot its lengthN = J(e) - J(e-1), which is2J(e-2)ate >= 3and1ate = 1, its offsetu = (g+1)/2 - J(e-1) - 1and its positionp = uabove the octave centreR = 2^(b-2)andp = N - 1 - ubelow it; then the tent identitymin(p, N - 1 - p) = C_dim - deg g_dimsays Law E's window length is the distance to the nearer end of the slot in the slot's own coordinate, and the reach law saysreach = R - jmax = 3 min(p, N - 1 - p) + 2 [e even] + [k odd](1 + (p mod 2)), withp == R mod 2whenevere >= 3so the parity term is the parity ofR; exactly one row per odd octave escapes, thee = 1row above centredim = 4^m + 3, wherereach = 5form >= 2andreach = 3atdim = 7. Off those escaping rowsfloor(reach/3) = C_dim - deg g_dim + [k odd and e even], and on them it reads1againstC_dim - deg g_dim = 0with the capK - deg g_dim = 0as well, somin(K - deg g_dim, floor(reach/3)) = C_dim - deg g_dimat every row: the corrector law's statement carries no span test and its branch is a slot statistic - the floor binds strictly iffkis even ande >= 2, the cap iffkis odd witheeven ordim = 4^m + 3, and they tie otherwise - reproducing the recorded censuses in floor, cap, tie order as 48, 61, 90 at odddim = 5..401and 60, 38, 2 at403..601with no mismatch, and 2399/2399 todim = 4801. This repairs Lemma W rather than resting on it: the landed uncapped inequalityC_dim - deg g_dim >= floor(a_0/3)is false atdim = 25(K = C_dim = deg g_dim = 0,jmax = 9,reach = 3, so0 >= 1) and at 29 of the 115 rowsdim = 23..251, exactly the cap-strict rows, while the family-cappedpsi-orbit boundC_dim - deg g_dim >= min(K - deg g_dim, floor(reach/3))holds throughout, and Lemma W'sa_0isreachand notjmax, sinceC_dim - deg g_dim = floor(reach/3)at 86 of those 115 rows and= floor(jmax/3)at none. So only the>=half of the ceiling law is promoted, to a consequence of the Verified reach law and the Verified generator law and not to a proof; the deduction is not span-test-free, sincereachis defined by the span test and thepsi-orbit needs its corrector valuation maximal; and one half stays open, thatz^(C_dim - deg g_dim + 1) g_dimdoes not lift.jmaxis therefore not a 2-adic valuation statistic ofRbut a slot-tent statistic, and the two rank readings that would replace the span test are Refuted with witnesses,corank(E boxed) = K - C_dim + 1failing atdim = 15and the first dependent column index2J(e)failing atdim = 7. Fit rows are the 399 rowsdim = 5..801, read once and unadjusted; out of sample are the 800 rowsdim = 803..2401swept cold plusdim = 4099anddim = 16387, all clean, and the swept ladder covers every class ofRmod 8. Witness: smith-window. - Proved The slot tent identity
min(p, N - 1 - p) = C_dim - deg g_dimholds at every odddim >= 5, granting Law E's closed forms forC_dimandg_dim, by exact arithmetic inb, e, k, Rwith no appeal to the module; the proof is a three-case split one, ande = 2never occurs (witness: spectra.md, The tent identity, the theorem) - Proved The window box length is
K = J(b-2) - (g+1)/2in both octave halves, wherebis least with2^b >= 3R - 1andg = abs(2R - 2^(b-1) - 1)(witness: spectra.md, The tent identity, Lemma 3) - Proved Law E's offset collapses to
C_dim - t 2^e = J(e) - (g+1)/2whetherkis even or odd: the ceiling deficit2 J(e-1)and the parity ofkcancel exactly (witness: spectra.md, The tent identity, Lemma 5) - Proved The slot length satisfies
N = J(e) - J(e-1) = 2 J(e-2)fore >= 2, so Law E'schi = 2 J(e-2) - 1equalsN - 1fore >= 3; ate = 1the bridge fails and the case closes because both sides vanish (witness: spectra.md, The tent identity, Lemma 6) - Proved The slot offset and Law E's offset reflect:
u + (C_dim - t 2^e) = N - 1, so{u, C_dim - t 2^e} = {p, N - 1 - p}in both octave halves (witness: spectra.md, The tent identity, Lemma 7) - Proved
s = (g+1)/2 <= J(b-2)at every odddim >= 5, hencee <= b - 2, hencek >= 1andt = (J(k) - 1)/2 >= 0; this is Law E's standing hypothesisk >= 1, now proved (witness: spectra.md, The tent identity, Lemma 4) - Proved
p == R mod 2whenevere >= 3, and the parity fails exactly at thee = 1rows above centre,R = 2^(b-2) + 1, that is exactly ondim = 2^j + 3forj >= 2; those rows havek = j - 1, so the reach law's escaping familydim = 4^m + 3is thekodd half of the set and no more,dim = 11being a parity-failing row outside it (witness: spectra.md, The tent identity, Lemma 8) - Proved From the ceiling law alone, with no use of the tent identity, the upper half of the layer-2 window law is free wherever
C_dim = K, that is whereverkis odd ore = 1, since every element ofV_2has coefficient degree at mostKwhile the candidatez^(C_dim - deg g_dim + 1) g_dimhas degreeC_dim + 1; the open rows are exactlykeven withe >= 3, 448 of 1199 over odddim = 5..2401and 29116 of 99999 over odddim = 5..200001(witness: spectra.md, The tent identity, What it buys, census by lab/py/smith-window) - Conjecture At the rows with
keven ande >= 3, the family element of coefficient degreeC_dim + 1has mod-4 obstruction outside the image of the mod-2 symbol on the coefficient box, for a deficit of exactlyK - C_dim = 2 J(e-1); this is the whole of what remains of the upper half of Law E (witness: spectra.md, The tent identity, What it buys) - Refuted The parity-failing rows of Lemma 8 are not the family
dim = 4^m + 3:dim = 11fails the parity and is not of that form, and 9 of the 19 failing rows belowdim = 2000001lie outside the family; the true set isdim = 2^j + 3forj >= 2(witness: spectra.md, The tent identity, Lemma 8 and What it buys)
The Apollonian gasket
- Proved The Descartes reflection needs no square root and acts on all three coordinates: in the coordinates
(k, k x, k y), a line beingk = 0with(k x, k y)its outward normal, the fourth circle tangent to three given ones isv' = 2(v_1 + v_2 + v_3) - v, by Vieta, so an integral root quadruple grows an integral packing; six identities ride along underB(u, v) = (sum u_i)(sum v_i) - 2 sum u_i v_i,B(k, k) = B(k, kx) = B(k, ky) = B(kx, ky) = 0andB(kx, kx) = B(ky, ky) = -4, true on both roots and preserved by the reflection, which lies in the orthogonal group ofB. Witness: lab/rs/apollonian, verbs strip and census, all six rechecked on 575969269 quadruples, 0 broken, an arithmetic check only. - Proved The circles of the strip packing
(0, 0, 2, 2)tangent to the liney = 0are exactly the Ford circles, one over every reduceda/b, no interval assumed, of curvature2 b^2: tangency isk y = 1at positive curvature;(0, 2 b^2, 2 d^2, k)has square discriminant64 b^2 d^2and roots2(b + d)^2and2(b - d)^2, the mediant and the Stern-Brocot parent; two are tangent exactly at(a d - b c)^2 = 1; the walk covers(0, 1), the root pair0/1and1/1the ends, and the period-1 translation the rest; conversely Dirichlet forces an overlap at irrationalpand nesting equality at rationalp. Witness: lab/rs/apollonian, verb ford, 4863601 mediants to denominator 4000 againstsum_{b <= 4000} phi(b) - 1, 0 broken, 0 misses. - Verified The Ford identification holds in both directions on the grown packing, not only on the Stern-Brocot walk: one period of the strip packing grown to curvature
2097152gives 20770674 circles of which 318963 carryk y = 1, every one passing the Ford test thatk/2is a squareb^2andk x = 2 a bwithgcd(a, b) = 1, 0 off-Ford, and 318963 issum_{b <= 1024} phi(b) - 1; the same count returns atQ = 32andQ = 181as 323 and 10059, the far line carries 318963 by the strip's reflection symmetry, and no circle leaves the open period, 0 outside0 < k x < k. Distinctness is controlled atT = 2048, 2448 circles and 2448 distinct. Witness: lab/rs/apollonian, verb strip. - Proved The stack's brightness reads off the packing's curvature: the Farey stack lights the node
a/bexactlyfloor(Q/b)times at depthQ, the one circle resting on that node has curvaturek = 2 b^2, so the brightness isfloor(Q sqrt(2/k)), and the nodes lit at depthQare exactly the tangency points of the line-tangent circles of curvature at most2 Q^2; summing over the half-open period[0, 1)givessum_{b <= Q} phi(b) floor(Q/b) = sum_{n <= Q} sum over b dividing n of phi(b) = Q(Q + 1)/2, the walk carrying(0, 1)and the node0/1adding itsQ. Witness: lab/rs/apollonian, verb ford, brightness 1275, 20100, 500500, 8002000 atQ = 50, 200, 1000, 4000againstQ(Q + 1)/2. - Verified The curvature census grows like a power of
Twhose local exponent, read as the ratiolog(N(T_2)/N(T_1))/log(T_2/T_1)and never as a fit, lands at1.305, the fourth place set by the grid: the bounded packing(-1, 2, 2, 3)givesN(T) = 5, 165, 3325, 67163, 1359167, 27463391, 555198593, ratios ending1.3055, 1.3057; the strip's one period gives2, 48, 950, 19298, 390478, 7899138on the decades, ratios ending1.3061, 1.3060, and20770674atT = 2097152, octave ratios ending1.3050, 1.3056.N(T)excludes the root quadruple, four circles bounded, one per strip period. Witness: lab/rs/apollonian, verbs census and strip, 67163 distinct against 67163 counted on theT <= 10^4control. - Verified The residues are the arithmetic the census can see: the bounded packing
(-1, 2, 2, 3)uses exactly the eight classes2, 3, 6, 11, 14, 15, 18, 23mod 24 over all 555198593 circles of curvature at most10^7, at counts 83211520, 55422929, 55455852, 83378348, 83354132, 55617906, 55576284 and 83181622, while the imprimitive strip packing uses exactly the four classes0, 2, 8, 18at 4144636, 6223160, 6241134 and 4161744 of its 20770674 circles; which integers inside those classes occur is closed by others and this tree makes no claim on it. Witness: lab/rs/apollonian, verbs census and strip. - Verified The residual dimension is
1.3056867280498771846..., rigorous to 128 places by an effective Ruelle-Bowen computation on a Chebyshev-Lagrange approximation of the transfer operator, Theorem 1.1 of Vytnova and Wormell 2024 reading1.3056867280 4987718464 5986206851 0408911060 ... +- 10^(-129); the counting asymptoticc T^alphais Kontorovich and Oh 2011 withalpha ~ 1.30568(8), McMullen 1998 reads1.305688. The census's bounded1.3057isalphacorrectly rounded to four places, off1.3e-5; the strip's1.3056and1.3060agree to three, off8.7e-5and3.1e-4. Witness: REFS.md, read at source; lab/rs/apollonian, verbs census and strip. - Verified No design carries the gasket's dimension inside the window the tree can see: a design is the attractor of similarities of one ratio
1/baseunder the open set condition so its dimension islog N/log basefor an integer cell countN, equal toalphaonly ifbase^alphais an integer, and over2 <= base <= 100the nearest approach is52^alpha = 174.005426001at gap0.005426001, then68,89,49,23,20at gaps0.008182, 0.011684, 0.015094, 0.022279, 0.026750, worst0.488110atbase = 47; the table refutes equality and nothing weaker, the nearest design dimension beinglog 351/log 89 = 1.305694144, offalphaby7.4e-6. Witness: lab/rs/apollonian, verb design. - Verified The packing grower is now in the publishable crate:
mrlynum::apolloniantakes a named integral root, grows it by the square-root-free reflection in exacti64triples(k, k x, k y)and rechecks all six invariants ofBon every quadruple, reproducing the generator's numbers from the crate: 2448 circles on one period of the strip to curvature 2048 and 950 to curvature 1000, the root excluded, 0 broken and 0 circles outside the open period, and 323 circles carryingk y = 1below 2048, every one passing the Ford testk = 2 b^2,k x = 2 a b,gcd(a, b) = 1. Witness:mrlynum::apollonian::growandis_ford, testevery_line_tangent_circle_is_the_ford_circle_over_its_own_fraction, 2448 and 323 of 323. - Verified The stack and the packing's tangency points agree fraction by fraction and not only in count: at depth 32 the 323 nodes the Farey stack lights inside the open period and the 323 tangency points of the line-tangent circles of curvature at most
2 Q^2 = 2048are the same set of reduced fractions with 0 missed either way and 0 off-Ford, the brightness of the period summing to 528 againstQ(Q + 1)/2, and at depth 16 the same reading gives 79 against 79 with 0 missed and brightness 136; the agreement is checked at every depth from 2 to 64 againstmrlynum::lattice::farey. Witness:mrlynum::apollonian::shadow, testthe_stack_is_the_shadow_of_the_line_tangent_circles, 0 missed at both depths. - Verified Two further bounded roots sit in the integer coordinates with all six invariants exact and hand back new censuses:
(-2, 3, 6, 7)placed as(-2, -1, 0), (3, 1, 0), (6, 5, 0), (7, 5, 2)and(-3, 4, 12, 13)placed as(-3, -1, 0), (4, 1, 0), (12, 7, 0), (13, 7, 2), each carrying a double Descartes root becausek_1 k_2 + k_2 k_3 + k_3 k_1 = 0, givingN(1000) = 1297andN(1000) = 741beside 3325 for(-1, 2, 2, 3)and 950 for the strip period, the root quadruple excluded throughout. Witness:mrlynum::apollonian::rootandgrow, testthe_growth_lands_on_the_counts_the_generator_prints, 1297 and 741.
The arithmetic pole
- Proved The comb zeta of base 3 digits
{0,1}has a genuine pole at everys_(0,k) = log_3 2 + 2 pi i k/log 3,k = 1..10: the residuelambda_(0,1)lies in[0.231891517689918, 0.231891517689919] + i [-0.501067414481069, -0.501067414481068]by interval arithmetic on Burnol's Proposition 5.1 with every truncation bounded by a proved tail, andRes = s_(0,k) c_kties it to thek-th Fourier coefficient of the log-periodic profile ofA(x); the profile control from exact counts and a second certified enclosure by the functional-equation route both meet the first. Witness: lab/py/burnol-residue, dimensions.md THE ARITHMETIC POLE.
The circle count
- Proved A design's corner disc count has a self-similar main term with a log-periodic multiplier: with
Fthe base-3 digit-restricted set of a design,fillits digit count andN(r)the filled cells whose centre lies in the closed Euclidean ball of radiusrabout the lattice corner,Nis independent of the level,M(r) = fill^level mu(B_(r 3^(-level))) = r^(log(fill)/log 3) G(log_3 r)withGpositive and 1-periodic, and|N(r) - M(r)| <= C(r), the crossing count, which isO(r^(dim-1))in everydimbecause a cell meeting the sphere lies in the shell| |y| - r | <= sqrt(dim), of orthant volume2^(-dim) omega_dim ((r + sqrt dim)^dim - max(r - sqrt dim, 0)^dim), soN(r) = r^(log(fill)/log 3) G(log_3 r) + O(r^(dim-1)), an unconditional savingr^0.8927892607on the carpet andr^0.7268330279on the sponge; the density-times-volume main term fails outright at the grid centre, whose middle block is empty at every level and where the relative error is exactly1. Witness: lab/rs/circle-crop (22028 asserted rows, 6802 with a live error band, 41mrlymath::shape::censuscross-checks, the crossing boundsC_full <= 3r + 5atdim = 2andC_full <= pi sqrt 3 (r^2 + 1)atdim = 3asserted at every radius), crop.md THE CIRCLE COUNT. - Verified The crossing exponent of the corner disc count reads
min 0.871371 / mean 0.898741 / max 0.969141per triadic step overr = 27..19682on the carpet and1.704391 / 1.733764 / 1.757218overr = 27..728on the sponge, both bands containing the dimension minus one; the defect exponent sits in[0.220478, 1.015046](carpet) and[0.645285, 1.730726](sponge); the powers of the base carry no resonance, ranking inside[0.1200, 0.1296]in the crossing profile atk = 3..8on the carpet while the defect's eight ranks average0.4788and reach0.8333;mu(B_1)is certified in[0.750767350, 0.751113415]on the carpet, excluding3/4, and[0.475928750, 0.485478125]on the sponge. Witness: lab/rs/circle-crop. - Refuted That the corner disc count resonates at
r = 3^n, the heuristic the page's own transform identity suggests (hat mu(3t) = (P(t)/m) hat mu(t), equality on integert):|delta(3^n)|,delta(r) = N(3r) - m N(r), ranks0.5000, 0.8333, 0.1111, 0.0185, 0.6605, 0.5514, 0.7167, 0.4390inside its own triadic window on the carpet (the fraction of the window with|delta(r)| <= |delta(3^n)|) with no trend anddelta(27) = 0exactly; what is periodic is the crossing profile, whose maximum sits at2.9671times each window's start and triples exactly fromr = 721; and square-root cancellation over the crossing cells fails, every central defect estimate sitting above half the crossing exponent. Witness: lab/rs/circle-crop. - Proved The crossing shell is a tree: the shell at level
jis the whole grid's shell at real radiusr/3^j, so it is a rooted tree of depthlevelwith2r+1leaves and2*floor(r/3^j)+1boxes per level, andC(r)counts the leaves whose path never takes the centre seat; mean branching is3 + (2k-2)/(2Q+1), exactly3at every level wherefloor(r/3^j)is1 mod 3. Witness: crossing cells brute-forced from the cell definition at every level of everyr <= 150and at 18 large and boundary radii with no fault, the live leaves equal the corner ball's Cut column at every radius of every depth 1..5 for codes 7, 11 and 15, no box lacks a crossed parent at anyr <= 242, andC(100) = 134andC(242) = 296read twice by paths sharing no code (lab/rs/circle-crop, crates/mrlydemo/tests/shell.rs, crop.md THE CIRCLE COUNT). - Proved The crossing ladder is an exact ratio of integer counts:
Psi(r) = prod_k g_k(r)withg_k = u_(k+1)/(1 - p_(level-1-k)),u_k = T_k/T_(k-1)andk = level-1-jthe depth from the top;g_0 = 1identically, andg_1 = 1exactly whenever the level-(level-1)or level-(level-2)centre box is uncrossed, so the profile carries at mostlevel-1informative ranks and oftenlevel-2. Witness: lab/rs/circle-crop ladder lines, the product asserted againstPsicomputed directly to1e-12atr = 80, 242, 1000, 6560. - Proved The crossing shell's transfer operator is the tripling map on the offset: with
R_j = r/3^jandy_j(x) = sqrt(R_j^2 - x^2), the offseta_j(i) = frac(y_j(i))satisfiesa_(j-1)(3i) = frac(3 a_j(i))at every level and column, becausey_(j-1)(3x) = 3 y_j(x)is an identity of reals and needs no hypothesis; the 9-bit box pattern ismask(floor(u - k sigma))fork = 0..3clipped to[0,2], withsigmathe scale-free slope. Witness: lab/rs/circle-crop derivation pass, the derived pattern law reproducing the shell with 2 faults of 2188 boxes at level 0 and none at levels 1..5 on the shallow arc atr = 6560, the steep half following by the shell's own symmetry. - Proved A 9-bit box pattern is realisable by a straight line exactly when
max_(k<l) (v_k - v_l - 1)/(l - k) < min_(l<k) (v_l - v_k + 1)/(k - l)with the upper end positive; the test returns exactly thirty masks, which are character for character the crossing shell's thirty, and it forbids the thirty-first, a zero step beside a step of two, so the extra pattern seen only at the top of the tree is a curvature state and not a line state. Witness: lab/rs/circle-crop derivation pass, stable at search radius 12 and 15 and asserted atr = 6560, 19682, 12345. - Verified The Perron root of the memory-one pattern matrix differs from 3 at
r = 6560, 19682, 12345, brackets[3.000861, 3.000862],[3.000948, 3.000949]and[2.997616, 2.997617], but this does not test the Markov property: the matrix row sums are exactlypopcount(s), so the model returns each level mass exactly (161, 485, 1457, 4373, 13121atr = 6560), the tree's own pooled branching is3.037736, 3.012422, 3.004124, 3.001373, 3.000457and never the exact 3, the certified distance from 3 falls monotonically0.323840, 0.002623, 0.002385, 0.000086as the parent count rises, and over 18 unused radii the sign ofrho - 3is positive 9 times and negative 9 times at sizes0.000336to0.005951. Witness: lab/rs/circle-crop operator, pair and sweep_radii lines. - Verified The thirty-pattern alphabet of the crossing shell's transfer operator belongs to the truncation levels
1..level-3and not to the tree: over levels1..levelthe alphabet is 31 atr = 6560, 19682and12345, the extra being the root's own pattern, and 228 of the 16683 radiir = 3000..19682leave the thirty over levels1..level-3and 1966 over levels1..level-1, none reading fewer. Witness: lab/rs/circle-crop every_level_states and scan lines, withr = 1395, 1739, 6570, 15122, 3182pinned at four truncations. - Verified Folding
N(r)/r^(log(fill)/log 3)at 16 offsets oflog_3 r mod 1and comparing consecutive triadic windows measures the collapse instead of assuming it: the carpet's largest gaps run0.353553, 0.222183, 0.110138, 0.042663, 0.015114fromR = 1toR = 243with shares of the window level0.534078, 0.305035, 0.145250, 0.055448, 0.019546, soR = 81andR = 243agree to two percent and the ladder falls like1/r; the deepest window opens atN(243)/243^(log(fill)/log 3) = 0.751038, inside the certifiedmu(B_1)bracket[0.750767350, 0.751113415], while the sponge reads0.229755atR = 9againstR = 27and the grid centre does not collapse at all, its share reading3.081886. Witness: mrlydemo crop_collapse, crates/mrlydemo/tests/crop.rs, site/check.ts. - Proved At
dim = 2, withlevelthe least level withr < 3^level, the crossing shell's digit rate is pinned to1/9with an unconditional power saving and the indexind(r) = prod_(j<level) (1 - p_j(r)) (9/8)^levelis bounded: the shell is a monotone lattice path, so a level-jbox carriesleaves(X) = w + h - 1cells withsum_X w = sum_X h = floor(r/3^j) + r + 1andsum_X leaves = 2r + 1, the coordinate swap makes the seat class's two marginals equal, andp_j(r) (2r+1) = 2 sum_(seat X) w(X) - #seatsexactly; that turns both counts into sums offloorof one circle arc over3^jresidue classes mod3^(j+1), where van der Corput's Satz 5 on closed subintervals[a, b]with3^(j+1) b + c < rand a residue split of the monotone incrementsy(x) - y(x+1)give|p_j(r) - 1/9| <= 13.60 R^(-1/3) + 305.08 R^(-1/2) + 9.84 R^(-1)atR = r/3^j, hencesum_(j<level) |p_j - 1/9| <= 781, and with1 - p_j >= 3^j/(2r+1)from box column0,|log ind(r)| <= 1191for everyr >= 1;Psiis untouched, soPhidoes not follow, and the staircase is a plane fact so the sponge has none of it. Witness: lab/rs/circle-crop index lines, every identity asserted in exact integers at every level ofr = 80, 242, 1000, 2186, 6560, 12345, 19682and the bound asserted live atj = 0forr = 212957, 531441, 2000000where the cap clears the trivial8/9; crop.md THE CIRCLE COUNT. - Proved At
dim = 2, withlevelthe least level withr < 3^level, no level-jcolumn block[3^j i, 3^j (i+1)]of the crossing shell of radiusrtracks a slope window of widthepsunless3^j < 2 eps r, so a leaf's tracked run is at mostfloor(log_3(2 eps r)) + 1levels, and no level-ncolumn block is a line's staircase oncen > log_3(1 + 2 sqrt(3r)): a block's slope spant(3^j (i+1)) - t(3^j i)is at least3^j/rbecauset(u) = u/sqrt(r^2 - u^2)hast' = r^2 (r^2 - u^2)^(-3/2) >= 1/r, and tracking is inherited downwards so the tracked levels are a run from the bottom and never a gap; at the Dirichlet widtheps = 1/b^2no level-jblock tracks a denominatorb >= sqrt(2 r/3^j), so no block at rankkfrom the top of thePsiladder tracks a rational withb >= sqrt(6) 3^(k/2)and ranks0to4are held tob <= 2, 4, 7, 12, 22; the block cap is sharp, sincea >= 1,ab + 1 <= b^2and8 * 3^(2j) b^4 < r^2force a level-jblock to track; and if the staircasefloor(sqrt(r^2 - X^2))agrees with a line's at three columnsU,U + m,U + 2min[0, r)then the second difference reads at least-1from the line and at most2 - m^2/rfrom the arc, som^2 <= 3r, which gives(3^n - 1)^2 <= 12 rfor a block but onlyw(X), h(X) <= 2 + 2 sqrt(3r)for a box and so excludes no box the arc enters and leaves through one side; hence every rankk < level - 1 - log_3(1 + 2 sqrt(3r)), which islevel/2 - 2.14ranks to leading order and never half of them, carries no frozen-slope resonance across a block, halving the exponent the refuted frozen route produced without boundingPsi, which stays Conjecture. Witness: lab/rs/circle-crop track, budget, secant, blind, boxes and boxline lines, the run asserted between the two exact integer counts on all1116slope rows ofF_30atr = 3^level - 1forlevel = 6, 7, 8, 9, run equal to the cap at102, 91, 93, 98of279slopes and to the floor at26, 72, 66, 63, the three-point condition attained at exactly the largest level the block cap allows at each radius, and atr = 19682level6exactly3of the53boxes with their whole content equal to a line's staircase,(16, 20),(19, 19)and(20, 16), the witness that the box statement fails; crop.md THE CIRCLE COUNT. - Refuted That a spectral gap of the frozen-slope transfer operator bounds
Psi: at slope1/3, where the pattern law is exact, the straight-line ladder giveslog Psirising by0.024224a level overlevel = 4..12identically at three line offsets, soPsi ~ 1.024520^levelwith survival rate0.910342above8/9, while at slope1/7it falls by0.009633a level; the hole is a full triadic cylinder only atsigma = 0, where the digits are independent andPsi = 1identically. Witness: lab/rs/circle-crop derivation pass; the circle escapes the frozen model only because it tracks a resonance fork-2levels at width3^-k. - Proved At
dim = 2, withR = r/3^j, the three constants of the crossing shell's digit-rate bound are explicit: over the3^jclasses each column sawtooth sum is at most4.5310 r R^(-1/3) + 101.0364 r R^(-1/2) + 2 r R^(-1) + 1and each box sawtooth sum at most4.5310 R^(2/3) + 101.0364 R^(1/2) + 3from3 pi 3^(-2/3)and175 * 3^(-1/2)rounded up, the residue split costs(7/9) sqrt(2r) <= 1.1000 r^(1/2)and(10/3) sqrt R + (4/3) sqrt(2R) <= 5.2190 R^(1/2), the counting terms are exact to2 * 3^jand2/3, the main terms cancel to(2r + 1)/9plus a residue below1/9, and the errors add to27.1860 r R^(-1/3) + 610.1581 r R^(-1/2) + 9.3334 r R^(-1) + 10.3334, which2r + 1 >= 2randR <= rfold into13.60 R^(-1/3) + 305.08 R^(-1/2) + 9.84 R^(-1). Witness: van der Corput 1923 Satz 5 as restated in Laugesen and Liu Theorem 18, with lab/rs/circle-crop asserting the bound per level atr = 80, 242, 1000, 2186, 6560, 12345, 19682and live atj = 0forr = 212957, 531441, 2000000. - Proved The geometric sum behind the drift cap is explicit:
sum_(j < level) R_j^(-delta) <= 3^delta/(3^delta - 1)reads3.2612,2.3661and1.5atdelta = 1/3, 1/2, 1, which is what carriessum_(j < level) abs(p_j(r) - 1/9) <= 781, and a Huxley-typedelta = 77/208in place of van der Corput's1/3moves only the first of the three, to2.9927. Witness: arithmetic on the closed form, with the drift sums0.223603, 0.245132, 0.328170, 0.256778, 0.260804, 0.446659, 0.267260printed against781by lab/rs/circle-crop. - Proved The certificate
abs(log ind(r)) <= 1191splits into two explicit blocks: whereR_jclears23157375, at which the digit-rate bound first falls under1/9with the crossing at23157374.055,1 - p_j >= 7/9and the mean value theorem givesabs(log(1 - p_j) - log(8/9)) <= (9/7) abs(p_j - 1/9), so that block costs at most(9/7) 781 <= 1004.15, while at most16levels fall below it, sinceR_j < 23157375asksj > log_3 r - 15.44andlog_3 r >= level - 1, each costinglog(3 R_j) < (i + 1) log 3at thei-th from the top, a tail of at mostlog 3 * n(n + 3)/2over the topnlevels and so at most167.0atn = 16. Witness: lab/rs/circle-crop index lines,abs(log ind)asserted against1191at every level ofr = 80, 242, 1000, 2186, 6560, 12345, 19682. - Verified Over the
277slopes ofF_30meeting the sharpness hypothesisa >= 1anda b + 1 <= b^2,1108rows atr = 3^level - 1forlevel = 6, 7, 8, 9, the proved cap#{j : 3^j b^2 < 2r}less the proved floor#{j : 8 * 3^(2j) b^4 < r^2}is never above2and attains it, so the two exact integer counts pin those tracked runs to within two levels at every radius swept; the remaining8rows are0/1and1/1, where the floor reads0by that hypothesis. Witness: lab/rs/circle-crop track lines.
The cocycle's joint spectral radius
- Proved The component cocycle of mixed Kronecker words is simultaneously triangularizable over
Zand its joint spectral radius is the largest fill: in the frame(gamma, h, v, phi) = ((1,1,1,1), (1,1,2,2), (1,2,1,2), (1,2,2,4))of components, horizontal runs, vertical runs and fill, every class matrix is nonnegative, integer and lower triangular with column sums(comp(A_c), r(c), s(c), fill_c)and diagonals(0,0,0,1), (0,1,0,2), (0,0,1,2), (0,0,0,2), (1,1,1,3), (1,2,2,4), so the cross-polytopeP = conv{+/- gamma, +/- h, +/- v, +/- phi}satisfiesM_c P subset fill_c Pwith exact integer residuals and its gauge is an extremal norm; henceJSR(F) = max fillandLSR(F) = min fillon all2^15 - 1subfamilies, the finiteness property holds with a one-letter spectrum maximizing product, and every word over{3, 6}has spectral radius exactly2^level. Witness: connectivity.md THE JOINT SPECTRAL RADIUS OF THE COCYCLE, lab/py/jsr-schedules. - Refuted That the joint spectral radius of a component-cocycle pair is a nontrivial invariant of the pair: the JSR depends on the alphabet only through its largest fill and the LSR only through its smallest, both attained by one-letter words, so on the 78 of 105 letter pairs whose fills differ the JSR rate
log max_c k_cstrictly exceedschiat every interior frequency; an exhaustive scan of all2^levelwords tolevel = 16on{3, 6}and{3, 7}never improves on the one-letter rates2and3, and the Blondel-Nesterov lifting equals(fill_1^k + fill_2^k)^(1/k)exactly, terminating at no finitek. Witness: connectivity.md THE JOINT SPECTRAL RADIUS OF THE COCYCLE, lab/py/jsr-schedules.
The codebook
- Proved Under a minimum-description-length score with a catalog of
A = 667atoms and at mostP = 59049positions, the name chargelog2 A + log2 Pkills every atom below 31 cells outright, 131 of the 667, while every surviving atom still pays its share oflog2 A; the arithmetic of the score, not a measurement. Witness: lab/py/codebook. - Verified The rearranged SVD of a level-5 carpet render returns its level-1 code
495exactly at four block splits (sigma_2/sigma_1 <= 3.3e-15) and peels the five-letter magic wordcarpet(3), void(3), net(3), htree(3), vtree(3)into495, 341, 186, 455, 365; under bit flips at 51 rates and 40 seeds each the code survives 40/40 top = 0.30, 12/40 at0.31, 0/40 from0.32, against a block-mean baseline whose closed-form failuref/(1 + 2f) = 0.277638,f = (8/9)^4, is derived from the fill law and not from the sweep. Witness: lab/py/codebook. - Verified The three-class codebook (Kronecker tiles, magic designs, life frames) under the MDL score loses to raw deflate on the tree's own render by
17212bits, on text by31375and on a halftone by31217at Kronecker level 2, edges it by29bits on random bytes where deflate itself expands the stream by47, and crosses deflate on the render only at catalog level 3; the uniform-bit control takes zero placements and saves-18bits at every catalog depth 2 to 5, and every corpus reconstructs bit for bit from placements plus residual. Witness: lab/py/codebook.
The Collatz carry
- Proved In base 2 read least significant digit first,
3n + 1 = n + 2n + 1has digitiequal ton_i + n_(i-1) + c_ioverGF(2)withn_(-1) = 0,c_0 = 1andc_(i+1) = MAJ(n_i, n_(i-1), c_i), and the substitutionM = 2n + 1clears the constant from the skeleton:M xor 2M = 2 (n xor 2n xor 1) + 1for everyn, so the carry-free step in theMcoordinate isM -> M xor 2M, elementary rule 60 with no boundary term, mirroring to rule 102 in the most significant digit first render (witness: lab/rs/carry-skeleton README THE METHOD,0mismatches on all three identities over everyn < 2^18). - Proved The Collatz carry is a four-state Mealy transducer on the state
(n_(i-1), c_i)reading least significant digit first, and its dependence radius is unbounded: withu_0 = 1andu_j = 1 - (j mod 2)for1 <= j < level, every majority fromc_1on propagates, soc_i = u_0for1 <= i <= leveland flipping digit0alone changes every digit of3n + 1from2tolevel. A MrlyMath automaton is a triple(dim, mask, kind)with a finite offset mask (automata.md section 7), so the step is no rung of that ladder at any level; the dial grades acceptors and not transducers, so what it grades here is the step's zero-carry set and not the step (witness: lab/rs/carry-skeleton README THE CONTROLS, the radius witness at everylevel = 2..40). - Proved For odd
mthe zero-carry set ofm n + 1in base 2 is exactly the even integers accepted by the width-(deg m + 1)ruleWof beneath.md's memory dial forbidding two1digits at a distance in the difference set{abs(j - j') : j, j' in supp m}: digit0of the sum readsn_0 + 1and digiti >= 1readssum_(j in supp m) n_(i-j), so the set depends on that difference set alone andm = 11andm = 15share one rule (witness: lab/rs/carry-skeleton README READS, set equality with0mismatches below2^16atm = 3, 5, 7, 9, 11, 15). - Proved The Collatz carry fires with density exactly
1/2: on uniform independent digits the state(n_(i-1), c_i)is an irreducible aperiodic Markov chain on four states with stationary vector(1/3, 1/6, 1/6, 1/3)on(0,0), (0,1), (1,0), (1,1), whose carry-on mass is1/6 + 1/3 = 1/2(witness: lab/rs/carry-skeleton README READS, exact integer balance residuals all0, and the mean ofd_locover everyn < 2^levelreadinglevel/2 + 1/3 - (-1)^level/(3 * 2^level)as an exact integer identity at everylevel = 8..22). - Proved The carry-free map
T_free(n) = n/2for evennand(n xor 2n xor 1)/2for oddnnever raises the base-2 digit count, and has exactly one cycle on the positive integers,{1}, which every orbit reaches: an oddnread asfinGF(2)[x]withf(0) = 1hasT_freeequal toA(f) = ((1 + x) f + 1)/x, affine witha = (1 + x)/xanda + 1 = 1/x, soA^k(f) + 1 = a^k (f + 1)andA^k(f) = fforcesa^k = 1orf = 1, and(1 + x)^k = x^kfails at everyk >= 1by the constant term. The carry-free drift is therefore exactly zero and all of the growth of a Collatz step is carry (witness: lab/rs/carry-skeleton README READS,0digit-count increases and0values failing to reach1over everyn < 2^20). - Proved The carry-on block of the Collatz carry's transfer matrix is
[[0, 1], [1, 1]], characteristic polynomialx^2 - x - 1, so a carry-on run survives one further digit at ratephi/2, and the worst-case carry run overleveldigits islevel + 1, attained atn = 2^level - 1(witness: lab/rs/carry-skeleton README READS, worst case pinned atlevel = 1, 2, 4, 8, 16, 32, 40). - Verified The zero-carry rules of
m n + 1carry codes7, 95, 23, 22015, 279atm = 3, 5, 7, 9, 11and widths2, 3, 3, 4, 4undermrlynum::memory::Rule::new(1, k, code)withRule::allowed, withcard Wof3, 6, 4, 12, 5,rhoof1.618034, 1.618034, 1.465571, 1.618034, 1.380278andkappaof0.098239, 0.167412, 0.115204, 0.201999, 0.115524;m = 15repeats them = 11row (witness: lab/rs/carry-skeleton README READS, every code rebuilt from the difference set andrho,kappataken bymrlynum::memory::perronandmrlynum::memory::kappa). - Verified The golden rule, code
7at width2, and the supergolden rule, code23at width3, are the zero-carry rules of3n + 1and7n + 1, andmrlynum::memory::kappareads0.098239and0.115204on them, reproducing beneath.md's two published couplings from the Collatz side with no shared code (witness: lab/rs/carry-skeleton README THE CONTROLS, the two values asserted to5e-7). - Conjecture The longest carry run of a Collatz step over
leveluniform digits grows likelog_(2/phi) level, base2/phi = sqrt 5 - 1 = 1.236068. The mechanism is Proved, the carry-on block being[[0, 1], [1, 1]]with Perron rootphi; the constant is not established, sampled mean depths6.338, 12.116, 18.462, 24.967, 31.481, 38.029atlevel = 16, 64, 256, 1024, 4096, 16384over200000uniform strings each, standard error at most0.014per mean, giving increments per quadrupling5.778, 6.346, 6.504, 6.514, 6.548against the predicted6.541119, rising towards it from below with the offset settling near-7.76(witness: lab/rs/carry-skeleton README READS, the depth table, no exponent fitted). - Refuted The local carry count
d_loc(n) = popcount((3n + 1) xor (n xor 2n xor 1))is no function of popcount, of the longest run of1digits, ofv_2, of the digit count, nor of all four read at once: the least clashing pairs are1, 2atd_loc2, 0for popcount and for the longest run,1, 3at2, 3forv_2,2, 3at0, 3for the digit count,3, 5at3, 4for(popcount, v_2)and19, 25at3, 4for all four, with256217518, 417177932, 659301399, 662864636, 88157572, 9331881unordered pairs below2^16sharing the statistic and disagreeing ond_loc; the last row subsumes every pair, so no pair is a summary either (witness: lab/rs/carry-skeleton README READS, the refutation table, six witnesses pinned as integer pairs).
The component exponent
- Proved The component count of a two-letter magic word has an exact closed form on 59 of the 105 letter pairs at base 2,
dim = 2, namely 9 of the 15 pairs of distinct symmetry classes and all 6 pairs inside one class:2^(k-m)withkthe last unit place andmthe unit count for a unit against a domino (16 pairs),2^(number of diagonal letters)for a unit against a diagonal (8),2^(level-r)withrthe terminal run for two dominoes of unlike orientation (4),2^kwithkthe last diagonal place for a domino against a diagonal (8),2^(n-j)withnthe number of full letters andjtheir terminal run for a domino against the full tile (4),1for the gasket class against the full tile (4), and1inside a class except2^levelinside the diagonal class (15); proved by the zero-contact cut on the first four families, again by a rank-1 telescope on the domino against the diagonal, by the row-block argument on the domino against the full tile, and by the contact split with thefill >= 3line on the rest; exhaustive per pair on all 32766 words of length at most 14 against the representation and all 254 words of length at most 7 against the drawn cells, zero mismatches. The other 46 pairs are closed by the suffix recursion below. Witness: lab/rs/magic-words, connectivity.md. - Proved The zero-contact cut: since contacts multiply, a suffix has
h = v = 0as soon as it holds one letter withh = 0and one withv = 0, adjacent copies of that suffix tile can never merge, andcomp(A_w) = fill(A_prefix) * comp(A_suffix)at the last such suffix; 49420 of all 54240 words of length at most 4 admit the cut with zero mismatches. Its scope is part of the law: the other 4820 words carry nonzero contact in one direction at every suffix, and every word over a domino and the full tile is among them, so that family needs the row-block argument instead. Witness: lab/rs/magic-words, connectivity.md. - Proved The row-block law, and the one non-trivial exponent found: over a domino and the full tile the filled set is a product of a row set with the whole column range,
|R| = 2^natnfull letters, each row ofRis a full line, and two rows ofRare adjacent exactly inside a block of2^jrows atjthe terminal run of full letters, socomp = 2^(n-j); at equal letter frequencies the exponent is(log 2)/2against per-letter values 0, 0 and a fill ceiling of(3/2) log 2, strictly between them, which no other named pair achieves. Witness: lab/rs/magic-words, connectivity.md. - Proved On every one of those 59 pairs, along any word in which both letters occur with positive frequency, the component growth rate exists, is a function of the letter frequency vector alone, and is read off the closed form; existence is earned from the formula and not assumed. The hypothesis is load-bearing and the same statement without it is false: over
{3, 6}at frequency vector(1, 0)the constant word3^levelhas rate 0, the word carrying the diagonal letter at the square places has ratelog 2, and the word carrying it at the powers of 2 has upper ratelog 2, lower rate(log 2)/2and no limit, the last two having orbit closures that are uniquely ergodic but not minimal. Witness: lab/rs/magic-words, connectivity.md. - Proved The constant word is a degenerate probe for the component exponent:
comp(A_(c^level)) = comp(A_c)^levelwithcomp(A_c) = 2exactly on the diagonal class, so the one linear functional exact on constant words isPhi(f) = (f_6 + f_9) log 2, and it fails at every interior frequency on 7 of the 9 named class pairs, holding only for a unit against a diagonal and for the gasket class against the full tile; the failure is a wrong shape rather than a wrong coefficient, since the true exponent extends to no vertex. The caveat travels with the result: on five of the seven, 28 of the 32 letter pairs, the exponent equals the fill exponent and so saturates the trivial ceilingcomp <= fill, carrying nothing the order-blind fill law did not already give. Witness: lab/rs/magic-words, connectivity.md. - Verified The Thue-Morse run structure that makes the exponent exact: no three equal letters in a row, so every terminal run has length at most 2 and every prefix rate is within
2/levelof its limit; exactlylevel/2of each letter at every even length, not merely in the limit; over all lengths to2^20the terminal run of one letter takes the value 0 on 524288 prefixes, 1 on 349526 and 2 on 174762; the first2^20letters hold 349525 complete runs of length 1 and 349525 of length 2 with one unfinished run at the cut; and the run-boundary wordt_n xor t_(n+1)is the period-doubling word on all 1048575 terms. Witness: lab/rs/magic-words. - Proved The remaining 46 letter pairs carry exact closed forms too, so all 105 are solved, and the mechanism is a suffix recursion rather than anything spectral: a heavy suffix letter, meaning one of the five connected codes 7, 11, 13, 14, 15 that carry both contacts, leaves the count unchanged because the block graph of
A_w (x) A_cis isomorphic to the cell graph; a zero-contact suffix letter, meaning one of 1, 2, 4, 8, 6, 9, leaves isolated cells and collapses the count to a fill; and a domino suffix letter turns the count into the number of maximal runs, whose recursionH(A_wq) = H(A_w) + fill(A_w)at a gasket letter telescopes. Hencecomp(A_w) = fill(A_(w_1..p))atpthe last zero-contact place on the 30 pairs of a heavy letter against a light one, giving3^(g-j),2^d 3^(g-j),4^(F-j)and2^d 4^(F-j)withjthe terminal heavy run, andcomp(A_w) = 1 + sum of fill(A_(w_1..i-1))over the gasket placesiat or before the last domino placemon the 16 gasket-against-domino pairs,(3,7)and(5,7)among them, the eight column-domino pairs being the transpose of the eight row-domino ones; exhaustive on all 753572 words of length at most 13 against the representation and all 11684 of length at most 7 against the drawn cells, zero mismatches. Witness: lab/rs/magic-words, connectivity.md. - Proved At every interior letter frequency the component exponent exists, is order-blind and equals the fill exponent
f_1 log fill_1 + f_2 log fill_2over the two letters on all 46 of those pairs; existence and order-blindness hence hold on all 105, saturation on 89 of them; the interior hypothesis is used exactly once, to force the terminal run of the heavy letter to beo(level), since a run ofeps levelwould freeze the other letter's count on that block and contradict its positive frequency, and the gasket-against-domino case runs through the sandwichT < comp(A_w) <= 1 + (3/2) TatT = fill(A_(w_1..i*-1))andi*the last gasket place at or before the last domino place, measured in[1.0004, 2.0000]on six named words with no violation. Nothing is claimed for a word whose letter frequencies fail to exist. Witness: lab/rs/magic-words, connectivity.md. - Proved The two rates the study could not identify are identified exactly: along the Thue-Morse word over any of the 16 gasket-against-domino pairs,
(3,7)and(5,7)included, the component exponent is(1/2) log 6under either letter reading, with the two-sided certificate|log comp(A_(w_1..level)) - (level/2) log 6| <= log 108 + (1/2) log(3/2) < 4.885at everylevel >= 4, because the word is cube-free, which caps the sandwich suffix atfill/Tin[6, 108], and balanced, which pins the gasket-letter count to within1/2oflevel/2; the study prints the value as0.895879734614027nats, a float labelled as such. Measured tolevel = 2^14on all 16 pairs and both readings the largest deviation is4.273459nats against the certificate's4.884864. Witness: lab/rs/magic-words, connectivity.md. - Proved The frequency functional
Phi(f) = (f_6 + f_9) log 2is refuted at every interior frequency on 78 of the 105 letter pairs and exact on 27, the 46 new pairs being refutations to a pair; and the exponent saturates the trivial ceilingcomp <= fillon 89 of the 105 and falls short on 16, so the domino against the full tile is the unique class pair on the whole alphabet, and not merely among the named 59, whose exponent sits strictly between the constant-word values and the fill ceiling. The comparison is against the value ofPhiand never against a periodic word. Witness: lab/rs/magic-words, connectivity.md. - Proved The interior hypothesis is sharp on a pair carrying no diagonal letter, so the pathology is not a property of the diagonal class: over
(3, 7)at frequency(1, 0)the constant word3^levelhas rate 0, the gasket at the square places giveslog 2, and the gasket at the powers of 2 has upper ratelog 2, lower rate(log 2)/2and no limit, withcomppinned tofill(A_(w_1..i*-1))ati* = 2^kthroughout(2^k, 2^(k+1)], so the accumulation set of the prefix rate is the whole interval[(1/2) log 2, log 2]and not its two endpoints. Witness: lab/rs/magic-words, connectivity.md. - Proved A common invariant cone exists and the gasket-against-domino pair is primitive in it, and none of it is needed:
phi = (1,2,2,4)^Tis a common right eigenvector withM_c phi = k_c phi, so it normalises the row orbit and only that orbit, and in the resulting chartcomp/fill = 1 - b - cwith the letters acting byN_gasket(b,c) = ((1+b)/3, (1+c)/3)andN_domino(b,c) = ((1+b)/2, 0); the set{0 <= b <= 1, 0 <= c <= 1/2, b + c <= 1}is invariant under both and the length-3 word gasket-domino-gasket maps it strictly inside, vertex images(5/9,1/3),(11/18,1/3),(5/9,1/3),(7/12,1/3)withb + cat most17/18, three being minimal since domino-gasket sends(1,0)to(2/3,1/3)on the face. Witness: lab/rs/magic-words, connectivity.md. - Verified A by-product and a smoothness split:
comp(A_((7,3)^k)) = (6^k + 4)/5, reading 2, 8, 44, 260, 1556, 9332 and checked tok = 8against both the closed form and the representation, a stationary control whose per-letter rate is(1/2) log 6again; and since every closed form on the other 89 pairs gives a count of the form2^i 3^j, the gasket against a domino is the only family whose counts are not smooth, the largest atlevel = 8over(3, 7)being1094 = 2 x 547. Witness: lab/rs/magic-words, connectivity.md. - Conjecture Which words with no letter frequencies carry a component exponent at all, now that all 105 letter pairs have closed forms and interior frequency settles the rate: over
(3, 7)the tripling wordW_(k+1) = W_k 7^|W_k| 3^|W_k|keeps both letters at lower density1/4and still has its prefix rate range over[0.4792, 1.4379]inlog 2units on1024 <= level <= 4096with no narrowing, so positive lower density is the wrong hypothesis, but that is measurement and not a proof that the limit fails. Witness: lab/rs/magic-words, connectivity.md. - Conjecture The accumulation set of the saturation
comp/fillalong Thue-Morse over a gasket-against-domino pair, plausibly the attractor of the two affine chart maps read along the word; the sampled value0.2325367033atlevel = 4096is a term of an oscillation and is neither a limit nor a maximum, the exact maxima atlevel >= 5being43397/186624and151/648under the two readings. Witness: lab/rs/magic-words, connectivity.md. - Conjecture Whether any alphabet of three or more letters, or any other order-sensitive observable, makes the component-style exponent depend on more than the letter frequencies, which is what a non-stationary result would need; at interior frequency on two letters it provably does not, on any of the 105 pairs. Witness: magic.md, connectivity.md.
- Conjecture Whether the same suffix recursion that closes the 46 reproduces the 59 forms proved by other means, which would collapse the whole table to one lemma, and whether the Euler, boundary and holes series of Hankel ranks 4, 8 and 11 answer to it as well. Witness: connectivity.md.
- Refuted That a difference between the component growth rate and the frequency-average prediction is a non-stationary result - on the whole settled class the exponent is a function of the letter frequencies alone, so Thue-Morse returns exactly what a periodic word of the same frequencies and almost every Bernoulli word return, and the tree's own stationary controls miss the prediction by the same amount; the difference refutes the frequency functional, not stationarity, and an aperiodic word witnesses nothing here. Witness: connectivity.md, lab/rs/magic-words.
- Refuted That the component exponent is a function of the letter frequencies for every word whose frequencies exist - over
{3, 6}the frequency vector(1, 0)carries the constant word at rate 0, the diagonal-at-squares word at ratelog 2, and the diagonal-at-powers-of-2 word with no rate at all; the statement holds only where both letters have positive frequency, and the same correction restores every family's closed-form rate. Witness: connectivity.md, lab/rs/magic-words. - Refuted That the top Lyapunov or matrix-norm exponent of the cocycle is the component exponent, and with it every route to
chithrough a norm theorem, a joint spectral radius or a projective contraction of forward orbits - along3^infthe largest entry ofM_3^levelis exactly2^(level+2) - 2, reading 6, 14, 62, 1022, 262142, 17179869182 atlevel = 1, 2, 4, 8, 16, 32, so the norm exponent islog 2, whilecomp(A_(3^level)) = 1at everyleveland the component exponent is 0; the observation functionalgammais a fixed vector of both heavy matrices and so sits on the boundary of the dual cone, which is the geometric form of the same obstruction. Witness: connectivity.md, lab/rs/magic-words. - Refuted That entrywise positivity in the standard basis decides whether the letter matrices preserve a common cone - neither
M_3norM_7is a non-negative matrix, so the test never applied, and none of the 8190 products of length at most 12 is entrywise positive, yet a common invariant cone does exist in the chart normalised by the right eigenvectorphi = (1,2,2,4)^Tand the pair is primitive in it at length 3. Witness: connectivity.md, lab/rs/magic-words. - Refuted That the Thue-Morse word is a named word along which the component exponent fails to exist - it converges, exactly, to
(1/2) log 6on every gasket-against-domino pair with a two-sided certificate; the genuine non-existence witness is the gasket at the powers of 2 at the boundary frequency(1, 0), whose orbit closure is countable and not minimal, so no uniquely ergodic minimal word is implicated. Witness: connectivity.md, lab/rs/magic-words.
The design Mobius meter
- Verified The design Mobius meter oscillates at the zeta ordinates and not at the design's pole lattice. Read
M_F(x)/x^(alpha/2)uniformly inlog x, Hann-windowed, against a local-median floor and a null of rigid shifts of each candidate list: at base 10 with the digit9missing all six strongest peaks sit within one bin of a nontrivial zeta zero, offsets0.068to0.216, with the full-set control at the same depth reading ten of ten, offsets0.018to0.196. Thirteen zeta ordinates are reachable in the band4 < gamma < 60, so a peak lands within one bin of one by chance with probability0.159and six of six isP = 1.6e-5. The pole lattice2 pi j/log basescores-0.592,-0.640,-0.734at base 3{0,1}, base 3{0,2}and base 5{0,1}, below its own null, while the counting function over the identical elements scores3.602,3.764and3.973, so the pipeline would have seen a lattice and there is none. Witness: lab/py/design-meter verb spectrum, lab/rs/mobius-designs, A084237. - Proved The identity
M_F(x) = sum_(n <= x) mu(n) A_F(n)/n + R_F(x)definesR_Fat every base and digit set, and the echo's size splits atalpha = 1/2. Partial summation givessum_(n <= x) mu(n) A_F(n)/n = A_F(x) H(x) - sum_(m in S_F, m <= x) H(m-1)withH(y) = sum_(n <= y) mu(n)/n, which isO(y^(-1/2 + eps))under RH, so the echo isO(x^(alpha - 1/2 + eps))whenalpha > 1/2, while foralpha < 1/2the second sum converges absolutely and the echo tends to the constantsum_n mu(n) A_F(n)/n, which is nonzero: base 16{0,1}reads-0.0937, -0.1330, -0.1242, -0.1051, -0.1099at10^3to10^7againstx^(alpha - 1/2)falling0.1778to0.0178, and base 10{0,1}reads-0.0500at10^7against0.0405. Against the square-root barx^(alpha/2)the echo dies atx^(-min(alpha, 1 - alpha)/2), equal to1only atalpha = 1, so the zeta zeros neither obstruct nor help the square-root conjecture, which is a statement aboutR_Falone. Verified separately at two designs: at base 10 missing9the echo carries six of six top peaks at zeta zeros and the residual none of the two it has, the echo being0.1342of the meter in root mean square against0.6476, and the echo's share of the meter falls0.356028, 0.242495, 0.207229there and0.208549, 0.099001, 0.047902at base 3{0,1}, share over prediction reading1.0000, 0.7387, 0.6846and1.0000, 0.9219, 0.8663, each design decaying at least as fast as its own rate. Witness: lab/py/design-meter verb spectrum, mobius.md. - Refuted A family law for the design meter's frequency set: it is not a function of
(base, alpha). Base 3{0,1}and base 9{0,1,2,3}sharealpha = 0.630930, element count1048575and log range to within1.4%, and their meters split ten peaks against none, where support-matched random-sign meters reach0to4peaks on the first support and0to2on the second over eight draws each, so the ten sit above their own null and the none does not; base 9{0,1,2,3}and base 9{0,1,3,4}sharebaseandalphaand split the same way, the second being base 3{0,1}element for element since its digits are the base-3 pairs00, 01, 10, 11. The scaled pair base 3{0,1}and{0,2}shares eight of ten peaks, so the scaling transfer of mobius.md carries into the spectrum while no(base, alpha)law does. Witness: lab/py/design-meter verb family, mobius.md. - Refuted The primitive quadratic Dirichlet
L-zeros of conductor3,4or5, the quadratic conductor each base carries, are no frequency family of the design meter: over eleven designs the largest score is0.372against a null of0.341at base 4{0,1,2}and the widest gap over a null is0.371against0.290at base 3{1,2}, while the zeta ordinates on the same meters reach1.130against0.392at base 10 missing9, so the pipeline would have seen an arc family; the wider prediction over arcs of denominatorbase^jis untestable by this spectrum and is not claimed. Witness: lab/py/design-meter verb spectrum.
The diagonal cut
- Conjecture Cook's (2011) Menger-slice code cuts along the normal
(1, 1, 0.5), not the centroid diagonal, so the base-3 diagonal cut is not Cook's slice; the reference row scoring the cut as Cook's is kept atyeswith that correction recorded beside it, and the row once scoredyesin error now readsno.
The digit-restricted Mobius exponent
- Conjecture
theta(F) = 1/2for every digit set with2 <= |F| <= base - 1and squarefree digit gcd - square-root cancellation against the set's own counting function: the 47 running-maximum exponents acrossbase = 3, 4, 5, 10read0.4465..0.5358with last-five-level drifts0.0157..0.1056, while the full-set controls, whose limiting exponent is1/2under RH and at least1/2unconditionally, read0.4413..0.4517at the same depths; the finite tables are consistent and decide nothing, single-cut exponents scattering0.22..0.53on the same data. Witness: lab/rs/mobius-designs, mobius.md. - Conjecture An unconditional Mertens-shape bound on the dense column: for
Fomitting exactly one digit,base >= 92317andx = base^levelwithlevelpast a point depending onbasealone,abs(M_F(x)) <= C(base) A_F(x) exp(-c(base) sqrt(log x))withC(base)andc(base) > 0effective, through a Dirichlet-approximation dissection whose region A is the ladder rungb = 4/5and whose one load-bearing minor-arc input is unread. Witness: lab/rs/mertens-numerology for the wall92317, Maynard 2022 for the imported lemmas. - Proved That dissection is dead at fixed digit count:
{0,1}at base 3 hasl^1exponentlog 2 / log 3 = 0.630929, above every bar the dissection sets, region B's1/4and region A's own ask included, thel^1floor again in arc-local form. Witness: exact arithmetic in the sentence that prints it. - Proved Vaughan's identity is circular here at power strength: the
mu_{<=U} * mu_{<=U} * 1piece carries the main termfill^level M_1(U)^2, so bounding the pieces one by one at power strength forcesM_1(U) << U^(-delta), which continues1/zetaintosigma > 1 - delta. Witness: the identity, carried out in the sentence that prints it.
The digit-restricted Mobius meter
- Proved Carry-free scaling ties the digit designs' Mobius meters together: for digit sets
F = a F'inside{0..base-1},m -> a mis a digit-length-preserving bijectionS_F' -> S_F(each scaled digit stays belowbase, so no carry occurs), givingM_F(base^level) = sum mu(a m); a square factor inakills the meter identically (F = {0,4}atbase = 5: zero at all 21 levels), and primea = pgivesM_(pF')(base^level) = -sum_(p not | m) mu(m), the{0,2}column atbase = 3reading as the{0,1}column twisted by the Thue-Morse sign of the binary index; asserted at every level on all eight scaled census families. Witness: mobius.md, lab/rs/mobius-designs. - Proved The base-4 anti-symmetry
M_{0,2}(4^level) = -M_{0,1}(4^level):4 | baseforces every element ofS_{0,1}to0or1 mod 4, so even elements carrymu = 0andM_{0,2}(x) = -M_{0,1}(x/2)at every realx, running maxima included sinceS_{0,1}is empty strictly between(4^level - 1)/3and4^level; exact at all 22 levels,-110/110atlevel = 15,34/-34and sharedMmax = 1553atlevel = 22. Witness: mobius.md, lab/rs/mobius-designs. - Proved No Euler product for a digit design:
S_Fis not multiplicatively closed, witness4 = 11_3and13 = 111_3inS_{0,1}at base 3 with4 x 13 = 52 = 1221_3outside, soM_Fis not the coefficient sum of an inverse Dirichlet series; the series itself is built literature (abscissa Kohler and Spilker 2009, continuation and poles Burnol 2026) and carries no Mobius sum anywhere. Witness: mobius.md, REFS.md. - Verified The digit-restricted Mobius census: exact
M_F(base^level)and running maximamax |M_F(x)|for all 38 digit sets with2 <= fill <= base - 1atbase = 3, 4, 5(depths 24, 22, 14, 21, 13, 11 by class), the ten base-10 one-digit-excluded columns to10^8, and full-set controls to3^17,4^13,5^11,10^8; factorization and sieve agree on thebase = 3{1,2}family at every level tolevel = 16, the base-10 control reproduces A084237, and an independent second-language recompute matched 99 sampled rows exactly. Witness: lab/rs/mobius-designs, mobius.md, A084237. - Proved A power saving for the Mobius meter on the dense digit columns, under GRH: assume
L(s, chi)has no zero insigma > 1/2for every Dirichlet characterchi, letFomit exactly one digite_0, and letbase >= 1499, orbase >= 1032whene_0is0orbase - 1; then for everyeps > 0and allx >= 2,|M_F(x)| <<_{base,eps} x^(3/4 + c'_base(e_0) + eps)withc'_base(e_0) = log PB'_base(1, e_0)/log base,PB_base(1) = 1 + Phi_base/baseandPhi_base = (4/pi) base + (2q/pi) H(ceil((base-2)/2)) + (1 - 2/pi)(base-2) + 0.727, and3/4 + c_base < alpha_base = log(base-1)/log base, so|M_F(x)| <<_{base,eps} A_F(x)^(1 - delta_base + eps)withdelta_base = (alpha_base - 3/4 - c_base)/alpha_base > 0, every fixeddelta' < delta_basedelivered and the endpoint never; orthogonality modbase^level, the shifted-gridl^1recursionc_level <= B_base(F) c_{level-1}, the kernel boundB_base(F) <= base PB_base(1)fromsin(pi v) <= 4v(1-v)and1/sin x <= 1/x + 1 - 2/piwith Parseval exact on the excluded digit, and the assembly with its geometric sum are derived, and the uniformmax_theta |sum_{n <= x} mu(n) e(n theta)| <<_eps x^(3/4 + eps)of Baker and Harman 1991 is quoted at source; the corollary atmexcluded digits runs wheneverPB_base(m) < (base-m) base^(-3/4), which holds atm <= 6, 78, 451atbase = 10^4, 10^5, 10^6and asymptotically form <= base^(1/2)(1-o(1)), andc_base -> 0givesdelta_base -> 1/4. The attempt to break it drives the chain below the wall, where the failure is quantified rather than hidden (c_base = 0.28087againstalpha_base = 0.999855atbase = 1000), checks the exponent test against the constant-space certificategap_base(m) = (base-m) base^(-3/4) - PB_base(m) > 0at every3 <= base < 20000, the cancellation-reduced and direct forms ofdelta_baseagainst each other to10^-9relative at every printed base, andPhi_baseagainst the exact shifted-grid kernel sum on a4001-point grid atbase = 50, 101, 200, where it is loose by under20%. Witness: mobius.md a power saving under GRH at large base, lab/rs/mertens-numerology. - Proved The ladder above that theorem, and its floor: for
1/2 <= a < 1, ifL(s, chi)has no zero insigma > afor every Dirichlet character then the same five steps give|M_F(x)| <<_{base,eps} A_F(x)^(1 - delta_base(a) + eps)withdelta_base(a) = (alpha_base - b(a) - c_base)/alpha_base > 0at everybase >= base_0(a),b(a)the smaller of the Baker and Harman 1991 table and Zhang 2024 Theorem 1.1 (Zhang strictly smaller inside(1/2, 4/7)and equal at both ends, by the factorisations-5(a - 1/2)(a - 2/5)/(4 - 2a)and-7(a - 4/7)(a - 4/5)/(4 - 2a), withb(a) >= 3/4throughout), so every common zero-free half plane buys the saving and GRH is only its first rung, the price of a weaker hypothesis being paid entirely in the base; the wallbase_0(a)exists and is a true least base at everya, sincePB_{base+1}(1) - PB_base(1) < 1.291/(base-2)forbase >= 40while the mass term gains(1-b)(base+1)^(-b)per step, so the gap steps up at everybase >= Q(b), the leastbasewith(1-b)(base-2)(base+1)^(-b) >= 1.291, and below that it is negative: exhaustively on3 <= base < 3690, and on[3690, Q(b)]by a majorant with one interior minimum whose endpoint values are both negative. The attempt to break it looks for a rung the floor misses and finds none: at everybin[3/4, 1), printed rung or not, minimality ofQ(b)givesgap_{Q(b)}(b, 1) < -1.56and a majorant below-0.95at both ends, with anyb < 1417/1850forcingQ(b) <= 1486and an empty range, the constants reproduced on ab-grid across the whole interval. Witness: mobius.md a power saving under GRH at large base, lab/rs/mertens-numerology. - Verified The rungs of that ladder:
(a, b(a), source, base_0(a), Q(b))reads(1/2, 3/4, both, 3690, 723),(13/25, 1417/1850, Zhang, 8578, 1486),(11/20, 913/1160, Zhang, 33547, 4754),(4/7, 4/5, both, 92317, 11221),(3/5, 4/5, BH, 92317, 11221),(2/3, 5/6, BH, 3107080, 216023),(3/4, 7/8, BH, 6939524168, 129458304), then(4/5, 9/10, BH, <= 3.09358e13, 128606353005),(9/10, 19/20, BH, <= 3.23663e34, <= 1.73431e28)and(19/20, 39/40, BH, <= 9.24614e83, <= 3.30712e68), a wall printing as an exact integer only below2^53with both neighbouring gaps above1024ulps and otherwise as an upper bound on the leastbase; the GRH rung reproduces the wall3690and the margin there isdelta_base <= -2.395807653 * 10^-6atbase = 3689againstdelta_base >= 5.863425182 * 10^-6atbase = 3690, withgap_base(1) <= -1.533059397 * 10^-4and>= 3.752213034 * 10^-4; them-budget atbase = 10^7falls1971, 1002, 365, 176, 176, 8along the rungs below that base. The attempt to break them reproduces every wall under4 * 10^6by an exhaustive scan frombase = 3against the bisection, requiresQ(b) < q_0(a)at every rung, sweeps3 <= base < 3690for an early close at every rung and finds none, and pins each rendered row as a string. Witness: lab/rs/mertens-numerology, mobius.md a power saving under GRH at large base. - Proved The
l^1floor is a wall on the method, not on the problem:sum_{r mod base} |g_F((t+r)/base)|^2 = base fillexactly, sosum_{r mod base} |g_F((t+r)/base)| >= base fill / max_r |g_F| >= basefor everyt, the shifted-grid recursion never contracts,B_base(F) >= baseandc_base >= 0at every base and every digit set; hence the decomposition needsalpha_base > 3/4, that isfill > base^(3/4), and every fixed-fillcolumn,F = {0,1}atbase = 3included, is beyond it with or without GRH, so it never meets the census or the exponent conjecture. The same floor kills the two neighbouring routes: Davenport's unconditionalx (log x)^(-A)in the quoted step exceedsA_F(x)by the powerx^(1 - alpha_base), so no unconditional saving follows inside this decomposition without an input of zero-free-strip strength, and Cauchy-Schwarz with Parseval on both factors gives exponent(1 + alpha_base)/2 > alpha_base, worse than trivial. The attempt to break it hunts a negativec_baseover3 <= base < 5000and aPB_base(1)below1and finds neither, Parseval forbidding both. Witness: mobius.md a power saving under GRH at large base, lab/rs/mertens-numerology. - Verified The cost-out of that saving against a hypothetical Type I defect: with the saving
delta_baseset beside the defect exponentm/(2(base-m) ln base)carried by a level-x^(alpha_base/2)distribution bound for the digit strings, a bound no page here states, the saving is below the defect at the wall (5.86342e-6against1.65022e-5atbase = 3690, a factor above2.8) and above it frombase = 3692on, the least such base in a scan of3690..10^5in which the difference rises at all96310steps, monotonicity beyond the scan unproved; atbase = 10^9it is1.16951e-1against2.41275e-11, and the tightest corollary rowbase = 10^6,m = 451reads3.14081e-5against1.63296e-5. The attempt to break it checks the crossover for a premature crossing atbase = 3690, 3691and for a single down-step in the scan and finds none, and holds the yardsticks apart:delta_baseis normalised to the mass, so as a power ofxthe saving isx^(alpha_base delta_base)withalpha_base >= 0.99993on every row compared, while the defect multipliesfill^level. Witness: lab/rs/mertens-numerology, mobius.md a power saving under GRH at large base. - Conjecture That the defect
x^(m/(2(base-m) ln base))of a level-x^(alpha_base/2)distribution bound for the digit strings, a bound no page here states, is absorbed by the GRH saving at all: the cost-out sets two exponents from two unrelated statements on two yardsticks side by side and no derivation joins them, so it is neither a necessary condition nor a proof that a Type I estimate forM_Ffollows, the string-to-interval bookkeeping and the bilinear half of any such argument being untouched; the comparison is decided at the wall and nowhere else, lost there by a factor under3and won two steps later, so any sharper constant that movesq_0must be re-costed rather than inherited. Witness: lab/rs/mertens-numerology, mobius.md a power saving under GRH at large base. - Verified The coefficient sequence a real Vaughan decomposition hands the bilinear sum is not the sequence that beats the method's diagonal floor: at the eight swept boxes with both sides above
x^(2/5), the boxes the identity produces, the Type II coefficientsum_{d | l, d <= x^(2/5)} mu(d)takes values in{-1, 0, 1}at seven of the eight and its full quadratic form sits in[0.6929, 1.2045]of its own diagonal, where a sign vector engineered against the column reads0.2043on such a box; over all eighty coefficient cells of the census, sixteen boxes, four families, two depths, two cuts and five real sequences, the form over the diagonal stays in[0.3138, 52.6676]with none below0.1and every departure from the swept band upward. Witness: lab/rs/rho-decoupling section menergy signed vaughan. - Proved The large-values refinement of the moment route is the
l^2route itself: splitting the grid at|hat F_level(a/base^level)| >= fill^level x^(-eta), bounding the large set by itsl^2mass under the fourth moment and Parseval and the rest by the threshold, all against Parseval on the bilinear side, gives the exponentmax(min(alpha + 1/2 - eta, (1 + alpha)/2), min((1 + alpha)/2, alpha + (nu_4 + 2 eta)/2)) = (1 + alpha)/2identically at everyeta >= 0and every digit set withalpha < 1, and the large-sieve constant of any grid subset forbase^levelconsecutive frequencies isbase^levelexactly, so no spacing enters. Witness: lab/rs/rho-decoupling section riesz large values chain, 66 rows withc = -(1 - alpha)/2. - Verified The large frequencies are adjacent or isolated grid points,
407in331runs at{0,1}base 3level = 12eta = eta_4against the fourth-moment count4096, least gap1/base^level, large-sieve constant onD_levelin1.06009e5..2.13280e5nearly at itsl^2floor1.05611e5; at the eight dense census cells the Type II sum ata_m = b_l = 1on the boxM = N = floor(x^(1/2)/2)is the representation count,0.26to0.41offill^level, and the balanced sum ata_m = 1_(base | m),b_l = 1a fixed share offill^level, so no bound uniform over bounded coefficients holds there; the sparse cell{0,1}base 100level = 3is void at the box. Witness: lab/rs/rho-decoupling sections riesz large values and riesz large values witness. - Proved The second-largest grid value of the digit transform is
max_(a != 0) |hat F_level(a/base^level)| = fill^(level-1) max_(b != 0 mod base) |g_F(b/base)|, equal tofill^(level-1)at one excluded digit and at{0,1}base 3, so the large set is the zero frequency alone exactly beloweta_1(level) = log(1/gamma_1)/(level log base), a threshold that vanishes with depth. Witness: lab/rs/rho-decoupling section riesz large values cells, eight cells at1/fill. - Conjecture Whether a Vaughan decomposition's coefficient sequence, a convolution and not a free sign vector, can be steered near the engineered sign vector that beats the Cauchy-Schwarz diagonal floor by a factor thirty-eight at a top box; and whether the arc regime
M, N >= x^(2/5)carries a dyadic box withR = x^(alpha - o(1)), the middle-divisor question on which the balanced route's refutation foralpha < 2/5is conditional. Witness: lab/rs/rho-decoupling, sections menergy signed engineered and menergy type II. - Refuted The adversarial pass on the census: an independent linear-sieve recompute in a second language rebuilt 99 rows - nine families, four controls, one excluded-digit column, meters, counts and running maxima - and first DISAGREED on eleven
{0,1}-family rows, traced to the recompute itself double-counting the boundarybase^lits length filter had already caught; fixed, it agrees on all 99. Two generator runs differ in zero of 784 shared rows, and a first-draft page table assembled by hand was wrong in multiple cells before every page table was switched to script extraction from the generator's printed rows. Witness: lab/rs/mobius-designs. - Refuted That the Mobius signs cancel the digit column's off-diagonal multiplicative correlation better than an unstructured sign vector on the same support: over sixteen boxes
|Sigma_mu|is0.0913to0.7178of the random-sign root mean square against0.0359to1.5048for the support-matched controls, the split against those controls is3, 9, 4at chi-square0.375against the uniform-rank null, and the fifteen-of-sixteen advantage over Liouville is the support of the Mobius function; a sign vector engineered against a known column drives the same Cauchy-Schwarz bound to0.0265of its diagonal floor, so the census refutes the arithmetic of the coefficients and not the method. Witness: lab/rs/rho-decoupling, sections menergy signed, menergy signed summary and menergy signed engineered. - Proved The major-arc input for
muon a digit design is effective. LetFbe a digit set withfill >= 2every prime of whose digit-difference gcd dividesbase, condition (E) in one dimension, and letx = base^level. Every real primitive Dirichlet character whose modulus has all its primes dividingbasehas conductor dividing8 rad(base), so the possible exceptional zeros run over a set of size bounded inbaseand Siegel's theorem is never invoked; with that,x^(-1) Sum_{a in M} hat F_level(a/x) S_mu(-a/x)is at mostfill^level exp(-c sqrt(log x))withceffectively computable, over the arcs|a/x - b/d| <= (log x)^C/xwithd <= (log x)^C, and there is no main term at any arc. Witness: mobius.md The pair route. - Proved Under condition (E) in one dimension and the large sieve
Sum_{d <= Q} Sum_{gcd(b,d)=1} |hat F_m(b/d)| << fill^m (Q^(2 alpha_1) + Q^2 base^(-m(1 - alpha_1)))at every scalem <= level, withalpha_1 < 1/2the sup-over-shiftl^1exponent, a digit design's level of distribution survives restriction to an initial segment:Sum_{d <= Q, gcd(d,base)=1} max_{y <= x} |#{n in D_level : n <= y, d | n, gcd(n,base)=1} - (1/d) #{n in D_level : n <= y, gcd(n,base)=1}| << fill^level (log x)^(-B)atQ <= x^(1 - alpha_1)(log x)^(-C), the same level as the full-range statement and one power oflog xless saving, because the transform's error is uniform in the target residue and the segment splits into at mostfillblocks per scale. Witness: mobius.md The pair route. - Proved The hybrid bound that carries the digit-restricted bilinear estimate holds at every base with the digit set's own dimension as its exponent. Let
Fbe a digit set withfill = abs(F) >= 2,alpha = log(fill)/log(base), sup-over-shiftl^1exponentalpha_1, and assume the shifted and perturbed large sieve it supplies by Farey spacing,sup over shifts of Sum_{a <= d} sup_{abs(eta) <= delta} F_Y(a/d + shift + eta) << (1 + delta d)(d^(alpha_1) + d Y^(-(1 - alpha_1)))at every scale. ForD, E, Y, Q_1powers ofbasewithD E << Y,Q_2 >= 1,q_1 ~ Q_1coprime tobaseandd ~ Dall of whose primes dividebase, the sum ofF_Y(a/(d q_1 q_2) + eta)overq_2 ~ Q_2coprime tobase, overa < d q_1 q_2coprime tod q_1 q_2, and overabs(eta) <= E/Ywith(eta + a/(d q_1 q_2)) Yan integer is<< (D E)^(alpha_1) (Q_1 Q_2^2)^(1 - alpha) + E^(alpha_1 + alpha/2) D^(1 + alpha/2) Q_1 Q_2^2 Y^(-alpha/2). Both exponents come from Parseval on a windowbase^r, whereint F^2 = base^(-r alpha)exactly when0is inFand≍otherwise, so the base-10 values1/21and10/21are1 - alpharounded up andalpha/2rounded down. Sincealpha + alpha_1 >= 1at every design, this never loses to the plainl^1bound in the modulus aspect. Witness: mobius.md The pair route. - Proved The lattice half of the digit-restricted bilinear estimate transfers to every base, and the five inequalities it asks are free below
1/3. Withx = base^level, the windowN K >= x^(1 - 2 beta),delta >= N/xandQ <= x^(1/2), the sum ofF_x(a_1/x) F_x(a_2/x)over pairs whose large contribution comes from a rank-2 lattice is<< (log x)^5 (Q + E)^(-eps/4) x/(N K), the source's own log power, whenever2 alpha_1 < alpha,(2 - alpha) 2 beta < 1 - alpha_1,2 beta (alpha_1 (3 - u) + u - 1) < u alpha/2for someuin(0, min(1, 2 alpha_1/alpha)],5 beta < 1 + alpha/2and2 beta < (1 - alpha_1)(1 - alpha_1 + alpha/2). The source writes a numerical check for the second and the fourth only; the first, third and fifth are read off steps it performs silently. All five are monotone in the three exponents, so the corneralpha = 1 - alpha_1,beta = 1/4decides them, and every one holds underalpha_1 < 1/3,beta <= 1/4and thel^1flooralpha + alpha_1 >= 1, with1/3sharp since three become equalities there. The floor and the threshold onbetaalone do not suffice, asalpha_1 = 0.40,alpha = 0.60,beta = 1/4shows. Base 10 clears all five as published. Witness: mobius.md The pair route. - Proved The pair route's eight inequalities are two. Write
alpha = log(fill)/log(base)for a digit set's dimension,alpha_1for the sup-over-shiftl^1exponent of its transform andbetafor the exceptional-set threshold. Of the eight inequalities the route asks, one is a ceiling onalpha_1alone,2 alpha_1 < alpha, and seven are caps onbetaat fixed(alpha, alpha_1); four of those fall inalpha_1and two are constant in it, so each takes its minimum over the region at the wallalpha_1 = alpha/2. At that wall the lattice cap(2 - alpha) 2 beta < 1 - alpha_1and the geometric-mean condition read exactly1/4, the last lattice cap reads(2 - alpha)/4and the fourth(1 + alpha/2)/5, all identities inalpha, so none of them ever cuts below the window threshold1/4inside the wall. Foralphain(1/2, 1)the region is therefore exactlyalpha_1 < alpha/2andbeta <= min(1/4, (2/5)(1 - alpha_1)), the greedy cap cutting fromalpha_1 = 3/8and from nowhere else. A sweep of66000cells,264000cap tests, finds no exception, and the two wall equalities hold at each of330rationalalpha. Witness: lab/py/mobius-region verb boundary. - Proved The exceptional-set threshold obeys the same Parseval floor as the
l^1exponent, and the pair route reaches onlyfill >= base^(3/4). The normalised transform is at most1pointwise, so the moment exponentm_tis non-increasing int; andm_2 = 1 - alphaexactly, since two length-leveldigit strings congruent modulobase^levelare equal. Hencem_t >= 1 - alphafor everyt <= 2, and since2 - t <= 1fort >= 1the thresholdbeta = inf over t in [1,2) of m_t/(2 - t)is at least1 - alphaat every base and every digit set, the same flooralpha + alpha_1 >= 1puts on thel^1exponent. The route's window conditionbeta <= 1/4alone then forcesalpha >= 3/4, that isfill >= base^(3/4), with equality only when thel^1floor is also an equality. That window condition is a convenience rather than a necessity, and dropping it does not widen the route: on the single-window branch, which carries the greedy step underalpha_1 <= 1 - (13/4) beta, the same two floors givealpha >= 13/17 = 0.764705..706, so that branch reaches onlyfill >= base^(13/17)and the gate rises. The weaker readingfill > sqrt(base), which follows fromalpha_1 < 1/2alone, stays true and is simply not sharp, so no earlier row is contradicted. Witness: lab/py/mobius-region verb check. - Verified The census of the pair criterion over 49 digit designs, and a second machine at base 21. Over the 38 proper digit sets of
base = 3, 4, 5, the ten base-10 one-missing-digit columns and base 21 missing0, one design clears the criterion, 47 are refuted and one is open, the open cell beingbase = 5withF = {0,1,3,4}, where the transform vanishes inside a window cell and the infimum matrix loses a row. A pass is decided at the pessimistic corner and a failure at the optimistic one, every cap being monotone in each parameter. A second implementation of the window method returnsalpha_1 in [0.2499715, 0.2499822]for base 21 missing0at five window digits and sub-scan8, against the five-digit[0.2499715, 0.2499821]already certified, agreeing on the lower bound to all seven printed digits and differing by one unit in the last on the upper; both run the same method at the same depth, so the agreement witnesses transcription and the upper-bound gap is the only independent information. The same machine reproduces base 10 missing5atalpha_1 in [0.3505101, 0.3506471],m_(235/154) <= 0.1362891andbeta <= 0.2875140against the three published values27/77,59/433and23/80. Witness: lab/py/mobius-region verbs criterion and params. - Proved The line half of the digit-restricted bilinear estimate and its two bookkeeping steps, at every base. With
x = base^level, a thresholdbetaadmissible and at most2/5, which with the Parseval floorbeta >= 1 - alphaforcesalpha >= 3/5on the design,delta >= N/x,N K >= x^(1 - 2 beta),Kabove the absolute constant of the pair dichotomy, andN >= x^(eps + max((5/4) beta, (5 beta - 1/2)/3)), the pair sum over the pairs whose large contribution lies on a line is<< (log x)^(O(1)) x^(-eps') x/(N K)forxpast a point depending onbase,fillandeps, witheps'a function ofepsand the implied constant depending on those three alone. The statement asks nothing of thel^1exponent and asks of the dimension only what the admissibility ofbetaalready encodes, so the wholel^1content of the route sits in the lattice half and the greedy step. Two write-outs complete it. For coefficients bounded by thej-fold divisor function, orthogonality on the grid withtau_j^2 <= tau_(j^2)gives#{a mod x : the exponential sum is at least x/C} <<_j C^2 (log x)^(j^2 - 1), so a Heath-Brown decomposition costs a log power where a 1-bounded sequence costs none. And Cauchy-Schwarz in the long variable turns the bilinear sum intox/Ntimes the pair sum of the transform against the sum overl_1, l_2 <= Nofmin(x/N, the inverse distance from (a_1 l_1 - a_2 l_2)/x to the nearest integer), which is the exact step at which all four coefficient factors leave by the triangle inequality; the dyadic split into level sets and pair-mass classes costs two more log powers. Witness: mobius.md The pair route. - Conjecture A digit set satisfying condition (E) in one dimension whose sup-over-shift
l^1exponent obeysalpha_1 < 1/4hasSum_{level in S_F, level <= x, gcd(level,base) = 1} mu(level) = O(A_F(x) (log x)^(-B))for everyB. The program is named: two Proved steps formu, the rest set-only or coefficient-free, and the lattice branch of the source's Section 14 in general parameters owed. Base 10 fails on two independent numbers,27/77against1/3and23/80against1/4. Witness: mobius.md The pair route. Superseded by the criterion row that names five lattice conditions and the thresholdbeta <= 1/4, under the same subsection in OPEN. - Conjecture , whose owed list and whose base-10 diagnosis are both superseded. A digit set satisfying condition (E) in one dimension whose sup-over-shift
l^1exponent obeysalpha_1 < 1/4hasSum_{level in S_F, level <= x, gcd(level,base) = 1} mu(level) = O(A_F(x) (log x)^(-B))for everyB. The program is named: the major-arc lemma and the level of distribution on an initial segment are Proved formu, and the lattice branch is Proved in general parameters. Three things are owed and none is a new idea: the line branch at general base, whose two lemmas are set-free and coefficient-free but whose own conditionsm_t < (2 - t) betaandN >= x^max((5/4) beta, (5 beta - 1/2)/3)are gathered into no statement yet; and the write-out at general base of two bookkeeping steps, the Parseval count of large frequencies for the Heath-Brown pieces and the dyadic reduction of the bilinear sum to the pair sum, both stated at source for arbitrary 1-bounded sequences. Base 10 now fails on one number only, the sharp thresholdbeta = inf_t m_t/(2 - t), at23/80against1/4. Witness: mobius.md The pair route. - Refuted The pair criterion cannot be met at base 10 at any excluded digit. An upper bound on a moment exponent bounds the threshold above and can never show the criterion fails, so the published miss of
3/80prices a gap and refutes nothing. Two monotonicities close it: on a cell[t_0, t_1]everythasm_t/(2 - t) >= m_(t_1)/(2 - t_0), and above a cut the Parseval value1 - alphaalone forces the ratio past1/4. With the moment bounded below by the infimum window matrix, adaptive chains of25to53cells certifybeta > 1/4at all ten one-missing-digit sets of base 10, the certified lower bounds running0.2502716to0.2541480, so no admissible threshold clears the window condition there and the route is dead at base 10 at every digit rather than merely unreached. The refuting certificates do not order the columns, their brackets[0.2510933, 0.2625620]at the digit9and[0.2515026, 0.2875159]at the digit4overlapping; run at the target0.2626the same chain certifiesbeta >= 0.2632014at each of the eight non-extreme digits, up to0.2645208at the digit7, above both extreme upper bounds, while the digits0and9come back undecided as they must, and that settles the two extreme digits as strictly the cheapest columns. The miss is at most0.0125620at the cheapest column and at least0.0139557at the digit4; the factor2.99between the two printed upper bounds is a ratio of upper bounds and not of misses. Witness: lab/py/mobius-region verbs threshold and threshold 0.2626. - Proved The one-step constant of the
l^1recursion is exact and cheap at one excluded digit. LetF = {0..base-1}less{e_0},phi_r = (t+r)/base,A_r = (-1)^r sin(pi t)/sin(pi phi_r)andc = e_0 - (base-1)/2. Thenabs(g_F(phi_r)) = abs(A_r - e(c phi_r)) = sqrt(A_r^2 + 1 - 2 A_r cos(2 pi c phi_r))for everytnot inZ, which is whereA_ris defined, sinceD_base(phi_r) = e((base-1)phi_r/2)(-1)^r sin(pi t)/sin(pi phi_r)and the unimodular factor divides out, soB_base(F) = sup_t sum_(r mod base) abs(g_F((t+r)/base))is a sup ofbasereal square roots and costsO(base)pert; the reduction reproduces the direct sum overFto12digits and reproduces the grid sups4.0000000000at base 3{0,1}and19.8885438199at base 10 missing9, the floored readings ofsplit's4.000000000and19.888543820. Witness: lab/py/mrly-pairing, verbonestep. - Proved Two exact symmetries of that constant:
B_base(F)is unchanged bye_0 -> base-1-e_0, because the digit reflection multipliesg_Fby a unimodular factor, and the shifted-grid sum is symmetric intabout1/2, becauser -> base-1-rcarriestto1-twithsign(A_r) cos(2 pi c phi_r)fixed; so the scan for the sup runs ontin[0, 1/2]and one_0 <= (base-1)/2. Witness: lab/py/mrly-pairing, verbonestep. - Proved The phase identity behind the one-step constant: for every
base, everye_0and everytin(0,1),sum_(r mod base) (1 + sign(A_r) cos(2 pi c phi_r)) = base + cos(2 pi c (t - 1/2)/base)/cos(pi c/base), by summing the geometric seriessum_r (-1)^r e(c r/base) = e(-c/(2q))/cos(pi c/base), which is wheree(c) = (-1)^(base-1)collapses the numerator to2; the right side is at leastbase + 1at everyt, sinceabs(2 pi c (t-1/2)/base) <= abs(pi c/base) < pi/2, and it reachesbase + 1/sin(pi/(2q))att = 1/2ande_0 in {0, base-1}. Witness: lab/py/mrly-pairing, verbonestep. - Proved The triangle split
abs(g_F) <= abs(D_base) + abs(g_E)of the shifted-grid step can be sharpened by a fixed share ofbaseat one excluded digit, with no new input. Forbase >= 17andm = 1,B_base(F) <= (4/pi) base + Psi_base + base/2 - sec(pi (e_0 - (base-1)/2)/base)/2, wherePsi_base = (2 base/pi) H(ceil((base-2)/2)) + (1 - 2/pi) basewithH(n) = ln n + gamma + 1/(2n), the desk convention of mobius.md, is the step 3 kernel constant less its two-point part, against the step 3 boundbase PB_base(1) = base + Phi_base = (4/pi) base + Psi_base + base + 0.00023954, the constant being0.727 - 2(1 - 2/pi)exactly. The proof isabs(a - e(psi))^2 = (a+1)^2 - 2a(1 + cos psi)withsqrt(1-X) <= 1 - X/2, thenabs(A_r) >= sin(pi t) = sands/(1+s) >= s/2, then the phase identity, then thet-dependent kernel boundsum_r abs(D_base(phi_r)) <= (4/pi) base + s Psi_basethat step 3's own two-point and pairing estimates give, and finallyh(tau) = cos(pi tau)(Psi_base - base/2) - cos(pi tau) cos(2 beta tau)/(2 cos beta)withbeta = pi (e_0 - (base-1)/2)/basehash' <= 0on[0, 1/2]oncePsi_base >= (1 + pi) base/2, first true atbase = 17, bysin(pi tau) >= 2 tau,sin x <= xandsec beta <= base. Witness: lab/py/mrly-pairing, verbonestep. - Proved That sharpening lowers the base of the conditional power saving with no new idea and no change to any other step: the least
basewith(base-1) base^(-b(a)) > B_base(F)/basefalls from3690to2446at every excluded digit and to1812ate_0 in {0, base-1}at the GRH rungb = 3/4, from8578to5700and4242atb = 1417/1850, and from33547to22416and16816atb = 913/1160, each an exhaustive scan frombase = 17in the generator, whoseheldcolumn prints3997555 = 4000000 - 2446 + 1and the five like counts, so every wall is an up-set over its whole scan and not a first crossing, while the three step 3 baselines are quoted from mobius.md and not rescanned. Witness: lab/py/mrly-pairing, verbonestep. - Proved The
l^1floor is higher thanbaseat one excluded digit: lettingt -> 0in the shifted-grid sum givesabs(g_F(0)) = base-1andabs(g_F(r/base)) = 1at everyr != 0, soB_base(F) >= 2(base-1)andc_base >= log(2 - 2/base)/log(base) > 0for everybase >= 3, and that endpoint is the seat atbase = 3by hand, the three terms collapsing to4 cos uon[0, pi/6)and4 cos(u - pi/3)on[pi/6, pi/3), both at most4. Hence no exact constant can push the method below the base where(base-1) base^(-3/4) > 2 - 2/base, which isbase^(1/4) > 2and sobase >= 17, and the sup-times-l^1method needsfill > (2 - 2/base) base^(3/4)and notfill > base^(3/4); the floor is too weak to givefill > 2 base^(3/4), since atbase = 17the basefill = 16lies between(2 - 2/base) base^(3/4) = 15.759and2 base^(3/4) = 16.744. Witness: lab/py/mrly-pairing, verbonestep. - Verified The exact one-step constant falls with the excluded digit, while the step 3 bound is one number for all of them: at
base = 3690,B_base(F)/base >= 5.750052ate_0 = 0and>= 6.392410ate_0 = 1844, against the exact kernel supK_base/base >= 6.191324, the proved kernel boundPhi_base/base <= 6.791445and1 + Phi_base/base = 7.791445; the split defect(K_base + base) - B_base(F)reads1.441272 baseate_0 = 0, flat to1.3e-5acrossbase = 100, 1000, 2234, 3690and agreeing to six digits with1 + (2/pi) ln 2 = 1.4412712, which nothing here proves is its limit, and0.798914 baseat the middle digit, where those same fourbaseread0.808644,0.799643,0.799091and0.798914, a spread of9.8e-3, so that branch is stable only to1e-2;Phi_base - K_basereads at most0.600121 basethere, so the two losses are the same order and the excluded digit's position is worth0.64 base. Each number is a grid scan ontin[0, 1/2]at cut1/4000with the sup seated att = 1/2. Witness: lab/py/mrly-pairing, verbonestep. - Verified The ceiling of the exact-constant lever, and what it is not: the measured
B_base(F)itself would put the GRH base at927at every excluded digit, the last failure beingbase = 926ate_0 = 462on a downward scan of17..2000over every digit, and at304ate_0 in {0, base-1}, last failure303on17..8000, against the proved2446and1812, so a further0.9 baseof slack is left in the sharpened bound, of which0.6 baseis the gap betweenPhi_baseand the exact kernel sup. The middle digit is not the maximiser at oddbaseand reading it alone reports the crossing232bases early: atbase = 695the worst digit ise_0 = 463withB_base(F)/base = 5.327344against(base-1) base^(-3/4) = 5.127089, a failure, while the middle digit passes by2.1e-5. Both bases are readings ofSigma(1/2), which is the sup on the cut at every(base, e_0)checked in the range but is not proved to be the sup, and neither crossing is proved monotone inbase, so they bound nothing and never enter a statement. Witness: lab/py/mrly-pairing, verbonestep. - Verified Nothing measured contradicts the sharpened bound: over every excluded digit at
base = 17..60the worst ratio ofB_base(F)to the bound is0.807189atbase = 60,e_0 = 29, at the seatsbase = 100, 1000, 2234, 3690it is0.876716atbase = 3690,e_0 = 1844, and4000draws at seed1009overbase in {17, 23, 60, 101, 333, 1000, 3690}withe_0andtuniform give worst ratio0.872146atbase = 3690,e_0 = 1701,t = 0.499866and no violation. Witness: lab/py/mrly-pairing, verbonestep. - Proved The pair route's gate is
fill >= base^(3/4), and dropping its window condition narrows the route rather than widening it.F_x <= 1pointwise makesm_tnon-increasing andm_2 = 1 - alphais exact by Parseval on the grid, sobeta >= 1 - alphaat every base and every digit set, and the window conditionbeta <= 1/4forcesalpha >= 3/4. The branch that drops it asksalpha_1 <= 1 - (13/4) beta, and withbeta <= m_1 <= alpha_1, thet = 1term of the infimum against the grid sum being one shift of the supremum, that readsbeta <= 4/17 = 0.235294andalpha >= 13/17 = 0.764705, so the gate rises tofill >= base^(13/17). The stepbeta <= alpha_1is load-bearing (lab/py/mobius-region, verb boundary prints the branch): without italpha = 0.9,alpha_1 = 0.155,beta = 0.26clears both floors,2 alpha_1 < alpha, the greedy condition and all five lattice conditions withbeta > 1/4. The weaker readingfill > sqrt(base)stays true and unsharp. Witness: mobius.md The pair route, lab/py/mobius-region verb check, which prints the two floors at four designs andbeta <= alpha_1att = 1at the base-21 recompute. - Proved The region the pair route asks for is exactly two inequalities. Of the eight, one is a ceiling on
alpha_1alone,2 alpha_1 < alpha, and seven are caps onbetaat fixed(alpha, alpha_1); four of the seven fall inalpha_1and three are constant in it, so each takes its minimum at the wallalpha_1 = alpha/2. There(2 - alpha) 2 beta < 1 - alpha_1reads1/4,2 beta < (1 - alpha_1)(1 - alpha_1 + alpha/2)reads(2 - alpha)/4and5 beta < 1 + alpha/2reads(1 + alpha/2)/5, three identities inalphawith the last two strictly above1/4on(1/2, 1); theu-condition has wall coefficient(3 alpha/2 - 1) + u (1 - alpha/2), so it reads exactly1/4foralpha >= 2/3and is vacuous foralphain(1/2, 2/3), where that coefficient is negative at small admissibleu. Vacuous or1/4, none of the four cuts, so foralphain(1/2, 1)the region isalpha_1 < alpha/2withbeta <= min(1/4, (2/5)(1 - alpha_1)), the greedy cap cutting below1/4exactly fromalpha_1 = 3/8, a threshold free ofalpha. Witness: mobius.md The pair route, lab/py/mobius-region verbs region and boundary. - Verified The pair route and the Mobius census cannot break each other, and no proved conditional exponent sits below a measured one. The criterion's conclusion is a log saving, so it caps
theta(F)at1inA_Funits, far above every measured running-maximum exponent of the census,0.4465to0.5358. The chain that does print an exponent is the GRH one,theta(F) <= 1 - (1/4 - alpha_1)/alpha, and it reads above1at every base-10 one-missing-digit column,1.1054746at the digit4, and0.9999819atbase = 21missing0, a saving under2 * 10^(-5)in the exponent against the trivial bound; so neither chain is falsified by the census at any design of it, and a design whose measured exponent rose above its own proved ceiling would refute one of them. Witness: lab/py/mobius-region verb criterion, mobius.md The pair route. - Proved The chord
1/sin x <= 1/x + (2/pi)(1 - 2/pi) xholds on(0, pi/2], wherecsc x - 1/xhas an all-positive Taylor series and so lies under its own chord; pairingrwithbase-1-rputs every shifted-grid argument inside(0, pi/2]att in (0, 1/2], andK(t) = K(1-t)carries the rest, soK(t) = sin(pi t) sum_(r mod base) 1/sin(pi (t+r)/base) <= (4/pi) base + sin(pi t) Psi'_basewithPsi'_base = (base/pi)(2 H(P-1) - 1 + 1/P) + (1 - 2/pi) base/2at evenbaseand(base/pi)(2 H(P-1) - 1 + 2/P) + (1 - 2/pi)(base/2 + 1/(2 base))at oddbase,P = floor(base/2),H(n) = ln n + gamma + 1/(2n)the desk convention of mobius.md; the paired argument sum isbase^2/4at evenbaseandP(P+1) + tat oddbase, the source of the odd1/(2 base), and at evenbasethe constant isPsi_base - base/2 + 2/pi. Witness: lab/py/mrly-pairing, verbonestep, the chord kernel block. - Verified The chord kernel bound cuts the gap between the proved kernel constant and the exact kernel sup
K_baseby a factor5.98: atbase = 3690the up-rounded gap columns givePsi_base - (K_base - (4/pi) base) <= 0.600121 baseandPsi'_base - (K_base - (4/pi) base) <= 0.100293 base, the same quantity the lemma-slack column floors to0.100292 base; the chord column reads0.100290, 0.100293, 0.100293atbase = 100, 1000, 2234, so the slack is flat to1e-5, and it is attained at the seatt = 1/2. Witness: lab/py/mrly-pairing, verbonestep, the chord kernel block. - Proved At one excluded digit and
base >= 36the one-step constant of the shifted-gridl^1recursion obeysB_base(F) <= (4/pi) base + Psi'_base + base/2 - sec(pi (e_0 - (base-1)/2)/base)/2, the phase identity and thesqrt(1-X) <= 1 - X/2chain of the earlier sharpening run against the chord kernel bound; the monotone step needsPsi'_base >= (1 + pi) base/2, which first holds atbase = 36withH(n) = ln n + gamma + 1/(2n), the desk convention of mobius.md, and atbase = 37with the harmonic number itself, the over-estimate safe elsewhere since it only raises an upper bound; the hypothesis is sufficient and not necessary, the max ofh(tau)sitting attau = 0at everye_0frombase = 8up on the exhaustive scan4..79. Witness: lab/py/mrly-pairing, verbonestep, the chord wall block; lab/rs/mertens-numerology,the_chord_floor_carries_its_harmonic_convention. - Verified The chord bound moves the GRH wall
base_0(1/2)from3690at step 3 and2446at the phase sharpening to1499at every excluded digit, and from1812to1032ate_0 in {0, base-1}, each an up-set over the exhaustive scan36..4000000; the rungsb = 1417/1850andb = 913/1160move from5700and22416to3525and14078, and from4242and16816to2459and10013, up-sets over36..8000000and36..40000000. Witness: lab/py/mrly-pairing, verbonestep, the chord wall block. - Verified Every chord wall costs out against the level-
x^(alpha/2)defect within five steps of itself: the savingdelta_basefirst exceeds1/(2(base-1) ln base)atbase = 1502for the wall1499and atbase = 1036for the wall1032, against2450for2446,1815for1812and3692for3690, every crossing an up-set to100000, each row scanned from its own floor,base >= 3at step 3,17at the phase sharpening and36at the chord, and no wall inherited. Witness: lab/rs/mertens-numerology, sharpened cost-out block,sharpened_cost_out_is_pinned. - Verified Nothing measured contradicts the chord bound: the worst ratio of the exact
B_base(F)to it is0.902124over everye_0atbase = 36..60,0.941239at the larger seats and0.936333over4000seeded draws of(base, e_0, t), against0.807189,0.876716and0.872146for the phase sharpening alone. Witness: lab/py/mrly-pairing, verbonestep, the chord falsification block. - Verified The weight the chord bound leaves behind is not free: at the seat
t = 1/2the kept weightw_r = abs(A_r)/(abs(A_r) + 1) >= s/(1 + s) >= s/2is worthbase/2, while dropping the singular terms by(1 + sign(A_r) cos) <= 2costs2 sum_(r mod base) 1/(abs(A_r) + 1) = (2 - 4/pi) base, measured0.726761 baseatbase = 1000, 3690, 20000against its exact limit2(1 - 2/pi) = 0.726761, a net-0.226761 base, so the route loses more than it wins. Witness: lab/py/mrly-pairing, verbonestep, the weight route block. - Proved Above each rung's step 3 wall the sharpened
m = 1certificate needs no scan:base PB_base(1) - base PB_base(1, e_0) = base/2 + sec(pi (e_0 - (base-1)/2)/base)/2 + 0.727 - 2(1 - 2/pi)with0.727 - 2(1 - 2/pi) = +2.3954 * 10^(-4)andabs(pi (e_0 - (base-1)/2)/base) < pi/2, soPB_base(1) - PB_base(1, e_0) > 1/2at everybase >= 17and every excluded digit, and the step 3 certificate(base-1) base^(-b(a)) - PB_base(1) > 0, proved positive fromq_0(a) = 3690,8578,33547on by the monotone floor atQ(b) = 723,1486,4754, carries the sharpened certificate over[q_0(a), infinity)unscanned. Witness: mobius.md step 3 sharpened and step 5, on lab/py/mrly-pairing verbonestep. - Verified Below each rung's step 3 wall the sharpened
m = 1certificate(base-1) base^(-b(a)) - PB_base(1, e_0) > 0is exhaustive and not a first crossing, so with the proved half aboveq_0(a)each sharpened wall is a half line and not a window: the scans17..4 * 10^6,17..8 * 10^6and17..4 * 10^7each run past their ownq_0(a)and hold at everybasefrom2446and1812atb = 3/4,5700and4242atb = 1417/1850,22416and16816atb = 913/1160, theheldcounts printing3997555,3998189,7994301,7995759,39977585,39983185, each equal tohi - w + 1. Witness: lab/py/mrly-pairing, verbonestep. - Proved The per-denominator Mobius input states, at the exact frequencies, and buys no exponent. Group the grid
a/base^levelof the orthogonality step bybase-power levelj, soa = a' base^(level-j)withbasenot dividinga'andhat F_level(a'/base^j) = fill^(level-j) hat F_j(a'/base^j)becauseg_Fat an integer isfill; withc_jthe primitive level-jsumsum abs(hat F_j(a'/base^j)),c_0 = 1andC_level = sum_j fill^(level-j) c_j, Baker-Harman's PROPOSITION p.194 eq. 6 under its hypothesis (4), thatL(s, chi)is zero-free insigma > afor EVERY Dirichlet character, taken at(r,Q)the frequency itself, where its second factor is1, givesabs(M_F(base^level)) <<_(base,eps) x^eps base^(-level) sum_(j <= level) fill^(level-j) c_j min(x^(b(a)), x^a base^(j/2))atx = base^level, the reduced denominator ofa'/base^jdividingbase^j. That sum lies in[m/base, 1]times the uniformbase^(-level) C_level x^(b(a)): Parseval on the shifted grid is exact,sum_(s mod base) abs(g_F((t+s)/base))^2 = qk, andabs(g_F) <= fill, sosum_s abs(g_F((t+s)/base)) >= base, henceC_j >= base C_(j-1)at everyjand the top level carriesc_level = C_level - fill C_(level-1) >= (m/base) C_level, whileb(a) <= a + 1/2at every rung keeps the uniform constantx^(b(a))on that level. So the exponent staysb(a) + c_base, the saving is at most-log(c_level/C_level)/(level log base) <= log(base/m)/(level log base)and vanishes withlevel, and the whole lever is worth one bounded factorbase/m. The bracket is proved for this corollary and for it alone, the level charge being an upper bound and not the pointwise truth: at compositebasea top-levela' = 5^level uhas true denominator2^level = x^0.301. Witness: lab/py/mrly-pairing verb perden, the exponent block,level(den - unif)reading-0.657068atbase = 3one digit off and-0.292383atbase = 10missing9, constant inlevel, the largest term sitting atargmax j = levelat every printed row by measurement and not by proof. - Verified The same tool at full strength buys no exponent either. Letting any reduced
r/Qserve any frequency,Q(1 + x abs(a/base^level - r/Q)) = Q + abs(aQ - r base^level), so the per-frequency constant ismin(x^(b(a)), x^a nu(a)^(1/2))withnu(a) = min_Q (Q + norm(aQ)_(base^level)), and the honest ratio to the uniform input rises withlevelwhile its exponent gain decays faster than1/level. Witness: lab/py/mrly-pairing verb perden, the full minor-arc block,nuchecked against a full search over every reducedr/Qatbase^level = 81with0mismatches, ratio0.817368,0.835986,0.851049,0.861910atbase = 3level = 6, 8, 10, 12and0.684136,0.705013,0.737968atbase = 10level = 4, 5, 6, withleveltimes the gain falling from-0.183564to-0.135265and from-0.164858to-0.131963; that the ratio is bounded below inlevelis measured over these seven rows and not proved. - Proved The
l^1mass of a digit transform decays geometrically downward from the top denominator. FromC_j >= base C_(j-1)the top level's share isc_j/C_j >= m/baseat everyj, and the levels belowJcarrysum_(j <= J) fill^(level-j) c_j = fill^(level-J) C_J <= (fill/base)^(level-J) C_level, so the mass on the levels of reduced denominator at mostx^(1/2), the tie atj = level/2included, is at most(1 - m/base)^(ceil(level/2))of the whole and falls geometrically inlevel. Witness: lab/py/mrly-pairing verb perden, the level-profile block, which asserts the decomposition identity, the floor and the cap at every printed row. - Verified The measured level profile at one excluded digit. Top-level shares
0.485846,0.510055,0.573574and0.676152atbase = 3level12,base = 10level6,base = 101level3andbase = 1499level2, against the proved floorm/base = 0.333333,0.100000,0.009901and0.000667, the last two short rows whereC_j/C_(j-1)is still moving,244.658399then234.507307atbase = 101, and so not converged constants; the levels of reduced denominator at mostx^(1/2)carry0.018474,0.117603,0.174294and0.323848against the proved cap0.087791,0.729000,0.980296and0.999333; the one-step ratiosC_j/C_(j-1)read3.889889,18.369403,234.507307and4625.632148, each above the proved floorbase. Witness: lab/py/mrly-pairing verb perden, level-profile block, reproducing verb split's18.369402635and its top share0.510055, and matched by brute force over the digit strings atC_j = 234.856179,913.566768and331.978584with top shares0.485833,0.485848and0.512017forbase = 3j = 4, 5andbase = 10j = 2. - Proved Baker-Harman's PROPOSITION is a
d-form minor-arc bound, and that is where it pays, inside eq. 6's printed range onQ, which the desk has not read. On a Dirichlet arcabs(theta - l/d) <= 1/d^2with(l,d) = 1it readsS_mu(theta) << x^(a+eps) d^(1/2) (1 + x/d^2)^(1/2) = x^(a+eps) (d + x/d)^(1/2) <= x^(a+eps) (d^(1/2) + x^(1/2) d^(-1/2)), which ata = 1/2isx^eps ((x d)^(1/2) + x d^(-1/2))under the generalized Riemann hypothesis. Unlike the rows above, where themincaps the PROPOSITION by the uniform THEOREM at the level that decides, this one applies eq. 6 at an arbitrary arc denominatordand so carries that unread range. Witness: lab/py/mrly-pairing verb perden, the arc block, derived from the statement quoted at source in REFS.md. - Proved The chord kernel constant beats the step 3 one at every base with no scan:
Psi'_base < Psi_baseat everybase >= 5, byPsi'_base = Psi_base - base/2 + 2/piat evenbaseand byPsi_base - Psi'_base = (2 base/pi)(H(P) - H(P-1)) + (base/pi)(1 - 2/P) + (1 - 2/pi)(base/2 - 1/(2q))at oddbase,P = floor(base/2), positive sinceH(P) - H(P-1) = ln(P/(P-1)) - 1/(2P(P-1))andln(P/(P-1)) > 1/(P - 1/2) > 1/(2P(P-1))atP >= 2. Witness:cargo test -p mertens-numerology the_chord_constant_saves_half_a_base,psi_chord(base) < psi(base)at everybasein36..3999,34 passed; 0 failed. - Proved Hence each chord wall is a half line and not a window:
base PB_base(1) - base PB'_base(1, e_0) = (Psi_base - Psi'_base) + base/2 + sec(pi (e_0 - (base-1)/2)/base)/2 + (0.727 - 2(1 - 2/pi)) > 0at everybase >= 36, so the step 3 certificate, positive frombase_0(a)on by the monotone floor, carries the chord certificate over[base_0(a), infinity)unscanned. Witness: mobius.md step 5, on lab/py/mrly-pairing verbonestep, chord walls1499and1032holding3998502and3998969of the scan36..4 * 10^6. - Conjecture The criterion, with the owed list it now carries. A digit set satisfying (E1) whose
l^1exponent obeysalpha_1 < 1/4hassum_(level in S_F, level <= x, (level,base) = 1) mu(level) = O_B(A_F(x) (log x)^(-B))for everyB. The two steps that read the sequence rather than the set are proved here, the major arcs formuat base-smooth moduli and the level of distribution on an initial segment; the lattice half, the line half and both bookkeeping steps are now written out at general base, so the three write-outs the program listed as owed are written and this supersedes the owed list carried by the earlier criterion rows in OPEN. One arithmetic item is left, the level of distribution at base-divisible moduli, needed only to drop(level, base) = 1: the level carries by the divisor split but the main term does not, being a digit-string count times1/d_2and not1/d. Of the source reading, the line branch's close is read once and owes a second reading. Witness: mobius.md The pair route. - Refuted The seat of
B_base(F)is nott = 1/2at everybase >= 10: atbase = 11,e_0 = 0the sup on the cut is22.5094271855att = 0.47275againstSigma(1/2) = 22.4703926508, and atbase = 13,e_0 = 0it is27.9876970872att = 0.47875against27.9570308138, so the seat is interior at both.t = 1/2is the seat at every family printed frombase = 100up, and is where the constant is read and not where it is proved to sit; the floor2(base-1)and the sup scan are untouched, while any wall read offSigma(1/2)alone is a reading and not a bound. Witness: lab/py/mrly-pairing, verbonestep. - Refuted Base 10 is refuted at every excluded digit, on both branches, rather than merely unreached. A published or certified moment exponent is an upper bound on
betaand can never show the criterion fails, so the publishedbeta <= 23/80prices a gap of3/80and refutes nothing. From below,F_x <= 1makesm_tnon-increasing andm_2 = 1 - alphais exact, so adaptive chains of25to53cells certifybeta > 1/4at all ten one-missing-digit sets of base 10, the certified lower bounds running0.2502716to0.2541480. One such certificate kills both branches: the merged window asksbeta <= 1/4, and the single-window branch asksalpha_1 <= 1 - (13/4) beta, which withbeta <= alpha_1readsbeta <= 4/17 < 1/4. At the target0.2626the same chain givesbeta >= 0.2632014at each of the eight non-extreme digits, up to0.2645208at the digit7, with the digits0and9undecided, so the two extreme digits are strictly the cheapest columns of the base. Witness: mobius.md The pair route, lab/py/mobius-region verbs threshold and threshold 0.2626. - Refuted The per-denominator weighting lowers neither the exponent cost
c_basenor the baseq_0of the conditional power saving on the dense digit columns. At the top levelj = levelthe charge isx^(a + 1/2)and the uniform constantx^(b(a)), anda + 1/2 - b(a)is1/4,47/185,61/232,19/70,3/10and1/3as exact rationals ata = 1/2, 13/25, 11/20, 4/7, 3/5, 2/3, so the top level is strictly worse at EVERY rung of both exponent tables and the crossing2(b(a) - a)never exceeds1/2; the certificate(base-1) base^(-b(a)) - PB_base(1, e_0) > 0takes no per-denominator quantity at all, so the GRH walls of the chord certificate stand untouched. Beatingx^(3/4)on the top level means bounding the Mobius exponential sum at denominatorbase^level = x, which is the conjecturalx^(1/2 + eps)at essentially every frequency and lies past the method's ceiling. Witness: lab/py/mrly-pairing verb perden, the rung block, every rung printingnoin itsbeats uniform at j = levelcolumn. - Proved Above the supremum the
L^pnorms of the digit transform buy nothing:max(fill^p, base fill^(p/2)) <= Lambda(p) <= base fill^(p-1)forcesLambda(p)^(1/p)/fillto1, reading1.224744, 1.029883, 1.004288, 1.000653, 1.000107atp = 2, 4, 6, 8, 10for{0,1}atbase 3. Witness: lab/rs/rho-decoupling, riesz higher moments. - Proved The unbalanced kernel carries no Type II estimate uniform over bounded coefficients at any digit set containing
0:a_m = b_l = 1makes the sum the box representation count and some admissible box carriesR >= x^(alpha - o(1)), while on the balanced sum the bound-to-trivial ratio rises through1,1.0134atlevel 12and1.0730atlevel 14at{0,1}base 3, the margin ofalphaover the achieved exponent falling0.035675to0.027009, and inside the arc regime the digit column is worse for the method than a random column of the same density at every cell. Witness: lab/rs/rho-decoupling, menergy type II. - Verified Two box witnesses floor every coefficient-free route at
x^alphaover the nine dense cells:a_m = b_l = 1reads0.19to0.41offill^levelanda_m = 1_(base divides m),b_l = 1reads0.0024to0.104, the second carried by the frequenciesa'/base^jat boundedj. Witness: lab/rs/rho-decoupling. - Conjecture That the same floor holds at every digit set, which rests on
R >= fill^level (log x)^(-C)and is void atalpha = 0.15where the box is empty. Witness: lab/rs/rho-decoupling. - Verified The cost-out of the GRH saving against the level-
x^(alpha/2)defect runs at the rungb = 3/4and at no rung above it, so no rung pasta = 1/2is set against the defect anywhere. Witness: lab/rs/mertens-numerology, the cost-out block.
The Eisenstein stack
- Proved The Eisenstein spun stack is the hexagonal twin of the Gaussian one: layers are the nonzero associate classes of
Z[omega], layerzthe latticez^-1 Z[omega]; the hexagonal circle count is the floor sumh(t) = sum_j (floor(t/(3j+1)) - floor(t/(3j+2))), the twin of the Gaussianfloor(t/(4j+1)) - floor(t/(4j+3)), equal to direct enumeration of classes for everytfrom 0 to 400; a node of reduced denominator class[d]has brightnessh(floor(N/N(d))), checked by literal stacking of all 31 layers at norm bound 50 in exact rational coordinates, 630 nodes and 0 mismatches, the origin at 31; the lit set hassum_{[d], N(d) <= N} Phi(d)points withPhi(d) = N(d) prod_{p | d} (1 - 1/N(p)), reading 630, 9606, 151020, 337026, 945486 and 2419950 at norm bounds 50, 200, 800, 1200, 2000 and 3200. Witness: lab/py/eisenstein-stackhex_classes_closed,hex_classes_direct,literal_stack,closed_brightness,totient_sum. - Proved A rotation keeps two hexagonal layers coincident iff it lies in
Q(sqrt -3), iff its cosine is rational and its sine a rational multiple ofsqrt 3, and those rotations are exactlyw/conj(w)for nonzerowinZ[omega]by Hilbert 90 (all 58 rational rotations of denominator at most 60 are reached from the box of side 20); at whole degrees exactly the six multiples of 60 survive, against four of 360 on the square lattice, by cyclotomic reduction moduloPhi_360and twelve minimal-polynomial spot checks; the hexagonal coincidence series is(1 + 3^-s)^-1 zeta_K(s)/zeta(2s) = prod_{p = 1 mod 3} (1 + p^-s)/(1 - p^-s), read at source in Pleasants, Baake and Roth and re-derived coefficient by coefficient to bound 100. Witness: lab/py/eisenstein-stackrotation_hits,field_rotation_degrees,spot_check_degrees,csl_zeta_ratio,csl_euler_product, REFS.md.
The hexagonal slice
- Verified The carpet face-count law
V(i) = 2 * 20^i + 4 * 8^i, visible faces6, 72, 1056, 18048, 336384, is A332705 verbatim, the surface area of the stage-iMenger sponge, with the same closed form on the entry. Witness: mrlymath::formulas::surface::surface, A332705. - Proved The carpet slice census
6, 42, 306, 2250, 16578isA299916(level+1): sectioning the sponge at levellevelonx + y + z = 1.5 * 3^level, a surviving cube cuts a hexagon of 6 mesh triangles or a triangle of 1, refinement triples the plane offset, and the 20 surviving subcubes split by coordinate sum as1, 3, 3, 6, 3, 3, 1, soH_(level+1) = 6 H_level + T_levelandT_(level+1) = 6 H_level + 3 T_level, the hexagon-triangle substitution proved by exhaustion; the ledger54 = 6*6 + 6*1 + 12punches exactly one 12-triangle hexagram per hexagon and none per triangle, so hexagram holes of then-th size numberA299916(n)and the mesh census is one index up; the recurrencea(n) = 9 a(n-1) - 12 a(n-2)gives the slice dimensionlog((9 + sqrt(33))/2)/log(3) = 1.818410; the empty area atlevel = 0..5resolves into1, 6, 42components of descending size, each with six radial maxima, sixfold symmetry to0.001andmax/minradius1.68against the hexagram'ssqrt(3). Witness: slice-recurrence-order,mrlymath::six::topologytestthe_carpet_slice_percolates_at_base_three, A299916. - Verified The slice vertex count
12k^2 - 6k + 1is A154105 atn = k - 1and the centered hexagonal number A003215 at index2k - 1(3m(m+1) + 1atm = 2k - 1), so a prime vertex count is a cuban prime, A002407; atk = 1..20ten values are prime,7, 37, 271, 397, 547, 919, 1657, 1951, 2269, 4219, and ten composite,91, 169, 721, 1141, 1387, 2611, 2977, 3367, 3781, 4681. Witness: mrlymath::formulas::six::solid_slice_vertices, A154105, A003215, A002407.
The layers as a dilation system
- Proved The stack's layers are a dilation system: the square wave
s(x) = (-1)^floor(x)is the odd 2-periodic extension of the constant 1, so the layerss(nx)are the dilates of one function in the sense of Hedenmalm, Lindqvist and Seip, with sine coefficientsa_n = 2 sqrt 2/(pi n)on oddnand 0 on even, and the symbolS(s) = (2 sqrt 2/pi)(1 - 2^(-1-s)) zeta(1 + s); the moire correlation law is exactly that system's Gram matrixsum_j a_(j n') a_(j m'), its both-odd hypothesis being the symbol's support on the odd integers, the lcm-grid integral and the symbol sum agreeing at all 78 pairsm <= n <= 12(1/15at(3,5),1/3at(3,9), 0 at(2,3)); the Gram vanishes unlessv_2(m) = v_2(n)and every block is the odd Gram, so the full system's Gram operator is a direct sum of copies of the odd one and the half-period form is one block over 4. Witness: lab/py/stack-dilationscheck_dilation_shift,check_gram_two_ways,check_blocks. - Proved The parity layers are complete and minimal in
L^2(0,1)but neither a Riesz basis nor a frame: the Riesz criterion needs the symbol bounded onRe s > 0andSis unbounded at the pole ofzeta(1 + s)(Hedenmalm-Lindqvist-Seip Theorems 5.2 and 3.1), the normalised coefficientsa_n/a_1being totally multiplicative with divergent prime sum (Corollary 5.3), completeness and minimality following from Corollary 5.8 with the biorthogonal system built from the Dirichlet inversemu(n)/non oddnand not itself a dilation system; the sharp frame bounds are the supremum and infimum of|S|on the half-plane, infinity and zero; the parity stack is the boundary casetau = 1of the source's examplezeta(tau + s), Riesz ifftau > 1. Witness: lab/py/stack-dilationscheck_inverse, REFS.md. - Proved No weighting of the scales moves the stack's symbol off the line
Re s = 1: a weight multiplies the symbol by its own Dirichlet series at the sames, and the Mobius weight givesa_1^2/S, the reciprocal up toa_1^2 = 8/pi^2; over the firstKodd scaleslambda_maxrises2.01467to2.47224andlambda_minfalls0.4393to0.3570forK = 25to200, condition number4.586to6.926, the determinant exact against the Smith product atK = 1..13. Witness: lab/py/stack-dilationscheck_inverse,spectrum,check_determinant. - Refuted The pole heuristic that the largest Gram eigenvalue grows like
(log N)^2: the spectral norm of a gcd matrix at exponent one overkdistinct integers is of order(log log k)^2by Lewko and Radziwill 2014 Theorem 2, which settles the exponent-one case that Gal 1949 bounded for the gcd sum, and the window agrees, the(log N)^2ratio falling 1.93 acrossK = 25..200against 1.41 for(log log N)^2. Witness: REFS.md, lab/py/stack-dilationsspectrum.
The leaning stack
- Proved The leaning stack shifts layer
nof the line stack by a driftt_n, its lines sitting wheren x - theta_nis an integer withtheta_n = n t_n mod 1. The linear leantheta_n = n deltais a translation, lit setF_Q + deltaand brightnessfloor(N/b), 278 nodes and 0 mismatches atN = 30. The quadratic leantheta_n = n^2 c/dlightsa/biffn (a d - b c n) = 0 mod b d, the lit layers a union of2^wresidue classes modulo the periodlcm(b, d*)withd*the leastkwithd | k^2andwthe number of primes withv_p(b) <= v_p(d) < 2 v_p(b); 0 mismatches against literal stacking on 10240 point-drift pairs atN = 60,b <= 20,d <= 16, and 0 solution-set mismatches;lcm(b, d*)is a period and not always the least, the least beinglcm(b, d*)/2exactly whenv_2(b) >= 1andv_2(d) = 2 v_2(b) - 1, 417 of 16384 tuples withb, d <= 20halving and 0 breaches of the rule. Witness: lab/py/leaning-stacklinear_lean,quadratic_lean,brightness_form,minimal_period_law,adversarial. - Proved The leaning stack's lit set reads the numerator and its brightest node leaves the origin: at
delta = 1/4the point1/4is lit byn = 0, 1 mod 4and3/4byn = 0, 3 mod 4,B_61 = 31against 30, 48 such pairs overb <= 12anddin 2, 4, 8, 9; the origin's brightness at driftc/disfloor(N/d*), so atdelta = 1/2the point1/2reads 60 atN = 60and the origin 30, the origin beaten at five of seven printed drifts; the origin's density1/d*is A019554, multiplicative witha(p^e) = p^ceil(e/2), its Dirichlet serieszeta(2s+1) zeta(s+1)/zeta(2s+2)recovered as1.826902against1.826907ats = 1; the phase census at prime drift denominator is a Legendre symbol,n^2 c/ptaking(p+1)/2values with multiplicity1 + (j c^-1/p), the centred twistS(c, p) = (c/p) S(1, p)holding coefficient by coefficient and the solution count being the Fourier sum of quadratic Gauss sums, 0 breaches atp = 5, 7, 11, 13. Witness: lab/py/leaning-stacklit_set,origin_law,gauss_sums. - Proved Layers
m != nof the quadratic lean share a lit point ifflcm(m, n)(m - n) deltais an integer, 0 criterion failures against literal intersection on 5280 pairs overm < n <= 12and every reduced drift withd <= 16, so at irrational drift no two layers ever coincide and brightness is at most 1 everywhere at everyN, the translation twin of the dead-spin theorem; the 325 lit points of layers1..25are distinct atsqrt 2 - 1andphi - 1, the closest approach toN = 120being9.202e-09, and the near-coincidences follow Weyl's equidistribution ofn^2 delta, star discrepancy0.019450, 0.006421and0.022253, 0.009391atN = 1000, 10000against1/sqrt N, four points and no exponent. Witness: lab/py/leaning-stacksharing_law,adversarial,irrational_lean. - Refuted The lean is a weight on the scales: no weight
wreproduces it, its brightness density2^w/lcm(b, d*)per unitNdepends on the numerator while every weighted stack readssum_{k <= N/b} w(kb), denominator-only, and no weight makes a node brighter than the integer, whichx = 1/2atdelta = 1/2is; the lean is the first operation on this tree outside the Dirichlet group with a closed form. Witness: lab/py/leaning-stackquadratic_lean,lit_set.
The memory dial
- Proved A width-
kruleWover the2^dimdigit vectors hasN_W(level) = 1^T A_W^(level-k+1) 1forlevel >= k - 1, where the states ofA_Ware the2^(dim(k-1))windows of widthk - 1andA_W[s][t] = 1iffsandtoverlap ink - 2digits and thek-window they form is allowed, with thek = 1case reading one state andA_W = [#W]; an accepted word of lengthlevelis exactly a path oflevel - k + 1steps (witness: lab/py/memory-census README THE TRANSFER MATRIX). - Proved The memory number
kappa(W) = log_2(#W)/k - log_2 rho(W)is nonnegative for every width-krule, since an accepted word of lengthmksplits intomdisjoint allowed windows and soN_W(mk) <= #W^m, givingrho^k <= #W; it is zero on every product ruleW = F^kwithFnon-empty, whereN_W(level) = #F^level, while the empty rule has#W = 0andrho = 0and carries nokappaat all (witness: lab/py/memory-census README THE MEMORY NUMBER). - Proved Every element of
G_(dim,k), the signed permutationsB_dimapplied diagonally to thekdigits of a window together with window reversal, preservesN_W(level)for everylevel: a diagonalB_dimelement conjugatesA_Wby a permutation matrix and reversal transposes it, andAandA^Tshare a characteristic polynomial (witness: lab/py/memory-census README THE GROUP). - Proved At
dim = 1the classes of width-krules under diagonalB_1alone number2^(2^k - 1) + 2^(2^(k-1) - 1), because the digit flip acts on the2^kwindows asw -> 2^k - 1 - win2^(k-1)two-cycles (witness: lab/py/memory-census README THE CENSUS, Burnside). - Proved The set of Perron roots occurring at width
kis contained in the set occurring at widthk + 1: the ruleW' = {(d_1..d_(k+1)) : (d_1..d_k) in W and (d_2..d_(k+1)) in W}accepts the same words of lengthk + 1and above, which is allrhoneeds, while atlevel = kexactly it has no window and accepts every word (witness: lab/py/memory-census README THE PERRON ROOTS). - Proved
G_(1,4) < G_(2,2) < B_4as permutation groups of the4-cube: flipping all four bits is the diagonalB_2element flipping both axes, and the width-4 window reversal is the(2,2)block swap composed with the diagonal axis swap (witness: lab/py/memory-census README THE GROUP). - Verified Width-
krules at base 2 in dimension 1 fall into3, 9, 88, 16960classes underG_(1,k)fork = 1..4, out of4, 16, 256, 65536rules, the orbit walk agreeing with an independent Burnside average on every row (witness: lab/py/memory-census census.csv, orbit walk and Burnside). - Verified Under diagonal
B_dimalone with no window reversal the counts are3, 10, 136, 32896atdim = 1andk = 1..4and6, 8548atdim = 2andk = 1, 2, against3, 9, 88, 16960and6, 4660with reversal (witness: lab/py/memory-census census.csv, orbit walk and Burnside). - Verified The memory dial at
k = 1is the plain design census:3classes atdim = 1and6atdim = 2, A000616 at1and2, with the two groups agreeing because reversal is trivial (witness: lab/py/memory-census census.csv, the(dim,1)rows). - Verified A width-
krule in dimensiondimis a subset of thek dim-cube counted with a smaller group, so the class counts meet or exceed A000616 atk dim, by factors1, 3/2, 4, 42.19atdim = 1andk = 1..4and1, 11.59atdim = 2, equal atk = 1where reversal is trivial and the two censuses coincide (witness: lab/py/memory-census census.csv column a000616). - Verified Code
7atdim = 1andk = 2, the rule forbidding the window11, has Perron root the golden ratio, minimal polynomialx^2 - x - 1andrho = 1.618033988749(witness: lab/py/memory-census classes.csv, PARI factor and polrootsreal). - Verified At
dim = 1andk = 3the four named roots land on the four expected codes, each the least code of its class: code127gives tribonaccix^3 - x^2 - x - 1at1.839286755214, code55golden, code23supergoldenx^3 - x^2 - 1at1.465571231876, code54plasticx^3 - x - 1at1.324717957244(witness: lab/py/memory-census classes.csv, PARI). - Verified The same four named polynomials occur in dimension 2 at width 2, on least codes
327tribonacci,19golden,323supergolden and326plastic, carrying121, 588, 54, 48classes, so the named roots are not a dimension-one accident (witness: lab/py/memory-census classes.csv). - Verified Across the whole census
kappa(W) = 0holds on exactly the non-empty product classes,2at every(1,k)and5at every(2,k), with zero counterexamples over19563live classes; the test is exact,kappa = 0iff the minimal polynomial ofrhodividesx^k - #W(witness: lab/py/memory-census census.csv columns classes_kappa0 and kappa0_nonproduct). - Verified For
k >= 2the largest memory number in the census is attained atrho = 1, by the largest rule of zero entropy, on a tie of1, 3, 4, 3classes whose least codes arelog_2(3)/2 = 0.792481on code11at(1,2),log_2(6)/3 = 0.861654on code175at(1,3),log_2(13)/4 = 0.925110on code49071at(1,4)andlog_2(10)/2 = 1.660964on code36079at(2,2); atk = 1every live rule is a product,kappais identically0and the maximum is attained on every live class, the full rule atrho = 2^dimincluded (witness: lab/py/memory-census census.csv columns kappa_max, kappa_max_code and kappa_max_ties). - Verified The window budget of zero entropy, the largest number of windows a live class with
rho = 1allows, is1, 3, 6, 13atdim = 1andk = 1..4and1, 10atdim = 2: a rule may allow that many windows and still accept subexponentially many words, code11at(1,2), which allows00, 01, 11, accepting every0^a 1^bwithN_W(level) = level + 1(witness: lab/py/memory-census census.csv column rho1_windows). - Verified The distinct characteristic polynomials number
3, 6, 23, 431atdim = 1andk = 1..4and5, 333atdim = 2andk = 1, 2, and the distinct minimal polynomials ofrhonumber3, 4, 10, 177and5, 185(witness: lab/py/memory-census census.csv, exact Faddeev-LeVerrier and PARI factor). - Verified The Perron roots that fail to dominate their conjugates strictly number
12of177at(1,4)and5of185at(2,2), and every one of them isp(x^m)for somem >= 2withpthe minimal polynomial of a strict root already in the census, for instancex^4 - x^2 - 1andx^6 - x^3 - 1for the golden ratio; strictness is decided numerically, PARI complex roots against a1e-20gap, and thestrictcolumn is left empty on the dead rowxso that the live count reads12and5(witness: lab/py/memory-census census.csv columns weak_perron_polys and weak_are_radicals). - Verified Burnside extends the class counts past the orbit walk at no cost: under
G_(1,k)fork = 1..8they are3, 9, 88, 16960, 1074036736, 4611686053860868096, 85070591730234617055658644612208132096, 28948022309329048855892746252171977006958709724020498949042189405102555529216(witness: lab/py/memory-census memory.py Burnside extension, 0.01s). - Verified None of
3, 9, 88, 16960,6, 4660,3, 4, 10, 177or3, 6, 23, 431appears in the local OEIS dump;3, 10, 136, 32896, 2147516416greps three hits, A055708, A056006 and A191363, each a list of integers with a sigma property agreeing only through the closed form2^(m-1)(2^m + 1)atm = 2^(k-1)(witness: grep of the local dump for each comma-delimited string, names read at source). - Verified The census, the crate and the demo read a corner the same way:
mrlymath::bang::universe::corners(dim)emits the corner vector row first andcorner_indexfolds it most significant first, so a crate design's corner integer atdim = 2isc = x + 2y, bit0the column and bit1the row, and no code label moves between the three (witness: crates/mrlydemo/tests/memory.rs::width_one_is_the_plane_design_cell_for_cell, which pins codes11and13, exchanged by the axis swap and drawn differently). - Verified The width-one memory rule is the plane design of the same code cell for cell, for codes
1, 7, 9, 11, 13, 14at every level one to six (witness:mrlydemo::memory::memory_sheetagainstmrlydemo::two::two_grid, testcrates/mrlydemo/tests/memory.rs::width_one_is_the_plane_design_cell_for_cell) - Verified The golden rule,
dim = 1width2code7, which forbids the window11, accepts2, 3, 5, 8, 13, 21, 34, 55words at levels one to eight, the Fibonacci numbers (witness:mrlynum::memory::counts, testthe_golden_rule_counts_the_fibonacci_numbers) - Verified The golden rule has Perron root
1.618034, growth exponent0.694242and memory numberkappa = log_2(3)/2 - log_2(phi) = 0.098239(witness:mrlynum::memory::perron,exponent,kappa, check rowmemory golden growth) - Verified The supergolden rule,
dim = 1width3code23, the sponge code read as a window rule, allows at most one1a window and accepts2, 4, 4, 6, 9, 13, 19, 28words at levels one to eight, the Narayana cow recurrencea(level) = a(level - 1) + a(level - 3)holding fromlevel = 2k = 6on and failing atlevel = 5, where the count is9againsta(4) + a(2) = 10(witness:mrlynum::memory::counts, testthe_supergolden_rule_counts_the_narayana_cows) - Verified The supergolden rule has Perron root
1.465571, the supergolden ratio, the real root ofx^3 = x^2 + 1(witness:mrlynum::memory::perron, check rowmemory cow root) - Verified The rule that forbids a digit twice in a row,
dim = 2width2code31710, accepts4, 12, 36, 108words at levels one to four, root exactly3since its transfer matrix isJ - Ion the four digits with minimal polynomialx - 3, and memory numberkappa = log_2(12)/2 - log_2(3) = 0.207519(witness:mrlydemo::memory::memory_read, check rowmemory no repeat, lab/py/memory-census classes.csv rowx - 3at(2,2)) - Verified The full rule accepts
2^(dim level)words at every dimension one to three and every width its span allows, and its growth exponent is the dimension (witness:mrlynum::memory::countsandexponent, testthe_full_rule_counts_every_word) - Verified The empty rule accepts every word shorter than its window and nothing at or past it, and its Perron root is exactly zero (witness:
mrlynum::memory::countsandperron, testthe_empty_rule_dies_past_its_window) - Proved The memory number
kappa(W) = log_2(card W) / k - log_2 rho, forcard Wthe allowed windows, is the bits per digit a rule spends on memory and is zero on every memoryless designW = F^kwithFnon-empty, so every width-one rule reads zero (witness:mrlynum::memory::kappaandallowed_windows, testwidth_one_is_the_memoryless_design) - Verified The plastic rule,
dim = 1width3code54, accepts2, 4, 4, 5, 7, 9, 12, 16words at levels one to eight, Perron root1.324717957the plastic number, the real root ofx^3 - x - 1, and memory number0.260981(witness:mrlydemo::memory::memory_read, testthe_width_three_presets_name_the_plastic_and_tribonacci_roots, check rowmemory plastic root) - Verified The tribonacci rule,
dim = 1width3code127, which forbids only the window111, accepts2, 4, 7, 13, 24, 44, 81, 149words at levels one to eight, Perron root1.839286755the tribonacci constant, the real root ofx^3 - x^2 - x - 1, and memory number0.056639(witness:mrlydemo::memory::memory_read, testthe_width_three_presets_name_the_plastic_and_tribonacci_roots, check rowmemory tribonacci root) - Verified The supergolden rule has memory number
kappa = 2/3 - log_2(1.465571232) = 0.115204(witness:mrlynum::memory::kappa) - Proved A width-
kdigit ruleWin dimensiondimat basebasecounts its accepted words by a path count: with states thebase^(dim(k-1))words ofk-1digit vectors andA[x,y]the number of allowed windows with prefixxand suffixy,N_W(level) = 1^T A^(level-k+1) 1for everylevel >= k-1, and atk = 1the matrix is[card W]so the count iscard W^level, today's fill law. (witness: beneath.md, The transfer matrix) - Proved A width-
krule in dimensiondimis a subset of the corners of thek dim-cube, so the raw census2^(base^(k dim))is the design count at dimensionk dimand transports unchanged, while the quotient does not: cube symmetry acts diagonally on thekwindows, so the group isB_dimof order2^dim dim!and notB_(k dim)of order2^(k dim) (k dim)!. (witness: beneath.md, Width k in dimension dim is a subset of the k dim-cube) - Proved The coupling
kappa(W) = log(card W)/(k log base) - log(rho(A))/log(base)of a width-krule is nonnegative, by cutting an accepted word of lengthmkinto itsmdisjoint windows so thatN_W(mk) <= card W^m, whilerho^(level-k+1) <= N_W(level)by the entry sum ofA^(level-k+1); andkappa = 0on every productW = G^kwithGnon-empty, whereN_W(level) = card G^levelandrho = card G, so every memoryless design with a non-empty rule sits at coupling zero. (witness: beneath.md, The coupling) - Proved Memory does not leave the lattice class: the counting series
sum_level N_W(level) x^levelof a width-krule is rational with denominatordet(I - x A), so atx = base^(-s)its poles sit on finitely many vertical linesRe s = log(abs(lambda))/log(base)over the nonzero eigenvalueslambdaofAand the pole set is invariant unders -> s + 2 pi i / log base, the same period as the memoryless case; one line can carry a finer progression, as atdim = 1,k = 2, code6, whose eigenvalues1and-1put poles at gappi / log baseonRe s = 0. (witness: beneath.md, What the dial does not buy; lab/py/memory-census, the class of code 6) - Proved The class count of width-
kbinary rules underG_(1,k)isa(2m) = 2^(2^(2m)-2) + 2^(2^(2m-1)-2) + 2^(2^(2m-1)+2^(m-1)-1)form >= 1anda(2m+1) = 2^(2^(2m+1)-2) + 2^(2^(2m)-1) + 2^(2^(2m)+2^m-2)form >= 0, by Burnside over the order-4 group: the digit flip fixes no window, reversal fixes the2^ceil(k/2)palindromes, and flip-reversal fixes the2^(k/2)antipalindromes at evenkand none at oddk; the form reproduces3, 9, 88, 16960and every Burnside extension term throughk = 8(witness: lab/py/memory-census verbburnside, the cycle index and the closed form agreeing atk = 1..11, and beneath.md, The memory dial). - Proved At
dim = 1andk >= 2every transfer matrix has determinant in{-1, 0, 1}, so the constant term of every characteristic polynomial is0,1or-1: rowssands + 2^(k-2)are both supported on the columns2sand2s+1taken modulo2^(k-1), those column pairs partition the columns assruns over0..2^(k-2)-1, and the matrix is therefore a row permutation of a block diagonal matrix with2^(k-2)blocks of size2 x 2over{0,1}; checked over all16, 256, 65536rules atk = 2, 3, 4(witness: lab/py/memory-census verblemmas, a Bareiss determinant and the signed block product agreeing in{-1,0,1}on every rule atk = 2, 3, 4, and beneath.md, The memory dial). - Proved Distinct minimal polynomials of the Perron root are distinct Perron roots: every conjugate of
rho(W)is a root of the characteristic polynomial ofA_Wand so an eigenvalue ofA_W, hence at mostrho(W)in modulus, so two conjugate Perron roots are equal in modulus and, both being nonnegative, equal; the3, 4, 10, 177minimal polynomials atdim = 1andk = 1..4are therefore3, 4, 10, 177distinct growth rates (witness: lab/py/memory-census verblemmas, no conjugate aboverhoon any of the 463 characteristic polynomials atk = 1..4, the 3, 4, 10, 177 minimal polynomials carrying 3, 4, 10, 177 distinctrho, and beneath.md, The memory dial). - Verified Second generators reproduce the memory census whole: a cycle-index Burnside counter gives
3, 9, 88, 16960, 1074036736, 4611686053860868096underG_(1,k)atk = 1..6and6, 4660, 1152921592116822016underG_(2,k)atk = 1..3, with the remaining extension terms atk = 7, 8andk = 4agreeing as well, and an exact integer Faddeev-LeVerrier enumeration over all rules, factored in PARI, gives3, 6, 23, 431characteristic polynomials and3, 4, 10, 177minimal polynomials atdim = 1andk = 1..4(witness: lab/py/memory-census verbburnsideatdim = 1, the census run's Burnside extension atdim = 2, verblemmasfor the polynomial counts, every cell reproduced). - Verified None of the memory-census counts is in the local OEIS dump:
3, 9, 88, 16960with every Burnside extension term throughk = 8,6, 4660with its extension throughk = 4,3, 4, 10, 177and3, 6, 23, 431each grep to zero hits as comma-delimited runs, while3, 10, 136, 32896hits A055708, A056006 and A191363 through the coincidence2^(2^k-1) + 2^(2^(k-1)-1) = A007582(2^(k-1)), and9and16960recur inside A367526, a grid tiling count with different neighbours (witness: grep of the local OEIS dump on the runs printed by lab/py/memory-census verbburnside, each hit read at source). - Verified The binary words of length
ncounted under the same group that the width-nrules are counted under, reversal together with bitwise complementation, are A005418 atn:1, 2, 3, 6, 10, 20, 36, 72atn = 1..8(witness: lab/py/memory-census verbburnside, the word orbits printed beside the class count, agreeing with the entry in the local OEIS dump). - Verified The Perron root of a transfer matrix is the largest root over the strongly connected components of its digraph, each component being irreducible with a simple root, so it is exact against that component's integer characteristic polynomial; at
dim = 1,k = 3, code5gives1, codes62,125and190give the plastic number1.324717957, code91gives1.380277569, code95gives the golden ratio1.618033989, and the coupling of codes125and190islog_2(6)/3 - log_2(1.324717957) = 0.455969; a stop comparing one scalar across two sweeps halts on a plateau of theI + Amass ratio and misses all six (witness: mrlynum::memory::perron and its test, lab/rs/memory-meter). - Verified The memory meter's control column is the Mertens function: the width-
1rule of code3at base2accepts every integer, and its meter reads-1, 1, 2, -23, -48, 212, 1037, 1928at10^1..10^8, asserted inside the run, which is A084237 (witness: lab/rs/memory-meter, thecontrol mertensline, and beneath.md, The memory meter). - Verified The same linear sieve reproduces the memoryless base-
3design meters exactly, so the memoryless row of the dial is pinned against the existing census: digits{0,1}read(M, max abs M) = (11, 105)atlevel = 14,(149, 173)atlevel = 16and(-30, 312)atlevel = 18, digits{1,2}read(-1461, 1582)atlevel = 18, each asserted; digits{0,2}atlevel = 20wants3^20, past the2^30sweep, and is printed unpinned atlevel = 14, 16, 18as(-10, 67),(-124, 152)and(67, 249). The four pinned pairs are read at source in lab/py/design-meter, which computes them and cites lab/rs/mobius-designs as their census (witness: lab/rs/memory-meter, thecontrol designlines, and beneath.md, The memory meter). - Verified The window-profile recurrence,
profile(n)beingprofile(n >> 1)unioned with the windown mod 2^k, reads the accepted integer set of every width-1,2and3rule atdim = 1, base2: on all276rules its masses agree with a direct digit recount below2^20, profile containment agrees withmrlynum::memory::Rule::acceptsbelow2^12, and at every one of the89phases the subset-sum transform of the per-profilemusums equals the independently carried per-rule meter (witness: lab/rs/memory-meter, thecontrol recountline, and beneath.md, The memory meter). - Verified Code
7at(dim, k) = (1, 2), the golden rule forbidding the window11, opens exactly the fibbinary integers A003714 without its zero, and its mass below2^levelis a Fibonacci number,A = 2178309below2^30; code11, forbidding10, opens exactly the Mersenne numbers A000225 without its zero and holds30elements below2^30, one per level (witness: lab/rs/memory-meter, thecontrol code 7andcontrol code 11lines, and beneath.md, The memory meter). - Verified The Mobius meter of every width
1,2,3rule atdim = 1, base2, read to2^30at the89phasesx = floor(2^(level + j/4)),level = 8..30,j = 0..3, no exponent fitted, each ratio at a named phase: at30.00the full line readsA = 1073741824,M = -10374,max abs M = 11173, ratios-0.316589and0.340973; the golden rule code7atk = 2,kappa = 0.098239, readsA = 2178309,M = 551,max abs M = 716, ratios0.373329,0.485125; thek = 3least codes23,54,127read normalised peaks0.731125,0.677943,1.239625atkappa = 0.115204, 0.260981, 0.056639(witness: lab/rs/memory-meter, theruleandrowlines, and beneath.md, The memory meter). - Verified A rule's
rhoandkappaare read off the transfer matrix of its word language whileAandMare read off its integer set, and on a rule that is not zero-closed those are different objects: atk = 3code5the word language grows on the self-loop000and carriesrho = 1, while the integer set holds3elements below2^30(witness: lab/rs/memory-meter, therule k=3 code=5line, and beneath.md, The memory meter). - Verified Over the census of
53rules of all three widths holding at least10^4integers below2^30, the floor fixed before any reading, the normalised peakmax abs M_W/sqrt(A_W)spans[0.293624, 1.239625]at phase30.00, least onk = 3code125and largest onk = 3code127, and spans[0.500000, 2.169240]over all89phases, the top onk = 3code232at phase16.75; the last-phase leader and the sweep-wide leader are different rules, so no rule is the dial's widest excursion (witness: lab/rs/memory-meter, thespanlines, and beneath.md, The memory meter). - Verified Read against the full line at the same phase, which needs no band and no grid, the factor
max abs M_W/sqrt(A_W)overmax abs M/sqrt(x)runs[0.861136, 3.635552]at phase30.00over the53census rules and reaches6.375774onk = 3code190at phase12.75over all phases (witness: lab/rs/memory-meter, thefactorlines, and beneath.md, The memory meter). - Verified Grouped by the coupling over the same
53rules at phase30.00, the mean normalised peak reads0.340973onkappa = 0with3rules, then0.622171on6,0.581446on14,0.644840on12and0.645966on18for the bands[10^-9, 0.1),[0.1, 0.2),[0.2, 0.3)and[0.3, 0.5); every band of positive coupling sits above thekappa = 0band, whose three rules are the full line under three codes, and among the positive bands the means are not monotone inkappa. Restricted tok = 3the same bands read0.340973, 0.698386, 0.581446, 0.644840, 0.645966on populations1, 4, 14, 12, 18(witness: lab/rs/memory-meter, thekappabandlines, and beneath.md, The memory meter). - Verified The full line's own normalised peak runs
[0.272410, 0.500000]over the grid, the ceiling at phase8.00, and that ceiling is a property of where the grid starts and not of the full line: below the grid the same ratio reads1.000000atx = 1,0.894427at5,0.832050at13,0.718421at31and0.565685at200(witness: lab/rs/memory-meter, thegridstartline, and beneath.md, The memory meter). - Verified The falsification fires. Five of the
53census rules never enter the full line's band at any phase where they hold10^4elements, all of them above it:k = 3codes159,182,190,218and250, holding211116,13607,31535,59860and4126645integers. The band's ceiling being grid-dependent, the same-phase factor is the instrument that carries the reading, and it is read rule by rule on the generator'sfactorlines (witness: lab/rs/memory-meter, theband outsidelines, and beneath.md, The memory meter). - Verified
16of the53census rules attain their sweep-wide normalised peak in the last quarter of the phases, from24.75on, so most of the dial peaked earlier and is not growing at the end of the sweep. No rule at any width holding at least1000elements hasM_W/sqrt(A_W)ormax abs M_W/sqrt(A_W)rise at every one of the last eight phases, but that test asksmax abs M_Wto grow about9%per quarter-level across two whole levels, so its empty answer carries little and the late-peak count is the informative statistic (witness: lab/rs/memory-meter, thelatepeakandclimbinglines, and beneath.md, The memory meter). - Verified Leading zeros move most rules' integer sets. A rule is zero-closed when prepending one zero changes no membership below
2^20: the zero-closed codes number3of4atk = 1,8of16atk = 2and64of256atk = 3, and are the codes allowing0with the empty code, those allowing01, and those allowing both010and011, asserted code for code. Under any number of zeros the word language agrees with the integer set on2of4,4of16and16of256codes, tested on every word to length14, so atk = 3the two readings part company on240of256(witness: lab/rs/memory-meter, thezeroclosedandreadinglines, and beneath.md, The memory meter). - Verified Equal mass is not the same set: code
14atk = 2, forbidding00, and code126atk = 3, forbidding000and111, each hold28655integers below2^20and each carryrho = 1.618033989, yet they share only1077of them, the symmetric difference is55156, and4is the least integer the second holds and the first does not; below2^30both hold3524576integers while their meters read-466and435and their normalised peaks0.454355and0.594444at phase30.00(witness: lab/rs/memory-meter, thepairline, and beneath.md, The memory meter). - Verified The matrix ladder of a memory design runs in double precision in the public crate.
mrlynum::automatoncarriesAutomaton,zeta,cofactor,residueanddenominator, every value beside its bound. The full rules, code15atk = 2and255atk = 3, meetmrlynum::ladderon the base 2 full design to7.18e-11ats = 2and2.03e-14ats = 0.3 + 40i, inside bounds; the product rule code8meets a direct Mersenne sum to1.12e-16; the golden rule code7meets a direct fibbinary sum with its Fibonacci tail bound, and every pinned golden reading meets the arbitrary-precision control inside its own bound, the fourzeta_Wvalues to3.0e-15and the largest of the fourteen rows1.134e-11against7.348e-11(witness: mrlynum::automaton, lab/py/memory-zeta, beneath.md, The memory zeta). - Proved The polynomial
beneath.mdnames the string equation of a memory rule is also the denominator of the rule's Dirichlet series, strictly more than that page proves.beneath.mdprovesdet(I - x A)denominates the counting series and namesdet(I - base^(-s) A) = 0the Moran replacement; the peel carries it tozeta_W, each level of(I - base^(-w) T) G_P(w) = E_P(w) + sum_(l >= 1) binom(-w,l) base^(-w-l) Gamma_l G_P(w+l)dividing bydet(I - base^(-w) T). So the poles ofzeta_Wlie inbase^(-s) lambda_i = base^m,lambda_ia nonzero eigenvalue andm >= 0whole, and that determinant is them = 0level's denominator, not the whole one (witness: mrlynum::automaton, beneath.md, The memory zeta). - Proved Right of the abscissa the matrix ladder carries its bound as a nonnegative vector and needs no norm and no primitivity, which settles the Conjecture row the ladder unit left open. For nonnegative
y,abs((I - base^(-w) T)^(-1)) y <= sum_(i >= 0) (base^(-Re w) T)^i yentrywise, sinceabs(base^(-w)) = base^(-Re w)andTis nonnegative; the remainder closes on the guidev = (I + T)^60 1, which meetsT v <= mu vfor the bracket's upper endmu, assum_(i > N) A^i y <= (max_u y_u/v_u) theta^(N+1)/(1 - theta) v,theta = base^(-Re w) mu < 1. The seed is exact:sum_(j >= P) E_j(sigma) <= base^(-(P-1)sigma) (I - base^(-sigma) T)^(-1) c_P(witness: mrlynum::automaton, beneath.md, The memory zeta). - Proved The residue of a memory zeta at a simple pole needs no eigenvector: the adjugate is the spectral projector in polynomial form. Faddeev-LeVerrier on
Tgives integer matricesM_kand integer coefficientsc_kwithadj(I - x T) = sum_(k < n) x^k M_kanddet(I - x T) = sum_(k <= n) c_k x^k, so withx = base^(-w)andNthe ladder numerator,Res_(w0) zeta_W = 1^T adj(I - x_0 T) N(w0) / (-x_0 log base det'(x_0)). The form is stable at the pole, wheredet(I - x_0 T) (I - x_0 T)^(-1)is not, and it dies exactly where the ladder unit said it would, at a multiple root, wheredet'(x_0) = 0and the pole order exceeds one (witness: mrlynum::automaton, beneath.md, The memory zeta). - Verified The golden rule carries two genuine pole combs interleaving at half a tooth.
Tof code7atk = 2is[[1,1],[1,0]]anddet(I - x T) = 1 - x - x^2, so one comb sits atRe s = log_2 phi = 0.6942419136306174withIm sin2 pi Z / log 2and one atRe s = -log_2 phiwithIm sin(2Z + 1) pi / log 2, the argumentpiof the negative eigenvalue shifting it half a period. The six residues atm = 0are under THE POLE COMB and none is zero. Comb two comes from the left-of-abscissa branch, so its path is the arbitrary-precision control and not the contour average: the six agree to6e-16and4.3e-12(witness: mrlynum::automaton, lab/py/memory-zeta, beneath.md, The memory zeta). - Verified Burnol's Proposition 5.1 survives the memory dial verbatim: the residue at the abscissa is the limit of the level digit sums. For code
7the direct sum ofn^(-alpha)over the fibbinary integers of exactlylevelbits, overlog 2, reads0.946747043404283,0.946743630023052and0.946743410426742atlevel = 16, 20, 24against the ladder's0.946743395641970, the gap falling like2^(-level)(witness: mrlynum::automaton, beneath.md, The memory zeta). - Verified The matrix Lyndon cofactor is the determinant with its adjugate, and it reads on the whole
m = 0comb where the series is singular.Z_W(s) = det(I - base^(-s) T) zeta_W(s)is carried asdet(I - base^(-s) T) D_(P-1)(s) + 1^T adj(I - base^(-s) T) N(s), so it never divides by the vanishing determinant; for code7it reads0.991729890316722ats = 3,0.973380053858285ats = 2and0.913335748872126ats = 0.8, each to a bound near1e-13, whilezeta_W(0.8) = 9.536379694275015is already climbing the pole at0.6942419136306174(witness: mrlynum::automaton, beneath.md, The memory zeta). - Proved Left of the abscissa a matrix ladder has no free denominator bound, and the module buys one with the residual of its own inverse.
abs(1 - k base^(-w))has no matrix analogue and the Neumann majorant diverges oncebase^(-Re w) rho >= 1, so the level closes on the computed inverseCcertified againstR = I - (I - base^(-w) T) C: for nonnegativey,abs((I - base^(-w) T)^(-1)) y <= abs(C)(y + (max_u y_u) r/(1 - r) 1)withrthe max row sum ofabs(R), and the module raises whenr >= 1. The second comb of code7is read only through that branch, at bounds near4e-9against1.3e-13on the first (witness: mrlynum::automaton, beneath.md, The memory zeta). - Verified The matrix Lyndon cofactor
Z_W(s) = det(I - 2^(-s) T) zeta_W(s)of the golden rule, code7at width2, has exactly20zeros in the box-0.95 < Re s < 2,0.02 < Im s < 43.1: the determinant strips bothm = 0combs in one factor, leavingZ_Wmeromorphic there with exactly4simple poles, the level-one teeth onRe s = -0.305758086, so each cell count is its argument-principle winding plus the level-one teeth the cell holds; all20are located with largestabs(Z_W)9.694e-12, largest surviving phase step0.999894radians against a cap of one, largest propagated bound1.474e-10, nothing within0.02of an outer box edge, and identical cell rows and zeros at contour seeds0.1,0.05and0.025, at7298,11777and21599evaluations, and with0 < Im s < 0.02,Im s > 43.1andRe s < -0.95uncounted,20is exact on the box (witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Verified The
4poles that census adds back are read and not assumed: a48-point circle mean ofZ_Wat each level-one tooth of code7gives residues-1.990368154340-0.795661945868i,-0.350975872907-0.436714265460i,-3.135030562964-2.032376530959iand-1.028888122837+2.036528502776i, radius0.05against radius0.02agreeing to7.3e-14, each simple to5.1e-05against(s - s_0) Z_Wat1e-5, while a blank point on the same line reads4.6e-16, and the same read at code23gives four residues of modulus2.231820,3.226224,2.438482and1.779516, the two radii agreeing to5.1e-14, against a blank point at6.3e-16(witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Proved
Z_Whas no zero inRe s >= 2on code7: the least element ofS_Wis1and the coefficients are nonnegative, soabs(zeta_W(s) - 1) <= zeta_W(2) - 1 < 1there fromzeta_W(2) = 1.415825532885 < 2, anddet(I - 2^(-s) T)has no root right of the abscissalog_2 phi, which makes the census box's right edge a wall and not a choice (witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Verified On code
7the first comb carries a zero comb and the second carries none: at the design family census radius0.45all4teeth of the comb onRe s = log_2 phibelowIm s = 43.1carry a zero, at distances0.317490225,0.045406362,0.143076282and0.070233751, while0of the5teeth onRe s = -log_2 phido, least distance0.666213518and largest0.758440773, and the emptiness holds over every point of every disc, the radius0.45disc reachingRe s = -1.144241913631, since the same census on-1.2 < Re s < 2, which admits no new pole line before-1.305758086369, returns the same20zeros, nineteen to twelve decimals and the twentieth to eleven, the same4of4and0of5and the same five distances (witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Verified The first-order tooth law
u_1 = -r/Rholds on code7's first comb to0.000951131,0.003342909,0.020403749and0.062287774and misses on the second by0.214394685,0.645682670,0.408924841,0.489190529and0.519744494, and it is a reading beside the census and not a second falsification:Ris a circle mean of radius0.3, three of the five second-comb predictions ofabs(u_1),0.501975708,0.398920848and0.301764481, are read outside that disc, and on the first comb the one prediction past0.3carries the worst miss (witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Verified The second comb's line carries zeros where its teeth do not: three of code
7's20zeros sit within0.05ofRe s = -log_2 phi, at0.000322593,0.014258173and0.043369824from that line, while their distances to the nearest tooth of the same comb are4.104099275,0.747618761and4.283371881, and stripping the4first-comb teeth leaves a second family of16with real parts in[-0.737611737911, 0.540957439322]; the excess is4.4times the0.68that20uniformly spread real parts would put in a window of width0.1on a box2.95wide, on a sample of20(witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Verified Exactly
9of the88width-3rule classes underG_(1,k)carry two pole lines, none with a repeated eigenvalue, and the cofactor's zeros are a resolved census on one printed box for all nine,S_Wread off the minimal base-2string:-1.15 < Re s < 2,0.02 < Im s < 20, contour seed0.05, which holds every radius0.45occupancy disc of every second line, the deepest reachingRe s = -1.144241913631; the nine read9to14zeros in20to36cells, every zero located, largest residual3.236e-11, largest surviving phase step0.999909radians against a cap of one, largest propagated bound9.110e-09, and no pole ofZ_Wwithin0.02of any contour, the least clearance being exactly0.02, from the cutIm s > 0.02to the level-mpole on the real axis. Resolved and not certified: nothing boundsZ_W'/Z_Won the contour, and two zeros sit within0.02of the left contour,-1.134547677+3.580553251ion code127and-1.143621954+17.814806003ion code63(witness: lab/py/memory-zeta, verbteeth, and beneath.md, The memory zeta). - Verified The occupancy reading is invariant across two boxes whose contours fail a
0.02guard in disjoint ways. On-1.2 < Re s < 2the pole linesRe s = -1.202842615688of codes54and62andRe s = -1.188629537248of code223sit0.002842615688and0.011370462752from the left contour, the first pair outside the box and so never added back; on-1.15 < Re s < 2every pole clears0.02and two zeros do not. Both boxes read50teeth,34occupied at radius0.45,23teeth predictingabs(u_1) < 0.3occupied22,15predicting at or above0.45occupied4,12between occupied8, and the same occupancy column on all nine rules; only the totals off the discs move, code23from13zeros to11and code31from14to13(witness: lab/py/memory-zeta, verbteeth, at--left -1.2and--left -1.15, and beneath.md, The memory zeta). - Proved With
S_Wread off the minimal base-2string, so that a word shorter than the window holds no window and is accepted, the width-3rule55accepts exactly the set of the width-2rule7with the single integer3adjoined, hencezeta_55(s) = zeta_7(s) + 3^(-s). Code55forbids exactly the windows011,110and111, which is exactly the ban on an adjacent pair of ones inside a3-window, and for length at least3the window starting atmin(i, level-3)holds the pair at(i, i+1), while the word11carries no window and is accepted; checked over1 .. 262143with3the only difference either way. Padded to the window width instead the two sets are equal and the claim is empty (witness: lab/py/memory-zeta, verbbridge, and beneath.md, The memory zeta). - Verified The width-
3ladder meets the controlled width-2one across that gap, which is the control on a new rule:Z_55(s) - Z_7(s) - det(I - 2^(-s) T) 3^(-s)reads at most1.168e-13over seven points including three teeth and one located zero, every point inside the sum of its own two bounds, so the4-state ladder, adjugate and peel meet the2-state ones that carry the stored arbitrary-precision control, itself met to1.134e-11on14rows with none outside its bound (witness: lab/py/memory-zeta, verbsbridgeandcontrol, and beneath.md, The memory zeta). - Verified One tooth of the
50carries two zeros inside the occupancy radius, so34occupied teeth hold35zeros: code54, second line, toothRe s = -0.202842615688,Im s = 14.612532469, holds0.213711738933+14.629308261174iat0.416892021and-0.597460129789+14.668266829134iat0.398533940, andabs(u_1) = 0.631828588there puts it in the bin the first-order law reads as empty. The other49teeth hold at most one, and the count is printed by the census itself astooth zeros 6against5occupied teeth on that rule (witness: lab/py/memory-zeta, verbsteethandcensus --width 3 --code 54, and beneath.md, The memory zeta). - Proved For a finite set
Fof positive integers disjoint fromS_W, the setS_W + F = S_W u Fhaszeta_(W+F)(s) = zeta_W(s) + P_F(s)withP_F(s) = sum_(n in F) n^(-s)a Dirichlet polynomial and so entire, hence the two series carry the same poles, the same orders and the same residues at every point of the plane, andZ_(W+F)(s) = Z_W(s) + det(I - base^(-s) A) P_F(s); adding a finite set is a knob on the zero set alone (witness: lab/py/memory-zeta verbdial, the off-tooth identityZ_(W+F)(s) - Z_W(s) - det(I - 2^(-s) T) P_F(s)missing by at most2.384e-15at code7and4.003e-16at code23against an added part of up to1.912203and1.708983). - Proved The knob cannot move the cofactor at a tooth: at every
m = 0toothtthe determinant vanishes, soZ_(W+F)(t) = Z_W(t)exactly, and the principal part ofzeta_Wattis fixed while the constant term becomesR + P_F(t), so the first-order zero position isu_1(F) = -r/(R + P_F(t)); every higher coefficient of the regular part moves too, the linear one byP_F'(t) = -log(n) n^(-t)(witness: lab/py/memory-zeta verbcensus, code55at width3readingr = 0.210170579-0.581938843iatIm s = 9.064720digit for digit against code7's andR = 1.313430833+1.119663028iagainst1.714940435+0.882338583i, a difference of-0.401509602+0.237324445iwhich is3^(-t)to nine decimals). - Verified The residue and tooth probes of the dial cannot falsify the perturbation's entirety and the off-tooth identity can: a
48-point circle mean annihilates an entire addition and the determinant vanishes at a tooth, so the printed gaps are an aliasing floor and a determinant residual and not a measurement, while the identity read off the teeth agrees to fifteen decimals against an added part of order one (witness: lab/py/memory-zeta verbdial,largest residue gap over every probe 1.776e-15, largest tooth value gap 1.250e-13, largest off-tooth identity miss 2.384e-15 against an added part of up to 1.912203at code7). - Verified The dial's disc probe reproduces the zero census it is read against: on code
7at width2it reads4of4teeth occupied on the comb atRe s = log_2 phiand0of5on the comb at-log_2 phi, and on code23at width3it reads3of4on the first comb and7of10on the second line, each occupancy an argument-principle count on a circle of radius0.45about the tooth with the level-mpoles inside added back (witness: lab/py/memory-zeta verbdial,edge guard splits 0on both baselines, a guard that covers the baselines and not the perturbed grid). - Verified Occupancy at radius
0.45under the knob is undetermined wherever a zero sits within the0.02guard of the occupancy circle and the inner count is0, which is9of the110cells of code7's second comb,10of the108of code23's abscissa comb and9of the270of code23's second line, so a minimum taken over a tooth's candidate row has two readings and the reading must be named (witness: lab/py/memory-zeta verbdial, per-line rowsoccupancy undetermined 9,occupancy undetermined 10andoccupancy undetermined 9). - Verified Every empty tooth of code
7's second comb is occupied by a single added integer from the22integers of2 .. 40outsideS_W, so the smallestFthat occupies a tooth of the empty comb has one element and that element is at most11under either reading of the seam, while the least singleton itself is radius-dependent at two of the five teeth:{3},{6},{7},{11},{11}on the inner reading against{3},{6},{3},{11},{6}on the outer, atIm s = 4.532360,13.597080,22.661801,31.726521and40.791241(witness: lab/py/memory-zeta verbdial, per-tooth rowssmallest singletonandouter reading occupied ... smallest singleton). - Verified Occupancy moves both ways on code
23and the count is stable under either reading of the seam: four empty teeth are filled,Im s = 9.064720by{7}or{6},20.807773by{5},29.872493by{7}and38.937214by{15}or{11}, and two occupied second-line teeth are emptied by a singleton off the seam,2.678332by{6}and42.645269by{6}and by{7}, so6of the14teeth of the box change occupancy under a one-element perturbation (witness: lab/py/memory-zeta verbdial,occupied teeth emptied by a singleton 2, both emptied teeth printing an empty seam list). - Verified The dial meets the cross-width control exactly where one exists:
S_7 + {3}isS_55, and the dial's grid at code7with the added element3reads the second comb's tooth atIm s = 4.532360occupied and the tooth at13.597080empty, which is the1of2the width-3four-state ladder prints for code55(witness: lab/py/memory-zeta verbsdial,bridgeandcensus,bridgereadingZ_55 - Z_7 - det(I - 2^(-s) T) 3^(-s)at most1.168e-13over seven points and the code55census readingzeros in the disc 1at4.532360and0at13.597080). - Verified The exact minimum of
abs(R + P_F(t))over all4158861subsetsFof size at most16of the22integers of2 .. 40outsideS_Wis1.095277075,0.784350607,1.295268436and1.662786204at code7's four abscissa-comb teeth, the greedy chain attains every one of them, and the disc at each exact minimiser keeps its zero off the seam,1/1,2/2,1/1and1/1, the tooth atIm s = 18.129441gaining a second zero rather than losing its first (witness: lab/py/memory-zeta verbdial --deep 16, rowsexact minimiser over the 4158861 subsets of size at most 16). - Conjecture Every width-
krule atdim = 1, base2, withrho > 1hasM_W(x) = O(A_W(x)^(1/2 + eps))for everyeps > 0: over all89phases every one of the53census rules has its sweep-wide maximum ofmax abs M_W/sqrt(A_W)inside[0.500000, 2.169240]and its same-phase factor against the full line inside[0.861136, 3.635552]at phase30.00, the sweep-wide maximum being6.375774on code190at phase12.75, with16of53peaking in the last quarter of the grid, against Mullner 2017, which givesM_W(x) = o(x)for an automatic set and no rate at all. A band at finite depth is not a rate and nothing here bounds the constant (witness: lab/rs/memory-meter, Mullner 2017, and beneath.md, The memory meter). - Conjecture What selects an occupied tooth is the first-order quantity
u_1 = -r/R, the residue ofzeta_Wat the tooth against the regular part ofZ_W/det, and not the spectrum. Over the50teeth of the nine two-line classes at width3,34teeth are occupied at radius0.45, the23whose predictionabs(u_1)falls below0.3, inside the radius0.3disc that buildsRand so where the reading is self-consistent, are occupied22times, and the15withabs(u_1)at or above0.45are occupied4times; the one exception inside0.3is code55's second-line tooth atIm s = 13.597080,abs(u_1) = 0.267301885with the nearest zero at0.497761908. Occupancy is a per-tooth Boolean and the law is a law onabs(u_1): the largest modulus missabs(d - abs(u_1))is0.739013203and the largest vector missabs(z - t - u_1)is1.287895060, both at code63's second-line tooth atIm s = 13.597080,abs(u_1) = 0.520202113against a nearest zero at1.259215316(witness: lab/py/memory-zeta, verbteeth, and beneath.md, The memory zeta). - Conjecture The knob's strength at a tooth
tisabs(n^(-t)) = n^(-Re t)and its direction the phase-Im(t) log nmod2 pi, so on a line withRe t < 0the strength grows withnand the largest candidate still reading empty rises with the tooth height, while on the abscissa comb, whereRe t = log(rho)/log(base) > 0, the strength decays and the flippers are confined to a bounded range ofnthat the phase selects inside: code7's second comb reads11,25,28,35on the inner seam convention and11,24,28,35on the outer, increasing under both, over a candidate range stopping at40(witness: lab/py/memory-zeta verbdial, per-tooth rowslast candidate reading emptyon both readings). - Refuted The Euler wall of
zeta.mdstands over the memory dial and its construction does not. The conclusion transfers:S_Wfor code7, the fibbinary integers, holds the coprime pair5and9whose product45 = 101101carries adjacent ones and leaves the set, so the indicator ofS_Wis not multiplicative and no Euler product over primes exists;45is the least such product over all coprime pairs ofS_Wbelow2^16. The construction does not:zeta.mdbuilds its witness from the repunitsR_candR_(c+1)of the least missing digitc, and a memory rule has no missing digit to take the least of (witness: mrlynum::automaton, beneath.md, The memory zeta). - Refuted "A memory rule's second pole comb carries no zero comb": the supergolden rule, code
23at width3, hasdet(I - x T) = 1 - x - x^3, one comb onRe s = log_2 psi = 0.551463089746and two interleaved onRe s = -0.275731544873from the conjugate eigenvalue pair of moduluspsi^(-1/2), and its census on-0.75 < Re s < 2,0.02 < Im s < 43.1reads24zeros in70cells, largest phase step0.998514, of which at radius0.45the first comb holds3of4teeth and the second line holds7of10, least distance0.170257380(witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Refuted "Symmetric pole combs give a symmetric zero set": code
7's two combs sit symmetrically aboutRe s = 0and code23's aboutRe s = 0.137865772436, yet under reflection in that line no zero of either census has a partner other than itself within0.05in both coordinates,0of20and0of24, there being no functional equation on either side; the exclusion bites once, code7's zero-0.023033432741+33.122746617086isitting0.046066865482from its own reflection and being the only self-match inside the tolerance on either census, code23's nearest missing at0.075316339787(witness: lab/py/memory-zeta, verbcensus, and beneath.md, The memory zeta). - Refuted No function of the spectrum selects an occupied comb, which is the falsification L7 named. Codes
55and63at width3and code7at width2all carrydet(I - x T) = 1 - x - x^2, so all three have the same two combs,Re s = log_2 phiat argument0andRe s = -log_2 phiat argumentpi, and the same teeth; on the second line at radius0.45they read1of2,0of2and0of2occupied, least tooth-to-zero distances0.264392586,1.259215316and0.702616482. Codes54and62share the whole spectrum,det(I - x T) = 1 - x^2 - x^3, and differ on both lines,2against1and3against4. Two rules with one spectrum reading two occupancies kills every function of it, monotone, threshold or otherwise; the ratioabs(lambda_2)/rhois neither, code223at0.430159709002reading0of4while code127at the smaller0.400890564601reads2of4and code62at0.655865618097reads4of4against code31at0.563624162161reading2of4(witness: lab/py/memory-zeta, verbteeth, and beneath.md, The memory zeta). - Refuted The pole data cannot select occupancy at all, the residue included, and one line proves it:
zeta_55 - zeta_7 = 3^(-s)is entire, so codes55and7carry the same poles, the same orders and the same residues at everym >= 0, while their zero sets differ, code55having a zero at-0.442302243578+4.612546440182iwhere code7reads-0.097731686660-0.868473160333iand reading1of2against0of2on the second line. Read atm = 0through the determinant the residues agree digit for digit,-0.259501222742937-0.592535006433179iat-log_2 phi + pi i/log 2and0.896350590641921+1.403072744223695iat-log_2 phi + 3 pi i/log 2from both rules (witness: lab/py/memory-zeta, verbbridge, and beneath.md, The memory zeta). - Refuted The first-order quantity
u_1(F) = -r/(R + P_F(t))selects occupancy under perturbation on the abscissa comb: at code7's toothIm s = 9.064720the exact minimiserF = [3, 6, 11, 12, 19, 22, 23, 35, 38, 39]drivesabs(R + P_F)to1.095277075, below the emptying thresholdabs(r)/rho = 1.374951382, so the law predictsabs(u_1) = 0.564905571and an empty disc, and the disc reads1/1with no seam (witness: lab/py/memory-zeta verbdial --deep 16, rowexact minimiser ... predicted abs(u1) 0.564905571 emptying threshold abs(r)/rho 1.374951382 zeros in the disc 1/1). - Refuted The first-order quantity is a selector across the perturbed family on a subdominant line: on code
7's second comb the grid holds110cells of which77read occupied, the law calls75right and the constantoccupiedpredictor77, and on code23's second line,270cells and222occupied, the law calls218against222; the deficit only widens on the outer reading of the seam,80against86and219against231(witness: lab/py/memory-zeta verbdial, per-line rowsfirst-order law agreesagainstthe constant occupied predictor agreeson both readings). - Refuted Only the smallest added integers flip a tooth of the abscissa comb: code
23's empty tooth atIm s = 9.064720is occupied by{7},{13}and{14}and by none of the smaller candidates5,6,10,11and12, so the flipping set is not an initial segment of the candidate list, and the two occupied teeth a singleton empties are emptied by{6}and{7}while the smaller candidate5occupies both (witness: lab/py/memory-zeta verbdial, code23tooth rowsmeasured 001000110000000000000000000 occupied 3 of 27,measured 101111111111111111111111111andmeasured 100111111111111111111111111). - Proved
G_(1,4) < G_(2,2) < B_4as permutation groups of the4-cube, flipping all four bits being the diagonalB_2element that flips both axes and the width-4window reversal being the(2,2)block swap composed with the diagonal axis swap, so one cube carries three nested groups and its class counts nest the other way,16960 > 4660 > 402, the last A000616 at4. Witness: lab/py/memory-census.
The moments of the digit transform
- Proved The even moments of the digit transform are additive energies counted by a carry DP:
sum_{a mod base^level} |hat F_level(a/base^level)|^(2r) = base^level E_r(level),E_rther-fold additive energy modulobase^levelof the length-levelstrings, C-finite inlevelof order at mostr(r+1)/2with growth constantLambda(2r) = base rho,rhothe certified Perron root of the carry-pair transfer matrix;Lambda(4) = 18at{0,1}base 3 (x - 6),2(23 + sqrt 353)at{0,1,2}base 4,(275 + 5 sqrt 2369)/2at{0,1,2,3}base 5, every value strictly inside[max(fill^4, base fill^2), base fill^3]; brute force atlevel <= 7, direct grid evaluation atlevel <= 6, the bounds and the recurrence asserted tolevel = 60. Witness: lab/rs/rho-decoupling (therieszmodule, 19 tests), mobius.md THE METER AND ITS YARDSTICK. - Proved The multiplicative energy
E_x(level) = #{n_1 n_2 = n_3 n_4}of a digit-restricted column has exponent2 alphafor every base and digit set:2K^2 - K <= E_x(level) <= K^2 max_m r(m)withr(m) <= d(m), soE_x(level) = fill^(2L) x^(o(1)); the census reads1, 15, 111, 655, 3179, 14211, ...to58760487atlevel = 1..12for{0,1}base 3 withtheta_x = 1.475642, 1.410978, 1.356938atlevel = 4, 8, 12falling toward1.261860; the shift family(base^i u, base^j v, base^(i') u, base^(j') v),i + j = i' + j',i != i', counted in closed form infillandlevelwhen0is a digit, is a floor on the excess over the two diagonals,0.4418of it at{0,1}base 3,level = 12and0.19to0.0003at the other families. Witness: lab/rs/rho-decoupling (themenergymodule, 27 tests), mobius.md THE METER AND ITS YARDSTICK. - Refuted That a moment of the digit transform alone carries the Type II estimate: Holder with the
2r-th moment and Parseval on the bilinear side givesx^(theta_p/p + 1/2 - 1/p) >= x^(alpha + 1/4)for every evenp >= 4and every digit set, above the trivialx^alpha, so the route needs the bilinear sum on the minor arcs below its own root mean square, which random-sign coefficients defeat on the census (minor arcs carrying0.79to0.86of thel^2mass, the supremum2.8to3.2timesx^(1/2)). Witness: lab/rs/rho-decoupling (thearcslines), mobius.md THE METER AND ITS YARDSTICK. - Refuted The sparse large-sieve shape
(fill^level + x^beta) x^(o(1))for the digit set at the pointsr/base^j: the exact constant isfill^(level-j) base^j = x^(alpha + beta(1 - alpha)), above bothx^alphaandx^betafor0 < beta < 1(the Gram eigenvalue atbase = 3,{0,1},level = 2,j = 1is exactly6). Witness: lab/rs/rho-decoupling. - Refuted That a Type II estimate on a digit set is a statement about coefficients whose sums over residue classes mod
base^jcancel forbase^jup tox^(2 eta/alpha): the Type II coefficients are hypothesised 1-bounded and nothing more, the polytope being a support constraint that supplies a divisor in[X^(9/25), X^(17/40)], and the Cauchy-Schwarz inmspends even that bound, the triangle inequality dropping the coefficient product to1; residue sums of the coefficient side occur only on the major arcs atbase <= (log X)^C. Witness: Maynard 2019 Proposition 7.2, Lemma 13.1 and the reduction (13.2), both read at source and quoted verbatim, with an adversarial pass confirming the wording and the pagination.
The node stack
- Proved The corner stack of the odd parity carpet is the Farey field, odd-restricted: with the edge set of a layer the cell sides separating ink from paper and the corner set the vertices of inked cells, layer
n's edges are the interior grid lines restricted to the odd rows and columns and its corners the full interior vertex grid, so the corner stack lights exactly the pairs(a/b, c/d)withbanddodd andlcm(b,d) <= N, at brightness the number of odd multiples oflcm(b,d)up toN, and the edge stack is the line stack in one coordinate times the 1D parity stack in the other; atN = 15literal stacking gives 536 lit points against 536 predicted, none missed and none invented, and 2352 segment tests with no breach. Witness: lab/py/node-stackparity_corner_predicted,parity_segment_check. - Proved The base-3 carpet's edge stack is a denominator-restricted Farey family: a period boundary
k/nis never an edge line, every other residue mod3^levelis (J_1 = {1, 2},J_2 = {1, ..., 8}), so the lit lines are the reduceda/bwith3 | bandb/3^min(v_3(b), level) <= N, at brightnessfloor(N/(b/3^min(v_3(b), level))) - floor(N/b); atlevel = 1the lit set is exactly the multiples of 3 inF_3N, 106 lines atN = 12and 100 atN = 6, level = 2, with no breach on 14628 and 10800 segment midpoints; the level-1 corner stack atN = 12lights 5029 corners at brightnessfloor(N/(m/gcd(m, 3)))against the plain Farey pair bound 157609. Witness: lab/py/node-stackcarpet_lines_reach,check_line_brightness_carpet,carpet_corner_stack. - Refuted The Sierpinski carpet's edge family is a numerator-restricted Farey sequence: the edge condition
a (3^level n/b) mod 3^level in J_levelis vacuous on the numerator becauseJ_levelis every nonzero residue, so the family is restricted by a divisibility of the denominator and must not be conflated with the cutoff-restricted Farey sequence of the Farey page; sibling designs removing another digit vector have proper residue sets and are the open door. Witness: lab/py/node-stackedge_residues.
The parity fill
- Proved The parity blend of the odd carpet stack has an exact rational fill: with
s_n = 1 - 2 C_nthe signed layer, the XOR of the layers is(1 - prod_n s_n)/2, and expanding the product over subsetsSof the scales and splittingprod_{n in S} C_n(u, v)into its two coordinates givesfill(N) = (1 - sum_S (-2)^|S| m_S^2)/2withm_Sthe measure of the set ofuwhere everyfloor(nu),n in S, is odd, a cell count on the grid oflcm(S); the fill reads1/9, 53/225, 3524/11025, 36284/99225, 19619/51975, 117419647/289864575, 109067744/289864575, 17006699344/45107387325, 6812188030619/19244451701475, 1114185811873/2749207385925atN = 3, 5, ..., 21, matching a literal 2D XOR count on the lcm cell grid at everyN <= 9and a 4096 raster at everyNwithin2.42e-04; coprime layers being independent, the exact fill equals the independent-Bernoulli fill(1 - prod_n (1 - 2 p_n))/2,p_n = ((n-1)/(2n))^2, atN = 3and5, and the vanishing triple massm_{3,5,7} = 0against the independent2/35breaks the agreement atN = 7. Witness: lab/py/parity-fillfill_exact,fill_literal,fill_independent,mass_table. - Verified The parity fill is not monotone in the layer count, falling from
0.405084502atN = 13to0.376271381atN = 15and0.353981924atN = 19, because 587 of the 1024 subsets of the odd scales3..21carry joint ink measure zero, the smallest being{3, 5, 7}, whose floors are never all odd at one point; the exact fill sits below the independent approximation at everyNfrom 7 to 21 with the deviation ratio growing to29.337331; every odd layer is invariant under the quarter turn about the centre (chi_n(1 - u) = chi_n(u)at oddn), so the fixed-increment parity fill obeysfill(d) = fill(90 - d)(Proved), 45 of 46 mirror pairs bit-equal on the raster; the square raster climbs0.320427, 0.375175, 0.424397, 0.444069atL = 4, 8, 14, 28. Witness: lab/py/parity-fillmass_table,section_independent,section_sweep,fill_raster. - Conjecture The parity fill of the odd carpet stack tends to
1/2: the raster climbs toward it while the exact deviation atL = 11is still9.47e-02and non-monotone, no rate derived; the moire law controls pairs while the expansion needs every subset mass, and which subsets of odd scales havem_S = 0is a covering question about the intervals[k/n, (k+1)/n)withkodd, open. Witness: lab/py/parity-fillfill_raster,mass_table. - Refuted The rational-increment eyes stand out in the parity fill: at
N = 55andR = 512the 89 nonzero whole-degree increments span0.490165to0.511161and the eyes at 18, 30 and 45 degrees read0.500185,0.494657and0.500282, inside the band at neither end, the one outlier being the unspun stack at0.475647; coincident-class layers carry different scales and share a sublattice, not a picture, so nothing cancels; the independent approximation'sO(2^-L)decay does not predict the exact deviation either, whose ratios run0.680to1.304and exceed 1 twice. Witness: lab/py/parity-fillsection_sweep,section_independent.
The parity-carpet stack spectrum
- Proved The flat odd-scale parity-carpet stack's spectrum is the divisor field of the frequency gcd and nothing more: the sine coefficient of the
L-layer stackG_Lat odd(a,b)is(1/(pi^2 ab))[1 - sigma_1^S(a)/L - sigma_1^S(b)/L + sigma_2^S(gcd(a,b))/L]and vanishes at any even index, the interaction part carrying exactlysigma_2(gcd(a,b))/(ab); Parseval splits the variance blockwise into the two terms of the carpet law, re-proving the moire variance formula; every spectral statistic is an Estermann-Ramanujan zeta quotient,sum sigma_2(gcd)(ab)^(-w) = lambda(w)^2 lambda(2w-2)andsum sigma_2(gcd)^2 (ab)^(-w) = lambda(w)^2 lambda(2w-2)^2 lambda(2w-4)/lambda(4w-4)withlambdathe odd zeta; a stack weightedn^(-s)renderssigma_(2-s)as its spectrum; divisor information only, no new L-function; coefficients checked cell-exactly atL = 14to 47 digits and Parseval against the exact rational variance; the object is the flat odd-scale stack, not the all-scales Farey stack. Witness: moire-correlation-laws.
The radix dial
- Proved The fill law survives the radix dial: a radix design accepts every word over
F, so it has(card F)^levelwords of lengthlevelat every ring, every base, every digit set and every twist, the twists appearing nowhere in the accept slot. The row restates the accept slot rather than proving anything beyond it. (witness:mrlynum::radix::Radix::fillagainstwordsinlab/rs/radix-designsverbnamed) - Proved Every place map
phi_d(x) = (u_d x + d) / baseof a base of normq >= 2is a similarity of ratioq^(-1/2)because a unit has modulus one, so allcard Fmaps contract equally and the similarity dimension iss = 2 log card F / log qwhatever the twists; this isHutchinson 19815.1(2) and 5.1(3) at a ring base. (witness:mrlynum::radix::Radix::dimensioninlab/rs/radix-designsverbnamed) - Proved Today's plane designs are the untwisted real-base row of the dial: at
R = Z[i],base = m, digits the box{a + c i : 0 <= a, c < m}and everyu_d = 1, the place map isx -> (x + d)/mon each coordinate, so the wordd_1 ... d_levellands on the level-levelcell of the plane design of the same code at basem, the code read in box row-major orderbit r q + cand not in the canonical residue order. (witness:mrlynum::radix::tileagainstmrlymath::bang::factory::createinlab/rs/radix-designsverbtoday) - Proved A twist keeps every count and moves only the place: the accept slot mentions no
u_dso the word count stays(card F)^level, every ratio staysq^(-1/2)since a twist has modulus one so the dimension is untouched, and the twists enter the definition only through where an image sits. (witness:mrlynum::radix::Radix::wordsinlab/rs/radix-designsverbnamed) - Proved An untwisted design on pairwise incongruent digits has no glue: reducing
sum_i d_i base^(level-i)modbaserecoversd_levelbecause the digits are distinct residues, and induction onlevelgives the rest, so the distinct-point count equals(card F)^levelat every level. The hypothesis is a hypothesis of the statement and not of the generator:Radix::newaccepts any digit list, andfrom_codeandtileare the two constructors that enforce it. (witness:mrlynum::radix::Radix::distinctinlab/rs/radix-designsverbnamed) - Proved The canonical least-norm residue system of a real base
monZ[i]is the box{a + c i : 0 <= a, c < m}atm = 2and at no largerm: the box holdsm-1of norm(m-1)^2 >= 4while its own class holds-1of norm1. (witness:mrlynum::radix::Base::residuesinlab/rs/radix-designsverbtoday) - Proved The four maps
z/3,e^(i pi/3) z/3 + 1/3,e^(-i pi/3) z/3 + 1/2 + i sqrt(3)/6,z/3 + 2/3arephi_dcoefficient for coefficient at base3onZ[omega]with digits0, 1, 2+w, 2and twists1, 1+w, -w, 1:e^(i pi/3) = 1 + w,e^(-i pi/3) = -wand(2 + w)/3 = 1/2 + i sqrt(3)/6, so(u_d x + d)/3at(d, u) = (0, 1), (1, 1+w), (2+w, -w), (2, 1)is that list in order. The1.241e-16printed at level5is a float evaluation of the same four maps and is a self-check of the crate's ring arithmetic, not an independent identification. (witness:lab/rs/radix-designsverbskochandcompare) - Verified The Sierpinski gasket is the untwisted code
7at base2onZ[omega]: against the three similarities of ratio1/2fixing the vertices of an equilateral triangle, written independently inf64and placed at(1, 1),(3, 1),(2, 1 + sqrt 3), the3^9 = 19683words agree to4.441e-16after the translation and positive scaling that the statement leaves free, pinned by the two corresponding words0^9and2^9and then measured at every word, with turn residual0. (witness:lab/rs/radix-designsverbcompare) - Verified That level-system reading is the code
7at base2+wonZ[omega]with twists1, w, 1: its3^8words are the segment starts word for word at level8to7.511e-16. The reading is the terdragon's own level-system and is carried by no source read here, so the name stays [Conjecture] until one is. (witness:lab/rs/radix-designsverbcompare) - Verified The five codes as printed: code
7at base2onZ[omega]of dimension1.584963, code3at1+ionZ[i], code7at2+wand code127at3+wonZ[omega]each of dimension2, all four untwisted withcard F = 3, 2, 3, 7, and code147at base3onZ[omega]twisted,card F = 4, dimension1.261860. (witness:lab/rs/radix-designsverbnamed) - Verified Every plane code at
q = 2andq = 3is the untwisted real-base radix design of the same code at level2:528codes checked,0mismatches, through the pixel map bitr q + cof the code is the cell at rowrand columnc, the column the real part and the row the imaginary part, which is box row-major order and not canonical residue order. (witness:lab/rs/radix-designsverbtoday) - Verified The distinct-point count equals the fill for code
7at base2to level11, code3at1+ito17, code7at2+wto11, code127at3+wto6and the twisted code147at3to8, so the Koch twist glues nothing inside that reach. (witness:lab/rs/radix-designsverbnamed) - Verified The classes of digit CODES under the residue action are
12, 4, 12, 8, 6, 84, 28over16, 4, 32, 16, 8, 512, 128codes atZ[i]bases2, 1+i, 2+iandZ[omega]bases2, 2+w, 3, 3+w; a Burnside count over the group and a direct orbit walk over all2^qcodes agree at every base. These are classes of codes and never designs up to similarity. (witness:lab/rs/radix-designsverbcensus) - Verified The group of a base is the units acting on residues by multiplication, joined by conjugation exactly when
conj(base)is an associate ofbase, the mirror failing at2+iand at3+w: the abstract groupR^* semidirect <conj>has order8, 8, 4onZ[i]at2, 1+i, 2+iand12, 12, 12, 6onZ[omega]at2, 2+w, 3, 3+w, and it acts on the residues through an image of order2, 1, 4, 6, 2, 12, 6. The action is not faithful: at1+ievery element is the identity permutation. Burnside over the abstract list stays correct, because the list is the image of one abstract group with each element once. (witness:mrlynum::radix::Base::groupinlab/rs/radix-designsverbcensus) - Verified The canonical residue systems printed:
0, 1, i, 1+iatZ[i]base2;0, 1at1+i;0, 1, i, -1, -iat2+i;0, 1, 1+w, watZ[omega]base2;0, 1, 1+wat2+w;0, 1, 1+w, w, -1, -1-w, -wat3+w; and0, 1, 1+w, w, -1, -1-w, -w, 2+w, 1+2wat3. (witness:mrlynum::radix::Base::residuesinlab/rs/radix-designsverbcensus) - Verified The twist vectors at base
3onZ[omega]number7^9 = 40353607summed over the512codes, not over the84classes:sum_k binom(9, k) 6^k = 7^9counts one6^(card F)for each code, and the two quotients are different quotients. No class count is claimed for twists, because no action of the group on twist vectors is defined here, and7^9counts only designs whose representative vector is canonical. (witness:lab/rs/radix-designsverbcensus) - Verified The twisted glue witness holds as stated:
Z[i], base2,F = {0, 1}, twists1, -1, level2has fill4and3distinct points, the words01and11both landing on1/4, that is on1after scaling bybase^2. (witness:mrlynum::radix::Radix::distinctinlab/rs/radix-designsverbnamed) - Proved The distinct-point count of that twisted design is
2^(level-1) + 1at every level: the scaled point of the word whose1s sit at positionsj_1 < ... < j_tissum_(k=1..t) (-1)^(k-1) 2^(level - j_k), an alternating sum of strictly decreasing powers of two with top exponent at mostlevel-1; such a sum is0or lies in[1, 2^(level-1)], since the alternating tail is smaller than the leading term; and every integernof[1, 2^(level-1)]is reached by exactly one choice, the greedy one, taking2^afor the leastawith2^a >= nand recursing onn - 2^a, whose modulus is below2^(a-1). Printed and checked at every level to16. (witness:lab/rs/radix-designsverbnamed) - Verified The code census is not the design census: at base
3onZ[omega]the84three-digit codes fall in13orbits of the residue action and in9similarity classes of the untwisted canonical digit sets, computed in exact arithmetic overQ(w), and the two partitions cross. Codes131, digits0, 1, 2+w, and137, digits0, w, 2+w, share an orbit and are not similar, though they are affinely conjugate; codes7, digits0, 1, 1+w, and42, digits1, w, -1-w, are similar and sit in different orbits. Among the36two-digit codes the census gives7orbits where similarity gives1class. (witness:lab/rs/radix-designsverbaffine) - Proved The Hausdorff dimension of a radix design is at most its similarity dimension
2 log(card F) / log q, with no hypothesis at all, byHutchinson 19815.1(4)(i), which givesH^s(K) < infinityanddim K <= sfor arbitrary contractions. (witness:mrlynum::radix::Radix::dimensioninlab/rs/radix-designsverbnamed) - Verified the Koch quintuple places
256words on256distinct points at level4, similarity dimension1.261860, no digit canonical -mrlydemo::radix::radix_read,site/check.tsrowradix koch design. - Verified the twindragon quintuple places
1024words on1024distinct points at level10, similarity dimension2.000000-mrlydemo::radix::radix_read,site/check.tsrowradix twindragon tiles. - Verified the carpet at base
3onZ[i]with the BOX digits fills64words at level2and has similarity dimension1.892789-mrlydemo::radix::radix_read,site/check.tsrowradix carpet fill. - Verified that same carpet codes
479over the canonical classes where it codes495in box row-major order, so the two readings of one design differ -mrlydemo::radix::radix_read,site/check.tsrowradix carpet fill. - Verified the digits
0, 1at base2onZ[i]twisted by1, -1glue4words onto3points at level2, and untwisted they glue nothing -mrlydemo::radix::radix_read,site/check.tsrowradix twisted glue,crates/mrlydemo/tests/radix.rs. - Verified four digits reach level
8and eight digits level5at the budget of2^16points -mrlydemo::radix::radix_cap,site/check.tsrowradix koch dimension. - Proved An untwisted radix design obeys the fill law: with every unit
u_d = 1, the wordd_1 ... d_levellands onbase^(-level) sum_i d_i base^(level-i), and reducing that integer modulobaserecoversd_levelbecause the digits are distinct residues, so induction gives distinct points for distinct words andfill(level) = card F^levelat every ring, base and digit set. (witness: beneath.md, The fill law, and where it stops) - Proved No plane radix design carries a rotation of order
5or8: a unit ofZ[i]solvesa^2 + c^2 = 1with four solutions and a unit ofZ[omega]solvesa^2 - ac + c^2 = 1with six, so every available twist has order1, 2, 3, 4or6; and a rotation preserving a rank-2 lattice is an integer matrix in a lattice basis with trace2 cos thetain{-2,-1,0,1,2}, the classical crystallographic restriction. (witness: beneath.md, What a plane lattice will not carry) - Proved A twist keeps every count the accept slot computes and every contraction ratio: the accept slot is the full shift on
Fand mentions nou_d, and every place mapphi_d(x) = (u_d x + d)/basehas ratioq^(-1/2)because a unit has modulus one, so the similarity dimension2 log(card F) / log qis untouched and the twists move only where an image sits and which words collide. (witness: beneath.md, The twist law) - Conjecture That design is the Koch curve:
Hutchinson 19813.3(2) gives the Koch curve as the attractor of four similitudes each carryinga_1 a_5toa_i a_(i+1)with positive determinant, and the four maps above are exactly those for the polyline0,1/3,1/2 + i sqrt(3)/6,2/3,1, but that polyline is read from its Figure 3.2 and not from its text, so the name rests on a figure and not on a sentence. (witness:lab/rs/radix-designsverbcompare) - Conjecture The twindragon is the untwisted code
3at base1+iand the flowsnake is the untwisted code127at base3+w: each is compared only against the maps(z + d)/baseover the residues of its own base, which is its definition as a radix set, so the comparison is a self-check at0and2.259e-16and no independent witness for either name exists here. (witness:lab/rs/radix-designsverbcompare) - Conjecture That bound is an equality: equality needs the open set condition,
Hutchinson 19815.3(1), which is a hypothesis per base and per twist and is checked at no base here. (witness:mrlynum::radix::Radix::dimensioninlab/rs/radix-designsverbnamed) - Refuted A code over residue classes does not name a radix design: the place moves with the chosen representative,
d + base mshifting the image ofphi_dbym, and the Koch digits0, 1, 2+w, 2are not the canonical representatives of their classes, since2and-1share a class mod3onZ[omega]and the canonical system holds-1. A design is a quintuple, ring, base, code, representative vector, twist vector. (witness:mrlynum::radix::Radix::canonicalinlab/rs/radix-designsverbkoch) - Refuted The terdragon is the untwisted code
7at base2+w: read the terdragon's own level-systemF -> F + F - Fat120degrees as a turtle, three segments to a level, normalise by the endpoint, and the untwisted design misses the3^8 = 6561segment starts by1.060at level8. (witness:lab/rs/radix-designsverbcompare) - Refuted The fill law is not inherited by a twisted radix design: at
R = Z[i],base = 2, canonical residues0, 1, i, 1+i, digit setF = {0,1}, twistsu_0 = 1andu_1 = -1, the words01and11both land on1/4, so two words of length two name one point and the cell count is3wherecard F^levelis4. A twisted design owes its fill law a proof of its own. (witness: beneath.md, The fill law, and where it stops) - Proved The conjugacy group of the untwisted canonical base family is the centraliser of
1/baseextended by translations. Conjugatingphi_d(x) = (x + d)/baseby an invertible real affineh(x) = H x + sgives(y + H d + s(base - 1))/base, again an untwisted place map exactly whenHcommutes with multiplication by1/base, ands(base - 1)sweeps the plane sinceN(base) >= 2forcesbase != 1. At a non-real base that centraliser isC, so the group is the similarity group; at a real base1/baseis the scalar(1/base) Iand the group is all ofGL_2(R)semidirectR^2. This bites at2onZ[i]and at2and3onZ[omega]. (witness:lab/rs/radix-designsverbaffine) - Proved The mirror
x -> v conj(x) + tpreserves the untwisted base family exactly whenconj(base) = base, and being an associate is not enough: a direct conjugacy keeps the derivative1/baseand a mirror one sends it to1/conj(base), so the mirrored object is a place map at baseconj(base). The code census admits conjugation at1+iand2+w, where the conjugacy group does not. At a real base the mirror is one element of the full affine group and not the only new one, so it is load-bearing for the similarity quotient alone. (witness:lab/rs/radix-designsverbaffine) - Verified The similarity census of the untwisted canonical digit sets runs at every base of the code census and every digit count
card Ffrom0toq, in exact arithmetic overQ(i)andQ(w): the classes total5, 3, 8, 6, 4, 117, 22atZ[i]bases2,1+i,2+iandZ[omega]bases2,2+w,3,3+w, against the code classes12, 4, 12, 8, 6, 84, 28, and bycard F = 0to9at base3onZ[omega]they are1, 1, 1, 9, 23, 30, 29, 16, 6, 1against code classes1, 3, 7, 13, 18, 18, 13, 7, 3, 1. (witness:lab/rs/radix-designsverbaffine) - Verified The conjugacy census of the same sets, the similarity group at the four non-real bases and
GL_2(Q)semidirectQ^2at the three real ones, totals5, 3, 8, 5, 4, 88, 22over the seven bases,135over the41cells against165similarity classes and154code classes. At base3onZ[omega]the affine classes bycard F = 0to9are1, 1, 1, 2, 11, 23, 26, 16, 6, 1, so512codes give84code classes and88affine classes and the design count still exceeds the code count under either name. (witness:lab/rs/radix-designsverbaffine) - Verified No two of the three quotients are comparable. Over the
41cells the similarity count is below the code count in17, equal in19and above it in5, the two partitions crossing in6; the affine count is below in19, equal in18and above in4, crossing in5. The lost crossing isZ[omega]base2atcard F = 3, where two orbits meet two similarity classes with codes7and11split and codes11and14merged, while all four triples are non-degenerate and fall in one affine class. (witness:lab/rs/radix-designsverbaffine) - Verified At base
3onZ[omega]andcard F = 3the84codes fall in13orbits,9similarity classes and2affine classes, the collinear triples against the rest. Codes131, digits0, 1, 2+w, and137, digits0, w, 2+w, share an orbit and are not similar, squared side lengths1, 1, 3against1, 3, 4, yet are affinely conjugate byH = [[0, 2], [1, -1]]of determinant-2; codes7, digits0, 1, 1+w, and131are affinely conjugate by the unimodularH = [[1, 1], [0, 1]]; codes7and42are similar in different orbits. (witness:lab/rs/radix-designsverbaffine) - Verified The census is controlled by two explicit conjugacies asserted in the verb,
H = [[0, 2], [1, -1]]carrying code131onto code137andH = [[1, 1], [0, 1]]carrying code7onto code131, and by the assertion that the similarity classes refine the affine classes pair by pair in every cell. The per-size orbit counts summing to12, 4, 12, 8, 6, 84, 28constrains the code column alone, and thef64rerun of the similarity normal form checks the exact arithmetic and not the group. (witness:lab/rs/radix-designsverbaffine)
The ratio-set power saving
- Proved Every occupied direction of the gasket ratio set obeys
max(z_1, z_2) > 2 min(z_1, z_2): the top base-3 digit ofm(z_1 + z_2)lies in exactly one of the disjoint binariesm z_1, m z_2and the other is a sum of distinct lower powers, hence at most(3^t - 1)/2, so the slopez_1/wnever lies in[1/3, 2/3]; checked against every occupied weight to 8192, every pair to height 120 and every ray at level 12, and shown sharp and strict by the adversarial pass at minimum ratio2.0000004over 14.3 million pairs at level 15, extremal at(3^14, (3^14 - 1)/2). Witness: lab/py/ratio-set-saving. - Proved The digit-congruence bound and the weight-layer reduction are one bound:
z_1 (1 + r) = r wforr = z_1 z_2^(-1) mod 3^k, andr = -1 mod 3would force3 | w, soz_1 = r w (1 + r)^(-1)is determined andz_1 -> ris injective for3^k > w, givingZ(w) <= 2 |R_k|with no failing weight to 8192;beta < 1from this side would needsigma_kto fall geometrically, exactly what criticality forbids. Witness: lab/py/ratio-set-saving, lab/py/occupancy-decay. - Proved Two relaxations of occupancy, both tight enough to keep the exponent:
Z(w) <= 2 N_P(1/w)because slopes of denominatorware1/wapart, andZ(w) <= Zinf(w)because the band is forward-invariant on every integer it contains, so a 3-adic witness suffices; the backward cone of0is{z_2 C - z_1 A : (A, C) a gasket pair}intersected with the band, rebuilt by an independent carry-pair dynamic programme with zero mismatches, andZinf/Zis at most1.5295over the eleven weights tested. Witness: lab/py/ratio-set-saving. - Proved
R_kis indexed by the modulus3^kandR_1is empty under the hypothesisu > 0, so|R_k| = 1, 3, 9, 23, 63, 168, 457, 1245, 3423, ...starts atk = 2; both studies carry the identical definition and the same offset, which pins the offset the submission candidate needs. Witness: lab/py/occupancy-decay, lab/py/ratio-set-saving. - Verified The weight layer read per weight rather than off a running maximum:
log Z(w) / log wpeaks at0.7093atw = 121andZ(w) / w^(log 2 / log 3)at1.5975atw = 1093over everyw <= 8192, with all twenty-four octave argmaxes binary base 3 as the scan prints for itself; on the repunits(3^k - 1)/2atk = 9, 11, 13and the shifts1 + 3^hath = 7, 9, 11, 13the exponent holds inside[0.6223, 0.6818]out tow = 1594324while unstructured neighbours collapse to[0.2861, 0.4272], and the mean forward reach is0.2249to0.2947timessqrt(w)off the structured families. Witness: lab/py/ratio-set-saving. - Refuted A uniform
D_n(q) <= C 2^n / qon the binary base-3 multiples ofqcoprime to 3, the divisor input to the power saving - every binarym < 3^hmakesm(1 + 3^h)binary below3^(2h), soD_2h(1 + 3^h) >= 2^hwhile4^h / qis only(2/3)^hof it, ratio(3/2)^h (1 + 3^(-h))reading2.0, 2.5, 3.5, 5.125, 7.625, 11.406, 17.094, 25.633ath = 1..8, and atn = 20the worst modulus below 500 isq = 244 = 1 + 3^5at1.8094; the breaking moduli are exactly the shift-ray weights. Witness: lab/py/ratio-set-saving. - Refuted The short-witness route, bounding the count by
3^(level cap)- mean minimal witness length runs3.875to27.287and max6to204over height32..16384, meanlev / log_3 heightrises1.553to3.305, and the share of occupied directions withlev <= 1.8073 log_3 xfalls0.875to0.3102, so every cap below2 log_3 xloses a majority of the count. Witness: lab/py/ratio-set-saving. - Refuted Two write-up claims of the first pass, caught by the adversarial read and corrected in place - the
log Z_max / log Wband was printed as[0.5000, 0.6404]when the script's ownW = 128row reads0.70099, true band[0.5000, 0.7010]and margin0.106not0.167; and tenZ_maxvalues were listed against nine arguments, the duplicateZ_max = 30at bothW = 128andW = 256having been dropped, shifting every later argument onto the wrong weight. Both are transcription, not mathematics. Witness: lab/py/ratio-set-saving. - Refuted
beta >= log 2 / log 3as a proved lower end of the weight-layer corridor - the binary-weight floorZ(w) >= #{coprime submasks}is proved, but atw = (3^k-1)/2the coprime cut leaves2, 6, 8, 30, 24, 126, 112againstw^(log 2 / log 3) = 2.4, 5.0, 10.3, 20.6, 41.3, 82.6, 165.3fork = 2..8, beating the exponent at oddkand losing at evenk, and no family supplies infinitely many good weights; the lower end is Conjecture. Witness: lab/py/ratio-set-saving. - Refuted The metric route to the weight-layer saving: the sandwich
Z(w) <= 2 N_P(1/w)is proved, but the cover of the slope set measures too large,n N_P(3^-n) / 3^nrising2.4132 -> 2.4785,log_3 N_P / nrising0.8783 -> 0.8997and the step exponent rising0.9333 -> 0.9504overn = 12..18, every reading monotone and every one above the0.8073needed, so the covering route caps atO(w / log w)exactly like the congruence seed; a missing-digit rational-counting import belongs at the 3-adic ratio setR_infand not at the slope variable. Witness: lab/py/ratio-set-saving. - Refuted Three printed statements of the second pass, caught by the adversarial read and corrected in place -
sigma_k < 1/9was dated tok = 13when it is1/9exactly atk = 2, 3, 4and first below atk = 5, the bound already beating the trivial count atw = 13(6 against 8.0) andw = 121(46 against 73.3); the slope cover was computed on one swap half only,51624against the saturated106994atn = 12; and the backward moves were called one per residue class when3kand3k - z_1are both0 mod 3and the class-z_2 mod 3has no preimage. A fourth broke on the fix: the cover atn = 19with three extra digits overflows int64 and printed a false1.9533, so the generator now refuses past1.5 * 3^(2n + extra) >= 2^63. Witness: lab/py/ratio-set-saving. - Refuted The digit-congruence containment as printed:
z_1 z_2^(-1) mod 3^k in R_kfails whenever3^k | z_1, witness the occupied ray(9,1)atk = 2, whereR_2 = {3}and the residue is0; the true image isR_k union {0}, the counting bound's tail terms doubling to pay for the adjoined class, and the mod-3 dichotomy is the casek = 2and notk = 1,R_1being empty underu > 0. Witness: coprime.md, lab/py/occupancy-decay, lab/py/ratio-set-saving. - Refuted The adversarial pass on the weight-layer run: an independent carry-pair dynamic programme reproduced every table to the last digit, the top-digit gap was checked over 14.3 million pairs at level 15 and found sharp and strict at minimum ratio
2.0000004with extremal witness(3^14, (3^14 - 1)/2),Z(w) <= 2 |R_k|was checked at every weight to 8192 with no failure, the backward cone was rebuilt with zero mismatches, and three printed statements plus the|R_k|offset were broken and fixed in place. Witness: lab/py/ratio-set-saving. - Refuted The adversarial pass on the run itself: the band was rederived on paper and sharpened to the halved interval
-z_2/2 < j < z_1/2, an independent all-coprime-pairs automaton reproduced everyA,ZsumandZ_maxrow to height 1024 and the full sweep, witnesses were reconstructed digit by digit for all 716 occupied directions to height 300 with zero failures, and Chow-Varju-Yu Theorem 1.2 and Kenyon were both verified accurate at source. Witness: lab/py/ratio-set-saving. - Proved The block rate of the critical band automaton is bracketed by the parity of the depth
b. Every column sum of every blockB(b, j)isSum_(c = a mod 3) binom(b, c) = (2^b + 2 cos(pi (b - 2a)/3))/3, so its deviation from2^b/3takes only two values,-1/3and2/3at evenband-2/3and1/3at oddb; hencelam_blies in2^b/3 + [-1/3, 2/3]at evenband in2^b/3 + [-2/3, 1/3]at oddb, and the two-sidedabs(3 lam_b/2^b - 1) <= 2^(1-b)holds at everyb. The parity refines which edge is which and not the rate, and the computed excess3 lam_b - 2^bis positive at every depth reached, so the upper edge is the live one. Witness: lab/py/band-return-times ladder. - Proved At the horizon
n = bk,kblocks of depthb, the column transfer is one matrix per residue fixed inkandL(k, bk) = Sum_j w_j B(b, j)^(k - r0(j)) h_j, the head lengthr0(j)free ofkbut not equal to 2: it is 1 at every sector belowb = 5, at most 2 atb = 5..10and at most 3 atb = 11..14. SoL(k, bk)obeys a constant-coefficient linear recurrence inkand the block ratelam_bis an algebraic integer. Witness: lab/py/band-return-times ladder, with an independent residue DP reproducingL(k,4k)andL(k,5k)tok = 12and factoring both characteristic polynomials in exact arithmetic. - Verified The block rates are exact algebraic integers:
lam_4 = 6from(x-1)(x-3)(x-5)(x-6),lam_5 = 3(5 + sqrt 5)/2from(x-1)(x^2 - 15x + 45),lam_6 = 13 + sqrt 79,lam_8 = (99 + 9 sqrt 65)/2, everylam_btob = 14having an exact minimal polynomial that divides the characteristic polynomial with zero remainder, the degree-four-and-up ones atb = 9, 11, 13, 14irreducible over the rationals by mod-p distinct-degree factorisation; and the block rate is the largest block spectral radius itself,max_j rho(B(b,j))agreeing with the certified interval to a relative1e-9at everyb. Witness: lab/py/band-return-times ladder. - Proved The carry transfer on the slot profile
s_r = ceil((n - r)/k)gives the primitive return countL(k, n)of the weightR_kexactly at everykand everyn, past the rigid depth the block ladder stops at, readingL(k, 4k) = 185, 1002, 5573, 31506, 180125, 1038402atk = 3..8. Witness: lab/py/band-return-times, verbreturns. - Verified The support of the return time of the weight
R_k, the lengths at which some primitive return exists, is{k} union [k + 2, 8k]at everyk = 2..12, one gap atk + 1and no other inside that range, with nothing pastn = 8kork = 12decided. Witness: lab/py/band-return-times, verbreturns. - Conjecture The FIRST return time is a far thinner object than the return count and takes
16, 16, 59, 80distinct lengths atk = 11..14, a single unpinned reading of the first-return sweep that no README prints and no pinned test carries. Witness: lab/py/band-return-times, verbhist. - Verified The minimal polynomial of the block rate
lam_bis exact at everyb <= 14,lam_7the dominant root ofx^3 - 63x^2 + 945x - 3402,lam_9ofx^4 - 255x^3 + 16065x^2 - 293787x + 1299078,lam_10ofx^3 - 392x^2 + 17469x - 96228,lam_11of a quintic,lam_12ofx^3 - 1551x^2 + 257256x - 5629338,lam_13of a sextic,lam_14ofx^4 - 6176x^3 + 3963141x^2 - 335533914x + 2583866142, certified by exact bisection to a width below1e-9at10.854101966, 21.888194417, 42.760932540, 85.780159867, 170.715620440, 341.700429300, 682.692831036, 1365.640975936, 2730.680876219, 5461.594643683overb = 5..14, with minimal recurrence orderbat evenband(b+1)/2at oddb, the even ladder staying in radicals throughb = 14and the odd leaving them atb = 11. Witness: lab/py/band-return-times, verbladder. - Conjecture The degree of the minimal polynomial of
lam_bisceil(b/4)at evenband(b-1)/2at oddb >= 3, a pattern observed on the thirteen rungsb = 2..14,b = 1printing degree1against the rule's0, and licensed at nob >= 15. Witness: lab/py/band-return-times, verbladder. - Verified A block ratio reads the block rate at odd depth and at no even one: the second root of the recurrence is
0.959422oflam_6,0.991055oflam_8and0.999909oflam_14, soL(k+1, b(k+1)) / L(k, bk)carries at most two correct digits atk = 160at every evenb <= 14, while at oddb = 5..13that root falls from0.381967to0.333404and the same ratio carries 66 to 76 correct digits there. Witness: lab/py/band-return-times, verbladder. - Proved The repunit sweep meets each direction
(z, R_k - z)twice, atzand atR_k - z, soPhi_k,Z(R_k),U_kandV_kare counts ofzvalues with the distinct directions half of each, every first-return count being even for that reason, and a sample size quoted without halving is doubled. Witness: lab/py/band-return-times, verbshistandcheck. - Verified The deep tail's survival has no law: the survival in distinct directions
S(b) = (1/2) #{z : d(z) > bk}atk = 14runs81, 65, 58, 56, 55, 52, 48, 42, 39, 37, 35, 30, 27, 20, 18, 14fromb = 2and reaches1atb = 42, the local exponent-log_2(S(2b)/S(b))reads0.481, 0.273, 1.415, 3.169atb = 2, 4, 8, 16with the sharpest resting on the two directions ofS(32), and a maximum-likelihood geometric fits ratio0.8958with pooledchi2 = 29.0on at most 16 degrees of freedom once the fit is carried from the doubledzcounts to the directions, so on 81 directions over 41 depths the survival is neither geometric nor shown not to be. Witness: lab/py/band-return-times, verbhist. - Conjecture The equidistribution model
D(k, N) = Sum 2^(#supp K) / mover the primitive liftsK = m R_kof base-3 length at mostNequals2^k L_k + 4^k / (3^k + 1)atN = 2k, the second term the primitive liftR_(2k)of multiplier3^k + 1and cancelling in every deep part below, and puts the deep partD(k, N) - D(k, 2k)at the critical cutoffN = floor(sqrt(R_k))inside[0.1476, 0.4429] * 2^katk = 8and inside[0.0373, 0.1122] * 2^katk = 16, so on the model the deep tail iso(2^k); it is never a prediction ofZ(R_k) - U_k, which it exceeds by the witness multiplicity, and0, 0, 0, 0, 5, 32, 51, 64, 73percent of that deep part atk = 8..16is carried by the free4/9per-digit increment extrapolated past 40 blocks, both ends leaning low because the return excessrhois above1at every depth reached and the upper end holding only whilerho < 3. Witness: lab/py/band-return-times, verbmodel. - Proved The inequality
N_K(m) <= #packingsis strict fromk = 5, whereT = {1},m = 7andK = 847carry the support{0, 2, 3, 4, 6}with four irreducibles, two decompositions of the whole and six distinct unions against seven packings, so boundingSum_T #packings_Tsuffices for the lift half and is strictly the harder target. Witness: lab/py/band-return-times, verbsliftandcheck. - Proved A column transfer for the lift count with a state set free of
kis a linear representation of that count as a series over the column word, so its state count is at least the series' Hankel rank, finite Hankel rank over a free monoid being exactly a linear representation with that rank as the minimal dimension. Witness: Schutzenberger 1961 in REFS.md. - Verified That Hankel rank reaches 253 at word length 7, so the floor bites at
k <= 15where2^7.5 = 181is below it, and the floor is neither an impossibility nor a second check read twice: the reversed reading is the transpose of the same matrix at equal side lengths, and a machine whose state set may grow withkalways exists, the residue automaton onmstates computingN_K(m)at cost3^kperT. Witness: lab/py/band-return-times, verblift. - Verified The first-return sweep reaches no
kpast 15 and the lift-family generator stops atk = 13, where3^(3k)passes2^63, so the deep tail stands on five points. Witness: lab/py/band-return-times, verbhist, and lab/py/ratio-set-saving, verbtail.
The registry's integers
- Proved The registry's written set is finite at every ceiling: a row renders at most 48 terms, so the 18066 rows write at most
48 * 18066 = 867168integers however far the ceiling is pushed, and the miss density tends to 1. The adversarial read kills the way the bound was first used -11133was read as0.01284of that cap, a comparison that is vacuous inside the census window because867168exceeds the ceiling100000; the honest saturation is11133/100000 = 0.11133, and the finiteness is the only claim of the lane untouched by a change of cap. Witness: lab/rs/integer-census. - Verified The census of
1..=100000over the whole registry: 18066 rows,7692closed,5044convolved,2665side grid and2665level grid, each tier matched against an independent derivation fromSPACES,ledger::designsandMeasure::applies, none unread; stops5529ceiling,6802cap,5735budget,390silent; never/once/multiple41/31/928at1000,3589/765/5646at10000,88867/2897/8236at100000, shares written0.9590,0.6411,0.1113; miss density by decade0,0,0.045556,0.394222,0.947533;347308(row, integer)incidences against360703(row, index, integer), so13395double counts are refused, and29144terms at or below zero are excluded and reported. Two independent refolds ofrows.csvby readers sharing no code with the sweep reproduce every one of these numbers with zero mismatches, and add four checks the study did not run - no duplicate key,max |written| = 48never exceeded, every in-range head term present inwritten, every ceiling row's head strictly increasing. Witness: lab/rs/integer-census. - Verified The miss set's arithmetic:
269, a prime, is the first missed integer and1..268the longest written run; the longest missed run is 447 wide on95265..95711with both neighbours written;100000is written by 103 rows; the written share on10000..100000by greatest prime factor falls0.5798,0.1406,0.0506,0.0313,0.0117over the bands1..10,10..100,100..1000,1000..10000,10000..100000; the tail written count by residue mod 12 runs1175, 440, 145, 194, 715, 176, 420, 224, 531, 358, 229, 116for a ratio10.13, and mod 61595, 664, 676, 552, 944, 292for5.46; primes750/9592with only158of the8363above10000; cubes46/46, fourth powers17/17, fifth10/10, sixth6/6, squares176/316with the largest written97969 = 313^2, carried by the single rowsequence_dim=4_code=28662_measure=voids_axis=sideon4k^4 - 8k^3 + 8k^2 - 4k + 1. Witness: lab/rs/integer-census. - Verified The first missed square is a cap artifact and not arithmetic: row multiplicity at
96^2, 97^2, 98^2, 99^2, 100^2is321, 19, 480, 0, 123, and deepening the rendered window to 96 terms writes at least 228 of the 316 squares and moves the first missed square from9801to38809 = 197^2. The adversarial read kills the mechanism first offered for it - that9801is odd and so outside the family(2k+2)^2- because97969 = 313^2is odd and written, and because that family was selected by grepping a head prefix out of the study's own rows; what survives is the frontier, printed by the generator over96..100rather than read off a chosen family. Witness: lab/rs/integer-census. - Verified The rendered window is measured rather than assumed harmless: the census at 8, 32 and 48 rendered terms writes
5263,8749and11133integers, so5870of the written set arrive only past term 8 and2384only past term 32, and the 8-term miss set opens269, 281, 302, 311where the 48-term one opens269, 362, 422, 443. Rebuilding a row'swrittencolumn from its 8-term head and the pinned stop rule alone, by Newton forward extension, passes1306of1306ceiling-stopped rows and1325of1333cap-stopped rows, the 8 failures being exactly the degree-6 detections an 8-term head cannot certify; the969budget-stopped rows carry no rendered length in their head and are declared untestable. Extending only the 1325 rebuilt cap rows to 96 terms gives a strict lower bound on a deeper census: at least11898written, first miss moved from269to362, longest written run at least361. The adversarial read kills the first statement of the rebuild check, which reported a pass-set size as a population size and omitted the budget stop kind entirely; the generator now prints the population by stop kind and the failing degrees. Witness: lab/rs/integer-census. - Verified The champions are small perfect powers:
16at 2858 rows,9at 2811,4at 2559,12at 2303,36at 2270,64at 2176,3at 1951,6at 1883,8at 1790,33at 1777, all twenty of the top twenty below 65 and carrying39007of the347308incidences, a share0.1123; the 366 perfect powers of the window carry58906incidences, a share0.1696against a density0.003660,46.34times their weight. The adversarial read kills the normalisation the enrichment was first printed under - a straddle-coverage ratio whose value at the integer 1 is definitional, since a written span containing 1 must start at 1, and which supplies27.6%of the squares mean - so the study prints unconditional means on1..1000instead:193.42over all integers,995.26over the squares,920.58over the perfect powers. Witness: lab/rs/integer-census. - Verified A champion is a property of a measure column, not of a design:
euler.sidewrites 1 in 695 of its 859 rows,peak.sidewrites 12 in 809 of its 1261,heights.sidewrites both 9 and 33 in 765 of its 1261, and the eight integers below 100 thatheights.sidewrites most often are9, 17, 25, 33, 41, 49, 57, 65, every one1 mod 8, which is what puts33 = 3 * 11tenth in a census otherwise made of powers. The adversarial read kills the mechanism first offered - thatheights.siderows are the progressions1 + s(k-1)- since only 840 of the 1261 rows have arithmetic heads and only 5 start at 1, witnesssequence_dim=2_code=6_measure=heights_axis=sidereading2, 4, 6, 8; the leader set and its1 mod 8law stand as printed. Witness: lab/rs/integer-census. - Verified The tiers split the census cleanly: of the 11133 written integers the closed tier covers 7628 with 3983 exclusive, the side grid 6203 with 2603, the level grid 1826 with 541, the convolved tier 792 with 130; above
30000there are 2174 written integers and the closed tier covers 1853 of them. Witness: lab/rs/integer-census. - Verified Two OEIS collisions, both explained and neither an identification: the ascending champion set opens
2, 3, 4, 6, 7, 8, 9, 12, 14, 15, 16, 18, a window of A100290 and of A336231 and of no other record in a dump of 398817, all three parting at the thirteenth term with 21, 19 and the census's 20; and the written-per-decade run9, 90, 859sits inside A209631 alone, which continues 6689 where the census gives 5452. Both searches index every window of the census sequence and walk every record, so they are exhaustive on both sides rather than sampled at offsets. Witness: lab/rs/integer-census, A100290, A336231, A209631. - Verified No recognizable family is systematically missed: 173 records of the dump hold at least ten distinct integers of
1..=100000and lie wholly inside the miss set, the longest being A361796 at 41 terms, which at a miss density of0.88867has probability about10^-2.1and is ordinary across 398817 records. Witness: lab/rs/integer-census, A361796. - Conjecture That a missed integer is written by no row at any depth. The miss set is a statement about the rendered window: 6802 rows are cut by the 48-term cap, the 96-term lower bound already moves at least 765 misses across,
269among them, and the cost of a true deeper census is cubic in the cap on the dimension-2 side grid. Witness: lab/rs/integer-census. - Conjecture That the miss set is new to the OEIS. It is clean only in its dense head: no record of the dump carries a 4-term window of the miss set at offsets
0..416, the first hit being offset 417 in A049537, and above that the miss set hits near-interval records - 852 hits atk = 4, 130 atk = 10, 37 atk = 15and 15 atk = 20, the 20-term witnesses A112820 and A118471. The absence rests on a dump, which is a snapshot, so it stays a conjecture under the standing caveat. Witness: lab/rs/integer-census, A049537, A112820, A118471. - Conjecture That the write-once set is absent from the OEIS. The 2897 integers written by exactly one row have no hit at any offset of any record at
k = 4, 10, 15, 20, a cleaner absence than the miss set's because the once set is thin where the miss set is an interval complement; the same dump caveat applies. Witness: lab/rs/integer-census. - Conjecture That the miss set has no arithmetic characterisation. No modulus to 64 separates written from missed, the written share has no common growth order, and the set is closed under nothing; the finiteness bound is the only theorem the lane offers. Witness: lab/rs/integer-census.
- Conjecture That no bounded union of named families reaches the written tail. Above
30000the rows' written sets collapse to 953 distinct families of which 875 own a tail integer no other family writes, covering 2005 of the 2174 tail integers, so every cover needs at least 875 families; the families are de-duplicated by written set and not by generating rule, so 953 is itself a lower bound on the number of rules. Witness: lab/rs/integer-census. - Conjecture That no reparametrisation of the multiplicity function
a(n) =rows writingnis submittable. It is absent from the dump at every offset tested, but it is a reading of the registry's own shape - the tier mix, the cap and the ceiling - rather than a function ofn, so its terms move with the instrument. Witness: lab/rs/integer-census. - Refuted The miss set is a union of residue classes - all 2079 classes mod
2..64hold a written integer on10000..100000, exhaustively, so no modulus in that range separates written from missed. Witness: lab/rs/integer-census. - Refuted The champions are the highly composite integers - on
1..1000the mean row count is193.42over all integers,995.26over the squares and920.58over the perfect powers, but only170.60over the 413 integers with at least eight divisors, below the overall mean; being a small perfect power is what a champion is, and being divisor-rich reads slightly against it. Witness: lab/rs/integer-census. - Refuted Multiplicity is driven by each row's first rendered term - dropping every row's first term removes
17036of the347308incidences,4.9%, and changes nothing: the written set stays11133, the never counts stay41,3589,88867in all three windows, and the leaders stay36at 2212,64at 2112,16at 2000 and9at 1999, the same integers in a different order. Witness: lab/rs/integer-census. - Refuted The multiplicity spectrum is geometric or a power law - with
S(m)the count of integers written by at leastmrows,S(1) = 11133andS(2) = 8236give a ratio0.7398predictingS(64) = 6.312e-5against the observed977, wrong by seven orders; the spectrum takes 410 distinct values to a maximum of 2858 and its local log-log slope is convex, so no single exponent fits. The adversarial read also kills the fit the power law was rejected by: the exponent first printed was a two-point secant with its amplitude pinned atS(1), not a fit, so the misfit figure it carried is not the minimax one - the rejection stands, the number behind it does not. Witness: lab/rs/integer-census. - Refuted The written tail is the union of a few dominant families - above
30000the rows' written sets collapse to 953 distinct families of which 875 own a tail integer no other family writes, so every cover of the tail needs at least 875 of them. Witness: lab/rs/integer-census. - Refuted No OEIS record contains any contiguous window of the miss set - the search behind that universal sampled 40 offsets spread over 88867 terms, and an exhaustive walk of every window against every record finds hits at every length tested: 852 at
k = 4, 130 atk = 10, 37 atk = 15and 15 atk = 20, with A112820 and A118471 each carrying 20 consecutive misses and A043635 lying wholly inside the miss set. What survives is the restricted statement, absence atk >= 4for offsets0..416. Witness: lab/rs/integer-census, A112820, A118471, A043635. - Refuted Every square below the ceiling is written - 140 of the 316 are missed, the first being
9801 = 99^2. Witness: lab/rs/integer-census.
The repunit layer
- Proved The binary-weight floor on the repunits
w = R_k = (3^k - 1)/2in closed form:Phi_k = sum_{q | rad R_k} mu(q) q^(-1) sum_{t mod q} P_{q,t}^(k/ord_q 3)withP_{q,t} = prod_{r < d} (1 + e(t 3^r/q)), C-finite inkprime by prime,N_k(2) = 2^(k-1),N_k(p) = (2^k + p - 1)/pwhenever2is a power of3modp(p = 5, 7, 23), andPhi_k = 2^k - 2wheneverR_kis prime; values2, 6, 8, 30, 24, 126, 112, 450, 460, 1958, 1344, 8190, 8064, 27360atk = 2..15by three methods. Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT FLOOR EXACTLY. - Proved The repunit excess is a lift family and a deep tail: a binary
Kis a multiple ofR_kexactly when its column counts satisfysum_r c_r 3^r = 0 mod R_k; below3^(2k)the multiples areK_T = a_(T^c) + 3^k a_Twith multiplier1 + 2 a_TandR_(2k); each lift setOcc_Tis occupied and stable ink, soZ(R_k) >= |union_T Occ_T|, and at primeR_k(k >= 15, first atk = 71)Z(R_k) - Phi_k >= 2^k/7 - 4 F(k+1) - 126. Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT EXCESS. - Verified The repunit excess
Z(R_k) - Phi_kreads0, 0, 0, 0, 0, 6, 6, 50, 70, 402, 290, 2198, 2376, 8830atk = 2..15; the lift union equalsZ(R_k)atk <= 10and falls short by18, 16, 108, 162, 624atk = 11..15; minimal witnesses reach 436 digits with a column used 27 times atk = 13; the drift factorises exactly asZ(R_k)/R_k^(log 2/log 3) = 2^(log 2/log 3) (1 - 3^(-k))^(-log 2/log 3) delta_k (1 + X_k)withdelta_k = Phi_k/2^kandX_krising0.0476to0.3227overk = 7..15. Witness: lab/py/ratio-set-saving (ratio.py repunit). - Conjecture The repunit drift is unbounded:
X_k = (Z(R_k) - Phi_k)/Phi_krises at every step fromk = 8and beats the random-lift limitsum_T 1/m_T = 1.41atk = 13, so no pointwiseZ(w) <= C w^(log 2/log 3)holds on the repunits and every exponent abovelog 2/log 3survives; the blocking lemma is whether|union_T Occ_T|plus the deep tail isO(2^k). Witness: lab/py/ratio-set-saving (ratio.py repunit), coprime.md THE REPUNIT DRIFT. - Refuted That
1.5975(the maximum ofZ(w)/w^(log 2/log 3)below8192, atw = 1093) bounds the layer: the repunits read1.7845and1.963681atk = 11, 13, so any pointwiseC w^(log 2/log 3)needsC >= 1.9636. Witness: lab/py/ratio-set-saving (ratio.py repunit). - Verified The deepest first return of the critical band automaton grows below the critical
sqrt(w)as a sign and not as an exclusion:log d_maxonlog wover 27 weights gives0.4055, 95 percent[0.3293, 0.4818], but one deletion moves the slope to0.4261and the interval to0.5034, covering1/2, so the leave-one-out range[0.3829, 0.4261]is what stands; the median has no single exponent,0.1802on every weight against0.2798atZ >= 8with 4 of 27 weights havingZ <= 2; and a two-predictor fit puts0.3385onlog wand0.1313onlog Z, so controlling for sample size lowers the exponent and the drift below1/2is understated. Witness: lab/py/band-return-times critical. - Proved The submasks of a binary
Kdivisible by a divisormof it are closed under complement insupp K, under disjoint union and under nested difference, soN_K(m)is even and every solution is a disjoint union of irreducible ones; the decomposition is not unique, soN_K(m)is the number of distinct unions of pairwise disjoint irreducibles and satisfiesN_K(m) <= #packings <= 2^iotafor the irreducible countiota, withN_K(m) = 2^iotaif and only if the irreducibles are pairwise disjoint, and then they partitionsupp K. Depth-free. The antipodal and run families of the repunit lift are the equality case, which is why their counts are exact powers of two, and the converse fails,k = 7with multiplier19having a power-of-two count and overlapping irreducibles. Witness: lab/py/band-return-times lift and check, the three closures asserted over every one of the2^(k-1)setsTat everyk = 2..9, and both witnesses pinned. - Verified The depth-2 lift census of the repunit reads
M_k = 2, 6, 14, 36, 68, 172, 306, 728, 1338, 2814, 5224, 11852, 20888, 43364, 84124, 172516, 327092atk = 1..17withM_k/2^kinside[1, 2.89356], and its Hankel matrix is9by9of full rank on all seventeen terms, so no linear recurrence of order at most 8; the irreducible supplySum_T iota_T / 2^ksits inside[0.738281, 0.890625]atk = 2..12, the even readings falling fromk = 6, whilemax_T iota_Tgrows2, 3, 4, 5, 6, 10, 14, 24, 31, 50, 68, and the equality case holds for1970of the2048multipliers atk = 12against1986whose count is a power of two. The sweep is exhaustive over everyTinside[1, k-1]; the multipliers meet the residue classes1and7mod9and never4, which is forced bya_T = Sum 3^iwithi >= 1and not a reading. Witness: lab/py/band-return-times lift. - Verified A column transfer for the submask count of the lift half needs at least 253 states where the return half needs
b/2: a machine reading thekcolumns with a state set free ofkis a linear representation of the count as a series over the column word, so its state count is at least that series' Hankel rank, and the rank reads3, 7, 14, 31, 62, 126, 253at word length1..7on each side against the full3, 7, 15, 31, 63, 127, 255, deficiency0, 0, 1, 0, 1, 1, 2. The words reach length 14, so the floor holds atk <= 15and is already worse than the2^(k/2)meet in the middle; whether the rank is unbounded is observed and not proved, and a rank levelling off would be a poly-time machine, so the route is blocked and not closed. The irreducible count has the same full-rank Hankel to word length 5. Witness: lab/py/band-return-times lift.
The second moment of the rays
- Refuted The non-shift residual of the second moment converges as
R(n)/phi^(2n) -> C ~ 3at ratephi^2- the normalised ratio reads 2.498, 3.045, 3.238, 3.182, 3.113, 2.983, 2.895 atn = 8, 10, 12, 13, 14, 15, 16, peaking atn = 12and falling by0.9724per level, andR(n)/R(n-1)sits at 2.573, 2.561, 2.509, 2.541, a rate near2.54, strictly belowphi^2 = 2.618; what survives isR(n) = O(phi^(2n))onn <= 16,lim R/phi^(2n)undecided,R = o(3^n)with room3/2.54rather than3/2.618, and Conjecture Z untouched. Witness: lemma-b-pincer. - Refuted The majorant
Sum_z M_n(z)(M_n(z)-1)is a route to Conjecture W - it grows2.907a level atn = 13against2.573forRitself, because it drops the coprimality of(s,t)and so counts each collinear pair once per common divisor; the exact identityR(n) = Sum_z P_n(z)survives and the golden ceilingM_n(z) <= F(n+1) - 1survives, but the step fromP_n(z)toM_n(z)^2 - M_n(z)does not. Witness: lab/py/gasket-witness-weights.
The slice ladder: rate and dead routes
- Conjecture The roots-of-unity circulant correction
Q_dim = fill/3 + (2/3)(-1)^(dim-1)(dim-1) cos(2 pi dim / 3)is worse than barefill/3: mean absolute error11.05299392007777488084818against0.1511524922667271359757626overdim = 2..50, a factor73.1248, with|rho - Q_dim| / |rho - fill/3|reaching1067922.7atdim = 50; its sign matches(-1)^(dim+1)only whendim = 0 mod 3, 16 of 49 cases; the order-dimroot-of-unity term is cancelled by finite-boundary effects, the empirical correction factor collapsing to-9.363982332e-7atdim = 50, so any model of the excess must derive the boundary cancellation. - Conjecture The three-block DFT decomposition of the carry matrix does not exist: the span of
1,omega^c,omega^(2c)is not invariant for anydim >= 5(relative Frobenius residual0.318to0.523), carry residues mod 3 are coupled for everydim >= 3soMdoes not commute withdiag(omega^c), and the three-root average(P(1) + P(omega) + P(omega^2))/3misses the Perron root by-9.191to+11.263while the true excess is-0.0435atdim = 20; the mod-3 block version has off-diagonal Frobenius mass of order one, ratio0.609to4.111overdim = 3..30with slope-0.00162 +- 0.00773perdim,p = 0.836, and a Schur correction atfill/3positive for everydim,0.343offill/3atdim = 30; one exact row-sum identity survives. - Conjecture The saddle-point route is closed: the transfer operator is coefficient decimation,
(Mv)(c) = [t^(c+dim)] P_dim(t) V(t^3)on a finite carry window, not multiplication by a scalar symbol; geometric vectorsz^care not eigenvectors, the all-ones vector is the only reflection-even one and is not an eigenvector either; on the unit circlemax|P_dim(e^(i theta))| = P_dim(1) = fill, whose cube root is exponentially smaller thanrho_dim, whilemax|P_dim|/3is exactlyfill/3and misses the whole effect; no non-tautologicalf_dim(theta)withrho_dim = max|f_dim|was found. - Conjecture Induction on
dimis closed from both ends: the same-size correction betweenM_dimandM_(dim+1)at odddimhas full rank at everydim = 3..19, determinants from-54atdim = 3to-441065669103434214513656226772598887664331096atdim = 19, so the matrix determinant lemma has no low-rank update to consume; the threshold determinant sequenced_dimsatisfies no recurrence surviving holdout - constant-coefficient orders 1 to 6 with degrees 0 to 5 on the full sequence and each parity subsequence, all 62 identifiable holonomic pairs withr s <= 40, normalisation byfill^nand bydim^betaforbeta = -4..4, Berlekamp-Massey over three primes at maximal linear complexity (20 for 39 terms, 10 per parity), the one determined fit (order 4, degree 2, odd subsequence) failing atdim = 35, 37, 39; the 2-adic valuation ofd_dimfits none of the tested elementary forms. - Conjecture Cauchy interlacing is closed: over all 27 pairs
2 <= dim <= 28,M_even(dim)is not the upper-left block ofM_even(dim+2)and none of the(n+1)^2row-column deletions of the larger matrix is the smaller, so no borderingu,v,alphaexist; the eigenvalue chain holds for every even start and fails for every odd one, witnesslambda_1(3) = 7.372281323269againstlambda_2(5) = 16.965208741322; the threshold count it was meant to prove is nevertheless exact ondim = 2..30- no eigenvalue abovefill/3at evendim, exactly one at odddim. - Refuted The decay rate of the slice-dimension excess is
3/4,4/3or8/3- at 320 digits overdim = 2..100the eigenvalue-scale one-step ratio extrapolates to0.742874554813847413, residual0.00712544518615from3/4, andr_inf = 1.34612251727283689, residual0.0127891839395from4/3, both far outside the4.5643e-8parity split and the fit-order spread; on the dimension scale2 r_inf = 2.6922450against8/3 = 2.666667; the coarsedim <= 50reading0.373, inverse2.68, and the sentence "the per-dimension factor approaches3/4from above" conflate the two scales; the constant is identified asprod_{k>=2} cos(2 pi/3^k) = 0.7428747134, within1e-8atdim = 61. Witness: slice-recurrence-order. - Refuted The excess has the clean shape
slice dimension - (solid dimension - 1) = (-1)^(dim+1) C r^(-dim) + o(r^(-dim))with a constantC-|delta_dim| r_inf^dimclimbs from52.4976468882atdim = 60to88.3872395676atdim = 100, a log-linear fit puts the prefactor atdim^1, and the form is|delta_dim| ~ A dim r_inf^(-dim)withA ~ 0.897520192686; the linear factor is the parity factordim - 1. Witness: slice-recurrence-order. - Refuted Conjecture S stated against the threshold
base^(dim-1)- at base 3,sgn(rho_dim - 3^(dim-1))matches the hypothesised sign in 25 of 49 cases overdim = 2..50, is wrong already atdim = 3where the difference is-1.627718676730986, and exact real-root counting finds no eigenvalue above3^(dim-1)at anydim = 2..20; at base 5,rho_dim < 5^(dim-1)at every testeddim,rho_3 - 25 = -1.5341439003; the only threshold that carries the statement isfill/3, the eigenvalue-scale form ofd - 1. Witness: slice-recurrence-order. - Refuted The even carry block has exploitable matrix structure - over
dim = 2..20the banded-plus-low-rank form does not exist (Toeplitz displacement rank equal to the full dimension fromdim >= 5, tridiagonal remainder of rankn-1at odd andnat evendim), total nonnegativity fails for everydim >= 4with an exact negative minor per row, onlydim = 2is symmetric and onlydim = 3, 4are positively diagonally symmetrizable (weights(1,6)), andM_even - (fill/3) Iis Metzler rather than a Z-matrix, so the M-matrix route is circular; the matrices havendistinct real roots at every testeddim, which is spectrally useless. Witness: slice-recurrence-order. - Refuted A simple positive test vector certifies the Collatz-Wielandt bound - the all-ones vector has ratios mixed around
fill/3for everydim = 3..50(dim = 2excepted, that matrix being one by one), one-parameter cosine, alternating and centred-quadratic corrections succeed only atdim = 2, 3, 4, and the Gaussianexp(-3 i^2 / dim)and binomial-centre profiles only atdim = 2; the Perron vector certifies at everydim <= 50(worst discrepancy9.15e-46), is peaked at index 0 and monotone non-increasing rather than bell-shaped, and has no closed form. Witness: slice-sign-even-half. - Refuted A cheap route proves the spectral separation
rho_dim/|lambda_2| -> 1- the common-amplitude Gaussian kernel predicts a limiting ratio 9 where the truth is(dim+2)/(dim-2) -> 1, discarding an order-dimparity modulation; the zero-shift2x2Schur complement has median relative error 0.625 overdim = 2..40and worst 0.9998, deteriorating withdim; the Perron profile peaks at index 0 for all 39 testeddim, a boundary-centred half-Gaussian at medianR^2 = 0.99999, not neardim/6; the second eigenvector has one sign change at every evendimand atdim = 3, 5but several at every odddimfrom 7 to 39; separation holds numerically todim = 60, and a proof must be uniform in a margin of order4/dim. Witness: slice-recurrence-order.
The spirograph loops
- Proved On a circle track
a/bin lowest terms, withs = -1inside ands = 1outside andrho = a + s b, a pencil at real seattwheel radii drawsz(phi) = rho e^(i b phi) + t b e^(i s rho phi)on[0, 2 pi). Settingsigmaanddeltafor the half sum and half difference,z(phi) = z(psi)readsrho sin(b delta) + t b sin(s rho delta) e^(i s a sigma) = 0, sosigmais a multiple ofpi / aandrho sin(b delta) = e t b sin(rho delta)witheplus or minus one. The number of unordered parameter pairs that meet isa/2times the number of suchdeltain the open interval(0, pi)over both signs. Witness: lab/rs/roulette-loops. - Proved Every self crossing of a trochoid on a circle track lies on one of the
amirror lines through the centre: the reflection in the line of angleb sigmafixes it. For a real seat those lines arek pi / a; a seat at anglealphaturns the curve by-s b alpha / aand turns its lines with it. Read offmrlynum::spirograph::traceat 24001 samples, the worst distance from a crossing to its line is4.33e-7of the frame over 30 cells at seat angles0and0.3, the floor being thef32the trace returns. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Proved A trochoid on a circle track has a point of multiplicity above two at exactly one reach,
rho / b: a multiple point needs every pairwisedeltato be a multiple ofpi / a, and such adeltasolves the crossing equation only there, where the curve runs through the centre at theaparameters(2j+1) pi / a. So the distinct double point count equals the parameter pair count elsewhere and falls short byC(a, 2) - 1at that reach. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Proved The parameter pair count of a trochoid on a circle track changes only where the crossing equation has a double root, and those are exactly the roots
deltaofa sin(m delta) = m sin(a delta), equivalentlysinc(m delta) = sinc(a delta), withm = a + 2 s b. Each carries the reachabs(cos(b delta) / cos(rho delta)), read asabs(rho sin(b delta)) / abs(b sin(rho delta))where both cosines vanish. A threshold is one such angle in[0, pi), not a reach; several angles can share a reach. Witness: lab/rs/roulette-loops. - Proved The ends
delta = 0anddelta = pisolve the crossing equation of a trochoid on a circle track at every reach, and a root is born at each end as the reach passes one, since the derivative there isrho b (1 - e t)andrho b ((-1)^b - e t (-1)^rho). The single tangency angle atdelta = 0stands for both births, which is why the jump at reach one isaand nota/2. Read off the equation,3/1inside has no root in(0, pi)at reach0.98and two at reach1.02, at0.1984and2.9432, count three. Witness: lab/rs/roulette-loops. - Proved On a tangency reach a trochoid on a circle track touches itself: the two branches meet with equal tangents, a tacnode, so the meeting count there is the transversal count just below plus
a/2for each tangency angle at that reach. The step function is read on the open intervals between tangency reaches and never on one. At reach squared27/2the hypotrochoid5/1has two tangency angles and two simple roots, so ten meetings against five below and fifteen above, the branches closing to8.88e-16at radius2.041241. Witness: lab/rs/roulette-loops. - Proved Swapping the wheel frequency
band the rim frequencyrhoof a trochoid on a circle track fixes every tangency angle, because the unordered pair{a, abs(m)}is{rho + b, abs(rho - b)}either way, and inverts every tangency reach, becauseabs(cos(b delta) / cos(rho delta))inverts. So the thresholds depend on the ordered pair and the fallinga < 2bstaircase is the reciprocal of the risinga > 2bone:5/1inside steps at3.674234614175and5/4inside at0.272165527. Witness: lab/rs/roulette-loops. - Proved The tangency equation of a trochoid on a circle track integrates:
a sin(m delta) - m sin(a delta)is2 a mtimes the integral ofsin(b t) sin(rho t)from0todelta, up to sign. That integral's derivative vanishes on(0, pi)only atj pi / rhoandk pi / b, and there the integral is exactly(-1)^(j+1) sin(b j pi / rho) rho / (rho^2 - b^2)and(-1)^k sin(rho k pi / b) b / (rho^2 - b^2), so the threshold count is a sign count over a merged Farey sequence and carries no numerics at all. Witness: lab/rs/roulette-loops. - Proved Every tangency reach of a trochoid on a circle track is an algebraic number in closed form. Expanding
sin(k delta)andcos(k delta)inu = sin^2(delta)by the integer recursion of Sakhnovich 2023, theorems 2.1 and 2.5, the tangency equation becomesu Q(u) = 0, timescos(delta)whenais even, for an explicit integer polynomialQ, and the reach squared isT(u) / B(u)for explicit integer polynomialsTandB. The recursion is the cited source's;Q,TandBare this study's. Witness: lab/rs/roulette-loops. - Proved Two pencils at complex seats
pandqon one wheel of a circle tracka/b, drawing distinct curves, meet at exactly(a/2) Nunordered parameter pairs, whereNcounts the roots in[0, 2 pi)ofrho^2 sin^2(b delta) = b^2 (P sin^2(rho delta) + E cos^2(rho delta) - s X sin(2 rho delta))withPandEthe squared halves of the sum and difference of the seats andXhalf the imaginary part ofqtimes the conjugate ofp. The equation ispiperiodic indeltasoNis even and the halving is exact. Witness: lab/rs/roulette-loops. - Proved The pair law counts parameter pairs, and a point count needs more: no self crossing of either curve may lie on the other, and neither seat may sit at reach
rho / b, where that curve alone losesC(a, 2) - 1points into the centre. The extra condition is codimension one and is not implied by the curves being distinct.:3/1inside with one seat at reachsqrt 5 - 1and one at the wheel's centre gives six parameter pairs and three points, all at radiusrho, while two percent either side gives six points. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Proved A pencil at the wheel's centre of a circle track
a/bdraws the circle of radiusrho, and the pair law collapses toabs(sin(b delta)) = b t / (2 rho)against a pencil at reacht, so those two curves meet2 a btimes below reach2 rho / band never above;10/3at8/3inside, read as48then0off the trace. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Verified For reach positive, not a tangency reach, not
rho / b, andmnonzero, the self crossing count of a trochoid on a circle tracka/bisa (b - 1) + a sign(m) twithtthe number of tangency angles whose reach is strictly below, counted with multiplicity. It runs froma (b - 1)toa (rho - 1), and the number of angles in[0, pi), countingdelta = 0, isabs(rho - b), the same integer as the smaller ofabs(m)anda. Witness: lab/rs/roulette-loops. - Verified The step function of a trochoid on a circle track holds on
179coprime fractionsa/bwithaat most24,357cases over the two sides withmnonzero, against the crossing equation's root count at the midpoint of every step, and on25578reads ofmrlynum::spirograph::traceat4001and12001samples over reach0.5to4in203steps forbin one to six andainb+1to eleven coprime, both sides, with no disagreement and every jump bracket0.0173wide or less. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Verified The exact integer sign count of the integral of
sin(b t) sin(rho t)over its critical values returnsabs(rho - b)on all29450coprime frequency pairsbandrhoup to220, with no root finding anywhere in the computation. Witness: lab/rs/roulette-loops. - Verified Over all
210swaps of the wheel and rim frequencies of a hypotrochoid withb + rhoat most26, every tangency reach times its partner under the swap is1to within1.47e-13. Witness: lab/rs/roulette-loops. - Verified The hypotrochoid
5/1has tangency reaches1and3.674234614175twice, the second exactly reach squared27/2atu = 5/6onQ(u) = 40 - 48 u, and its count runs0,5,15. The hypotrochoid7/2has1and2.353415666603twice, reach squared(81 + 21 sqrt 21) / 32at the smaller root ofQ(u) = 192 u^2 - 336 u + 140, and counts7,14,28. Witness: lab/rs/roulette-loops. - Verified The epitrochoid
5/1has tangency reaches1,4.180967894379twice and5.789603394549twice, the last two exactly reach squared(102 - 7 sqrt 21) / 4and(102 + 7 sqrt 21) / 4onQ(u) = -320 u^2 + 448 u - 140, and its count runs0,5,15,25, four values for three distinct reaches because two angles share each of the last two. Witness: lab/rs/roulette-loops. - Verified When
ais even,delta = pi/2is always a tangency angle of the trochoid on a circle tracka/band its reach is the rationalrho / b, which is also the one reach where the curve runs through the centre with allabranches:3at4/1inside,5/3at8/3inside,13/5at8/5outside. There a step and the centre correction fall on the same reach and the step function is not read. Witness: lab/rs/roulette-loops. - Verified At reach
rho / bthe distinct self crossing point count of a trochoid withaodd is the step function lessC(a, 2) - 1, read offmrlynum::spirograph::traceat 24001 samples as1for3/1,5/2,5/3and7/4inside,6for5/1and5/4inside,8for7/2inside,7for3/1,10for3/2and21for5/2outside, the two counts agreeing three percent either side. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Verified The pair law matches
mrlynum::spirograph::traceon48reads over5/1,7/2and8/3inside and5/2outside at reaches0.6,1.3,2.4and3.7against three seat kinds, equal reach, shorter reach and the wheel's centre, on the parameter pair count exactly. Witness: lab/rs/roulette-loops, mrlynum::spirograph::trace. - Verified The pair count
2 a bof two distinct trochoids from one wheel survives the loop threshold, which is a tangency of one curve with itself and never of two curves with each other. For two seats at one reach and half anglenuapart on5/1inside it first leaves2 a bat2.242763,1.741061,1.379486,1.143270,1.047854,1.010207and1.002194fornuof1,0.5,0.2,0.05,0.01,0.001and0.0001. The pair threshold is not monotone innu:8/3inside gives1.117596atnu = 1against1.523254atnu = 0.5. Witness: lab/rs/roulette-loops. - Verified On a tangency reach the meeting count of a trochoid is the count below plus
a/2per tangency angle there, read as21against14and28for7/2inside,55against44and66for11/4inside,6against3and9for3/1outside, and15against10and20and then25against20and30for5/2outside, the two branches closing to1e-14or better in every case. Witness: lab/rs/roulette-loops. - Conjecture For every coprime
a/band both sides the trochoid's tangency angle count isabs(rho - b)and every angle moves the self crossing count by exactlya sign(m), so the count runs froma (b - 1)toa (rho - 1)inabs(rho - b)equal steps. The angle count is exhaustive to frequency220in exact integers and the step size toaat most eleven against the trace; what is missing is a proof that the merged Farey sign sequence changes sign exactlyabs(rho - b) - 1times inside(0, pi). Witness: lab/rs/roulette-loops. - Conjecture The first reach at which two trochoids from seats at one reach and half angle
nuapart stop meeting2 a btimes is above one for every positivenu, with infimum one, the excess falling likenu^(2/3). The reading is seven samplednuat one fraction,5/1inside, whose excesses fall by4.69then4.65per decade against10^(2/3) = 4.64. There is no bound and no third decade. Witness: lab/rs/roulette-loops.
The spirograph nodes
- Proved One curve of a circle roulette crosses itself exactly
a(b - 1)times when its seat obeys0 < abs(p) < min(1, M/b), fora/bthe ring over the wheel in lowest terms andM = a - binside,M = a + boutside: the crossing equation reduces on the torus toA abs(sin(b x)) = C abs(sin(M x))withA = r M / bandC = r abs(p), every root carrying exactlyahalf sums, and that is the zero set of the imaginary parts ofA e^(i b x) -+ C e^(i M x), whose arguments climb strictly whileA > CandA b > C M, so each takes exactly2bzeros and, onceC > 0, the two share onlyx = 0andx = pi. Witness: research/lab/rs/roulette-nodes, mrlylab::roulette::nodes. - Proved Two distinct curves of one wheel on a circle track cross exactly
2abtimes when both seats lie in the window,0 < abs(p) < min(1, M/b), and share a radius: the half difference equation gains only a phase, each branch keeps its2bzeros and the two share none, so the root count is4band the crossing counta 4b / 2. For seats of different radii the same count follows from the sufficient bound2 A sqrt(1 - k^2) > r(abs(p) + abs(q))withk = r sqrt(abs(p) abs(q)) M / (A b), far from necessary: inside7/3at seats0.950and0.672the bound reads1.604against1.622and fails while the count is 42. Witness: research/lab/rs/roulette-nodes. - Verified A whole design carries one node count,
2ab C(k, 2) + k a(b - 1)crossings withkits distinct curves, so the design enters only throughk: 5553 cells and 4455175 crossings over both tracks, everya/bin lowest terms withaat most 20 andbat most 10, four designs and seven reaches inside the window0 < abs(p) < min(1, M/b), every count three sample counts alike; 143 cells are aligned and printed, 26 need a further doubling, none goes unsettled, and two disagree by a few crossings at a near tangency, inside20/3at seat0.250and outside10/9at0.400, both read as the law by the torus. Witness: research/lab/rs/roulette-nodes. - Verified A roulette cuts the plane into
nodes + 2regions, the unbounded one among them, at a generic reach with every seat in the window0 < abs(p) < min(1, M/b),nodescounting distinct transversal double points: the picture is a connected 4-regular plane graph and Euler gives the count,k = 1withb = 1carrying no node and 2 regions by Jordan. A flood of the rastered walls at 1600 and at 2400 pixels returns 2, 7, 16, 8 and 32 for one seat inside3/1,5/2,7/3and two seats inside3/1,5/2, and 1206 for the carpet inside7/3at the alignment reach, where 1288 crossings sit at 1148 nodes of 2352 branches and the count isbranches - points + 2. Witness: research/lab/rs/roulette-nodes. - Verified The self law ends at the crest of
abs(sin(b x)) / abs(sin(M x)), the least of its local maxima, never below the seat thresholdC/A = 1because the ratio reaches 1 at the midpoint of two consecutive zeros ofsin(b x): over 213 cells and the 31 inside ratios witha < 2bandaat most 20, every count below the crest isa(b - 1), every count above it is smaller, always a multiple ofa, never rising, and every ladder ends ata(a - b). At exactlyC/A = 1the curve runs through the centre,abranches meet, and the counts 25 at7/5and 31 at7/6are neither the law nor a multiple ofa. Witness: lab/rs/roulette-nodes. - Proved Two pencils on a circle track
a/bin lowest terms draw one curve if and only if a rotation of2 pi/babout the wheel's centre carries one seat to the other; the converse is read offabs(z)^2 = A^2 + C^2 + 2 A C cos(a u - arg p), whose phase runs overaturns, with Niven's theorem cutting the square lattice to the quarter turns. So curves coincide by half turns whenbis even and by quarter turns when4dividesb, andkis the pencil set modulo the rotations of ordergcd(b, 4); on a line track a seat's angle is a shift, so two seats of one radius draw translates of one shape and never one curve. Witness: mrlynum::spirograph::representatives, lab/rs/roulette-reaches, spirograph.md. - Refuted The loop threshold is not where a design's node laws end: inside a track with
a < 2bthe seat leaves the centre path first and the counts fall whileabs(p)is still under 1,7/6reading 35, 21 and 7 self crossings at seats0.158,0.175and0.9againsta(b - 1) = 35. One seat past that threshold is enough to lose the pair law where the self law still holds: inside7/4at seats0.900and0.636two curves cross 42 times against2ab = 56while both self counts hold at 21 under the crest1.333. Past it the pair count is no function ofaandb, reading 6 against 12 at3/2and 8 against 24 at4/3. Witness: lab/rs/roulette-nodes.
The spirograph reaches
- Proved A pencil at complex seat
pwheel radii on a wheel rolling on a circle tracka/bin lowest terms drawsz(psi) = r e^(i b psi) (A + p e^(i eps a psi))onpsiin[0, 2 pi), withA = abs(a/b + eps),eps = -1inside and+1outside. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::point. - Proved That trochoid's picture turns
afold, sincez(psi + 2 pi / a) = e^(2 pi i b / a) z(psi)with noepsbecausee^(i eps a 2 pi / a) = 1, and turning the seat byalphaturns the whole curve by-b eps alpha / a, since shiftingpsiby-alpha / (eps a)absorbs the seat turn and leaves the prefactore^(-i eps b alpha / a); the four seats of one square orbit therefore draw four rotations of one master curve and the seat modulus is the only shape parameter. Witness: research/lab/rs/roulette-reaches. - Proved Writing
xfor the seat's phase andm(x) = 4 a (b eps x / a + arg(A + p e^(ix))) / pi, withpnot zero the radiusabs(A + p e^(ix))is strictly decreasing on[0, pi], so the trochoid meets every circle strictly between the two apex radii in exactly2 apoints, at the anglesc + m/8andc - m/8in units of a turn overa, with seat offsetc = -b eps arg(p) / (2 pi). Witness: lab/rs/roulette-reaches. - Proved While the seat modulus is under
Athe mark runs from0at the outer apex to4 b epsat the inner one, and pastAthe pointA + p e^(ix)circles the origin so the inner value is4 b eps + 4 ainstead. Witness: lab/rs/roulette-reaches. - Proved The mark is one to one in the radius whenever the seat modulus is under
min(1, A): while it is underAthe derivative ofarg(A + p e^(ix))inxgrows withcos x, running from minus the modulus overAminus the modulus atx = pito the modulus overAplus the modulus atx = 0, and each of those stays underb/aexactly when the modulus is under one, while pastAthe derivative atx = piexceeds one and the mark turns back. Witness: lab/rs/roulette-reaches. - Proved That window is sharp but for one endpoint: at modulus one the binding derivative meets
b/aat the single phasex = 0inside and atx = pioutside, so the mark is still one to one there, and every larger modulus fails. Witness: lab/rs/roulette-reaches. - Proved Two trochoids of one seat modulus whose seat offsets differ by a quarter turn cross only on the circles where the mark is a whole number, and a curve crosses itself only where the mark is a multiple of four; the quarter turn is needed, since seats a fifth of a turn apart on
7/3inside cross where the mark is plus or minus1.2modulo four. Witness: lab/rs/roulette-reaches. - Proved Inside the window the mark's range has length
4 b, so a trochoid on a circle tracka/bhasb - 1self crossing circles anda (b - 1)self crossings, and two distinct curves of one seat modulus a quarter turn apart have2 bcrossing circles and2 a bcrossings. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::trace. - Proved Three trochoids of one seat modulus on a circle track never run through one point unless the modulus is
A: the radius squaredA^2 + q^2 + 2 A q cos xfor modulusqis strictly decreasing inxon[0, pi], so one radius fixes one phase and one mark for all three at once, the angles arec + m/8andc - m/8, two of the three must share a sign, and that forces their seat offsets to differ by a multiple of a turn overa, which makes the two curves the same curve. Witness: lab/rs/roulette-reaches. - Proved That argument needs only the monotone radius, so it carries past the one to one window, holds for
beven, and holds at both apexes where the two signs merge. Witness: lab/rs/roulette-reaches. - Proved At seat modulus
Aon a circle tracka/bevery trochoid of that modulus runs through the centre,atimes each; inside this needsb < a < 2 bfor a modulus under one, and outside it never happens becauseA = a/b + 1exceeds one. Witness: lab/rs/roulette-reaches. - Proved A meeting of trochoids from the carpet's two seat moduli on a circle track
a/bhappens exactly when both marks are whole numbers at one radius and one eighth class collects three or more branches; the seat offsets are the exact eighths-b eps dmod 8 for compass indexd, so the test is integer arithmetic and never a tolerance, each meeting class holdsapoints because the picture turnsafold, and each meeting swallows five of the generic picture's double points. Witness: lab/rs/roulette-reaches. - Proved A trochoid on a circle track
a/bsits at whole mark congruent tojmodulo four exactly wherew^(a + 2 b eps) (A + p w)^a = i^j (A w + p)^aon the unit circle, which follows fromabs(A + p w)^2 = (A + p w)(A w + p) / w; squaring the mark condition loses half the angle, so the law pins the mark only modulo four. Witness: lab/rs/roulette-reaches. - Proved The carpet alignment reaches on a circle track
a/bare contained in the real algebraic set cut out by that law for the corner modulus, the same law for the edge modulus, and the equal radius equation, three real equations in three real unknowns over the field generated by the square root of two; the containment is proper, since the law pins the mark only modulo four and the marks-10,-6and-2share one system on7/3inside, but the mod four branches are disjoint and closed inside the window because the mark is continuous there, so an isolated alignment reach is an isolated point of that set and hence an algebraic number. Witness: lab/rs/roulette-reaches. - Verified The reduction agrees with
mrlynum::spirograph::pointto2.138e-13over all 98 circle tracks withbin1..8andainb+1..13coprime, both sides, on all eight carpet fill seats at reach0.83and 29 phases a seat, and the seat offset classes reproducemrlynum::spirograph::distincton all 98. Witness: lab/rs/roulette-reaches, mrlynum::spirograph. - Verified The node counts
a (b - 1)and2 a bneed the seat modulus undermin(1, A)and not merely under one: the radius and mark census of the study gives7/5inside4self classes and10pair classes per pair at modulus0.3900underA = 0.4, and the pair count falls to8at0.4100, while4/3inside falls from2self classes to1between0.3267and0.3400, both well under the cusp threshold one. Witness: lab/rs/roulette-reaches. - Verified The carpet on
7/3inside has 24 alignment reaches over the scan, 21 transversal and 3 tangential; every transversal meeting carries four branches, twelve of them from four distinct curves and nine from three, one curve bringing two branches where its own self crossing lands on the meeting. Witness: lab/rs/roulette-reaches. - Verified The
7/3inside transversal reach near0.79is0.791009415157with marks(-6, -9), ring1.005704332357wheel radii and corner seat modulus0.527339610104; the f64 bracket is1.1e-16and the exact law residual4.18e-15, so the printed twelve decimals round safe. Witness: lab/rs/roulette-reaches. - Verified The four curves predicted to meet at that reach do meet on the crate's own curve: the four meeting seats sit
2.167e-5,1.441e-6,7.697e-8and5.590e-9from the point the algebra names, read in f64 frommrlynum::spirograph::pointat 2000, 8000, 32000 and 128000 samples, falling like the square of the sample count, while the other four seats stay1.206e-1away. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::point. - Verified The same read off
mrlynum::spirograph::tracegives2.162e-5,1.526e-6and1.109e-7at 2000, 8000 and 32000 samples, tracking the f64 column until it reaches the f32 floor:tracereturnsf32, half a step at that radius is1.192e-7, so the third column measures rounding rather than convergence and only the first two carry the square law. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::trace. - Verified At the control reaches
0.781009and0.801009no class carries more than two branches and the four seats stand1.767e-2and1.771e-2off the point that meets at0.791009415157. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::trace. - Verified The node count drops at a transversal alignment:
7/3inside carries 184 crossing classes at a generic reach and 164 at the reach0.791009415157, the four meetings swallowing five double points each, and since the picture turnsafold those are 1288 and 1148 nodes. Witness: lab/rs/roulette-reaches. - Verified The tangential alignment family is not empty: inside the window the corner band contains the edge band, so a corner pair's crossing radius sweeps through both edge apex radii, and on
7/3inside three such reaches sit in the scan, at0.687455178256with marks(-7, -12),0.948942238176with(-1, 0)and1.176138007019with(-5, -12). Witness: lab/rs/roulette-reaches. - Verified The two sided falsification holds over all 98 circle tracks with
bin1..8andainb+1..13coprime, inside and outside, inside the window: 2157 alignment reaches, 193 of them tangential, every one carrying a node past two branches read offmrlynum::spirograph::pointin f64 and offmrlynum::spirograph::tracein f32 at 8000 samples, worst gap2.445e-4in f64 against a worst f32 floor of9.537e-7, and none of the 98 control reaches carrying one. Witness: lab/rs/roulette-reaches, mrlynum::spirograph::trace. - Verified Every transversal alignment carries
4 / gcd(b, 4)meeting classes, and the reach counts are stable in the scan:7/3inside gives 24,12/7inside 153,13/7inside 177,9/5inside 89,13/8inside 11 and13/7outside 61, each at both 6000 and 24000 steps. Witness: lab/rs/roulette-reaches. - Conjecture Every carpet alignment reach is an isolated point of the real algebraic set that contains it, and so an algebraic number. The scan finds each reach as a simple sign change of a continuous defect, and no two of the 2157 reaches over the 98 tracks coincide, but nothing in the run certifies isolation, and a failed integer relation search to degree 48 with coefficients under
1e7at 200 digits on the7/3reach0.791009415157is consistent with either answer. Witness: lab/rs/roulette-reaches. - Conjecture The number of carpet alignment reaches on a circle track
a/binside the window follows the window's own width: inside it climbs withawhilea < 2 b, where the window isAand grows witha, and falls oncea > 2 b, where the window is the fixed one,b = 3inside giving 18, 28 fora = 4, 5and then 24, 21, 19, 18, 15 fora = 7, 8, 10, 11, 13, andb = 5inside rising 39, 55, 71, 89 and then falling 79, 68, 64; outside it barely moves witha,b = 3giving 9, 9, 11, 11, 11, 11, 12 andb = 7giving 57, 57, 57, 57, 57, 61. No closed count is proved. Witness: lab/rs/roulette-reaches.
The spirograph walls
- Proved On a circle track
R/r = a/bin lowest terms a pencil at complex seatpdraws a closed curve whose signed area over the whole track, counterclockwise positive and counted with multiplicity so that it is the winding number integrated over the plane, ispi b rho (rho -+ d^2/r), minus inside and plus outside, withrho = R -+ rthe centre circle's radius andd = r abs(p). Green's theorem onz(t) = rho e^(i t) + p r e^(-+ i (rho/r) t)gives it, the cross terms carryinge^(-+ i a t / b)overbcentre turns and integrating to zero, and no hypothesis on the reach is needed since loops are counted with their sign. Witness: mrlynum::spirograph::signed_area, lab/rs/roulette-cover. - Proved Every curve of a circle roulette lies in the closed annulus from
abs(rho - d)torho + dabout the track's centre and attains both bounds, sinceabs(z)^2 = rho^2 + d^2 + 2 rho d cos(a t / b -+ arg p)and the phase runs overafull turns. The whole roulette therefore sits in the disc of radiusrho + max dand enters no disc of radius undermin abs(rho - d), the least over the seats and not the outermost seat's own, since seats on either side ofrhokeep their own inner radius; a trace of 200001 points per curve meets both radii on all 48 cases with worst gap3.55e-15, the five ratios with a seat pastrhoincluded. Witness: mrlynum::spirograph::disc, lab/rs/roulette-cover. - Proved The fluid poured at the centre of a circle track always fills at least the disc of radius
min abs(rho - d), which no curve enters, so the hole is at least that radius over the disc's radius, squared. The raster reads no leak on all 48 cases, the slack running from0.000111at four quarter-turn copies inside7/3to0.461499at one pencil outside2/1, and to0.142005at one pencil inside4/1over the inside cases alone; read instead with the outermost seat the bound is false, and one pencil inside5/4at reach0.9is the smallest counterexample, inner radius2.6and notrho - d. Witness: mrlynum::spirograph::disc, lab/rs/roulette-cover. - Proved At
b = 1with one distinct curve below the loop threshold the roulette is a simple closed curve on both sides, so its complement has exactly two components: the shape between the walls is the wall alone and covers nothing, while the fluid poured at the centre fills the whole inside, the centre lying inside because the winding number about it isb = 1. The hole is therefore the signed area over the disc's area,rho (rho -+ d^2/r) / (rho + d)^2, minus inside and plus outside, met to8.70e-5at worst over the 16 ratios2/1to9/1on both sides while the cover falls like the pixel to at most0.000124. Witness: mrlynum::spirograph::cover, lab/rs/roulette-cover. - Proved For one distinct curve the shape between the walls is the union of the bounded complement components other than the one holding the centre, so it is empty for a simple curve and of positive area as soon as the curve crosses itself: one pencil at reach
0.9inside covers-0.000030on a bar of0.000064, zero to its bar, at3/1with no self crossing,0.003269at3/2witha(b - 1) = 3crossings, and0.273092at7/3with14. Witness: mrlynum::spirograph::cover, lab/rs/roulette-cover. - Verified The mean signed winding number of the enclosing disc's pixel centres, read by scanline against the polylines and never off a flood, meets the sum of the distinct curves' signed areas over the disc's area on all 48 cases at all four raster sides, worst gap
1.73e-3at the carpet's corners outside5/8at side 256 and4.84e-4at side 2048, with no reading outside the perimeter bound. At side 2048:0.282984against0.282996for one pencil inside3/1,1.678772against1.678770for four quarter-turn copies inside7/3,9.103089against9.103448for the carpet's fills inside7/3. Witness: mrlynum::spirograph::cover, lab/rs/roulette-cover. - Verified The raster cover converges like the pixel: on all 48 cases the successive differences fall by a factor of at most
0.626as the side doubles from 256 to 2048, so the Richardson limit ofc(n) = c + A/ncarries a bar of at most0.000354. The carpet's fills inside7/3at reach0.9cover0.800044on a bar of0.000343from the ladder0.814487, 0.807142, 0.803764, 0.801904, its corners cover0.765594, four quarter-turn copies of one seat cover0.629299, two cover0.443227, one pencil covers0.273092, and outside5/8the fills cover0.758414and the corners0.867284. Witness: mrlynum::spirograph::cover, lab/rs/roulette-cover. - Verified The cover reads the distinct curves and not the pencils: two half-turn copies of one seat inside
5/2are one curve under the coincidence law and cover0.213852, the single pencil's own figure, while inside7/3the same two seats are two curves and cover0.443227; the closed form follows the same law, the carpet's eight fills inside5/2summing to3.346939over four curves where a sum over the eight seats would read6.693878. Witness: mrlynum::spirograph::cover, lab/rs/roulette-cover. - Conjecture No closed form for the cover shows itself on the small cases: all three candidates fail on all 48, and the walls are stitched at the parameters where the outermost and innermost arcs cross, so an exact area would be a sum over the regions those crossings cut, which no study here computes. Adding curves does not act independently either: four quarter-turn copies inside
7/3cover0.629299where the independent-union guess1 - (1 - p)^kon the single curve's0.273092gives0.720798. Witness: lab/rs/roulette-cover. - Refuted The full annulus between the walls' extreme radii,
4 rho d / (rho + d)^2, which is4 d (a - b) b / (a - b + b d)^2inside, is not the cover: the fluid poured from outside reaches into every bay between the outermost arcs, and the form overshoots on all 48 cases, closest at the carpet's fills inside7/3with0.856124against0.800044on a bar of0.000343, worst at one pencil inside2/1with0.997230against0.000017. Witness: lab/rs/roulette-cover. - Refuted The sum of the distinct curves' enclosed areas over the disc's area is not the cover: it counts multiplicity, so it reads
9.103448for the carpet's fills inside7/3where a cover cannot pass1, and atb = 1it is the hole and not the cover,0.282996against a cover of zero inside3/1. Witness: lab/rs/roulette-cover. - Refuted The single simple curve's form
rho (rho -+ d^2/r) / (rho + d)^2is not the cover at any ratio: atb = 1the cover is zero and the form is the hole, and aboveb = 1it misses,0.139898against0.273092on a bar of0.000076for one pencil inside7/3and0.347206against0.800044for the carpet's fills there. Witness: lab/rs/roulette-cover.
The spun stack
- Proved The dead-spin theorem: rotated layers
(m, alpha)and(n, beta)of the line stack share a node off the origin iffcosandsinofalpha - betaare both rational, and the shared set is thenR_alpha (1/gcd(m,n)) Z^2, of densitygcd(m,n)^2per unit area; at whole degrees Niven's theorem makes the conditionalpha = beta mod 90, exactly 4 of 360 degrees having bothcosandsinrational by reduction ofzeta^d + zeta^-dmodPhi_360; the rational rotations are exactlyw^2/N(w)for nonzero Gaussianw, notz/|z|,(1 + i)/sqrt 2the counterexample, all 68 rational unit-circle points of denominator at most 60 reached from the box of side 12. Witness: lab/py/spun-stackrational_angle_degrees,dead_spin_pairs,pythagorean_hits. - Proved The exact spun stack indexes layers by the nonzero associate classes of
Z[i], layerzthe latticez^-1 Z[i]; its lit nodes in the unit square are the Gaussian rationalsu/din lowest terms, the node with reduced denominatordis lit by exactly the layersddivides, and its brightness isg(floor(N/N(d)))withg(t) = sum_j (floor(t/(4j+1)) - floor(t/(4j+3))), the Gauss circle count of nonzero classes of norm at mosttand the Gaussian twin offloor(N/b); the lit set hassum_{[d], N(d) <= N} Phi(d)nodes, the Gaussian totient sum; 672 nodes and 0 mismatches against exact literal stacking at norm bound 50, counts 672, 10608, 168088 at norm bounds 50, 200, 800. Witness: lab/py/spun-stackliteral_stack,closed_brightness,totient_sum. - Proved A fixed rotation with a fixed geometric scale per layer is multiplication by one complex
c: the layersc^-k Z[i]overlap off the origin iffcis inQ(i)and nest iffcis inZ[i], and then brightness isdepth + 1 - address, a pure address with no moire, the base-cnumeration tree (base-1 + ithe twindragon); Verified atc = 1 + idepth 8 andc = 2 + idepth 4, 256 and 625 nodes, 0 mismatches, overlaps 440, 220 and 0 over the box of side 10 for1 + i,3/2 + i/2andsqrt 2 e^i. Witness: lab/py/spun-stackbase_depth_check,base_c_overlap. - Verified No Franel-Landau theorem for the Gaussian Farey set is found in the sources read (Sayous arXiv:2407.04380 proves equidistribution on
C/Z[i]with no rate and a gap law, naming neither Franel nor Landau; Estala-Arias arXiv:1908.03658 states RH forzeta_Kon measures over the positive reals; Huxley Acta Arith. 18 (1971) and Kanemitsu-Yoshimoto Acta Arith. 75 (1996) unread), so an RH-equivalent forzeta_Krendered by the spun stack is unstated, neither proved nor refuted; the named obstruction is that Franel-Landau needs a rank andC/Z[i]carries no canonical linear order. Witness: lab/py/spun-stack, REFS.md. Superseded: Huxley 1971 and Kanemitsu-Yoshimoto 1996 are read at source, the rank obstruction blocks only the rank functional, and the FourierL^2equivalence is proved under Franel one field up. - Proved The centre is a node of every spin schedule of the odd carpet stack: rotation about the centre preserves distance from it and layer
n's cell containing the centre has inradius1/(2n), so a disc of radius1/(2N)lies inside one cell of all layers at every angle; atN = 55the centre reads ink14/28, the scalesn = 3 mod 4, the unspun value, under every schedule and every raster. Witness: lab/py/spin-rendermain. - Proved The unspun odd carpet stack at
N = 55attains its global ink maximum18/28on exactly four square cells of side1/159, total area4/25281 = 0.000158222: ink at(u, v)is the size of the intersection of the two scale sets, so a maximum needs them equal and maximal; the one-dimensional maxima over 636 exact breakpoints are[1/3, 18/53)and[35/53, 2/3), and the scale set is invariant underx -> 1 - xbecausefloor(n(1 - x)) = n - 1 - floor(nx)withn - 1even, so both intervals carry the same 18 scales and all four products are maxima. Witness: lab/py/spin-renderdiagonal_maximum. - Verified Spinning by whole degrees destroys the unspun maximum and shrinks its cell: peak ink falls from
18/28to14/28under a one-degree increment and16/28under the prime-degree schedule, the golden and Gaussian schedules,17/28under random angles, the peak cell area from3.95523e-05to9.80453e-06and1.65596e-05, atR = 256, 512, 1024, 2048and under a zoom at effectiveR = 51200; spinning leaves the fade law alone,rms sqrt(L)in the layer countLatL = 28running0.401417to0.460395over six schedules, the unspun raster matching the exact rational covariance sum0.309477, 0.389754, 0.426869, 0.458411atL = 4, 8, 14, 28to0.4%, the lane'sc = 0.522being the limit constant and not theL = 28value. Witness: lab/py/spin-renderreport,main. - Proved The eyes of the fixed increment: under the schedule that turns layer
kbyk theta, two layers with indicesj, kshare an exact lattice iff(j - k) thetais a multiple of 90 degrees (the odd carpet being invariant under a quarter turn), so attheta = 90 p/qin lowest terms the layers fall into exactlyqangle classes and the sharing pairs numbersum_classes C(size, 2), while at an irrationaltheta/90no pair shares; on the 28 odd scales to 55 the count reads 378 attheta/90 = 0, 182 at1/2, 117 at1/3and2/3, 84 at1/4and3/4, 65 at1/5and2/5, 52 at1/6, 36 at1/8, 30 at1/9and 0 atsqrt 2 - 1, confirmed by the pairwise exact test and by the Niven-free rational-angle test at the whole-degree increments; the moire switches on exactly past the Farey fractions of a quarter turn. Witness: lab/py/spun-stackincrement_classes. - Proved The node-count constant of the spun stacks: for every imaginary quadratic field
Kwith class numberh,wunits and discriminantD_K,sum_{N(a) <= N} Phi(a) = (rho_K/(2 zeta_K(2))) N^2 + O(N^(3/2))over nonzero ideals withPhi = N * mu_Kandrho_K = 2 pi h/(w sqrt |D_K|), by Dirichlet convolution and Abel summation on the ideal countA(t) = rho_K t + O(sqrt t), itself derived one ideal class at a time from the lattice of covolumeN(a) sqrt |D_K|/2; the Gaussian constant ispi/(8 zeta(2) G) = 0.260634696495and the Eisenstein constantpi/(6 sqrt 3 zeta(2) L(2, chi_-3)) = 0.235217881630, the nine published node counts recounted exactly and extended to norm bound 102400 wherecount/(c N^2)reads0.999746and1.000049, the deviation scaled byN^(3/2)never past0.119and the ratios oscillating about 1, withD = -20(h = 2, ratio1.000001117) andD = -23(h = 3, ratio0.999886) at 102400 as the class-number witnesses; the observedN log Nsize of the error stays Conjecture; the literature's complex Farey constantpi/(sqrt |D_K| zeta_K(2))counts element denominators and iswtimes this one, the sets being equal. For a general number field the same argument runs from any ideal count with errorO(t^theta),0 < theta < 1. Witness: lab/py/totient-constantmain,norm_totient_sum,farey_set. - Conjecture The Gaussian Farey stack's node count is asymptotically
pi N^2/(8 zeta(2) G) = 0.260635 N^2withGCatalan's constant; the ratios read0.268800, 0.265200, 0.262638at norm bounds 50, 200, 800; the literature count of the complex Farey set is 4 times this, the order of the unit group, a convention difference unresolved. Witness: lab/py/spun-stacktotient_sum. Superseded: the constant is Proved and the convention resolved, see the constant row under The spun stack in SETTLED. - Refuted A whole-degree prime schedule (layer
katp_kdegrees) is coincidence-free: 5 of the 435 layer pairs toN = 30share, all at relative angle exactly 90 (7 and 97, 11 and 101, 13 and 103, 17 and 107, 19 and 109 degrees), each sharing a lattice of densitygcd(m,n)^2per unit area whose count in the open unit square with the origin excluded reads1, 9, 49, 1, 9and is angle-dependent (2, 3, 4atg = 2over degrees 1 to 89), not a formula; the other 430 pairs are dead with margin0.003390. Witness: lab/py/spun-stackdead_spin_pairs,unit_square_shares,share_count_spread. - Refuted A resolution-stable off-centre maximum in a spun render is an exact coincidence: the stack is piecewise constant on cells of positive area, so any cell wider than a pixel holds its position at every resolution, and the prime-degree schedule shows one at
(0.19469, 0.15501)drifting0.29px fromR = 1024to2048; raster stability measures cell area, and the discriminators are the peak value and the cell area. Witness: lab/py/spin-renderdrift.
The stack algebra
- Proved Stacking is Dirichlet convolution: the
u-stack of thev-stack draws the inner scalenat scaleknwith weightu(k) v(n), so the composite weight isu * v, exact at every scalem <= Nunder the hyperbolic cutkn <= Nand only form <= min(K, M)under a rectangular cut (10 of 16 scales differ above24in the24 x 40case atu = v = mu). The plain stack iszeta, the stack of stacks iszeta^2with scalendrawnd(n)times, and1 * mu = ecollapses the Mobius stack of the plain stack to one layer. Checked by literal double stacking in exact rationals atN = 60by three routes sharing no inner loop onu = v = 1,u = 1, v = mu,u = v = muandu = 1, v = n^-1, 1102, 1102, 974 and 1102 nodes, zero mismatches. The group carries no RH content: RH sits at the inverse of1alone, whoseb = 1node isM(N). Witness: lab/py/stack-algebraconvolution_check. - Proved Every selected line stack has a closed-form node at denominator
b: evensfloor(N/lcm(2,b)), odds0at evenbandceil(floor(N/b)/2)at oddb, primespi(N)atb = 1,1at primeb <= Nand0elsewhere, squarefree the double divisor sumsum_{d^2 <= N/b, gcd(d,b) = 1} mu(d) sum_{e | b} mu(e) floor(N/(b d^2 e)), prime powersfloor(log_p N) - i + 1atb = p^i; zero mismatches against literal stacking at everyb <= NforN = 30, 61, 200, 501; the primes-only stack atN = 501lightsb = 1and the 95 primes, every prime node at brightness exactly 1. Witness: lab/py/stack-algebraselection_closed_forms. - Proved The primes-only carpet stack fades at exactly the independent rate: distinct primes are coprime, so every layer pair has covariance exactly 0 by the gcd law,
L Varof theL-layer mean is the mean of the per-layer variances identically and the ratio to independent layers is exactly 1 at everyL; with16 p^4 Var_p = 3p^4 - 4p^3 - 2p^2 + 4p - 1 = (p-1)^2 (3p-1)(p+1)the constant isc^2 = 3/16,c = sqrt(3)/4 = 0.4330127, approached from below at rateO(log log p_L / L),L Varreading0.1429334753, 0.1595579958, 0.1833424270, 0.1869968711atL = 5, 10, 100, 1000; the odd stack under the same estimator reads0.2708541and factor1.202738atL = 4000, converging to the lane's1.2054. The criterion is pairwise coprimality, not primality, the odd primes being the densest uncorrelated selection by least-prime-factor injectivity; the squarefree-odd rival fails withCov(C_15, C_21) = 284/99225 = 0.0028621819and ratio1.308596over 1000 layers. Witness: lab/py/stack-algebraprime_carpet_variance,squarefree_carpet_variance. - Proved The
s-harmonic stack: weightsn^-sare completely multiplicative, so the nodea/breadsb^-s H_s(floor(N/b))and tends tozeta(s)/b^s, and the total node masssum_b phi(b) zeta(s) b^-sequalszeta(s-1)fors > 2, read atN = 16000as1.644872, 1.202057, 1.082323againstzeta(2), zeta(3), zeta(4). Ats = 1the renormalisation is Davenport's expansion ata = mu,sum mu(n)/n ((nx)) = -sin(2 pi x)/pi, so the renormalised Mobius stack of the sawtooth is one sine; truncated atn <= 10^5over five rationalxthe max error is5.49e-03, 1.37e-03, 2.08e-04at cuts10^3, 10^4, 10^5; the{nx}form differs by(1/2) sum mu(n)/n, whose vanishing is the prime number theorem, read as-0.00048723atn <= 10^5; the identity is Verified through arXiv:2005.08279 equation 1.1, which quotes it, not at the 1937 source. Witness: lab/py/stack-algebraharmonic_stack,davenport_check. - Refuted Everything inside the Dirichlet group of stacks is closed form: the group contains
1andmualike, so membership buys nothing and closed-form-ness is a property of the weight, not of the algebra; the group statement carries no RH content and RH sits at exactly one element, the inverse of1. Witness: lab/py/stack-algebra.
The tent rank law
- Proved The palindromic module reformulation: mod 2 at odd
dim(R = (dim-1)/2,n = R+1,M = 6R+2) the symbol isG = (1+t)^(4R)(1+t+t^2)with 4-block coefficientsC(R, a), andnullity_2(M_even) = dim{H : no exponent == 1 mod 3, deg H <= M, G | H, t^M H(1/t) = H}- palindromy folds theR+1kernel conditions onto one residue class mod 3; the explicit kernel vectorsH_(b,i) = t^s (1+t^3)^i (1+t)^(2^b)withs = (M - 3i - 2^b)/2,ieven,i + 2^b >= 4R,3i + 2^b <= Mare independent since3R - 1 <= 2^b <= 6R - 4forces a uniqueb, and numbertent(dim), sonullity_2 >= tent(dim)with troughs exactly where3Ris adjacent to a power of 2; the reversal involution on thet^3-chain of the single generator givesnullity_even = ceil(nullity_full/2)exactly; the staircase submatrix (rowsc' = R - j, leftmost pivots atR - 1 - 3j) yields onlyfloor((R-1)/3) + 1independent rows, the wrong third of the rank; without the(1+t+t^2)hypothesis the valuation lemma yields onlytent + 1(witnessesR = 2, 4, 7); matrix nullity equalstentat 21dimthrough 511 and at every odddim = 3..401, the module identities toR = 1024. Witness: slice-sign-even-half. - Proved Lemma M, sharp with equality: for every
d >= 2andr in {0, 1, 2}, the maximal(1+t)-valuation over nonzeroH in F_2[t]with no exponent== r mod 3anddeg H <= dismu_r(d) = max_(2^b <= d) [floor((d - s_0 - 2^b)/3) + 2^b],s_0 = (r + 2^b) mod 3, attained byt^(s_0)(1+t^3)^i(1+t)^(2^b)- the Frobenius splitH = A^2 + t B^2gives the exact case lawv(H) = 2v(A) / 2v(B) / 2 min / 2w + 1(the equal-valuation case forced byC' = B_1^2, a unit at 1), classes mover -> (2r, 2r + 1), the recursionM_r(d) <= Phi(M_(2r)(floor(d/2)), M_(2r+1)(floor((d-1)/2)))withPhi(X, Y) = max(2X, 2Y, 2 min(X, Y) + 1)has the closed form as supersolution by lifting the child's maximising Frobenius blockb -> b + 1(six integer inequalities,X = Yforcingb_e = b_oby a numerator gap>= 2^(min+1) - 3, finite windowsd = 5..12with 24 evaluations, 8 tight, and base casesd = 2..4); the corollary Lemma M' for(1+t+t^2) | HisM'_r(d) = M_r(d - 3) + 1ford >= 5, the cheapest purchase of valuation being one Frobenius block plus(1+t^3)padding at exchange rate 3:1, which is wheresup nullity/n = 1/3comes from; brute-forced tod <= 16000(failure set exactly the fourd < 2pairs), the upper bound certified independently by full rank of Lucas submask matrices atd = 1023..8193, the supersolution tight at 4926 points up to2^60with minimum slack 0, the case law exact on allH < 2^17, and the true minimum of the moduleYcomputed at 204Rup to 1025. Witness: slice-sign-even-half. - Proved The one-class window lemma, by the parity of an index:
Y = Z ∩ G F_2[t]isF_2[t^3]-free of rank 2 with generator degreesdelta_1 < delta_2in distinct classes mod 3 anddelta_1 + delta_2 = 12R + 5exactly - truncation counting givesdim_(F_2) Z/Y = (delta_1 + delta_2 - 2)/3, the projection onto the missing exponent class identifies the cokernel ofZ -> F_2[t]/(G)withF_2[u]/gcd(A_0, A_1, u A_2)of dimension exactly 1 (since(1+t^3) | Gbut(1+t^3)^2does not), sodim Z/Y = deg G - 1 = 4R + 1; the sum is odd, sodelta_1 <= 6R + 2 = M < delta_2in two lines, margins 0 and 2 impossible and margin 1 iffdelta_1 = M; explicitly{delta_1, delta_2} = {12R - 2A + 2[a even], 2A + 3 + 2[a odd]}witha = floor(log_2(4R - 1)),A = 2^a, fromA + 2 <= 4R <= 2A; hencenullity_2(M_full)(dim) = floor((M - delta_1)/3) + 1andnullity_2(M_even)(dim) = ceil(nullity_full/2)in closed form for every odddim; the identity generalises asdelta_1 + delta_2 = 3(deg G - deg_u gcd) + 2at 400 randomG, the closed form holds toR = 200000, margins below 5 lie in{1, 3, 4}exactly as parity predicts,R = 683 = J(11)hasdelta_1 = M(margin 1) andR = 1365 = J(12)margin 3. Witness: slice-sign-even-half. - Proved The Jacobsthal tent rank law, entire: for every odd
dim = 2R + 1 >= 3, base 3, middle-digit design,nullity_2(M_even)(dim) = tent(dim) = 1 + dist(R, {J(a), J(a) + 1})witha = floor(log_2(4R - 1)), and sharplynullity_2(M_even) <= ceil(n/3),n = (dim+1)/2, with equality exactly atdim in {3} ∪ {2^(2j) + 1}; withm = R - J(a)all four (parity ofa) x (branch) cells reduce tonullity_full = 1 - 2m(m <= 0) or2m(m >= 1), the parity ofacancelling completely, and halving givesnullity_even = 1 + d_a(R); the nearest-trough index isaitself (ana - 1reading was rejected exhaustively), margins exactly 1 at both window endpoints propagate by 1-Lipschitzness,R = 1is the sole reason the cap isceilrather thanfloor, and the odd-apeaks miss by exactly 1; closed form equals tent equals the real transfer-matrix nullity at every odddim = 3..1401, closed-form checks toR = 500000with points to2^60(argmin strictly unique everywhere), no residue family past the cap (max excess 0); sov_2(det M_even) = tent(dim) + X(dim)with the tent capped atceil(n/3), and base-3 strictness rides on the cascade layersX(dim)alone. Witness: slice-sign-even-half.
The tile monoid
- Proved Factorisation of a 0/1 tile is unique once the ordered side profile is named: if
A (x) B = A' (x) B'withA, A'of sidemandB, B'of siden, all non-empty, then cutting the composite into anm x marray ofn x nblocks readsAoff as the 0/1 indicator of the non-zero blocks andBas any one of them, since every non-zero block equalsBandBis not the zero tile, soA = A'andB = B'; the non-empty tiles under the Kronecker product are therefore a monoid graded by side, cancellative and atomic, whose block test decides factorability at a named shape inO(N^2)of exact integer comparison, the 0/1 hypothesis being load-bearing since over the rationalsA (x) B = (kA) (x) (k^-1 B), and the block reading being the 0/1 shadow of the Van Loan and Pitsianis rearrangement. This is a rediscovery and is cited, not claimed: it is Lemma 2.4 and section 2 of Voet and De Novellis, Identifying Kronecker product factorizations, arXiv:2510.25292, for binary matrices under equality. Witness: lab/rs/code-factorisation, magic.md, arXiv:2510.25292. - Proved The ordered side profile is not recoverable from the composite, so the tile monoid has no unique factorisation, and the failure is not axis-separable:
[6]{(0,0),(2,2)}is bothc1 (x) c257.base3andc17.base3 (x) c1, all four letters of prime side and hence irreducible with differing multisets, and the tile is not a rectangle; the mechanism is an infinite family rather than a side-6 accident, sinceI_m (x) I_n = I_mn = I_n (x) I_mandE_m (x) E_n = E_mn = E_n (x) E_mat every pair of sides by the symmetry of(nm - 1) - x = (n - 1 - i) m + (m - 1 - j)inmandn, the same digit identity the diagonal action already carries, so takingmandndistinct primes gives four irreducible letters at every side with two distinct prime factors; the existence of shape-distinct factorisations is Example 2.5 of Voet and De Novellis, and new here are the axis-separable refutation and the I/E family. Witness: lab/rs/code-factorisation, magic.md, arXiv:2510.25292. - Proved Neither the length nor the side multiset of a factorisation is an invariant of the composite, first at side 12 and at no smaller side:
[12]{(0,0),(3,3)}reads as three irreducible letters of sides2, 2, 3and as two of sides3, 4, the side-4 letter[4]{(0,0),(3,3)}being irreducible because its one candidate cut has two unequal blocks, while every side below 12 is a prime power, where factorisation is unique, or a product of two distinct primes, where every letter has prime side; the short reading needs a letter of composite side, which no plane code is, so length and the side multiset are invariants for free inside the magic-word submonoid generated by prime-side letters and fail in the full monoid, and the alphabet of the words is not the alphabet of the monoid, 65310 of the 65535 non-empty side-4 tiles being irreducible already and the reducible share falling from0.343328%at side 4 to0.0000221%at side 6; a factorisation whose sizes are not all prime is Example 2.6 of Voet and De Novellis, and new here are the minimality of side 12 and the alphabet gap. Witness: lab/rs/code-factorisation, magic.md, arXiv:2510.25292. - Proved Two factorisations of one tile admit a common refinement exactly when the union of their cut chains is totally ordered by divisibility, because a cut at
d'dividing a cut atdfactors the side-dleft factor through the side-d'one; so unique factorisation holds at every prime-power side, where the divisors are a chain, and fails exactly when the cut setL(C)holds two incomparable divisors, checked with zero mismatches against direct enumeration of every irreducible factorisation over all 339795 side-12 plane-code composites, of which 7023 carry two or more factorisations and 2376 carry factorisations of unequal length. Witness: lab/rs/code-factorisation, magic.md. - Proved The tile monoid is not a trace monoid, so no canonicalisation may sort or commute letters:
[2]{(0,0)} (x) [3]{(1,1)} = [6]{(1,1)} = [3]{(0,0)} (x) [2]{(1,1)}uses four pairwise distinct irreducible letters, which no commutation of a letter pair can produce, and only 11 of the 171 side-6 cross-shape tiles are honest commutations against 160 rewritings. Witness: lab/rs/code-factorisation, magic.md. - Proved Two letters render one tile at one side only at side 3: if a base-2 code and a base-3 code agree cell for cell at one
sidethen rowrequals rowr'wheneverr = r'mod 2 or mod 3, and atside >= 4those two partitions join the whole row range, so every row and every column agrees and a non-empty constant tile is the full tile; the census is 480 pairs at side 2, 15 at side 3 and the full tile alone at sides 4, 5, 6, 7, 8, 9, 12 and 18, the carpet's side-3 partner is uniquelyc495of fill 8, and at side 9 the readings separate into fills 65, 72 and 64 on three pairwise distinct tiles, though read as level-2 fractals of the side-3 letter they do not diverge at all, since at side 3 they are one tile. Witness: lab/rs/code-factorisation, magic.md. - Proved The canonical name of a composite is the code together with its ordered side profile,
c<code>(side_1 x side_2 x ... x side_level), and the two non-injectivities are different objects that must be disambiguated in order: the render collision belongs to the alphabet alone and tabulates once per base and side, since fixed-shape uniqueness proves the fold never creates one, while the fold collision belongs to the profile; profiles of different length occur, so the tie-break orders profiles by length first, finest before coarsest, then lexicographically, before the diagonal-action class rep breaks what is left. Witness: lab/rs/code-factorisation, magic.md. - Verified The side-6 census: the two shape images are injective at 7665 tiles each, 171 tiles lie in both, so 15159 of the
2^36 - 1side-6 tiles are reducible once the overlap is removed and 68719461576 are irreducible; of the 171, 121 are axis-separable and 50 are not, 11 are commutations and 160 rewritings, fills run1:36 2:64 3:32 4:16 6:14 12:8 36:1over the 171 and2:16 3:32 6:2over the 50 with outer-fill signature(1,1):24 (1,2):8 (1,3):16 (2,3):2, and the 48 that are neither separable nor commuting are exactly the 48 carrying a one-cell letter in at least one reading and exactly the 48 carrying a one-cell outer factor in at least one reading, three statistics on one set checked as sets rather than as counts, since the two one-cell readings differ elsewhere (0:23 1:8 2:140against0:23 1:60 2:88over the 171). Witness: lab/rs/code-factorisation, magic.md. - Verified
121 = 11 x 11is arithmetic with a checked bijection: the 121 axis-separable side-6 cross-shape tiles are exactly the productsR x Cof the 11 lines that factor in both radix orders,{0} {1} {0,1} {2} {0,2} {3} {4} {5} {3,5} {4,5} {0..5}, verified as set equality and not as a count. Witness: lab/rs/code-factorisation, magic.md. - Verified Counting reducible tiles at prime-power side is inclusion-exclusion over the divisor chain, equivalently the series
I = T/(1+T)on the grading, giving 225 at side 4, 1962675 at side 8, 261121 at side 9, 553402322215537199175 at side 16 and(2^25 - 1)^2 = 1125899839733761at side 25, cross-validated in one dimension against exhaustive brute force atN = 4, 8, 16, 9reading 9, 63, 1431, 49; nothing new happens at a prime-power side, where the two side-8 shape images of 983025 tiles each meet in exactly the 3375 triple products of base-2 codes, checked as set equality, so 3375 is pure associativity and never stands beside 171. Witness: lab/rs/code-factorisation, magic.md. - Proved One-cell letters commute exactly when
a(n - 1) = b(m - 1), givinggcd(m - 1, n - 1) + 1singleton pairs per axis and, where no common power exists,gcd(m - 1, n - 1) + 2commuting pairs in one dimension, checked at nine side pairs and exceeded only at(3,9)at 7 against 4 through the common-power branch; at base 2 against base 3 this gives the 11 commuting code pairs(1,1) (2,4) (3,7) (4,64) (5,73) (6,84) (8,256) (9,273) (10,292) (12,448) (15,511), nine of them a commuting row line against a commuting column line and the other two the diagonal and the antidiagonal, with base-2 codes 7, 11, 13, 14 unpartnered, so the carpet code itself does not commute. Witness: lab/rs/code-factorisation, magic.md. - Conjecture The cut set
L(C)is closed under gcd, with zero failures over every non-empty subset of a line atN = 1..20and over all 339795 side-12 plane-code composites and no proof; it is the one missing structural fact, since with itL(C)is a meet-subsemilattice of the divisor lattice and the canonical name closes, and without it there is no counting theorem at non-prime-power side, where 171 and 15159 are enumeration rather than formula. Witness: lab/rs/code-factorisation, magic.md. - Conjecture Two tiles commute under the Kronecker product exactly when they are powers of one common tile or the members at their two sides of one scale-free family, the one-cell case being settled by
a(n - 1) = b(m - 1)and the general case tested only at(2,3)in two dimensions and at ten side pairs in one; relatedly, whether the diagonal and the antidiagonal are the only permutation tiles factoring in both radix orders at every coprime split. The next coprime test needs all2^25side-5 codes, so this has to be settled by proof and not by search. Witness: lab/rs/code-factorisation, magic.md. - Conjecture The three-family description of cross-shape collisions at a coprime shape - axis-separable rectangles, tiles with a fill-1 outer factor, and the diagonal pair - is exhaustive at side 6 and untested anywhere else. Witness: lab/rs/code-factorisation, magic.md.
- Conjecture An intrinsic description of which tiles are Kronecker products, rather than the block test's algorithm and the published decomposition graph; and what the irreducible letters of composite side do, now that they are known to exist and to be generic, which is the question the plane-code word census could not see. Witness: lab/rs/code-factorisation, magic.md.
- Conjecture The diagonal embedding
D -> {(x,x) : x in D}is an injective, divisor-closed embedding of the one-dimensional digit-set monoid into the tile monoid preserving cut sets and irreducibility, and a diagonal tile is axis-separable only at one cell; so a line sweep is a tile sweep, the whole non-uniqueness phenomenon already lives in one dimension, and it lifts to tiles no rectangle can explain. Witness: lab/rs/code-factorisation. - Refuted That every shape-distinct factorisation of a tile is axis-separable, which would have closed the question with a one-line lemma -
[6]{(0,0),(2,2)}factors asc1 (x) c257.q3and asc17.q3 (x) c1with four irreducible letters and is not a rectangle, separability covering 121 of the 171 side-6 cross-shape tiles and none of the diagonal family, and the diagonal and antidiagonal families put a non-separable witness at every side with two distinct prime factors, so the door stays open. Witness: lab/rs/code-factorisation, magic.md. - Refuted That the mechanism of a shape-distinct factorisation is always a side-6 cross-shape collision sitting inside the word - the side-12 tile
[12]{(0,0),(3,3)}has cut set{1,2,3,4,12}with no cut at 6, so no side-6 collision sits inside it, and its two readings differ in length; the earlier statement was read off a sample of words over plane codes and is a property of that universe, not a law. Witness: lab/rs/code-factorisation, magic.md. - Refuted That the length and the side multiset of a factorisation are invariants of the composite - true inside the magic-word submonoid, where every plane code has prime side and every word over it has length exactly the number of prime factors of the side, and false in the full tile monoid, first at side 12, where
[12]{(0,0),(3,3)}reads at lengths 3 and 2; the plane-code census could not have found the witness, since the short reading needs the irreducible side-4 letter[4]{(0,0),(3,3)}, which is no plane code. Witness: lab/rs/code-factorisation, magic.md. - Refuted That the cut set
L(C)is closed under lcm, and with it the naive reading that any two factorisations refine to a common one - the line{0,3}atN = 12hasL = {1,2,3,4,12}, holding 2 and 3 and not 6, and the first failure by mask order at that side is the line{1,2}with the same cut set; 132 failures over every line toN = 20and 2376 over the 339795 side-12 plane-code composites, against zero failures of gcd closure in both sweeps. Witness: lab/rs/code-factorisation, magic.md. - Refuted That the commuting pairs are the four corner cells plus the scale-free families of row, column, full tile, diagonal and antidiagonal - the cells
[3]{(1,1)}and[5]{(2,2)}commute at side 15, both readings giving[15]{(7,7)}, and neither is a corner cell nor a member of any of those families; the four-corner picture is an artifact ofgcd(1,2) = 1at sides(2,3), the correct criterion for one-cell letters beinga(n - 1) = b(m - 1). Witness: lab/rs/code-factorisation, magic.md. - Refuted That the reachable literature cannot reach the tile factorisation question, an earlier positioning against graph products - the isomorphism-versus-equality gap is real for graph products, but Voet and De Novellis, arXiv:2510.25292, is a binary-matrix paper working under equality that already contains fixed-shape uniqueness, the prime vocabulary, the shape-distinct factorisation, the non-prime factor sizes and a decomposition graph enumerating every factorisation; the Proved core recorded above is a rediscovery, and the single verbatim quotation the old positioning rested on could not be recovered from its source and is withdrawn rather than carried. Witness: magic.md, arXiv:2510.25292.
- Refuted The annotation
1125899839733761 = 65535^2in a draft of the prime-power counts - the integer is right and its name is wrong,1125899839733761 = (2^25 - 1)^2 = 33554431^2at side 25, while65535^2 = 4294836225is a side-16 term; transcription, not mathematics, and the generator now prints the identity beside the value. Witness: lab/rs/code-factorisation.
The zeros of the design zeta
- Verified This specific infinite design zeta has zeros in its own half-plane of absolute convergence, which the integers forbid, and the claim is the object and not the principle, since the positive-term Dirichlet series
1 + 2^(-s)has abscissa of absolute convergence-infinityand zeros at(2m+1) pi i/log 2. The census counts zeros of the Lyndon cofactorZ(s) = zeta_F(s)(1 - fill base^(-s)), analytic onRe s > alpha - 1, so it needs no pole-free strip and leaves no sliver against the pole line, on the single stripalpha - 0.92 < Re s < alpha + 3.02,0.02 < Im s < 60, split atRe s = alphaexactly. Base 3F = {0,1}atalpha = log_3 2carries 3 zeros right of the abscissa and 20 left of it inside that strip; base 10 missing the digit 9 atalpha = log_10 9carries 13 right and 25 left; base 3F = {0,2}carries 3 right, in the same three boxes as{0,1}. The largest surviving phase step on any census contour is0.9896and the largest propagated bound met at any census evaluation is9.99e-11, both printed beside every count. The base 2 full digit set is the control on both sides and each side names its object: zeros ofzetainalpha + 0.02 < Re s < alpha + 3.02count0, which is what the Euler product forbids, computed and not quoted; zeros ofzetainalpha - 0.98 < Re s < alpha - 0.02count13, the first thirteen belowIm s = 60; and the teeth of the cofactor1 - 2 base^(-s), which sit exactly ONRe s = alphaand are not zeros ofzeta, bring the one-strip count to19 = 13 + 6with6 = floor(60 log 2/2 pi). Right of the abscissa no continuation is used, since the positive series converges absolutely there and the ladder only rearranges it. The count is resolved and not certified: the largest surviving phase step is printed and nothing boundszeta_F'/zeta_Fon the contour, so a zero pair closer than the surviving spacing would stay invisible. Witness: lab/py/design-zeta. - Proved Scaled digit columns share a zero set exactly: for a positive integer
awitha max F <= base - 1, so thataFstays inside{0..base-1}, the carry-free bijectionm -> a mgiveszeta_(aF)(s) = a^(-s) zeta_F(s), an exponential factor with no zeros and no poles, sozeta_(aF)andzeta_Fhave the same zeros and residues in the ratioa^(-s_(m,j)), and the proof uses0 in Fnowhere. Base 3{0,2}against{0,1}agrees to5.6e-43at three points, and on what was censused, the stripalpha < Re s < alpha + 3.02,0.02 < Im s < 60, the two censuses coincide box for box: winding one inIm [22.01, 24.01], inIm [28.01, 30.01]and inIm [56.00, 58.00]for both, and zero in every other box. Left of the abscissa{0,2}is not censused and is inferred from the theorem. On the Mobius side the same bijection twists the meter by a sign, so the transfer is exact on both faces and trivial on one of them. Witness: lab/py/design-zeta, mobius.md. - Proved The Euler-product bridge between the two faces of RH is absent on a design:
zeta M = 1on the full set,S_Fis not multiplicatively closed for any properF, andzeta_F M_Fis not1, so no known route runs from a zero ofzeta_Ftotheta(F)and the zero census carries no bound on the square-root conjecture. What survives is not the zeros but the position product:G_levelpairs againsta = 1anda = mualike and the arithmetic sits entirely in the kernel. Coons 2010 Theorem 2.3 rules out the automatic-continuation route toM_Fand nothing wider. Witness: mobius.md, lab/py/design-zeta, lab/py/mrly-euler, REFS.md. - Proved The zeros of the design zeta are read off one analytic function and their positions near the pole lattice are forced by the residues. The Lyndon cofactor
Z(s) = zeta_F(s)(1 - fill base^(-s))is analytic onRe s > alpha - 1, since1 - fill base^(-s)cancels exactly them = 0line of the digit recursion's poles and no other; the poles ofZare thoses_(m,j) = alpha - m + 2 pi i j/log basewithm >= 1at whichzeta_Fhas a nonvanishing residue, the nearest line to that half-plane beingRe s = alpha - 1with residue-s_(1,j) gamma_1 r_j/fill, and on a full digit setZhas no pole at all, beingzeta(s)(1 - base^(1-s)), entire. One peel level givesZ(s) = E_1(s) + sum_(l >= 1) binom(-s,l) base^(-s-l) gamma_l zeta_F(s+l)withE_1(s) = sum_(a in F, a != 0) a^(-s)andgamma_l = sum_(a in F) a^l, checked against brute-force digit summation to1.6e-14with and without0inF, andZ(s) a_min^s -> 1to the right. A zero ofzeta_Fright ofalpha - 1is always a zero ofZ; conversely a zero ofZis a zero ofzeta_Fexcept at a poles_(0,j)withr_j = 0, whereZvanishes andzeta_Fis regular. Ats_(0,j)one hasfill base^(-s_(0,j)) = 1exactly for everyj, so withu = s - s_(0,j)the periodic factor is1 - base^(-u)with nojdependence andzeta_F(s) = Z(s)(1/(L u) + 1/2 + L u/12 - L^3 u^3/720 + ...),L = log base, giving residueZ_0/L, regular partZ_1/L + Z_0/2and its derivativeZ_2/L + Z_1/2 + Z_0 L/12from the Taylor coefficients ofZalone, on a disc of radius at least1and exactly1whenr_jdoes not vanish. Witness: lab/py/zeta-locus, lab/py/design-zeta, lab/py/burnol-residue. - Verified The zeros of the design zeta near the abscissa are a residue comb whose tooth position the residue and the regular part predict. A zero near the pole
s_(0,j)solvesu(R_j + R'_j u + ...) = -r_j, first orderu_1 = -r_j/R_jand second order the near root ofR'_j u^2 + R_j u + r_j = 0, both built from the Laurent data with nothing fitted. Over 20 designs toIm s = 40(every scaling class atbase = 3andbase = 4, two atbase = 5, base 9{0,1,2}, base 16{0,1,2,3}, base 10 missing 9, base 2 full set) one assignment radius0.45, fixed by the discs not overlapping and not by the tooth law so that every count is conditional on it, serves both the count and the tooth, discs never overlapping since the smallest period in the sweep is2.2662: the argument principle on that circle gives 164 poles carrying one zero ofZ, 40 none and 8 two, of which 21 are the residue-null pole centres of the three full-set columns and are zeros ofZthat are not zeros ofzeta_F, leaving 143 poles with one zero ofzeta_F, 61 with none and 8 with two. All 151 poles carrying a zero have their zeros located by a polar grid inside that same disc and not by the prediction, so no tooth is selected by the law it tests and no pole carrying a zero is left without one. Comparing prediction to tooth afterwards,miss2/miss1has median0.1637withmiss2 < miss1at 147 of the 151, and the accuracy is conditional on the tooth being close: the 43 teeth atabs(u) < 0.1have largest first-order miss0.01446and largest second-order miss0.00164, the 84 atabs(u) < 0.2have0.10815and0.01526, while the 31 atabs(u) >= 0.3reach1.64614and the prediction says nothing. The densest column is the sharpest: base 10 missing 9 atfill/base = 0.9locates 15 teeth to a largest first-order miss of0.013602and a median of0.000841. Witness: lab/py/zeta-locus. - Verified The critical line is the second family of the full digit set. On a full digit set
zeta_Fiszeta, whose only pole iss = 1 = alpha, so it is regular at everys_(0,j)withj != 0and the residue there vanishes as a one-line consequence rather than a measurement; the machinery reads those residues as1e-26to1e-33, which is a control of the engine, and the comb is empty. The winding of the cofactor overalpha - 0.92 < Re s < alpha + 3.02,0.02 < Im s < 40then splits exactly as six zeros ofzetaplusfloor(40 log base/2 pi)cofactor-only teeth, those teeth being the zeros of1 - base^(1-s)onRe s = 1by exact arithmetic:10 = 6 + 4atbase = 2,12 = 6 + 6atbase = 3and14 = 6 + 8atbase = 4. The six survivors readRe s = 0.5atIm s = 14.1347251417, 21.0220396388, 25.0108575801, 30.4248761259, 32.9350615877, 37.5861781588at all three bases, and the three columns share that zero set to1e-26because they are one arithmetic object. On a design the same split leaves a second family that is not a line atalpha/2: its real parts run-0.273079611to0.391038600over the 7 zeros belowIm 40at base 3{0,1}againstalpha/2 = 0.3154648768,-0.30495894to0.28101268over 6 zeros at base 4{0,1}against0.25, and0.060261843to0.97363028over 5 zeros at base 16{0,1,2,3}against0.25, the spread being the witness and no per-design mean claimed. Witness: lab/py/zeta-locus. - Proved The second family of the design zeta does not depend on which comb is stripped, and the next pole line's comb is computed from the first one's residues. For
m >= 1the cofactorZ_m(s) = zeta_F(s) prod_(i <= m)(1 - fill base^(-(s+i)))has exactly the zeros ofZ(s) = zeta_F(s)(1 - fill base^(-s))insidealpha - 1 < Re s < alpha + 3.02, since each extra factor vanishes only onRe s = alpha - ifori >= 1, so the survivors of the assignment are one set under every comb. WhatZ_madds is the level-icomb, and its Laurent data is forced by the level-zero data:Z(s) = E_1(s) + sum_(l >= 1) binom(-s,l) base^(-s-l) gamma_l zeta_F(s+l)is singular ats_(1,j) = alpha - 1 + 2 pi i j/log basethrough itsl = 1term alone, and withbase^(-s_(1,j)-1) = base^(-s_(0,j)) = 1/filland1 - fill base^(-s_(1,j)) = 1 - basethe residue ofzeta_Fthere isr_(1,j) = s_(1,j) gamma_1 r_(0,j)/(fill(base-1)), so the level-one comb is empty wherever the level-zero comb is, and at the full digit sets_(1,0) = alpha - 1 = 0makes it vanish, which iszetahaving no pole ats = 0; the lab printsabs r_(1,0) = 0.0with the null flag set andabs r_(1,1) = 8.89623e-29at the base 2 full set. Witness: lab/py/zeta-family, lab/py/zeta-locus, lab/py/design-zeta. - Verified The second family of the design zeta, split out and censused over twenty-two designs at a stated assignment radius, with no gap at that radius on any design. Stripping the level-zero and level-one combs at
rho = 0.45, a constant fixed only by the pole discs not overlapping and not by the tooth law, which is accurate only insideabs(u) < 0.2, the twenty designs of the locus sweep plus base 5{0,1,2,3}and base 10 missing two digits give 377 zeros wound by the argument principle, 351 located, 171 teeth of which 9 are level-one teeth, 19 cofactor-only zeros at null-residue poles and 161 second-family zeros, each design censused to its own printed height,40except the four base 3 designs at42.894, base 9{0,1,2}at41.464and base 10 missing two at25.923. There is no gap atrhoon a design: the distance from a second-family zero to the nearest live pole has minimum0.45510938at base 4{2,3},0.45909168at base 3{0,1},0.48696667at base 4{0,1,2}and0.50481072at base 4{1,3}, with base 4{2,3}putting five of its eight inside0.45 < abs(u) < 0.6, so every count is conditional onrhoand falls asrhorises,N_2reading8, 7, 13, 9, 14atrho = 0.45against7, 6, 12, 8, 7atrho = 0.6on base 3{0,1}and the four base 4 two-digit designs. The full digit set is where the gap exists: at base 2 the nearest live pole to a second-family zero is14.143566away and no radius below0.9moves any count. Where the located count falls short of the winding, base 4{2,3}at 12 of 18 being the worst,N_2is a lower bound. Witness: lab/py/zeta-family verb tests. - Verified Seventeen designs carry a lower bound on the Mertens exponent of their own Mobius, and the strongest bound is radius-robust. Nineteen of the twenty-two designs have a censused zero of
zeta_Fstrictly right ofalpha, twelve of them in the second family, and at the seventeen of them whose digit set contains1, so thatnu_Fexists, the transport theorem gives thatsum_(n <= x) nu_F(n)is notO(x^(Re rho - eps)); base 4{2,3}and{0,2,3}omit the digit1and carry a zero but nonu_F. Base 10 missing two digits has a zero at1.00151438765 + 2.77402670058 iagainstalpha = 0.903089987, a second base-10 column where the design's own Mobius has a Mertens exponent above 1 and so abovexitself; that zero is a level-zero tooth atabs(u) = 0.1083of thej = 1pole, deep inside every assignment radius tested, so the bound does not depend on where the comb is cut. Base 4{1,2}has a second-family zero at0.940012431696 + 13.0678968771 iagainstalpha = 1/2, an exponent of0.94against a design mass exponent of0.5, and base 3{0,1}reads0.720787601477atIm 28.6056765649againstalpha = 0.630929754. Witness: lab/py/zeta-family verb tests, lab/py/mrly-pairing verb inverse. - Verified What converges as a design fills is the ordinate set and not the real part. Against the derived null of a quarter of the mean gap between consecutive
zetaordinates in the range, the exact expectation for an equally spaced ordinate set of the same density and conservative for one with gap variance, the mean distance from a second-family ordinate to the nearestzetaordinate divided by that null falls monotonically inalpha:2.0495374at base 5{0,1}withalpha = 0.430676558,1.8953371at base 4{0,1}with0.5,0.75419266at base 3{0,1}with0.630929754,0.51648744at base 4{0,1,2}with0.792481250,0.32356636at base 5{0,1,2,3}with0.861353116,0.090501352at base 10 missing two with0.903089987and1.0429899e-23at the base 2 full set. The base andfillconfounds are dead: the fall is monotone at fixed base,2.0495374to0.32356636inside base 5 and1.8953371to0.51648744inside base 4, and at fixedfill = 2across bases,2.0495374, 1.8953371, 0.75419266, 1.0429899e-23atalpha = 0.430676558, 0.5, 0.630929754, 1; the nulls move only1.0425839to1.3595166across the ladder while the raw mean distance falls2.4032315to0.12303809, so the denominator does not drive it. Over the same designsmean abs(Re s - 1/2)reads0.36482392, 0.39426128, 0.3901396, 0.25540269, 0.31452367, 0.20473972and2.4065966e-23and does not fall monotonically, so atalpha = 0.903the heights are pinned to2.3percent of the mean gap while the real parts are still0.20off1/2.alphais a trend and not a function: the four base 4 two-digit designs at onealpha = 1/2spread0.79050661to2.8404536. The matching is nearest-ordinate and not injective, 3 distinct ordinates for 4 design zeros at base 10 missing two. Witness: lab/py/zeta-family verb limit. - Proved The ordinate shadow is a first-order perturbation and its constant-free form is a Newton step from the zeta zero. The discrete position identity
1_(D_level)(n) = base^(-level) sum_(a mod base^level) G_level(a/base^level) e(-n a/base^level)on0 <= n < base^levelgiveszeta_(F,level)(s) = base^(-level) sum_(a mod base^level) G_level(a/base^level) S_level(s, a/base^level)withS_level(s,x) = sum_(1 <= n < base^level) e(-nx) n^(-s), reproduced from the transform to8.326e-40atlevel = 2on ten designs, and sinceG_level(0) = fill^levelthea = 0fibre carries the weight(fill/base)^levelexactly against the partial sum ofzetatobase^level, with no arc and no limit. That identity splits the polynomial at levellevelagainst a TRUNCATED zeta while the object is the continuedzeta_Fagainst the fullzeta, and(fill/base)^levelfalls to0withlevelwhile both series tend to1on the right, so no level is forced andc = fill/baseis thelevel = 1reading and a definition. For any constantcthe splitzeta_F = c zeta + E_FgivesE_F(rho_0) = zeta_F(rho_0)at a zerorho_0ofzeta, an identity carrying no information aboutc, and a first-order zero ofzeta_Fatrho_0 - zeta_F(rho_0)/(c zeta'(rho_0)); readingc zeta'(rho_0)aszeta_F'(rho_0)removes the constant and givesrho_0 - zeta_F(rho_0)/zeta_F'(rho_0), Taylor at a simple zero ofzeta_F. The offset is one complex number, so at the zeros this law pairs the ordinate offset and the real-part offset are one quantity. The continuous form, the mass ofG_levelonabs(t) < 1/(2 base^level), is the exact sinc sum1/base^level + sum_(n in D_level, n > 0) sin(pi n/base^level)/(pi n)and equalskappa_level(F) (fill/base)^levelwithkappa_levelrunning0.6015221to0.96774464over the ladder atlevel = 1, 2, 3, so it adds no constant the fibre does not give. Witness: lab/py/zeta-shadow verb mass, lab/py/mrly-euler verb position. - Verified The constant-free first-order step predicts the design zero attached to each zeta zero, and it sharpens as the offset shrinks. Over nine designs at twelve zeta zeros to
Im s = 56.4462476971, six toIm s = 37.5861781588at the two densest so the rungs do not share one height, both predictions are computed fromzeta_F(rho_0),zeta_F'(rho_0),zeta'(rho_0)and the digit density alone and the zero is located afterwards by Newton fromrho_0, accepted only atabs(zeta_F) < 1e-16, within1.5ofrho_0and0.02clear of the pole lattice, largest ladder bound9.001e-23. The step's median ratio reads1.3843088, 1.284225, 1.2481449, 1.2060106, 1.2042502, 0.89075541, 1.0195598, 1.005076, 0.99741809atalpha = 0.430676558, 0.5, 0.630929754, 0.792481250, 0.861353116, 0.903089987, 0.954242509, 0.982877878, 0.994835739, with largestabs(ratio - 1)0.14041at base 20 missing one digit and0.01734at base 50 missing one digit, bands[0.94875, 1.14041]and[0.98266, 1.01144]; pooled over the ladder that largest deviation runs0.01734, 0.0508884, 0.193158, 0.83912, 3.32327over the bucketsabs off < 0.05,< 0.1,< 0.2,< 0.4and above, on7, 4, 14, 18, 44zeros. Thelevel = 1readingc = fill/baseis the looser column, median ratio1.4129353, 1.2842149, 1.0955991, 1.1806066, 1.1372453, 1.276577, 1.1347487, 1.0320127, 1.0507079with largestabs(ratio - 1)0.24964and0.0821168at the two dense rungs, five times looser than the step at base 50, and the couplingzeta_F'(rho_0)/zeta'(rho_0)does not select it either,median abs(coupling - fill/base)reading0.24057225and0.08291158there againstmedian abs(coupling - 1)0.27619434and0.079335871, a flip between the two rungs while the candidates differ only by0.05and0.02. Nine zeros at the three sparsest designs have no located zero inside the trust region, predicted offsets0.95618855to3.0967393, so those rungs' medians are conditioned on Newton succeeding. The base 2 full set is the exact control,abs(zeta_F(rho_0))between1.85e-34and1.329e-25at all twelve zeros, soE_F = 0and both offsets are0. Witness: lab/py/zeta-shadow verb predict. - Verified The paired shadow offset carries its exponent in the missing-digit density rather than in
1 - alpha, and two new rungs sample the interval betweenalpha = 0.954and1. The median paired offset divided bym/base = 1 - fill/basereads1.6463532, 1.2495026, 1.8345578, 1.5731321, 2.2102406, 1.6634381, 2.2424916, 1.8779239, 1.051349across the nine rungs and divided by1 - alphareads1.7350628, 1.2495026, 1.6569184, 1.8951686, 3.1883019, 3.432954, 4.9008186, 5.4839111, 4.0716338; a least squares in the logs, a fit and not a theorem, gives(m/base)^1.04544atR2 0.957842against(1-alpha)^0.71691atR2 0.944011, the first column spanning2.13297and the second4.38888, som/basecarries the exponent by a factor of2.05764inside the4.28797that(1-alpha)/(m/base)itself spans over this ladder, which is the whole discrimination the two normalisations admit here. The new rungs are base 20 missing its top digit atalpha = 0.9828778777and base 50 missing its top digit atalpha = 0.9948357391, all six zeros located at each, medianabs(E_F(rho_0))0.11830158and0.028066806and median offset0.093896196and0.021026979, so the PAIRED offset falls fast across that interval; this bounds no maximum over the whole second family and touches no jump clause, since the pairing selects zeros for closeness to azetazero and censuses nothing. Read in the form of the family row, the mean distance from a located design ordinate to the nearestzetaordinate over a quarter of the mean gap between consecutivezetaordinates in the range gives0.81218635, 0.57141859, 0.50488757, 0.37447728, 0.20954319, 0.29197634, 0.14794812, 0.052888241, 0.011098646and0at the full set; the pairing is zeta-zero-first where the family row's is design-zero-first, so this is a parallel ladder and not that row recomputed. Witness: lab/py/zeta-shadow verb rungs. - Proved A positive Rouche margin proves exactly one zero of the design zeta in a disc about a pole, with every input bounded from the digit recursion itself. Write
Z(s_0+u) = P(u) + T(u)at a poles_0 = s_(0,j)with nonvanishing residue, whereP(u) = (1 - base^(-u)) D_(P-1)(s_0+u) + E_P(s_0+u)is entire with Taylor coefficients the exact finite sumssum_n n^(-s_0)(-log n)^m/m!convolved against those of1 - e^(-L u), andTis thel >= 1part of the ladder numerator, bounded onabs(u) <= R_2byB_T = sum_(l >= 1) binom(abs(s_0)+R_2+l-1, l) base^(-sigma-l) gamma_l G(sigma+l)atsigma = Re s_0 - R_2withGthe peeled majorant. Thatlsum is closed by a majorant ratio and not by an observed one, the term ratio itself not being monotone: sincegamma_(l+1)/gamma_l <= a_maxandG(sigma+l+1)/G(sigma+l) <= base^(-(P-1))because every string in the pools is at leastbase^(P-1), the term ratio is at mostR_l = ((abs(s_0)+R_2+l)/(l+1)) a_max base^(-P), which decreases inlonceabs(s_0)+R_2 >= 1and is belowa_max base^(-P)otherwise, so stopping at the firstlwithR_l < 1and addingterm_l R_l/(1-R_l)is a proof. Thenabs(Z_n) <= B_T/R_2^nforn >= 2beyond the explicit part, so onabs(u) = rhoone hasabs(Z - (Z_0 + Z_1 u)) <= sum_(m >= 2) abs(P_m) rho^m + B_T tau^2/(1-tau)withtau = rho/R_2, whileabs(Z_0 + Z_1 u) >= abs(Z_1) rho - abs(Z_0); when the first is strictly less than the second the linear model andZhave the same zero count inabs(u) < rhoby Rouche, and that count is one becauseabs(Z_0/Z_1) < rhofollows from the same inequality. Since the residue does not vanish,Z(s_0) != 0and the zero is a zero ofzeta_F. No step uses a differenced quantity:Z_0is the ladder value with its propagated bound andZ_1is the first Fourier mode ofTon a circle of radiusR < R_2withNsamples, whose aliasing is at most(B_T/R_2)(R/R_2)^N/(1-(R/R_2)^N), plus an exactp_1. The peel depthPand the radiirhoandR_2are free parameters of the proof. Witness: lab/py/zeta-locus, lab/py/design-zeta. - Verified The residue comb carries exactly one zero of the design zeta at eleven certified poles, the peel depth is the lever that decides which, and the certificate fails at every pole carrying none or two. Running the Rouche margin with the peel depth raised at each pole until the certificate fires or the string pool caps, over 106 poles at base 3, base 5, base 9, base 16 and base 10 missing 9 to
Im s = 40inside a fifteen minute budget, gives 11 certified, 60 failed, 7 residue-null and excluded because there the model's zero is the pole centre, a zero of the cofactor that is not a zero ofzeta_F, and 28 skipped when a design spent its budget. The certified eleven, with depth, margin and the radius the proof used: base 3{0,1}j = 2atP = 7,0.13418242,rho = 0.205;j = 5atP = 7,0.028140545,rho = 0.16;j = 7atP = 9,0.00082974181,rho = 0.175; base 5{0,1}j = 4atP = 7,0.15035818,rho = 0.2775;j = 5atP = 7,0.12269904,rho = 0.295; base 9{0,1,2}j = 5atP = 5,0.038456894,rho = 0.26; and base 10 missing 9 atj = 1, 2, 3, 4, 7, all atP = 3, margins0.047105507,0.030062806,0.045802462,0.043508323and0.046292701at radii0.1275, 0.105, 0.1025, 0.09, 0.0725, each on 24 contour samples. Every certified disc agrees with the argument principle count of one and none disagrees; of the 19 poles carrying zero or two zeros inabs(u) < 0.45that the budget evaluated none is certified, the two double poles reached, base 3{1,2}j = 3andj = 5, both failing, while base 5{1,2}j = 7and base 10j = 15were skipped for budget. Base 10 is not closed by any sharper majorant but by peeling: at the automatic depthP = 2itsB_Truns1.08atj = 1to38.1atj = 15, and atP = 3it runs0.2096to1.2010over the eight poles reached, five of which certify. Proximity of the tooth is no threshold, the certifiedabs(Z_0/Z_1)running0.0282669to0.149708and base 3{0,1}j = 7at0.104443failing atP = 7and certifying atP = 9. The margins are evaluated in high precision and not in ball arithmetic, which is the one step between this row and Proved. Witness: lab/py/zeta-locus. - Refuted The locus of the zeros of the design zeta is no curve
Re s = f(Im s)shared by designs of equalalpha, no comb in the pole-period residue, and no law inalphaandfill/base. The witness against a shared curve is a pair of zeros of nearly equal imaginary part and very different real part on two designs of equalalpha, which a single curve cannot carry: base 4{1,2}and base 16{0,1,2,3}, bothalpha = 1/2, hold zeros0.015058apart inIm snearIm s = 4.72and0.817047apart inRe s; base 4{0,1}against{2,3}, equal inalphaand infill/base, gives0.0136014against0.719693nearIm s = 17.64; base 4{0,1}against{1,2}gives0.0063091against0.280397nearIm s = 22.87and base 4{1,2}against{2,3}gives0.00638631against0.198012nearIm s = 31.79, each pair drawn from censuses of the same box and the same height. Equality of bothalphaandfill/basetherefore fixes nothing. Within one design the worst real-part gap between two zeros of equalfrac(Im s log base/2 pi)runs0.077591803at base 10 missing 9 to0.65632474at base 3{0,1}, so the fractional part fixes nothing either, and the zeros per period atalpha = 1/2reads1.1897445at base 16,1.2868204at base 9 and1.586326, 2.0395621, 2.0395621, 2.2661801at base 4, so no counting law inalphaalone survives. The single exception isalpha = 1, where the full digit sets atbase = 2, 3, 4are one arithmetic object and do share every zero. Witness: lab/py/zeta-locus. - Refuted The second family of the design zeta is not symmetric about any vertical line
Re s = c_F. Readingc_Fas the midpoint of the real parts of the two second-family zeros of leastIm sand testing the rest, no second-family zero in any design has a reflection partner: the reflection branch needs two second-family zeros within the0.05test tolerance inIm s, and the smallest ordinate gap inside a design is far above that on every design tested, so the branch cannot fire at all. Every pair the sweep records is a self-pair, a real part landing within0.05ofc_F, and self-pairs occur below the chance rate: over the ten designs recensused the tally is 8 self-pairs and 0 reflection partners of 47 zeros tested, a rate of0.170213against the0.229904that drawing each real part uniformly from that design's own observed band predicts, and over the full sweep 22 of 117. The three full-set controls pair 13 of 13 atc_F = 1/2to1e-22, where the functional equation makes every zero its own partner.c_Fis not a quantity either:c_F - alpha/2runs-0.28413232to+0.47788515andc_F - 1/2runs-0.78413232to+0.28664994, so it is notalpha/2, nottheta(F)and not1/2. Witness: lab/py/zeta-family verb symmetry. - Refuted There is no counting law for the second family in
alphaor infill, at either assignment radius. The four base 4 two-digit designs sharealpha = 1/2andfill/base = 1/2exactly and giveN_2(40) = 7, 13, 9, 14atrho = 0.45and6, 12, 8, 7atrho = 0.6, withN_2(80) = 20, 30, 22, 29and17, 26, 21, 20: a factor of two at onealphaand onefill/baseat both radii, so the refutation is radius-robust even though the integers are not. The subject of the spread is comb occupancy and not the second family, base 4{0,1}and{2,3}differing by 29 percent in total winding, 14 against 18, and by a factor of two inN_2because 7 of 8 poles are occupied against 4 of 8. Read asN_2(T) = c_F T log T + d_F Tfrom the two heights,c_Fatalpha = 1/2is0.10820213, 0.072134752, 0.072134752, 0.018033688, spread0.09016844, against the base 3 and base 4 full-set controls0.15486803and0.16230319, the classical1/(2 pi) = 0.15915494and a control spread of0.0074351582. Every winding is the nearest integer to a numerically integrated phase whose largest surviving step runs0.9205to0.9998against a cap of1, so the counts are Verified and not Proved. Witness: lab/py/zeta-family verbs tests and count. - Refuted The real parts of the second family do not contract to
alpha/2as a design fills, so the critical line is not thealpha -> 1limit of MrlyMath. The refuted law is thatmax abs(Re s - alpha/2) -> 0asalpha -> 1. Undivided, that statistic stays flat along the ladder carryingalphatoward 1, reading0.2275679549at base 5{0,1}withalpha = 0.430676558,0.5549589411at base 4{0,1}with0.5,0.5885444877at base 3{0,1}with0.630929754,0.4233198337at base 4{0,1,2}with0.792481250,0.5365616661at base 5{0,1,2,3}with0.861353116and0.3151426744at base 10 missing two with0.903089987, then collapsing to1.43e-22,1.10e-21and1.76e-22at the base 2, 3 and 4 full sets. At base 10 missing 9,alpha = 0.954242509, the second family reads0.216084781875to0.70401657869aboutalpha/2 = 0.477121255, a band of width0.488against1 - alpha = 0.0458. Divided by1 - alphathe statistic runs0.39971647to5.7047812with no monotone inalpha, falling from3.8699872to3.2519104on the last two rungs, so the refutation rests on the undivided spread and not on the ratio. Witness: lab/py/zeta-family verb limit. - Refuted The ordinate shadow does not explain why a design's ordinates converge before its real parts, because at the zeros it pairs it separates neither. The first-order offset is one complex number, so for a paired zero the ordinate offset and the real-part offset are one quantity with no preferred phase: per zero
abs(Im off)/abs(Re off)spans0.137681to6.11895at base 20 missing its top digit and0.14167to18.7749at base 50 missing its top digit, and rung by rung the mediansmedian abs(Im off)againstmedian abs(Re s - 1/2)read0.55734029/0.43095421, 0.49670656/0.28603903, 0.48081533/0.22535435, 0.30633741/0.16748977, 0.12823995/0.36138728, 0.25093621/0.12181102, 0.11574693/0.19332005, 0.058239278/0.049215607, 0.011954894/0.010995712atalpha = 0.430676558to0.994835739, the ordinate offset larger on six rungs and smaller on three with both falling along the ladder. The law binds only the zeros Newton reaches from azetazero inside1.5of it and this lab enumerates no design zero, so it neither explains nor forbids what a design-zero-first census reports; the census contrast and this row are both consistent with a mixture in which the partnered zeros approach in both coordinates while the rest of the second family does not approach at all, and that mixture has no witness until the unpartnered count is measured. Witness: lab/py/zeta-shadow verb rungs, lab/py/zeta-family verb limit. - Verified The peeled continuation of a digit-design Dirichlet series runs in double precision inside the public crate.
mrlynum::laddercarriesDesign,zeta,cofactorandresidueonmrlynum::design::elementsandmrlynum::zeta::Complex, and returns every value beside a bound. Against the arbitrary-precision lab at the base 2 full set the gaps are7.4e-11ats = 2,4.6e-14ats = 0.3 + 40iand7.5e-12ats = -1 + 2iagainst reported bounds3.8e-10,1.3e-11and6.8e-10; the base 3 residues meet the certified enclosures to3.8e-15against bounds near8e-14. Five adversary breaks are repaired and no pinned number moved. Witness: mrlynum::ladder, lab/py/design-zeta. - Proved The carried scale of a double-precision ladder majorises every intermediate magnitude of the value recursion, term by term. Beside the propagated truncation bound the module carries
scale_j = (sum_(n in E_P) n^(-Re w) + cut + sum_l abs(binom(-w,l) base^(-w-l) gamma_l) scale_(j+l)) / abs(1 - fill base^(-w)). The induction is immediate: the base entries start attail >= 0,poly_scale(E_P, Re w) >= abs(poly(E_P, w))term by term, and every step applies the same nonnegative weights and the same divisor modulus, soscale_j >= abs(value_j)at every level. Witness: mrlynum::ladder. - Verified The rounding charge of the double-precision ladder is measured and not counted, and it holds with a factor of fifteen to spare. The reported bound is
truncation + ROUNDING * scalewithROUNDING = 1e-13; a count of about 75 roundings over up to 115 levels gives9.5e-13, an order above the constant, so the charge is not a standalone bound. Measured over four designs at 28 points each plus the real axis the worst ratio of true error to returned bound is0.0667, atbase = 3,F = {0,1},s = 0.5 + 40i, and the error never exceeded the bound anywhere probed; on a rejected rung the truncation half carries the bound and that ratio reaches451. Witness: mrlynum::ladder. - Verified The wall of the double-precision port is cancellation and not truncation, and it is visible at
Re s = -1. Ats = -1 + 2ion the base 2 full set the truncation bound falls to1.1e-20at shift12and to7.8e-206at shift114while the carried bound sticks at5.6e-10, because the peeled tailG_P(-1+2i)has modulus5.6e3againstzeta_F(-1+2i)of modulus0.183, a loss of four and a half digits; the module raises rather than returns at any tolerance under that. The lab reaches2.8e-32there only by lifting the working precision with the height. Witness: mrlynum::ladder, lab/py/design-zeta. - Proved The residue column below a pole of a digit-design zeta is a finite recursion in the peeled variables, Burnol's Proposition 7.1 in peeled form. With
R_mthe residue ats_(m,j) = alpha - m + 2 pi i j / log base, taking residues in the peel identity atw = s_(m,j)killsE_Pand leaves only the terms whose shifted argument is a pole:(1 - base^m) R_m = sum_(l = 1)^m binom(-s_(m,j), l) base^(-s_(m,j)-l) gamma_l R_(m-l)withR_0the numerator overlog base, sincefill base^(-s_(m,j)) = base^m. At base 3 onF = {0,1}them = 1,j = 1value0.6950303416383606 + 0.37779086109705695imeets the eight-node contour average on a circle of radius0.05. Witness: mrlynum::ladder, REFS.md Burnol 2026. - Refuted The pole lattice does not force the zeros of a design zeta: at base 3
{0,1}the two polished zeros right of the abscissa are0.665639628004 + 23.0347504431 iand0.720787601477 + 28.6056765649 i, an ordinate gap of5.5709261against the pole period2 pi/log 3 = 5.7192017, short by0.148, because the shifted termssum_(l >= 1) binom(-s,l) base^(-s-l) gamma_l zeta_F(s+l)of the digit recursion are not2 pi i/log baseperiodic although1 - fill base^(-s)is. Witness: lab/py/zeta-locus verb census.
Transparent fraction
- Conjecture The common-box transparent fraction does not grow to
24.5%:GRID(n) = (n-1)/(4n)for oddnreproduces1/6, 2/9, 13/54, 27/110atn = 3, 9, 27, 55, reads0.2495463atn = 551and0.2499504atn = 5041, and its limit is1/4;24.5%is then = 55value, and atn = 0the normalization is undefined.
Walk dimension
- Verified Mass does not fix music: codes 127 and 239 share fill 7 and dimension
log(7)/log(3) = 1.771244with identical density at every level, yet their walk dimensions separate by about 0.39 (2.26 against 2.64), both generators agreeing and every drift bar an order of magnitude smaller than the gap. Witness: lab/rs/walk-dimension. - Conjecture Fixed mass does not fix the drum either: all nine fill-8 tiles recomputed at
side = 243andside = 729under both boundary conventions give centre1.2111, edge-midpoint0.9661, corner0.9634(shipped convention1.2093 / 0.9666 / 0.9633) at full held fraction, so the 0.25 spread is not a dropped-component artifact and "mass falls faster than stiffness" fails at exactly fixed mass.
Wallis sieve
- Proved The solid Wallis sieve, which drops the centre cube of every surviving cube cut into
(2k+1)^3at levelk, keeps the limit volumeprod_{n odd >= 3} (1 - n^(-3)) = pi^(3/2) / (8 |Gamma(7/4 - i sqrt(3)/4)|^2) = 0.948815486, by the Weierstrass product for1/Gammaafterm^3 - 1 = (m - 1)(m - w)(m - w^2)turns thek-th factor intok (k + (1 - w)/2)(k + (1 - w^2)/2) / (k + 1/2)^3with the three shifts summing to3/2; the plane sieve's limit area is Wallis'spi/4. Witness:mrlynum::sieve::solid_limit, evaluated by the log series to one ulp of0.9488154857196796, checked against the truncated product to1e-14and against the ratio formcosh(pi sqrt(3)/2) / (3 pi)over the even product. - Proved The Wallis sieve is a mixed-radix schedule word: letter
kis the side-(2k+1)tile with its centre cell removed, the word is their Kronecker fold, and the word's fill is the product of the letters' fills exactly, so any odd schedule in any dimension is a sieve with area the product of its letters' survival ratios. Witness:mrlynum::sieve::ratio, the raster count against the product at levels 1 to 3 in both schedules. - Proved A schedule of distinct odd letters buys area and a constant one buys a dimension: with strictly increasing odd sides
sum s_k^(-dim)converges, the limit area is positive and the odd word's fill exponentdim + log(ratio_level) / log(side_level)walks up todim(1.972027at plane level 4), while the constant side-sword's stands atlog(s^dim - 1) / log sforever (log 8 / log 3 = 1.892789for the carpet); a schedule that merely varies,3, 5, 3, 5, ..., loses its area and holdslog 192 / log 15 = 1.941432. Witness:mrlynum::sieve::exponent. - Verified The plane sieve's truncated product reads
0.785398262at two million factors againstpi/4 = 0.785398163, the identity being Wallis's. Witness:mrlynum::sieve::ratio, the test that pins its nine-digit rounding.
Waves
- Proved Riesz product: the DFT of a base-2 design mask popped at level
levelat frequencyxion anNtorus is the product overj = 0..level-1of the level-1 tile polynomialP(side^j xi / N)minus the tile centre value, since the offsets are digit sums and the exponential sum factorises; checked at codes 7, 6, 9 and levels 2 to 4 over all256 x 256frequencies, largest error2.5e-12, the subtracted term 1 for code 9 and 0 for codes 7 and 6. Witness: lab/py/kernel-waves. - Verified From the density-0.5 soup on the 256 torus, 64 steps at one seed, the Bugs, wide-survive and narrow-birth windows reach no ring still on the box
r = 5, 13masks or the design masks code 7 at levels 2 to 4 and codes 6 and 9 at level 3: 0 of 21 cells, 10 dead, 6 flat frozen soups, 5 active; a wide survive on a mask of 512 ones or more freezes the soup unchanged. Witness: lab/py/kernel-waves. - Verified On box
r = 5, carpet code 7 at levels 2 and 3 and diagonal code 9 at level 3 every one of 130 ring stills has its peak ringk*inside the mask first negative band of the ring-mean signed DFT,k*/k_2from 0.77 to 1.17,k*read on the ringsk <= 128which drop a fifth of the frequencies; as a universal law it fails on 3 of 176: boxr = 13atk* = 10, code 7 level 4 atk* = 2, code 6 level 3 atk* = 8. Witness: lab/py/kernel-waves. - Verified The carpet family median still wavelength over mask side is 0.729 at levels 2 and 3, equal to
256/k_2/sideat both; level 4 reads 0.790 against 0.632 where the 256 torus holds 3.2 mask widths. Witness: lab/py/kernel-waves. - Verified On the carpet cell graph at
level = 3, 512 cells on 4-neighbour adjacency with LaplacianD - A, the strong nodal domain counts of the returned eigenvectors are1, 2, 2, 4, 4, 4, 4, 5, 8, 8, 8, 8fork = 1..12with multiplicities1, 2, 2, 1, 1, 2, 2, 1, 2, 2, 1, 1, Courantnu_k <= kholds on all 512 at every zero tolerance from1e-12to1e-6, the spectrum has 380 classes at gap1e-8of which 130 are degenerate covering 262 indices with multiplicity up to 4, andnu_k / kfalls in five bins of width0.2as0, 42, 217, 193, 60at tolerance1e-9; counts for the returned basis only. Witness: lab/py/carpet-nodal. - Verified At
level = 4, 4096 carpet cells, the counts are1, 2, 2, 4, 4, 4, 4, 5, 4, 4, 8, 8with the same multiplicity pattern, where the4, 4atk = 9, 10rests on 64 cells at|v| = 1.4e-7in each returned vector and reads8, 8at tolerance1e-6as atlevel = 3; Courant holds on all 4096, the spectrum has 3056 classes of which 1022 are degenerate covering 2062 indices with multiplicity up to 20, the bins are24, 797, 2061, 971, 243, and the top eigenvector has 12 cells below the zero tolerance so its printed count is 4084 while no edge joins two nonzero cells of one sign. Witness: lab/py/carpet-nodal. - Verified The nodal count on a degenerate eigenvalue is basis-dependent: at the double eigenvalue
k = 6, 7of the carpet cell graph the two returned vectors have 4 strong nodal domains each and their normalised sum and difference have 6 each, atlevel = 3andlevel = 4alike, and such a disagreement occurs at 108 of the 129 double eigenvalues atlevel = 3and 971 of 1021 atlevel = 4. Witness: lab/py/carpet-nodal. - Proved By the discrete nodal domain theorem every eigenvector of an eigenvalue of index
kand multiplicityron a connected graph has at mostk + r - 1strong and at mostkweak nodal domains, so at the double eigenvaluek = 6, 7of the carpet cell graph atlevel = 3andlevel = 4, index 6 and multiplicity 2 read at gap1e-8, no vector of the eigenspace has more than 7 strong domains, and the returned basis sum and difference reach 6. Witness: lab/py/carpet-nodal. - Verified On the control grids
22 x 22and64 x 64the separable cosine basis has exactly(p + 1)(q + 1)strong nodal domains on all 484 and all 4096 eigenvectors, the returned basis satisfies Courant on all of them with degenerate index fractions0.9566and0.9846and multiplicity up to 21 and 63, and the mean ofnu_k / koverk >= 2at tolerance1e-9is0.605and0.536on the carpet (0.602to0.610atlevel = 3across tolerances1e-12to1e-6) against0.508and0.465on the separable grid and0.433and0.330on the returned grid basis. Witness: lab/py/carpet-nodal. - Conjecture A Larger-than-Life still sits where the kernel ring-mean transform is negative because a pattern there has its count anti-correlated with its state, which a birth window below the mean and a survive window above it hold fixed; the correlation is
-0.52to-0.85on the strongest stills of the four lobe masks; a proof, a 1024 torus for the side-81 mask and the cross mask lobe are open. Witness: lab/py/kernel-waves. - Refuted The wavelength of a ring still is the mask width,
k*at the first minimumk_minof the mask ring-mean transform: over 180 window rules at two seeds, 2520 runs and 176 ring stills,k*sits within one ring ofk_minin 25, 21 of them on the under-resolved side-81 mask; witness boxr = 5, all 25 ring stills atk* = 30..36againstk_min = 24andk_2 = 32, wavelength 7.1 to 8.5 cells for a mask 11 wide. Witness: lab/py/kernel-waves. - Refuted One
k*per mask across rules: boxr = 5spreadsk* = 30..36over the grid rules and seeds, one rule alone reading 32 at one seed and 36 at the other; the spread is up to two fifths (10 to 14 on carpet level 3) and never leaves the mask negative lobe on the four masks where the lobe law holds. Witness: lab/py/kernel-waves. - Verified The FFT count step on a power-of-two torus agrees cell for cell with the direct neighbour count under a wrap boundary, on the Moore mask and the level-2 carpet mask over 8 steps. Witness: mrlydemo::chladni against mrlymath::life::next_grid.
- Verified Under the wide-survive window rule, the Bugs birth with
S[0.28, 0.60], from a density-0.5 soup on a 256 torus, the three masks of 512 cells or more in the sweep, the boxr = 13at 728 cells and code 7 at levels 3 and 4, freeze the soup unchanged. Witness: lab/py/kernel-waves.
Weighted designs
- Proved For a weighted design (a probability vector on
|F| >= 2cells) the Dirichlet root ofsum_f w_f^s = 1is identically1, so it is the arithmetic class of thelog w_f, never the root, that carries the mass-stopping countN(t) = #{words of mass >= t}:Nis log-periodic exactly when the group generated by thelog w_fis cyclic (for rational weights, when the prime-exponent matrix has rank 1) and smooth otherwise, by Lalley's renewal dichotomy onf = -log w; and every length observable keeps itslog baseripple at every weight,mu(B(r)) = w_0 mu(B(qr))at a corner fixed point forr < min_{f != 0} |f|/base. Witness: lab/py/weighted-designs. - Verified The multifractal pressure of a weighted design with equal contraction
1/baseunder the open set condition istau(s) = log(sum_f w_f^s)/log(base), sof(alpha) = inf_s (alpha s + tau(s))is explicit: the box moments at levellevelcarry it exactly assum_i mu_i^s = (sum_f w_f^s)^level, the coarse-grained band sits under the transform at every level (f_level <= ffromN_i mu_i^s <= base^(level tau(s))), exact at both endpoints and deficient by0.176458, 0.147536, 0.127619at the band's middlealpha = 1.077324384at levels 6, 8, 10 on the three-cell weighted gasket (base 3, cells(0,0) (2,0) (0,2), weights3/8, 3/8, 1/4), the deficit matching Stirling's series, and the JSR bracket validates on the hat mask atalpha = 1and on D4 atalphain[0.4929285, 0.5500157]against the closed form2 - log_2(1 + sqrt 3) = 0.5500157. Witness: lab/py/weighted-designs, Cawley and Mauldin 1992. - Refuted That
delta, the Dirichlet root, is a weight observable of a design (it is1at every probability vector), and that a norm upper bound may print truncated: D4's norm upper is0.710581107211, so the safe print is0.7105812andalpha's upper0.5501at four digits,0.5500sitting strictly below the closed form0.5500156865. Witness: lab/py/weighted-designs. - Refuted The Type II route through the multiplicative energy of a column: with
|a|, |b| <= 1, two Cauchy-Schwarz steps give|Sigma|^2 <= M E_x(M, N) <= 2MN E_x(level)^(1/2) x^(o(1)), hence|Sigma| <= x^((1 + alpha)/2 + o(1)), missing the trivialx^alphaby(1 - alpha)/2for every digit set withalpha < 1; the unbalanced sum has no estimate at all sincea = b = 1returns the representation count itself, and the balanced form returns the box's own trivial bound on the census (bound over trivial1.0134atlevel = 12rising to1.0730atlevel = 14). Witness: lab/rs/rho-decoupling (themenergymodule), mobius.md THE METER AND ITS YARDSTICK.