
Spectra
The diagonal slice of a cube fractal is a hexagon with a tile grammar. Everything published about that grammar stops at base 3; this page asks what happens at every other odd base.
- The base axis is the open thread. The dimension axis - the same
d - 1comparison run alongDat fixed base 3 - is settled and lives on the shelf. - The spectra demo draws the Laplacian of a design, its degenerate families and the slope that reads the spectral dimension.
- Every number on this page is regenerated by
lab/odd-base-slice-grammar, a raster-free digit recursion cross-checked against a direct layer census. What stays Conjecture is the grammar itself: a2x2map reproducing cell counts is weaker than a substitution acting on tiles, and only base 3 has the latter from a source.
WHAT IS KNOWN
Cited facts only.
- The cut is Perez-Duarte's. "Slice of Menger", showing "a very interesting pattern of stars and hexagons" (Flickr), credited directly by Abel.
- Hart popularised it in Mathematical Impressions, with a Scientific American mirror.
- Cook published working code, applying the base-3 digit predicate to a plane through the cube's centre (Cook 2011). Its prose says the normal runs to
(1, 1, 1)while the listing setsnormal = (1, 1, 0.5), so the published plane is not the centroid diagonal. - The substitution rule is Abel's, verbatim: "replace each hexagon with 6 hexagons and 6 triangles, and replace each triangle with 1 hexagon and 3 triangles". As a matrix on
(hexagons, triangles)that is[[6,1],[6,3]], trace 9, determinant 12. - The dimension is Abel's, and he states it as a computation rather than a proof:
3^d = (9+sqrt(33))/2, sod = log_3((9+sqrt(33))/2) = 1.8184, with the hedge "it takes a bit more work to turn the above computation into a full proof". - A299916 counts holes, not tiles. Its name is
a(n) = A299914(2n+1), offset 0, terms1, 6, 42, 306, 2250, 16578, 122202, signature(9,-12); the Menger reading is a comment on the entry, not the definition. That the two are the same object is Proved, by the hexagram bijection in cuts, and the index shift is load-bearing: the mesh-triangle census isA299916(n+1). - The two-tile move is published at base 3. Hocking's Bridges paper, resolved in REFS, treats the base-3 slice as a closed fractal family on a hexagon and a triangle, which is a directed-graph iterated function system under another name. What is unpublished is every other base.
- The nearest real theory looks elsewhere. Slice dimension is solved for almost every plane (Marstrand 1954, Mattila 1975); the centroid diagonal is a single maximally arithmetic plane, exactly the case those theorems exclude. So a plane landing off
d - 1contradicts nothing and dodges no theorem. - The upstream is grey literature. A photograph, a video, three blog posts and an OEIS comment. Adjacent work does not close the gap: one generalisation runs along dimension, another changes the solid, and none touches base 5, 7 or 9.
THE CLAIM
- Conjecture. For every odd base
b, the centroid diagonal slice of the parity solidmrly_bang_d3_23is a graph-directed set on exactly two tiles, whose2x2integer substitution matrix is a fixed rational function ofbwithin each class ofb mod 4, and whose slice dimension sits aboved - 1whenb = 3 mod 4and below it whenb = 1 mod 4. - The method builds no raster. The plane
x + y + z = 3*b^L/2meets three diagonal layers and the coordinate sum splits assum_k b^k * sigma_kover independently chosen digit triples, so the tile census is a memoised digit recursion with nothing allocated. - The four rules. Verified by
lab/odd-base-slice-grammar; that they are tile grammars is the claim above. Two-term rulesx9 -12atb = 3,x11 +62at 5,x42 -288at 7,x28 +693at 9, with dimensions1.8184 / 1.6869 / 1.8026 / 1.7204againstd - 1 = 1.7268 / 1.7304 / 1.7430 / 1.7544. - Their arithmetic is only self-consistent: each printed dimension is
log_bof the dominant root of its own printed rule, so a wrong rule and its own wrong dimension agree by construction. - The base-3 rung is the one external target, and it passes. Verified. A cold census returns Abel's
[[6,1],[6,3]]and hexagons1, 6, 42, 306, 2250, 16578, 122202; the grammar cannot be fitted to that. - The matrices. Verified by
lab/odd-base-slice-grammar.[[7,3],[30,4]]atb = 5,[[30,3],[24,12]]at 7,[[19,9],[96,9]]at 9, all non-negative, reproducing cell counts level after level. Counts obeying a fixed2x2map is weaker than a substitution acting on tiles, and onlyb = 3has the latter from a source. - The closed form. Verified at
b = 3..21bylab/odd-base-slice-grammar; every oddbis the claim above. On(hexagons, triangles):[[3(b+1)(3b-1)/16, (b+1)(b+5)/32], [3(b+1)^2/8, 3(b+1)^2/16]]whenb = 3 mod 4, and[[(3b^2+6b+7)/16, 3(b-1)(b+3)/32], [3(b-1)(3b+5)/8, (b+3)^2/16]]whenb = 1 mod 4. Both reproduce every census matrix atb = 3..21. - What would falsify it. Any odd base whose slice needs a third tile symbol; any census breaking its own two-term recurrence past the fitted levels; any base where the mod-4 side is wrong.
- What a result would be worth. No candidate row returns an OEIS hit, and no paper treats the diagonal cross-section at any base but 3. A confirmed row at
b = 5is new; an unconfirmed one is a number in a file.
OPEN QUESTIONS
- Which sponge is the base-
bsponge? Cook's predicate is "at most one coordinate in the middle third"; this page inherits "at most one odd coordinate" frommrly_bang_d3_23. The two agree atb = 3and nowhere else, and there is no canonical base-5 Menger sponge, so the whole generalisation rests on an unstated choice. - The choice is not cosmetic, and the two rules land on opposite sides. Verified. At
b = 5,D = 3the middle-digit rule fills112of125and its central diagonal slice sits ABOVEd - 1, excess+2.888e-02withdim_slice = 1.960651against1.931768; the odd-coordinate rule fills81of125and sits BELOW,1.6869against1.7304. Nod - 1claim atb = 5can be quoted without naming the rule. - Does the mod-4 split have a mechanism, or is it numerology? Conjecture. It holds at every odd
bup to 401 by exact rational comparison inlab/odd-base-slice-grammar, so it is not four data points. The candidate mechanism - the middle diagonal layer sits at coordinate sum3*(b-1)/2, odd exactly whenb = 3 mod 4, forcing a different parity of cell into the middle layer in each class - is unwritten and unchecked. - The split is a property of the rule as well as the base. The mod-4 statement is about the odd-coordinate solid, and the middle-digit solid contradicts it at
b = 5. Any statement of it must pin base, dimension and digit rule before it means anything. - Is the two-tile grammar geometric, or only arithmetic? Reproducing cell counts is weaker than a substitution acting on tiles, and no source supplies the latter past
b = 3. - Does the base axis factor at all? cuts walks the dimension axis at fixed base 3 and has a theorem there: the order law, from a factorisation of the digit polynomial. The same three-step argument - digit polynomial, carry contraction, palindromic symmetry - is what the two-tile claim has never been given, and it is exactly the kind of statement that would decide the mod-4 split.
WHERE THE REST LIVES
- The dimension axis at fixed base 3: the
ceil(D/2)order law, the product formula over 3-adic angle towers, and the unconditional pinning|rho_D - fill/3| <= 2(D-1)/3are thecarlomitchener/research/slice-recurrence-orderlane. - The sign law in every even dimension at bases 3 and 5, the certificate machines, the transient constant
ln(R)/4, the tent rank law and the layer-2 window law are thecarlomitchener/research/slice-sign-even-halflane. - The layer-2 window itself - its generator
g_D, its ceilingC_D, the family shift law and the corrector law behind them - is regenerated bylab/smith-window. - So are the two statements that close the corrector law. Law E's slot has length
N = J(e) - J(e-1)and a positionpmeasured from the octave centre; the tent identity ismin(p, N - 1 - p) = C_D - deg g_D, and the reach law isreach = R - jmax = 3 min(p, N - 1 - p) + 2 [e even] + [k odd](1 + p mod 2), with one row per odd octave escaping it atD = 4^m + 3. - Off those escaping rows
floor(reach/3) = C_D - deg g_D + [k odd and e even]; on them it reads1againstC_D - deg g_D = K - deg g_D = 0, somin(K - deg g_D, floor(reach/3)) = C_D - deg g_Dat every row and the corrector law's statement reads off(b, e, k, R)with no span test in it. The deduction behind it still carries one. - The carry matrix
M_evenis defined once, in cuts, and is not redefined here. - The hexagram bijection and the mesh census: cuts. The hexagon mesh itself: slices. The fill polynomial of
mrly_bang_d3_23: method. - Every finding on a tagged line: DISCOVERIES. Every source resolved: REFS.